Answer: A color image uses 16 bits to represent a pixel. What is the maximum number of different colors that can be represented? With 16 bits, we can represent up to 2^16 different colors. Assume six devices are arranged in a mesh topology.
Explanation:
The terms 16-bit picture, high color image, and 32K color image are all used to describe images that have 16 bits per pixel.
What is a pixel?The smallest addressable element in a raster image or the smallest point in an all points addressable display device is known as a pixel (abbreviated as px), pel, or picture element in digital imaging.
The smallest component in most digital display systems that can be changed by software are pixels.
Photos with 16 bits per pixel are referred to as 16-bit pictures, high color images, and 32K color images.
The number of distinct colors that can be represented by 16 bits, where there are 5 bits for each of the red, green, and blue values and the 16th bit can be the alpha bit, is around 32 thousand.
Thus, the maximum number of different colors that can be represented is 32 thousand.
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Given the following code, what logic would you need to include to print all even values stored within the array:
int[] myArray = {1,2,38,4,54,6,7,8,9,10};
for (int i = 0; i < myArray.length; i++) {
//your code goes here
}
NOTE: Your response should be just the missing logic--not the entire problem set.
The missing logic whigh would allow all the even numbers stored within the array to be printed is if(myArray[i]%2 == 0)
Even numbers are divisible by 2, and hence, will leave no remainder when divided by 2. Using the modulo operator, each iterated value in the array should be checked if it has a remainder of 0, when divided by 2.Hence, if the remainder is 0, then the value is even and the value should be printed.
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