Answer:
For (1): The correct option is (a)
For (2): The correct option is (a) and 333.6 kJ of heat will be absorbed when 70.9 g of ammonia reacts.
Explanation:
There are 2 types of reactions that are classified based on enthalpy change:
Endothermic reactions: These are the reactions where heat is absorbed by the reaction. The change in enthalpy of the reaction, [tex]\Delta H_{rxn}[/tex] is positive for these reactions.
Exothermic reactions: These are the reactions where heat is released by the reaction. The change in enthalpy of the reaction, [tex]\Delta H_{rxn}[/tex] is negative for these reactions.
For (1):For the given chemical reaction:
[tex]2NH_3(g)\rightarrow N_2(g)+3H_2(g);Delta H=160kJ[/tex]
As the change in enthalpy or heat of the reaction is positive. Thus, the reaction is an endothermic reaction because heat is absorbed by the reaction.
For (2):When ammonia reacts, some amount of heat will be absorbed by the reaction. Thus, we can say the heat will be absorbed.
The number of moles is calculated by using the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of ammonia = 70.9 g
Molar mass of ammonia = 17 g/mol
Using equation 1:
[tex]\text{Moles of ammonia}=\frac{70.9g}{17g/mol}=4.17mol[/tex]
By stoichiometry of the reaction:
If 2 mole of ammonia reacts, the heat absorbed is 160 kJ
So, if 4.17 moles of ammonia reacts, the heat absorbed will be = [tex]\frac{160kJ}{2mol}\times 4.17mol=333.6kJ[/tex]
Hence, 333.6 kJ of heat will be absorbed when 70.9 g of ammonia reacts
Organic foods do not contain chemicals.
True
Or
False
Answer:
True
Explanation:
The word Organic refers to the methods used to cultivate and process farm agricultural products. Organic foods are edible and nutritious substances consumed (both plants and animals) that are free from the use of synthetics and chemicals. In plants, the include the use of organic manure that serves as fertilizers and carrying out the weeding process by hand weeding. In animals, diseases can be prevented by maintaining a clean house or rotational grazing.
The benefit of organic foods are to produce food substances with no chemical substances.
Please help
Why are different products formed in the combustion of butane ?
Explain please thanks :)
Consider the following equilibrium:
2H2(g)+S2(g)⇌2H2S(g)Kc=1.08×107 at 700 ∘C.
What is Kp?
Answer:
Consider the following equilibrium:
2H2(g)+S2(g)⇌2H2S(g)Kc=1.08×107 at 700 ∘C.
What is Kp?
Explanation:
Given,
[tex]Kc=1.08 * 10^7[/tex]
The relation between Kp and Kc is:
[tex]Kp=Kc * (RT)^d^e^l^t^a^(^n^)[/tex]
Where delta n represents the change in the number of moles.
For the given equation,
The Delta n = Number of moles of products - number of moles of reactants
(2-(2+1))
=-1.
Hence,
Kp=Kc/RT.
Thus,
[tex]Kp=1.08 * 10^7 / 8.314 J.K6-1.mol^-^1 x 973 K\\Kp=1335.06[/tex]
The answer is Kp=1335.06
The value of [tex]K_p[/tex] is [tex]1.35\times 10^5[/tex].
Explanation:
The relation between [tex]K_p \& K_c[/tex] is given by:
[tex]K_p=K_c(RT)^{\Delta n_g}[/tex]
Where:
[tex]K_c[/tex] = The equilibrium constant of reaction in terms of concentration
[tex]K_p[/tex] = The equilibrium constant of reaction in terms of partial pressure
R= The universal gas constant
T = The temperature of the equilibrium
[tex]n_g[/tex]= Change in gaseus moles
Given:
An equilibrium reaction, 700°C:
[tex]2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g),K_c=1.08\times 10^7[/tex]
To find:
The equilibrium constant in terms of partial pressure, [tex]K_p[/tex].
Solution:
The equilibrium constant of reaction in terms of concentration= [tex]K_c[/tex]
[tex]K_c=1.08\times 10^7[/tex]
The equilibrium constant of reaction in terms of partial pressure =[tex]K_p=?[/tex]
The gaseous moles of reactant side = [tex]n_r= 3[/tex]
The gaseous moles of product side = [tex]n_p= 2[/tex]
The temperature at which equilibrium is given = T
[tex]T = 700^oC+273.15 K=973.15K[/tex]
The change in gaseous mole = [tex]n_g=n_p-n_r=2-3 = -1[/tex]
[tex]K_p=1.08\times 10^7\times (0.0821 atm L/mol K\times 973.15 K)^{-1}\\K_p=1.35\times 10^5[/tex]
The value of [tex]K_p[/tex] is [tex]1.35\times 10^5[/tex].
Learn more equilibrium constants here:
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Rank the following substances/solutions in order of lowest boiling point to highest boiling point where 1 has the lowest boiling point and 5 has the highest boiling point. pure water; 1.0 m NaCl; 0.5 m KBr, 0.75 m CaCl2; 1.5 m glucose (C6H12O6)
Answer:
1) pure water
2) 0.75 m CaCl2
3) 1.0 m NaCl
4) 0.5 m KBr
5) 1.5 m glucose (C6H12O6)
Explanation:
Boiling point elevation is a colligative property. Coligative properties are properties that depend on the amount of solute present in the system. The boiling point of solvents increase due to the presence of solutes.
The boiling point elevation depends on the number of particles the solute forms in solution and the molality of the solute. The more the number of particles formed by the solute and the greater the molality of the solute, the greater the magnitude of boiling point elevation.
The order of decreasing hoping point elevation is;
1) 0.75 m CaCl2
2) 1.0 m NaCl
3) 0.5 m KBr
4) 1.5 m glucose (C6H12O6)
(S)-Pentan-2-ol was treated sequentially with methanesulfonyl chloride (CH3SO2Cl) and then potassium iodide. What is the final product that forms
Answer:
(S)-Pentan-2-ol was treated sequentially with methanesulfonyl chloride (CH3SO2Cl) and then potassium iodide. What is the final product that forms
Explanation:
Alcohols are poor leaving groups.
To make -OH group a better-leaving group, it should be treated with sulfonyl chlorides.
Then, methane sulfonyl group makes will be substituted on the -OH group and forms sulfonyl esters and makes it a better leaving group.
After that treating with KI proceeds through nucleophilic bimolecular substitution and the final product formed is shown below:.
Draw structures corresponding to the following IUPAC names:(a) (Z)-2-Ethyl-2-buten-1-ol (b) 3-Cyclohexen-1-ol(c) trans-3-Chlorocycloheptanol (d) 1,4-Pentanediol(e) 2,6-Dimethylphenol (f ) o-(2-Hydroxyethyl)phenol
Answer:
Draw structures corresponding to the following IUPAC names:(a) (Z)-2-Ethyl-2-buten-1-ol (b) 3-Cyclohexen-1-ol(c) trans-3-Chlorocycloheptanol (d) 1,4-Pentanediol(e) 2,6-Dimethylphenol (f ) o-(2-Hydroxyethyl)phenol
Explanation:
According to IUPAC rules, the name of a compound is:
Prefix+root word+suffix
1) Select the longest carbon chain and it gives the root word.
2) The substituents give the prefix.
3) The functional group gives the secondary suffix and the type of carbon chain gives the primary suffix.
The structure of the given compounds are shown below:
bio-chemisty of protain
Answer:
Protein biochemistry is the study of proteins. Protein biochemistry is a scientific field dedicated to the study of proteins, complex chains of amino acids which make up the building blocks of all living organisms.
Explanation:
I hope that helped
Copy and Pasted!
Answer:
Listen to what guy said on top.
Explanation:
polypeptide structures consisting of one or more long chains of amino acids residue.....
or my answer
find out the equivalent weight of Ca(OH)2
Answer:
The equivalent weight of calcium hydroxide is 1/2 he mass of a mol of calcium hydroxide. 1 mol Ca(OH)2 = 74 grams Ca(OH)2 ; 1 equivalent Ca(OH)2 = 37 grams Ca(OH)2......
Explanation:
HOPE IT HELPS YOU
Choose the substance with the higher entropy in each pair. Assume constant temperature, except in part (5)
(i) 1 mol of SO2(g) or 1 mol of SO3(g)
(ii) 1 mol of CO2(s) or 1 mol of CO2(g)
(iii) 3 mol of O2(g) or 2 mol of O3(g)
(iv) 1 mol of KBr(s) or 1 mol of KBr(aq)
(v) Seawater at 2°C or at 23°C
(vi) 1 mol of CF4(g) or 1 mol of CCl4(g)
Answer:
I) 1 mol of SO3(g)
2) 1 mol of CO2(g)
3) 3 mol of O2(g)
4) 1 mol of KBr(aq)
5) Seawater at 23°C
6) 1 mol of CCl4(g)
Explanation:
In molecules having greater numbers of atoms, there is an increase the number of ways by which the molecule vibrates thereby leading to a higher number of possible microstates and overall increase in entropy of the system. Hence, 1 mol of SO3(g) has a higher entropy than 1 mol of SO2.
Gases have a higher entropy than liquids and liquids have a higher entropy than gases.
Also, the greater the molecular weight of a molecule, the higher the entropy. Higher number of moles of a gas as well as the increase in temperature of a substance are also factors that lead to higher entropy.
Certain ketones such as fructose can be oxidized by Benedict's reagent under basic conditions to form what type of compound
Answer:
Certain ketones such as fructose can be oxidized by Benedict's reagent under basic conditions to form what type of compound
Explanation:
Benedict's solution is a mixture of copper sulfate, anhydrous sodium carbonate, and sodium citrate.
In presence of mild reducing agents, Cu(II) ion in Benedict's solution becomes the Cu(I) ion.
Fructose has an alpha-hydroxy ketone group.
It undergoes tautomerism and forms alpha-hydroxy aldehyde which gives a positive test with Benedict's reagent.
During this test, aldehydes will be converted into carboxylic acids.
The reaction of fructose with Benedict's reagent is shown below:
define the following terms atom
plz help ASAP on my final project I will give you20$
Answer:
hey friend
how can I help you
Does Every Chemical Have a formula?
Yes.
Each chemical substance has a specific chemical composition, so these chemical substances have their own chemical formula.
I hope this helps!
Di- n- pentyl ether can be converted to 1- bromopentane by treatment with HBr through essentially a(n) ________ mechanism.
Answer:
SN1 mechanism
Explanation:
The mechanism of this reaction is shown in the image attached.
The Di- n- pentyl ether is first protonated. The CH3(CH2)4OH is now a good leaving group as shown.
The attack of the bromide ion on the cation formed completes the mechanism to yield 1- bromopentane as shown in the mechanism.
If 11g of a gas occupies 5.6dm'3at s.t.p., calculate it's vapour density (1.0mol of a gas occupies 22.4dm'3at s.t.p.).
Answer:
[tex]{ \boxed{ \bf{vapour \: density = 2 \times molecular \: mass}}} \\{ \tt{ PV= (\frac{m}{ m_{r}}) RT}} \\ { \tt{3 \times 5.6 = \frac{11}{m _{r}} \times 0.0831 \times 273}} \\ { \tt{m _{r} = 14.85 \: g}} \\ \\ { \bf{vapour \: density = 2 \times m _{r}}} \\ = 2 \times 14.85 \\ = 29.7 \: { \tt{g {dm}^{ - 3} }}[/tex]
the force of attraction between non polar molecules are what (a)electrovalent bond (b)covalent bond (c)Hydrogen bond (d)Van der waals forces
Answer:
d. van der waals force
Explanation:
Van der Waals force :
the weakest intermolecular forceand consist of dipole-dipole force and dispersion force.
In an endothermic reaction, reactants are __ products.
equal to
less stable than
more stable than
equally stable than
when a polar bond is formed between 2 atoms which atom receives a partial positive charge
Answer:
The more electronegative atom in a covalent bond
Which is a nervous system test?
Answer:
Sorry, is there supposed to be an attachment, If so kindly republish your Question.
define saturated and unsaturated fats
Explanation:
Saturated fats are defined as the fat where fatty acid chains contain only single bonds.
For example, stearic acid, palmitic acid etc.
Unsaturated fats are defined as the fat where fatty acids contain one or more number of double bonds on the carbon atoms.
For example, oleic acid, palmitoleic acid etc.
For which of the following transitions would a hydrogen atom absorb a photon with the longest wavelength?
a. n = 1 to n = 2
b. n = 3 to n = 2
c. n = 5 to n = 6
d. n = 7 to n = 6
Answer:
Hence among the options a and c, option d is that the correct answer because it has rock bottom energy ( as n value increases, energy decreases as energy levels come closer).
Explanation:
The relation between energy and wavelength is:
[tex]\Lambda = hC/E[/tex]
From this equation, it's clear that wavelength and energy are inversely proportional to every other. The Lower the energy of a specific transition, the longest will the wavelength be of that specific transition.
Among the given options, options b and d are often ruled out, since those transitions produce to release of a photon because it is coming down from an excited state.
For each of the following changes at equilibrium, indicate whether the equilibrium shifts in the direction of products, reactants, or does not change: CaCO3(s)+heat⇌CaO(s)+CO2(g)
1) increasing the temperature
shifts equilibrium in the direction of the reactants
does not change
shifts equilibrium in the direction of the products
2) decreasing the volume of the container
shifts equilibrium in the direction of the reactants
shifts equilibrium in the direction of the products
does not change
3) adding a catalyst
shifts equilibrium in the direction of the reactants
shifts equilibrium in the direction of the products
does not change
4) adding more CaO(s)
does not change
shifts equilibrium in the direction of the reactants
shifts equilibrium in the direction of the products
Answer:
shifts equilibrium in the direction of the products
shifts equilibrium in the direction of the reactants
does not change
shifts equilibrium in the direction of the reactants
Explanation:
When a constraint such as a change in pressure, concentration or temperature is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.
The reaction is endothermic as written. Hence, increase in temperature increases the rate of forward reaction thereby shifting the equilibrium position towards the products.
When the volume of a reaction is decreased, the equilibrium position shifts in the direction which produces the least total volume. In this case, decrease in volume shifts the equilibrium position towards the reactants.
A catalyst has no effect on the equilibrium position. However, a catalyst may cause equilibrium to be achieved faster or at a lower temperature.
When more CaO is added, the equilibrium position shifts towards the reactants side and more CaCO3 is produced.
The bond angles in SCl2 are expected to be Multiple Choice a little more than 109.5°. 109.5°. 120°. a little less than 109.5°. 180°.
Answer:
a little less than 109.5°
Explanation:
SCl2 has four regions of electron density around the central atom of the molecule. This implies that it has a tetrahedral electron domain geometry with an expected bond angle of 109.5° according to valence shell electron pair repulsion theory.
However, there are two lone pair of electrons on the central atom of the molecule which decreases the bond angle a little less than 109.5° owing to repulsion between electron pairs.
a sample of salt has 1.74 moles of sodium chloride. how many formula units of the ionic compound are in the sample?
Answer:
A sample of salt has 1.74 moles of sodium chloride. how many formula units of the ionic compound are in the sample?
Explanation:
Given, 1.74 moles of NaCl.
Since one mole of NaCl consists of --- [tex]6.023 * 10^2^3[/tex] formula units.
Then, 1.74mol of NaCl contains how many formula units of NaCl?
[tex]1.74 mol x \frac{6.023x10^2^3}{1 mol} \\=10.5x10^2^3[/tex]formula units.
Hence, the given sample has 10.5x10^23 formula units.
When 1-methylcyclopentene undergoes acid catalyzed hydration, the major product formed is 1-methylcyclopentanol. What change(s) in the reactants would result in 2-methylcyclopentanol being the major product
Answer:
Conversion of 1-methyl cyclopentene to 2-methyl cyclopentanol.
Explanation:
When alkenes react with diborane followed by the reaction with hydrogen peroxide and NaOH then the least substituted carbon in the double bond will be substituted.
The formation of 2-methyl cyclopentanol from 1-methyl cyclopentene is shown below:
pls help ive been stuck on this question for a while im not good with chemistry lol.
Answer:
The answer would be B, putting thermal energy into something means you're adding heat into it.
every sperm has ____(one/two) sex chromosomes
PLEASE TELL THE ANSWER!!
Two chromosomes
Explanation:
The chromosomes are XY
Please mark me brainliest
Answer:
Two
Explanation:
Every sperm cell has two chromosomes.One is X and other is Y .They are found in pairs either XY or XXWhen Michelle's blood was testedthe chloride level was 0.45 g/dL. . What is this value in milliequivalents per liter? b. According to Table 9.6, is this value abovebelow within the normal range ?
Answer:
?what
Explanation:
i am having a hard time reading this
Why the catalytic and optical properties of nanomaterial are different from bulk material
Answer:
The material properties of nanostructures are different from the bulk due to the high surface area over volume ratio and possible appearance of quantum effects at the nanoscale. ... Yu; they found that the structural distortions on the quantum dots depend both on the kind of dopant and on the size of the dots.
Explanation:
hope it helps
