A circle has a central angle of 6 rad that intersects an arc of length 14 inches. Which equation find the length of the radius, R, of the circle?

area of OAB = 72 = (1/2) sin (AOB) * OA * OB solve the above for sin(AOB) to find sin(AOB) = 1/2 area of ODC = 288 = (1/2) sin (DOC) * OD * OD Note that sin(DOC) = sin(AOB) = 1/2, OD = 18 + y and OC = 16 + x and substitute in the above to obtain the first equation in x and y 1152 = (18 + y)(16 + x)...

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Answer:

Step-by-step explanation:

[tex]a^{m}* a^{n}=a^{m+n}\\\\\\(\frac{-1}{2})^{-19}*(\frac{-1}{2})^{8}=(\frac{-1}{2})^{-2x +1}\\\\(\frac{-1}{2})^{-19+8}=(\frac{-1}{2})^{-2x+1}\\\\\\(\frac{-1}{2})^{-11}=(\frac{-1}{2})^{-2x+1}[/tex]

As bases are equal in boht sides, we can compare the exponents.

-2x + 1 = -11

Subtract 1 form both sides

-2x = -11 - 1

-2x = -12

Divide both sides by -2

x = -12/-2

x = 6

=========================================================

Explanation:

We don't have a direct variation because the initial cost isn't $0

The equation for this situation is y = 25x+375, where x is the number of yearbooks purchased and y is the total cost.

Notice how this line doesn't go through the origin. All direct variation graphs are straight lines through the origin.

So that's why we have partial variation instead.

The initial cost is simply the set up cost, aka the cost when x = 0. That initial cost is $375. The initial cost is located at the y intercept.

From that initial cost, we then add on multiples of $25 depending on how many yearbooks are purchased.

-----------------

In short, because the initial cost is $375, which is some nonzero value, this means we don't have direct variation. Instead, we have partial variation.

Part G

The two angles ABD and DBC form a straight line, so the angles add to 180 degrees.

Let's solve for x.

angle ABD + angle DBC = 180

(0.5x+20) + (2x-10) = 180

2.5x+10 = 180

2.5x = 180-10

2.5x = 170

x = 170/2.5

x = 68

Then we'll use this to find angle ABD

angle ABD = 0.5*x + 20

angle ABD = 0.5*68 + 20

angle ABD = 34 + 20

angle ABD = 54

============================================================

Part H

Use the value of x we found back in part G to find the measure of angle DBC

angle DBC = 2x - 10

angle DBC = 2(68) - 10

angle DBC = 136 - 10

angle DBC = 126

An alternative is to subtract the measure of angle ABD from 180

angle ABD + angle DBC = 180

angle DBC = 180 - (angle ABD)

angle DBC = 180 - 54

angle DBC = 126

============================================================

Part I

This time, the two angles add to 90 degrees as shown by the square corner marker.

(angle XYW) + (angle WYZ) = 90

(1.25x - 10) + (0.75x + 20) = 90

2x + 10 = 90

2x = 90-10

2x = 80

x = 80/2

x = 40

which then leads to,

angle XYW = 1.25*x - 10

angle XYW = 1.25*40 - 10

angle XYW = 50 - 10

angle XYW = 40

============================================================

Part J

We can subtract the result of part I from 90 degrees to get the answer

angle WYZ = 90 - (angle XYW)

angle WYZ = 90 - 40

angle WYZ = 50

Or we could plug the x value x = 40 into the expression for angle WYZ

angle WYZ = 0.75*x + 20

angle WYZ = 0.75*40 + 20

angle WYZ = 30 + 20

angle WYZ = 50

============================================================

Summary:

The answers we found were

Answer:

G. m∠ABD = 54°

H. m∠DBC = 126°

I. m∠XYW = 40°

J. m∠WYZ = 50°

Step-by-step explanation:

∠ABD and ∠DBC are supplementary angles. This means their angles have a sum of 180°.

[tex]\frac{1}{2}x+20+2x-10=180\\\frac{5}{2}x+10=180\\\frac{5}{2}x=170\\x=68[/tex]

m∠ABD = 1/2(68) + 20 = 34 + 20 = 54

m∠DBC = 2(68) - 10 = 136 - 10 = 126

Same concept for ∠XYW and ∠WYZ only this time they are complementary angles. This means their angles have a sum of 90°.

[tex]1\frac{1}{4}x-10+\frac{3}{4}x+20=90\\2x+10=90\\2x=80\\x=40[/tex]

m∠XYW = 1 1/4(40) - 10 = 50 - 10 = 40

m∠WYZ = 3/4(40) + 20 = 30 + 20 = 50

Answer:

y=1

Step-by-step explanation:

5=2-3y+6

3y=2-5+6

3y= -3+6

3y= 3

3y÷3=3÷3

y=1

Answer:

16

Step-by-step explanation:

Substitute y = 5 into the expression

y² - 3y + 6

= 5² - 3(5) + 6

= 25 - 15 + 6

= 16

Answer:

Step-by-step explanation:

∠DHG is an inscribed angle. This angle, by definition, measures half the measure of its intercepted arc. The intercepted arc is arc DG, the one in question. This means that, by the rule, if the angle is 85 degrees, the arc is 2(85) = 170°

Answer:

it's actually  110, i took the test and got 170 wrong

Step-by-step explanation:

Answer:

30.7

Step-by-step explanation:

Assuming the angled are degrees and not radian.

side BC= (11÷sin67)•sin28= 5.6

angle ABC= 180-67-28=85°

A= 11•5.6•sin85÷2≈30.68

Answer:

3(2×2+1)+3×(2×2)/3=1×3=4×3

36+3+4=3=12

36+3+4-3-12

43-15

28

Answer:

The base cost of the camera, exclusive of sales tax, is $160.

Step-by-step explanation:

Set up this equation and solve for x, which is the cost of the camera:

$3.20 = $0.02x [0.02 = 2%]

Solve the equation by dividing $3.20 by 0.02. The answer is $160.

Answer: $160 for the camera

Step-by-step explanation:

0.2x160=3.2

$160

[tex]\huge\underline\blue{✏ANSWER}[/tex]

(no answer found.)

(maybe can found on other apps?)

#BrainliestBunch

Answer:

12

Step-by-step explanation:

1) Vector AB (-2-(-6); -1-(-1))= (4; 0). Vector module is module AB=sqrt (4*4+0*0)= 4

2) The module of Vector BC is sqrt((-1-(-2))*(-1 - (-2))+ (-4-(-1))* (-4-(-1))= sqrt (9+1)= sqrt 10.

3) The module of AC is sqrt ((-1-(-6))*(-1-(-6))+ (-4-(-1))*(-4-(-1))= sqrt (25+9)= sqrt 34.

4) Having the triangle with the sides AB, BC, AC use the theorem of cos:

sqrt34*sqrt34= sqrt 10*sqrt 10 + 4*4- 2*sqrt10*4*cosB

34-10-16= -8 sqrt 10*cosB

c0sB= (-1)/ sqrt10

5) Find out sinB that is equal to Sqrt (1- ((-1)/sqrt 10)* ((-1)/sqrt10))= sqrt (9/10)= 3/sqrt10.

6)S= 4*sqrt10*3/sqrt10= 4*3=12. The area is equal to 12.

Answer:

2x^2 + x - 1

If I did anything you didn't understand let me know so I can explain.  

Step-by-step explanation:

All of them are quadratics so let's use that.

The first one is 2x^2 + x - 1.  To find the axis of symmetry the strategy is usually to find the two zeroes of a quadratic and pick the number between them.  Something to  notice though is that 2x^2 + x - 1 is just 2x^2 + x sshifted down 1, so they both have the same axis of symmetry.  So I am going to ignore the constant, because then finding the zeroes is much much simpler.  I am going to do this with all opions.

So 2x^2 + x - 1 I am just going to use 2x^2 + x.  If you factor out an x you get x(2x + 1)  So now we have it in factored form and we know the zeroes are 0 and -1/2.  The number directly in between these is -1/4, so the axis of symmetry is x = -1/4.  I don't know if there is only one with that axis of symmetry so i am going to check the rest.

2x^2 - x + 1 means we are only going to look at 2x^2 - x.  factoring we get x(2x - 1) so the zeroes are 0 and 1/2, so the axis of symmetry is at 1/4.

x^2 + 2x - 1 we only use x^2 + 2x.  Factored form is x(x+2) so zeroes are 0 and -2 whichh means axis of symmetry is -1

x^2 - 2x + 1 has the same axis of symmetry as x^2 - 2x, which has zeros at 0 and 2 so the axis of symmetry is at 1.

So yep, it was just the first one.

9514 1404 393

Answer:

  (a)  f(x) = 2x^2 +x -1

Step-by-step explanation:

For ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For the offered answer choices, the axes of symmetry are ...

  a) x = -1/(2·2) = -1/4 . . . . . . the function we're looking for

  b) x = -(-1)/(2·2) = 1/4

  c) x = -2/(2·1) = -1

  d) x = -(-2)/(2·1) = 1

The function with axis of symmetry x = -1/4 is f(x) = 2x^2 +x -1.

Step-by-step explanation:

solution

Coordinate (-3,-1)(2,2)

x¹=-3 x²=2, y¹=-1 y²=2

M=(y²-y¹)/(x²-x¹)

M=(2+1)/(2+3) => 3/5

Equation of line

M=(y-y¹)/(x-x¹)

3/5 = (y+1)/(x+3)

cross multiply

3(x+3)=5(y+1)

3x+9=5y+5

5y-3x=4

5y=4+3x

y=4/5 + 3x/5

(C)

Answer:

20 P 9 means selecting 9 objects (order matters) out of 20 objects.

So in this case, the eight choice of a line up of 9 has 13 options.

For example, think about it this way. The first choice has 20 options, 2nd has 19, and so on...

So the answer is 13

Let me know if this helps!

Answer:

sgehwjwnnwjwjj2629937463u83

Answer: 60

Step-by-step explanation:

The blank space can be filled with 60, as this is a simple problem of distributive property

Answer:

x=400 m is the correct answer

Answer and Step-by-step explanation:

2n is the algebraic expression for twice n.

#teamtrees #PAW (Plant And Water)

Answer:

1. Angles 2, 3 and angles 1,3 are complementary angles(Given)

2. To prove :

Since Angles 2, 3 and angles 1,3 are complementary.

When angles are complementary, then the sum of the measures of angles is 90 degrees.

So,  and  (Definition of Complementary angles)

3.  (Substitution)

4.  (Subtraction property of equality)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

The answer is 12.

Step-by-step explanation:

Since one of the sides on the smaller polygon is two and on the other one is six that must mean the scale is multiply by 3 because 2x3=6. So 4 times 3 is 12.

So, w = 12

Answer:

Step-by-step explanation:

Table I

Given function is,

f(x) = [tex]b^x[/tex]

From the table attached,

For x = 0.827, value of function f(0.827) = 5,

f(0.827) = [tex]b^{0.827}[/tex]

Therefore, [tex]b^{0.827}=5[/tex]

[tex]\text{log}(b^{0.827})=\text{log}(5)[/tex]

0.827[log(b)] = log(5)

log(b) = 0.8452

b = [tex]10^{0.8452}[/tex]

b = 7

Therefore, function 'f' will be,

f(x) = [tex]7^x[/tex]

For f(x) = 9,

9 = [tex]7^x[/tex]

log(9) = log([tex]7^x[/tex])

log(9) = x[log(7)]

x = 1.129

Table II

Given function is g(x) = [tex]\text{log}_b(x)[/tex]

From the given table,

For x = 7, g(x) = 1

1 = [tex]\text{log}_b(7)[/tex]

[tex]b^1=7[/tex]

b = 7

Therefore, the function 'g' will be,

g(x) = [tex]\text{log}_7(x)[/tex]

For g(x) = 1.318

1.318 = [tex]\text{log}_7(x)[/tex]

[tex]x=7^{1.318}[/tex]

[tex]x=12.9968[/tex]

[tex]x=13.997[/tex]

The new coordinates are ( -3 , -6) , Option B is the answer.

Reflection means to create a mirror image of an object along any axis .

The shape and size of the object remains constant while reflection.

An object of coordinate ( -3 ,6) is given

This is reflected in the x axis .

When an object is reflected along any axis , the coordinate of that axis remains the same while the coordinate of the other changes to its additive inverse .

object  ( -3 ,6) is reflected along x axis ,

( x, y) ----> ( x , -y)

The new coordinates are ( -3 , -6)

Therefore Option B is the answer.

To know more about Reflection

https://brainly.com/question/15487308

#SPJ2

The ratio of the number of students who went to the zoo to the number of students who did not go to the zoo is 1: 5. Hence option C is true.

Given that;

The students in Shawn's class got to choose whether to visit the zoo or the aquarium.

Here, 3 students went to the zoo and 15 students went to the aquarium.

Hence, the ratio of the number of students who went to the zoo to the number of students who did not go to the zoo is,

Ratio = 3 : 15

Ratio = 3/15

Ratio = 1/5

Ratio = 1 : 5

Thus, option C is true.

Learn more about the ratio visit:

https://brainly.com/question/12024093

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Answer:

Step-by-step explanation:

In a kite, the angles between the two non- congruent side have the same degree.

x = 114 degrees

In a quadrilateral the sum of the inner angles is 360 degrees

88 + (114 * 2) + y = 360

88 + 228 + y = 360

316 + y = 360

y = (360 - 316)

y = 44 degrees

Answer:

3.6

Step-by-step explanation:

the ratio of AB to AD is 3/5 so the ratio of BC to DE is also 3/5, therefore BC=3/5 DE= (3/5)6= 3.6

Answer: $427140

Step-by-step explanation:

Firstly, we'll add MP to the profit and this will be:

= Rs 400000 + Rs 20000

= Rs 420000

Since there is a discount of 10%, this will then be:

= 420000 - (10% × 420000)

= 420000 - 42000

= $378000

With a VAT of 13%, then the final price will be:

= $378000 + (13% × $378000)

= $378000 + (0.13 × $378000)

= $378000 + $49140

= $427140

Answer:

answered by g a u t h m a t h

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

it has all the properties matching with a rhombus

answer from gauthmath