Answer:
The graph is attached below.
Step-by-step explanation:
The volume of the box containing the coffee mugs is,
[tex]V=x^{3}[/tex]
Then the function representing the side length, in inches, for the box is:
[tex]g(x)=x[/tex]
Now, it is provided that the company decides to double the volume of the box.
That is, the new volume will be:
[tex]V_{n}=2x^{3}[/tex]
Then the side length, in inches, for the box will be:
[tex]g_{n}(x)=\sqrt[3]{2x^{3}} =\sqrt[3]{2}x[/tex]
Then the graph representing the function, formed using the following points is:
[tex]x\ \ \ \ \ \ \ \ \ g_{n}(x)\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\0\ \ \ \ \ \ \ \ \ \ \ 0\\1\ \ \ \ \ \ \ \ \ \ \ 2^{1/3}[/tex]
Answer:
c
Step-by-step explanation:
London answered 20 questions correctly on her multiple choice history final that had a total of 80 problems. What percentage of questions did London answer correctly on the final exam?
Answer:
25%
Step-by-step explanation:
correct/total
20/80
1/4
Changing to a decimal
.25
.25*100%
25%
Answer:
1/4 or 25%
Step-by-step explanation:
1). 20 / 80 = 1 / 4 = 25 %
Hope this helps
The Stem-and-Leaf Graph shows the amount of money each student spends on food per day in dollars. What is the median for the data in this Stem-and-Leaf Plot? A. $55 B. $73 C. $81 D. $84
Answer:
B) $73
Step-by-step explanation:
add all of your values and divide by the amount of values
52+55+55+55+59+64+66+68+72+73+73+73+73+75+81+81+83+84+84+86+87=
1,499
1,499 divided by 21 = 71.3809523...
which rounds to 73
HOPE THIS HELPS!!! :)
The median is of $48 in the stem leaf plot and option B is correct.
What is Statistics?Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.
The median of a data-set is the value that separates the bottom 50% from the upper 50% of values.
The graph has 16 values, already ordered.
It is an even number, hence the median is the mean of the 8th and the 9th values, which considering the key are both 48,
Hence, the median is of $48 and option B is correct.
To learn more on Statistics click:
https://brainly.com/question/30218856
#SPJ3
Stem-and-Leaf Plot shows the amount of money each student spends
on travel per day in dollars. What is the median for the data in this graph?
Stem Leaf
A) $35
B) $48
C) $53
D) $54
HELP!! For questions 9-12 evaluate each function for the given value
Answer:
9). h² - 7h + 11
10). 2a² + 14a + 16
11). 3
12). 2h + 4x - 3
Step-by-step explanation:
9). If j(x) = x² + x - 1
j(h - 4) = (h - 4)² +(h - 4) - 1
= h² - 8h + 16 + h - 4 - 1
= h² - 7h + 11
10). If f(x) = 2x² + 2x - 8
f(a + 3) = 2(a + 3)² + 2(a + 3) - 8
= 2(a² + 6a + 9) + 2a + 6 - 8
= 2a² + 12a + 18 + 2a - 2
= 2a² + 14a + 16
11). If f(x) = 3x - 1
[tex]\frac{f(x+h)-f(x)}{h}=\frac{3(x+h)-1-(3x-1)}{h}[/tex]
[tex]=\frac{3x+3h-1-3x+1}{h}[/tex]
= 3
12). If, f(t) = 2t² - 3t + 7
[tex]\frac{f(x+h)-f(x)}{h}=\frac{2(x+h)^{2}-3(x+h)+7-(2x^2-3x+7)}{h}[/tex]
[tex]=\frac{2(x^2+h^2+2hx)-3x-3h+7-2x^2+3x-7}{h}[/tex]
[tex]=\frac{2x^2+2h^2+4hx-3x-3h+7-2x^2+3x-7}{h}[/tex]
[tex]=\frac{2h^2+4hx-3h}{h}[/tex]
= 2h + 4x - 3
(a²b²-c²)(a²b²+c²)
simplify
Answer:
a⁴b⁴ - c⁴
Step-by-step explanation:
The difference of squares formula states that (a - b)(a + b) = a² - b². In this case, a = a²b² and b = c² so a² - b² = (a²b²)² - (c²)² = a⁴b⁴ - c⁴.
Answer:
a^4b^4 - c^4.
Step-by-step explanation:
(a²b²-c²)(a²b²+c²)
Difference of 2 squares:
= (a²b²)^2 - (c²)^2
= a^4b^4 - c^4.
What type of number is that? Multiple answers.
Answer:
A & C
Step-by-step explanation:
-9 is a whole number is rational
Please answer answer question
Answer:
c=13.42
Step-by-step explanation:
[tex]A^2+B^2=C^2\\6^2+14^2=C^2\\C^2=144+36\\C^2=180\\\sqrt{c^2}=\sqrt{180} \\c=13.42[/tex]
Create a box plot for either the girls or boys data. Give 2 valid conclusions based on the data collected? (4 points)
Answer:
1) Please find attached the box and whiskers chart created with Excel
2) The conclusions are;
a) The measure of central tendency (the mean and the median) are approximately equal,
b) The standard deviation for the first five data points is 14.17 while the standard deviation for the whole ten data points is 23.99 as such the data values appeared more clustered at the center and show wider spread towards right ends of the chart
Due to the lack of correlation between the standard deviation and the five data values, the data is not uniformly distributed
Step-by-step explanation:
The given data is as follows;
1, 2, 3, 4, 5, 6, 7, 8, 9, 10
15, 18, 22, 32, 50, 50, 55, 56, 81, 81
The first quartile Q₁ = 22
The second quartile, Q₂ (Median) = 50
The third quartile, Q₃ = 56
The interquartile range IQR = 56 - 22 = 34
The minimum value = 15
The maximum value = 81
The mean = 46
The standard deviation = 23.99
Therefore, the measure of central tendency (the mean and the median) are approximately equal,
The data values appeared more clustered at the center and show wider spread towards the left and right ends of the chart
The standard deviation for the first five data points is 14.17 while the standard deviation for the last five data points is
Due to the lack of correlation between the standard deviation and the five data values, the data is not uniformly distributed.
What are the solutions to the quadratic equation 4x2 = 64? A. x = −16 and x = 16 B.x = −8 and x = 8 C.x = −4 and x = 4 D.x = −2 and x = 2
Answer:
x = ±4
Step-by-step explanation:
4x^2 = 64
Divide each by 4
4x^2 /4= 64/4
x^2 = 16
Take the square root of each side
sqrt(x^2) = ±sqrt(16)
x = ±4
Answer:
[tex]\boxed{\boxed{x=\pm 4}}[/tex]
Step-by-step explanation:
[tex]4x^2 = 64[/tex]
Divide both sides by 4.
[tex](4x^2)/4 = 64/4[/tex]
Simplify.
[tex]x^2 =16[/tex]
Take the square root on both sides.
[tex]\sqrt{x^2 } =\pm \sqrt{16}[/tex]
Simplify.
[tex]x=\pm 4[/tex]
What is the solution to this system of equations? x+3y−z=6 4x−2y+2z=−10 6x+z=−12 (−4, 0, 12) (0, −2, −12) (2, 1, −3) (−3, 5, 6)
Answer:
Solution : (− 3, 5, 6)
Step-by-step explanation:
We have the following system of equations that we have to solve for,
[tex]\begin{bmatrix}x+3y-z=6\\ 4x-2y+2z=-10\\ 6x+z=-12\end{bmatrix}[/tex]
To solve this problem we can start by writing the matrix with their respective coefficients --- (1)
[tex]\begin{bmatrix}1&3&-1&|&6\\ 4&-2&2&|&-10\\ 6&0&1&|&-12\end{bmatrix}[/tex]
Now we can reduce this to row echelon form, receiving our solution --- (2)
[tex]\begin{pmatrix}1&3&-1&6\\ 4&-2&2&-10\\ 6&0&1&-12\end{pmatrix}[/tex] Swap row 1 and 3,
[tex]\begin{pmatrix}6&0&1&-12\\ 4&-2&2&-10\\ 1&3&-1&6\end{pmatrix}[/tex] Cancel leading coefficient in row 3,
[tex]\begin{pmatrix}6&0&1&-12\\ 0&-2&\frac{4}{3}&-2\\ 0&3&-\frac{7}{6}&8\end{pmatrix}[/tex] Swap row 2 and 3
[tex]\begin{pmatrix}6&0&1&-12\\ 0&3&-\frac{7}{6}&8\\ 0&-2&\frac{4}{3}&-2\end{pmatrix}[/tex] Cancel leading coefficient in row 3
[tex]\begin{pmatrix}6&0&1&-12\\ 0&3&-\frac{7}{6}&8\\ 0&0&\frac{5}{9}&\frac{10}{3}\end{pmatrix}[/tex]
At this point you can see that we have to cancel the leading coefficient in each row, to row echelon form. Continuing this pattern we have the following matrix,
[tex]\begin{bmatrix}1&0&0&|&-3\\ 0&1&0&|&5\\ 0&0&1&|&6\end{bmatrix}[/tex]
As you can see, x = - 3, y = 5, and z = 6, giving us a solution of (− 3, 5, 6). This is the fourth option.
Need Help Trigonometry
Answer:
tan(<G) = [tex] \frac{HI}{GI} [/tex]
Step-by-step explanation:
Given:
Right triangle ∆GHI,
Required:
Equivalent of tan(<G)
SOLUTION:
Recall the acronym for trigonometric ratios of angles in a right triangle: SOHCAHTOA.
Thus, the TOA in the acronym above stands for:
Tan(θ) = side opposite to θ ÷ side adjacent to θ
Where,
θ is the angle of interest = <G
Opposite side = HI
Adjacent side = GI
The equivalent of tan(<G) = [tex] \frac{HI}{GI} [/tex]
please help :) 1) Scientists develop knowledge by making blank about the natural world that may lead to a scientific question. 2) A scientific question may lead to a(n) blank , which can be tested. The results of blank can lead to changes in scientific knowledge.
Answer:
You just answered my question so you can ask yours, what a sped. Now i'm doing the same thing.
Step-by-step explanation:
COMPUTE
3 ( 2 1/2 - 1 ) + 3/10
Answer:
[tex] \boxed{ \frac{24}{5} }[/tex]Step-by-step explanation:
[tex] \mathsf{3(2 \frac{1}{2} - 1) + \frac{3}{10} }[/tex]
Convert mixed number to improper fraction
[tex] \mathrm{3( \frac{5}{2} - 1) + \frac{3}{10} }[/tex]
Calculate the difference
⇒[tex] \mathrm{3( \frac{5 \times 1}{2 \times 1} - \frac{1 \times 2}{1 \times 2} }) + \frac{3}{10} [/tex]
⇒[tex] \mathrm{ 3 \times( \frac{5}{2} - \frac{2}{2}) } + \frac{3}{10} [/tex]
⇒[tex] \mathrm{3 \times ( \frac{5 - 2}{2} ) + \frac{3}{10} }[/tex]
⇒[tex] \mathrm{3 \times \frac{3}{2} + \frac{3}{10} }[/tex]
Calculate the product
⇒[tex] \mathrm{ \frac{3 \times 3}{1 \times 2} + \frac{3}{10} }[/tex]
⇒[tex] \mathrm{ \frac{9}{2} + \frac{3}{10}} [/tex]
Add the fractions
⇒[tex] \mathsf{ \frac{9 \times 5}{2 \times 5} + \frac{3 \times 1}{10 \times 1} }[/tex]
⇒[tex] \mathrm{ \frac{45}{10} + \frac{3}{10} }[/tex]
⇒[tex] \mathrm{ \frac{45 + 3}{10 } }[/tex]
⇒[tex] \mathrm{ \frac{48}{10} }[/tex]
Reduce the numerator and denominator by 2
⇒[tex] \mathrm{ \frac{24}{5} }[/tex]
Further more explanation:
Addition and Subtraction of like fractions
While performing the addition and subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.
For example :
Add : [tex] \mathsf{ \frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} } = \frac{4}{5} [/tex]
Subtract : [tex] \mathsf{ \frac{5}{7} - \frac{4}{7} = \frac{5 - 4}{7} = \frac{3}{7} }[/tex]
So, sum of like fractions : [tex] \mathsf{ = \frac{sum \: of \: their \: number}{common \: denominator} }[/tex]
Difference of like fractions : [tex] \mathsf{ \frac{difference \: of \: their \: numerator}{common \: denominator} }[/tex]
Addition and subtraction of unlike fractions
While performing the addition and subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus, obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator.
For example:
[tex] \mathsf{add \: \frac{1}{2} \: and \: \frac{1}{3} }[/tex]
L.C.M of 2 and 3 = 6
So, ⇒[tex] \mathsf{ \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} }[/tex]
⇒[tex] \mathsf{ \frac{3}{6} + \frac{2}{6} }[/tex]
⇒[tex] \frac{5}{6} [/tex]
Multiplication of fractions
To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.
When any number or fraction is divided by a fraction, we multiply the dividend by reciprocal of the divisor. Let's consider a multiplication of a whole number by a fraction:
[tex] \mathsf{4 \times \frac{3}{2} = \frac{4 \times 3}{2} = \frac{12}{2} = 6}[/tex]
Multiplication for [tex] \mathsf{ \frac{6}{5} \: and \: \frac{25}{3} }[/tex] is done by the similar process
[tex] \mathsf{ = \frac{6}{5} \times \frac{25}{3} = 2 \times 5 \times 10}[/tex]
Hope I helped!
Best regards!
sam ran 63,756 feet in 70 minutes what is sams rate in miles per hour? (there are 5,280 feet in one mile)
Divide total feet by feet in a mile:
63,756/5280 = 12.075 miles
Divide 70 minutes by 60 minutes per hour:
70/60 = 1.166666 hours( round to 1.17)
Miles per hour = total miles/ total hours:
12.075/1.17 = 10.32 miles per hour
Simplify the expression. (3x2 – 4x + 1) + (-x2 + x – 9)
[tex](3x^2 - 4x + 1) + (-x^2 + x - 9)=\\3x^2-4x+1-x^2+x-9=\\2x^2-3x-8[/tex]
Type the correct answer in the box. Use numerals instead of words. The height of a baseball, in feet, is represented by this expression, where t is time in seconds. -16t squared+64t+3 The height of the baseball after 3.5 seconds is BLANK feet.
Answer:
31 Feets
Step-by-step explanation:
Given the expression for the height of a baseball:
Height(t) = -16t^2 +64t +3
Height in Feets ; time (t) in seconds
Height of baseball after 3.5 seconds :
Height(3.5) = -16(3.5)^2 + 64(3.5) + 3
Height = - 16(12.25) + 64(3.5) + 3
Height = - 196 + 224 + 3
Height = 31 Feets
Height after 3.5 seconds = 31 feets
BELL RINGER #2
A consultant charges $45 for each hour she works on a consultation, plus a flat $30
consulting fee. How many hours of work are included in a $210 bill for a consultation?
A. 2 4/5
B. 4
c. 4 2/3
D. 5 1 / 2
E. 7
Answer:
A. 2 4/5
Step-by-step explanation:
To find how many hours she worked for $210, you must get the amount of money she gets in 1 hour.
Because she charges $43 dollars every hour, and fines a fee of $30 flat, we must add both of the amount to get how many she earns in 1 hour.
So:
$45 + $30= $75
She earn $75 in 1 hour.
Next, divide $210 dollars that she earned for working for hour(s) to the amount of money she earned in 1 hour to find how many hours she worked.
So:
$210 ÷ $75= 2.8 hours
The answer is 2.8 hours
Because the given answers is in fraction, we must change the decimal into a fraction.
To change a decimal into a fraction, you must place the decimal over its place value.
Because 8 in the decimal 2.8 is in the tenths place, you must place it over 10
So:
2.8 into a decimal is 2 8/10
Simplify (only simplify if possible):
Divide 8 and 10 to their GCF which is 2.
So:
8 ÷ 2= 4
10 ÷ 2= 5
So the fraction and the answer is now:
2 4/5
I hope this helps! I'm sorry if it's wrong and too complicated.
Please help! Algebra 2!!
Mistake found
3x-2(2x-4)=2
3x - 4x - 8 = 2 instead of 3x - 4x + 8 = 2
Correct answer
x= -13 y= -30
Answer:
See below.
Step-by-step explanation:
So we have the system of equations:
[tex]3x-2y=21 \text{ and } y=2x-4[/tex]
The student took the following steps:
[tex]3x-2(2x-4)=21\\3x-4x-8=21\\-x-8=21\\-x=29\\x=-29\\y=2(-29)-4=-58-4=-62[/tex]
The student's mistake is in step 2. He/she distributed incorrectly. You are supposed to distribute the -2 to both terms, so it should be -4x plus 8, since -2 times -4 is positive 8. Fixing that mistake, we will have:
[tex]3x-2(2x-4)=21\\3x-4x+8=21 \\-x+8=21\\-x=13\\x=-13\\y=2(-13)-4=-26-4=-30[/tex]
Thus, the final answers should be (-13, -30).
Please answer this question now
Hi there! :)
Answer:
[tex]\huge\boxed{V = 359.01 mm^{3} }[/tex]
Use the formula V = 1/3(bh) to solve for the volume of the cone where b = πr² where π ≈ 3.14:
Find the area of the base:
b = π(7)²
b = 49π
b = 153.86 mm²
Find the volume:
V = 1/3(153.86 · 7)
V = 1/3(1077.02)
V = 359.006 ≈ 359.01 mm³.
Express the distance between the given numbers using absolute value. Then find the distance by evaluating the absolute value expression.
-7.5 and 5.4
Answer:
Step-by-step explanation:
m
Consider the equation: 12x=13-x^212x=13−x 2 12, x, equals, 13, minus, x, squared 1) Rewrite the equation by completing the square. Your equation should look like (x+c)^2=d(x+c) 2 =dleft parenthesis, x, plus, c, right parenthesis, squared, equals, d or (x-c)^2=d(x−c) 2 =dleft parenthesis, x, minus, c, right parenthesis, squared, equals, d. 2) What are the solutions to the equation
Answer:
[tex](x + 6)^2 = 49[/tex]
[tex]x = 1[/tex] or [tex]x = -13[/tex]
Step-by-step explanation:
Given
[tex]12x = 13 - x^2[/tex]
Using Completing the Square
[tex]12x = 13 - x^2[/tex] ---- Add [tex]x^2[/tex] to both sides
[tex]x^2 + 12x = 13 - x^2 + x^2[/tex]
[tex]x^2 + 12x = 13[/tex]
Divide the coefficient of x by 2; then add the square to both sides
[tex]x^2 + 12x + 6^2 = 13 + 6^2[/tex]
[tex]x^2 + 12x + 36 = 13 + 36[/tex]
[tex]x^2 + 12x + 36 = 49[/tex]
Factorize
[tex]x^2 + 6x + 6x + 36 = 49[/tex]
[tex]x(x + 6) + 6(x + 6) = 49[/tex]
[tex](x + 6)(x + 6) = 49[/tex]
[tex](x + 6)^2 = 49[/tex]
Hence, the equation is [tex](x + 6)^2 = 49[/tex]
Solving further
Take square root of both sides
[tex](x + 6) = \sqrt{49}[/tex]
[tex]x + 6 = \±7[/tex]
[tex]x = \±7- 6[/tex]
This implies that
[tex]x = 7 - 6[/tex] or [tex]x = -7 -6[/tex]
[tex]x = 1[/tex] or [tex]x = -13[/tex]
HEnce, the solutions are [tex]x = 1[/tex] or [tex]x = -13[/tex]
Answer:
(x+6)^2=49 and x=−6±7
Step-by-step explanation:
50.For the direct variation such that when y = 2 then x = 3, find the constant of variation ( k ) and then find the value of y when x = –0.5.
Step-by-step explanation:
Since it's a direct variation
y = kx
where k is the constant of proportionality
To find the value of y when x = –0.5 we must first find the relationship between the variables
When
x = 3
y = 2
2 = 3k
Divide both sides by 3
[tex]k = \frac{3}{2} [/tex]
So the formula for the variation is
[tex]y = \frac{3}{2} x[/tex]When x = - 0.5 or - 1/2
[tex]y = \frac{3}{2} ( - \frac{1}{2} )[/tex]
We have the final answer as
[tex]y = - \frac{3}{4} [/tex]Hope this helps you
The two-way frequency table below shows data on years working with the company and college degree status for Tom's coworkers. Complete the following two-way table of row relative frequencies. (If necessary, round your answers to the nearest hundredth.)
Answer:
Lets start with the top row.
First, add the two values.
5+14=19
Now, divide each value by the total.
5/19=0.26315789473
Round the decimal to the nearest hundredth.
5/19=0.26
14/19=0.73684210526
Round it to the nearest hundredth.
14/19=0.74
Now, The second row.
Add the two values.
16+7=23
Divide the first value by the total.
16/23=0.69565217391
Round it to the nearest hundredth.
16/23=0.70
Divide the second value by the total.
7/23=0.30434782608
Round to the nearest hundredth.
7/23=0.30
Done!
Answer:
Row 1: 0.26 0.74
Row 2: 0.70 0.30
Step-by-step explanation:
Khan
Solve each system of equations 4x+6y=3 and -10x-15y=-4
Answer:
There is no solution
Step-by-step explanation:
they all subtract eachother out
5. Eight adults and six children travel in a cable car.
Estimate the total mass of the people in the cable car.
Answer: 1880 pounds
Step-by-step explanation: when you take the average adult weight, around 160 lbs. you multiply that by eight. you get 1280. then you estimate that each of the children weigh around 100 lbs, then you add 600 to 1280 and get 1,880 lbs
Which of the following statements is not true concerning the equation x^2 - c = 0 for c > 0
A. A quadratic system in this form can always be solved by factoring.
B. This equation is not considered to be a quadratic equation because it is not in the form ax^2 + bx + c = 0
C. The left-hand side of this equation is called a difference of two squares
D. A quadratic equation in this form can always be solved using the square root property.
Which of the following steps would not be necessary when using the square root property to solve a quadratic equation?
A. After applying the square root property, solve the resulting equations.
B. Isolate the quantity being squared
C. The square root property may be applied only if the constant is positive
D. When taking the square root of both sides, use plus-minus on the square root of the constant.
Which of the following steps can be performed can be performed so that the square root property may easily be applied to 2x^2 = 16?
A. The square root property requires a quantity squared by itself on one side of the equation. The only quantity is squared by 16, so divide both sides by 2 before applying the square root property
B. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X, so divide both sides by 16 before applying the square root property
C. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X, so divide both sides by 2 before applying the square root property
Answer:
The correct option are;
1) D. A quadratic equation of this form can always be solved using the square root property
2) B. Isolate the quantity being squared
3) C. The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is X so divide both sides by 2 before applying the square root property
Step-by-step explanation:
Where the quadratic equation is of the form x² = b, the square root property method can be used to solve the equation. Due to the nature of square roots, putting a plus-minus before the square root of the constant on the right hand side of the equation after taking the square roots of both sides of the equation, two answers are produced.
It is however to first isolate the term with the squared variable, after which the square root of both sides of the equation is taken.
In the expression 3x^2+y+-5 which of the following choices is the exponent in the term 3x^2?
A. 3
B. 2
C. X
D. None of these choices
Answer:
2
Step-by-step explanation:
3x^2
The coefficient is 3
The variable is x
The exponent is 2
I will rate you a brainlest☆
Answer:
A 0.6 0.9 1.2 1.5 1.8
B 3/8 5/8 7/8 9/8 11/8
C -7 -5 -3 -2 -1
D 1, 1 1/3, 1 2/3, 2, 2 1/3
E 0.61 0.72 0.83 0.94 1.05
Step-by-step explanation:
Answer:
A. x x 1.2 1.5 1.8
B. 3/8 x x x 1 2/8
C. x x -3 -2 -1
D. 0 x x x 5 1/3
E. x x 0.83 0.94 1.05
Step-by-step explanation:
hope it helped
BRAINLIEST!! The equation of the line is Y=2.x- 1.8. Based on the graph which of the following are true?
(select all that apply)
A. If tony stays for 30 minutes in the record store it is likely her will spend $70
B. Each additional minute tony spends in the store is associated with an additional cost of $2.40
C. The correlation coefficient for the line of best fits 2.4
D. The line of best fit will have a positive correlation coefficient.
Answer:
b y=2.4x -1.8
Step-by-step explanation:
the equation y=2.4x -1.8 represents 2.4 from it
In an examination ,80%examines passed in english,70%In mathematics and 60% in both subjects.if 45 examines failed in both subject.
1.draw a venn-diagram to represent the above information .
2.find the number of examines who passed only one subject.
3.find the number of student who failed in mathematics.
Answer:
1. Please refer to attached diagram.
2. 135
3. 135
Step-by-step explanation:
Given that
80%examines passed in English, n(E) = 80%
70%In mathematics, n(M) = 70%
and 60% in both subjects, n(E [tex]\cap[/tex] M) = 60%
45 examines failed in both subject.
1. Venn Diagram is attached in the answer area.
One circle represents the pass examines in Maths and
Other circle represents the pass examines in English.
Rectangle represents the total number of examines that appeared for the exam.
Rectangle minus the area of union of circles represent the number of students who failed in both subjects.
2. To find the number of examines who passed in only one subject.
i.e. n(E) - n(E [tex]\cap[/tex] M) + n(M) - n(E [tex]\cap[/tex] M) = (80 - 60 + 70 - 60)% = 30%
Let us find the number of students who passed in atleast one subject:
[tex]n(E\cup M) = n(E) +n(M)-n(E \cap M)\\\Rightarrow n(E\cup M) = (80 +70-60)\% = \bold{90\%}[/tex]
So, number of students who failed in both subjects = 100 - 90% = 10% of total students = 45
So, total number of students appeared = 450
So, number of examines who passed in only one subject = 450 [tex]\times[/tex] 30% = 135
3. Number of students who failed in mathematics.
100% - Passed in Mathematics = 100% - 70% = 30% of 450 = 135
Distribute 10 (3x + 8x2).
Answer:
30x+160
simple all you had to do is 10*3x and 8x2=16 and 10*16 and you will get 30x+160
Step-by-step explanation:
Answer:
30x + 80x^2
Step-by-step explanation:
10 (3x + 8x^2)
10 * 3x + 10 * 8x^2
30x + 80x^2