A charge (uniform linear density = 8.8 nC/m) lies on a string that is stretched along an x axis from x = 0 to x = 3.1 m. Determine the magnitude of the electric field at x = 5.2 m on the x axis.

Answer:

Explanation:

Load ( L ) = 800 N

Effort ( E ) = 200 N

Load distance ( LD ) = 10 cm

Effort distance ( ED ) = ?

now, Let's find the effort distance:

[tex] \mathsf{L \times LD = E \times ED}[/tex]

Plug the values

[tex] \mathsf{800 \times 10 = 200 \times ED}[/tex]

Multiply the numbers

[tex] \mathsf{8000 = 200 \: ED}[/tex]

Swipe the sides of the equation

[tex] \mathsf{200 \: ED = 8000}[/tex]

Divide both sides of the equation by 200

[tex] \mathsf{ \frac{200 \: ED }{200} = \frac{8000}{200} }[/tex]

Calculate

[tex] \mathsf{ED \: = \: 40 \: cm}[/tex]

Hope I helped!

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Answer:

Fnet = F√2

Fnet = kq²/r² √2

Explanation:

A exerts a force F on B, and C exerts an equal force F on B perpendicular to that.  The net force can be found with Pythagorean theorem:

Fnet = √(F² + F²)

Fnet = F√2

The force between two charges particles is:

F = k q₁ q₂ / r²

where

k is Coulomb's constant, q₁ and q₂ are the charges, and r is the distance between the charges.

If we say the charge of each particle is q, then:

F = kq²/r²

Substituting:

Fnet = kq²/r² √2

Answer:

20 N

Explanation:

In air, the normal force is equal to the weight.

∑F = ma

N − mg = 0

N = mg

Submerged in water, the normal force is equal to the weight minus the buoyant force:

∑F = ma

B + N − mg = 0

N = mg − B

Plugging in values:

80 N = 100 N − B

B = 20 N

Answer:

173psig

Explanation:

The storage cylinder of recovered R-410A is mixture of difluoromethane and pentafluoroethane which is used as a refrigerant in air conditioning application. The refrigeration sector has low temperatures for installation. The pressure of cylinder at 80 F will be 173 psig. The pure refrigerants have inside a container have saturation temperature which is equal to ambient temperature.

A containment canister of recovered r-410a has an estimated pressure of 173psig.

The retrieved R-410A preservation container is a blend of difluoromethane and pentafluoroethane, that is used as a compressor in air conditioning systems.

Assembly conditions in the freezer industry are extremely low. At 80 degrees Fahrenheit, the cylinder pressure will be 173 pounds per square inch.

The specific heat capacity of pure refrigeration systems within a cylinder is the same as the room temperature.

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Answer:

B. 0.2 J/g/°C

Explanation:

The solid phase is the first segment (from 0°C to 50°C).

q = mCΔT

200 J = (20 g) C (50°C)

C = 0.2 J/g/°C

Answer:

Its inductance L = 166 mH

Explanation:

Since a current, I = 0.698 A is obtained when a voltage , V = 5.62 V is applied, the resistance of the coil is gotten from V = IR

R = V/I = 5.62/0.698 = 8.052 Ω

Since we have a current of I' = 0.36 A (rms) when a voltage of V' = 35.1 V (rms) is applied, the impedance Z of the coil is gotten from

V₀' = I₀'Z where V₀ = maximum voltage = √2V' and I₀ = maximum current = √2I'

Z = V'/I' = √2 × 35.1 V/√2 × 0.36 V = 97.5 Ω

WE now find the reactance X of the coil from

Z² = X² + R²

X = √(Z² - R²)

= √(97.5² - 8.05²)

= √(9506.25 - 64.8025)

= √9441.4475

= 97.17 Ω

Now, the reactance X = 2πfL where f = frequency of generator = 93.1 Hz and L = inductance of coil.

L = X/2πf

= 97.17/2π(93.1 Hz)

= 97.17 Ω/584.965 rad/s

= 0.166 H

= 166 mH

Its inductance L = 166 mH

Answer:

True

Explanation:

Thats is true since it cannot be a vector because speed only gives a magnitude, not a direction as well.

Answer:

What separates athletes from their competitors is the word itself, separation — gaining it on the offensive side, or taking it away on the defensive side (There are exceptions of course, one being the contest of offensive linemen and defensive linemen in football where the inverse is true). Speed, strength, and power are great ways to create separation in sports. However, speed, strength, and power all have genetic ceilings

Answer:

The name of the force is elastic (spring) force

Explanation:

The elastic force which is the restoration force of an elastic (spring like) object that tries to return to its initial non-stretched state built up by the pulling of the bow by the archer (using the muscles) pushes on the arrow which the archer releases the same time he leaves the bow string, and the arrow flies in the direction already pointed by the archer

The arrow ultimately falls down due to gravity forces that acts on all objects within the Earths gravitational field. However due to the speed of constant horizontal speed of the arrow and increasing downward speed of the due to the gravity force, the falling of the arrow looks disappointing.

Answer:

490Nm

Explanation:

Given the following :

Mass of rock = 5kg

Height or distance = 10 meters

A rock with mass of 5kg is carried up a small hill 10 meters high. how much work had to be done in carrying the rock up hill?

Workdone is product of force and distance.

Workdone = force * distance

Recall :

Force = mass * acceleration due to gravity (g)

g = 9.8m/s^2

Force = 5 * 9.8 = 49 N

Therefore,

Workdone = 49 × 10 = 490Nm

Answer:

x = 27.3 m

Explanation:

This is a projectile launching exercise, let's start by looking for the time it takes for the rock to reach the height of the window.

Let's use trigonometry to find the velocities of the rock

           sin 40 = [tex]v_{oy}[/tex] / v

           cos 40 = v₀ₓ / v

           v_{oy}= v sin 40

           v₀ₓ = v cos 40

           v_{oy} = 30 sin 40 = 19.28 m / s

           v₀ₓ = v cos 40

           v₀ₓ = 30 cos 40 = 22.98 m / s

we look for the time

        [tex]v_{y}^2[/tex] = v_{oy}^2 - 2 g y

         v_{y}^2 = 19.28 2 - 2 9.8 16 = 371.71 - 313.6 = 58.118

        v_{y} = 7.623 m / s

we calculate the time

          v_{y} = v_{oy} - gt

          t = (v_{oy} - v_{y}) / g

          t = (19.28 -7.623) / 9.8

          t = 1,189 s

since the time is the same for both movements let's use this time to find the horizontal distance

           x = v₀ₓ t

           x = 22.98 1,189

           x = 27.3 m

Explanation:

The answer is option B

The number of reactant molecules and product molecules is even.

Answer:

$876.96

Explanation:

The energy used is:

3500 W × (24 hr/day) × (120 day) × (1 kW / 1000 W) = 10,080 kWh.

So the cost is:

10,080 kWh × ($0.087 / kWh) = $876.96

Answer:

proton and neutron respectively.

Explanation:

Atoms of the same element will always have the same number of proton but will have different numbers of neutron if their mass numbers are different.

Answer:

Reproducible by other scientists

Explanation:

I just took the test

Answer:

[tex]\huge\boxed{Divide\ distance \ by \ time}[/tex]

Explanation:

Speed = Distance / Time

So, to find distance, we actually divide distance by rime.

Answer:

[tex]\large \boxed{\mathrm{divide \ distance \ by \ time}}[/tex]

Explanation:

Using the formula to calculate speed:

[tex]\displaystyle \sf speed =\frac{distance}{time}[/tex]

We divide the distance by the time taken to get the average speed.

Answer;

7.238°

Explanation

From question we know that the grating has 1,970 grooves per centimeter, we can convert to from (cm) to (nm) for unit consistency

The slit separation is expressed below

d=1cm/1970

d=0.0005076

=5076nm

Then the angle (in degrees) that the red light of wavelength 640 nm appear in first order can be calculated using expression below

Sin(x)= mλ/d

Where λ= wavelength=640 nm

d=slit separation

Sin(x)= mλ/d

Sin(x)=(1×640)/5076

=0.126

sin-1(0.126)

X= 7.238°

Therefore,the angle (in degrees) that the red light of wavelength 640 nm appear in first order is 7.238°

It isn't best to wear loose fitting clothing when exercising, as you may not feel too comfortable. It depends on the person. However there are a few advantages.

• Tight clothing may not be comfortable as well

• Looser clothing allows easy evaporation of sweat

Then again when it says " loose - fitting " it may mean not too baggy. Baggy clothing can have an impact on your physical activity.

Answer All of the above

For people on a p e x

Answer:

D

Explanation:

because light has no space nor mass

Explanation:

Given that,

Number of loops are 3

Length of slinky is 3.75 m

They time 20 oscillations in  6.73 s.

We need to find the wavelength of  the standing wave.

For 3 loops, [tex]L=\dfrac{3\lambda}{2}[/tex]

Here, [tex]\lambda[/tex] is the wavelength of the standing wave

So,

[tex]\lambda=\dfrac{2L}{3}\\\\\lambda=\dfrac{2\times 3.75}{3}\\\\\lambda=2.5\ m[/tex]

So, the wavelength of the standing wave is 2.5 m.

Find answers and explanations in the attachments

Answer:

Explanation:

) (C) Suppose the piston is fixed. Find the energy input required to raise the temperature to 700 K.

Answer:

The area of the sheet of metal = 4.255 m²

The volume of the sheet of metal = 0.08553 m³

Explanation:

The area of a rectangle is given by the following relation;

Area, A = Length × Breadth

Therefore, the area of the rectangular sheet of metal, A[tex]_m[/tex], is given as follows;

A[tex]_m[/tex]  = 4.234 m × 1.005 m = 4.255 m²

The area of the sheet of metal = 4.255 m²

The volume of the metal sheet id given by the relation, volume V[tex]_m[/tex]= area × Thickness

The thickness of the sheet of metal = 2.01 cm = 0.0201 m

Therefore,

V[tex]_m[/tex] = 4.255 m × 0.0201 m = 0.08553 m³

The volume of the sheet of metal = 0.08553 m³.

Answer:

Are yarr mei bhi Indian hu.....

Explanation:

Tumse milkar accha laga

Answer:

The angle the projectile was fired is [tex]45^o[/tex]

Explanation:

Recall the formulas for maximum height and ranges for a projectile fired with initial velocity "v" at an angle [tex]\theta[/tex]:

[tex]h = \frac{v^2\,sin^2(\theta)}{2\,g}\\R=\frac{v^2\,sin(2\,\theta)}{g}[/tex]

we can use them to solve for the angle by first isolating the value [tex]v^2[/tex] which is common in both equations:

[tex]v^2=2\,h\,g/sin^2(\theta)=2\,(15)\,g/sin^2(\theta)=30\,(g)/sin^2(\theta) \\ \\v^2=R\,g/sin(2\,\theta)=60\,(g)/sin(2\,\theta)[/tex]

and now, making those to expressions equal and using the formula for the sine of a double angle, we get:

[tex]\frac{30\,(9.8)}{sin^2(\theta)} =\frac{60\,(g)}{sin(2\,\theta)} \\30\,(g)\,sin(2\,\theta)=60\,(g)\,sin^2(\theta)\\sin(2\,\theta)=2\,sin^2(\theta)\\2\,sin(\theta)\,cos(\theta)=2\,sin(\theta)\,sin(\theta)\\cos(\theta)=sin(\theta)[/tex]

This happens when [tex]\theta=45^o[/tex]  

Answer:

The reading of the vernier calliper is 3.93 mm

Explanation:

The given instrument is a micrometer screw gauge that has a main scale reading and a vernier scale reading

The the question, we have;

The individual divisions of the main scale = 0.5 mm

The reading on the main scale = 3.5 mm

The reading on the vernier scale = 43

The accuracy of the vernier caliper = 0.01

Reading on the vernier scale multiplied by the accuracy of the vernier caliper = 43 × 0.01 = 0.43 mm

The reading of the micrometer screw gauge = The reading on the main scale + Reading on the vernier scale multiplied by the accuracy of the vernier caliper

Therefore, the reading of the micrometer screw gauge = 3.5 + 0.43= 3.93 mm

The reading of the vernier calliper = 3.93 mm.

Answer:

C. sound energy

Explanation:

hope this helps

Answer:

The distance Mr Franklin applied the force is 400 m

Explanation:

The efficiency of the machine = 80%

The force applied by the machine = 800 N

The distance over which the force is applied by the machine = 20 m

The force applied by Mr. Franklin = 50 N

The work done by the machine = 800 × 20 = 16000 J

The ideal work at 100% efficiency = X

80% of X = 16000 J

X = 16000 N/0.8 = 20,000 J

Therefore, we have have;

Work = Force × Distance;

20,000 J = 50 N × Distance Mr Franklin applied the force

Distance Mr Franklin applied the force = 20,000 J/(50 N) = 400 m

The distance Mr Franklin applied the force = 400 m.

Answer:

the awnser in 400m

Explanation:

did the test on edge 2020 and got it right

Answer:

number 6 is wrong

the answer is pesticides

2.combines are used for harvesting or threshing.so number 2 is wrong

at least you tried

Explanation:

there is no such thing as weedicides

Answer:

1. True

2.True

3.False

4. True

5. True

6.False

7.False

8.True

9.False

10.False

Answer:

The angular frequency of the block is ω = 5.64 rad/s

Explanation:

The speed of the block v = rω where r = amplitude of the oscillation and ω = angular frequency of the oscillation.

Now ω = v/r since v = speed of the block = 62 cm/s and r = the amplitude of the oscillation = 11 cm.

The angular frequency of the oscillation ω is

ω = v/r

ω = 62 cm/s ÷ 11 cm

ω = 5.64 rad/s

So, the angular frequency of the block is ω = 5.64 rad/s

Answer:

OPTION (C)

Explanation:

m(magnification) = -0.4 means a real, inverted and diminished image is formed in front of the mirror.

Answer:

0.699 L of the fluid will overflow

Explanation:

We know that the change in volume ΔV = V₀β(T₂ - T₁) where V₀ = volume of radiator = 21.1 L, β = coefficient of volume expansion of fluid = 400 × 10⁻⁶/°C

and T₁ = initial temperature of radiator = 12.2°C and T₂ = final temperature of radiator = 95.0°C

Substituting these values into the equation, we have

ΔV = V₀β(T₂ - T₁)

= 21.1 L × 400 × 10⁻⁶/°C × (95.0°C - 12.2°C)

= 21.1 L × 400 × 10⁻⁶/°C × 82.8°C = 698832 × 10⁻⁶ L

= 0.698832 L

≅ 0.699 L = 0.7 L to the nearest tenth litre

So, 0.699 L of the fluid will overflow