A cộng b tất cả bình phương bằng bảo nhiêu

9514 1404 393

Answer:

  21.5 cm

Step-by-step explanation:

Consider rectangle PQRS. Its area is ...

  A = LW

  90 cm² = PQ×QR = PQ×(20 cm)

  (90 cm²)/(20 cm) = PQ = 4.5 cm . . . . . . BC has this value, too

__

Consider the perimeter of ABCD. It is given by ...

  P = 2(L +W)

  52 cm = 2(AB +BC) . . . . substitute known value for P

  26 cm = AB +4.5 cm . . . . use known value for BC, divide by 2

  21.5 cm = AB

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = [tex]\frac{FV-SV}{SV}*100[/tex]        (FV = final value, SV = starting value)

Percentage increase = [tex]\frac{1.4214 - 0.7107}{0.7107}*100[/tex]

Percentage increase = [tex]\frac{0.7107}{0.7107}*100[/tex]

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = [tex]\frac{10,201-10,100}{10,100}*100[/tex]

                                                             = [tex]\frac{101}{10,100}*100[/tex]

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = [tex]\frac{10,303.01-10,201}{10,201} *100[/tex]

                                                              = 1%

PC of product B from 3rd to 4th year [tex]=\frac{10,406.04-10,303.01}{10,303.01}*100[/tex]

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

Answer:

A) The price of product A is increasing by 3% per year.

(B) The product A recorded a greater percentage change in price over the previous year.

Step-by-step explanation:

(A)

The function representing the price, in dollars, of product A after x years is:

FA(x)=0.69*(1.03)x

The function  FA(x)can be written as:

FA(x)=0.69*1+(0.03)x

The function FA(x) is similar to the exponential growth function, y=a(1+r)x .

Here r is the growth rate.

Thus, it can be said that the price of product A is increasing by 3% per year.

(B)

Consider the data of product B for the year 3 and 4.

The price of product B for year 3 and 4 are 10,303.01 and 10,406.04.

Compute the percent price change from year 3 to 4 as follows:

10406.04-10303.01/10303.01*100

which is 0.999%

~1%

The price of product B is increasing by 1% per year.

Thus, the product A recorded a greater percentage change in price over the previous year.

is 20 ÷ 5 the question? if so he was penalized 4 times. 5 × 4 is 20

Yes, they are quite similar. the p-value obtained using the theory-based method (p < 0.0001) agree with that obtained using the randomization/simulation - based method (p < 0.0001)

P- value is the probability of obtaining a value of test statistic more extreme in the direction of alternative hypothesis than the observed one. In easy words if p -value < level of significance we reject H0 in favor of H1.

Here:

p-value < 0.0001 => we reject H0.

If the statistical software renders a p value of 0.000 it means that the value is very low, with many "0" before any other digit.

So the interpretation would be that the results are significant, same as in the case of other values below the selected threshold for significance.

Therefore, yes they are quite similar.

Learn more about balsa wood here:

https://brainly.com/question/33256379

#SPJ2

Incomplete Question:

Student researchers investigated whether balsa wood is less elastic after it has been immersed in water. They took 60 pieces of balsa wood and randomly assigned half to be immersed in water and the other half not to be. They measured the elasticity by seeing how far (in inches) the piece of wood would project a dime into the air.

Does the p-value obtained using the theory-based method (p < 0.0001) agree with that obtained using the randomization/simulation-based method (p < 0.0001)?

A. No, they are different.

B. Yes, they are quite similar.

Answer:

first you have to find the number of ways 3 men can be chosen, then the number of ways 2 women can be chosen, and then you need to multiply these numbers together to get the number of ways because multiplication will show the total arrangements possibilities. use combination since order does not matter.

number ways for 2 out of 10 women total: 10 choose 2= 45

number of ways for 3 out of 9 men total: 9 choose 3= 84

84x45= 3780

3780 total ways

number of ways

Answer:

B

Step-by-step explanation:

Area = L * W

L = 12 m

W = 10 m

Area = 12 m * 10 m

Area = 120 m^2

Answer;

A. 120m²

Given That :-

To find :-

Solution :-

[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \sf Length = 12m\: \: \: \: \: \: \: \: \: \: \: \\ \begin{gathered}\begin{gathered}\boxed{\begin{array}{}\bf { \red{}}\\{\qquad \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{}\\ { \sf{ }}\\ { \sf{ }} \\ \\ { \sf{ }}\end{array}}\end{gathered}\end{gathered} \sf \: Width = 10m \end{gathered}\end{gathered} \end{gathered} \end{gathered}[/tex]

The area of a rectangle is equal to the length times the width.

Substitute the values of the length l =12 and width w = 10 into the formula for the area of a rectangle.

Multiply 12m by 10m

Hence, Area of rectangle is 120m² which means option A. is correct answer.

Answer: the answer is x= -11.

Given:

In quadrilateral ABCD, angle B=90° , AB=9m, BC=40m, CD=15m, DA=28m.

To find:

The area of the quadrilateral ABCD.

Solution:

In quadrilateral ABCD, draw a diagonal AC.

Using Pythagoras theorem in triangle ABC, we get

[tex]AC^2=AB^2+BC^2[/tex]

[tex]AC^2=9^2+40^2[/tex]

[tex]AC^2=81+1600[/tex]

[tex]AC^2=1681[/tex]

Taking square root on both sides, we get

[tex]AC=\sqrt{1681}[/tex]

[tex]AC=41[/tex]

Area of the triangle ABC is:

[tex]A_1=\dfrac{1}{2}\times base\times height[/tex]

[tex]A_1=\dfrac{1}{2}\times BC\times AB[/tex]

[tex]A_1=\dfrac{1}{2}\times 40\times 9[/tex]

[tex]A_1=180[/tex]

So, the area of the triangle ABC is 180 square m.

According to the Heron's formula, the area of a triangle is

[tex]Area=\sqrt{s(s-a)(s-b)(s-c)}[/tex]

where,

[tex]s=\dfrac{a+b+c}{2}[/tex]

In triangle ACD,

[tex]s=\dfrac{28+15+41}{2}[/tex]

[tex]s=\dfrac{84}{2}[/tex]

[tex]s=42[/tex]

Using Heron's formula, the area of the triangle ACD, we get

[tex]A_2=\sqrt{42(42-28)(42-15)(42-41)}[/tex]

[tex]A_2=\sqrt{42(14)(27)(1)}[/tex]

[tex]A_2=\sqrt{15876}[/tex]

[tex]A_2=126[/tex]

Now, the area of the quadrilateral is the sum of area of the triangle ABC and triangle ACD.

[tex]A=A_1+A_2[/tex]

[tex]A=180+126[/tex]

[tex]A=306[/tex]

Therefore, the area of the quadrilateral ABCD is 306 square meter.

Answer:

(a) A = 5 to 10 years old

B = 11 to 13 years old

C = adequate calcium intake

I = inadequate calcium intake.

(b) P(A) = 0.52, P(B) = 0.48, P(I|A) = 0.18, P(I|B) = 0.57.

Step-by-step explanation:

Complete question

Please find the attached image

(a) A = 5 to 10 years old

B = 11 to 13 years old

C = adequate calcium intake

I = inadequate calcium intake.

b) P(A) = 0.52, P(B) = 0.48, P(I|A) = 0.18, P(I|B) = 0.57.

Step-by-step explanation:

the answer is already as simplified as it could be

Answer:

H+C = 393

H - 57 = C

~~~~~~~~~~~~~~~~

H + H - 57 = 393

2H = 450

H = 225

C = 168

Step-by-step explanation:

Answer:

b.  [tex]\frac{7+\sqrt{61} }{6} ,\frac{7-\sqrt{61} }{6}[/tex]

Step-by-step explanation:

[tex]3x^{2} -1=7x[/tex]

Quadratic equations are suppose to be written as: [tex]ax^2+bx+c=0[/tex]

so the new quadratic equation for this problem will be: [tex]3x^{2} -1-7x=0[/tex]

Now rearrange the terms: [tex]3x^{2} -7x-1=0[/tex]

Then use the Quadratic Formula to Solve for the Quadratic Equation

Quadratic Formula = [tex]x=\frac{-b±}{} \frac{\sqrt{b^2-4ac} }{2a}[/tex]

Note: Ignore the A in the quadratic formula

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

[tex]3x^{2} -7x-1=0[/tex]

a = 3

b = -7

c = -1

[tex]x=-(-7)±\frac{\sqrt{(-7)^2-4(3)(-1)} }{2(3)}[/tex]

Evaluate The Exponent

[tex]x=\frac{7±\sqrt{(49)-4(3)(-1)} }{2(3)}[/tex]

Multiply The Numbers

[tex]x=\frac{7±\sqrt{49+12} }{2(3)}[/tex]

Add The Numbers

[tex]x=\frac{7±\sqrt{61} }{2(3)}[/tex]

Multiply The Numbers

[tex]x=\frac{7±\sqrt{61} }{6}[/tex]

C.(f-g)(x) = 4x^3 +5x²-7x-1

Step-by-step explanation:

Given information :

[tex]f(x) = 4 {x}^{3} + 5 {x}^{2} - 3x - 6 \\ g(x) = 4x - 5[/tex]

Find :

[tex](f - g)(x) = \\ (4 {x}^{3} + 5 {x}^{2} - 3x - 6) \\ - 4x -5[/tex]

Open bracket and Simplify

[tex]4 {x}^{3} + 5 {x}^{2} - 3x - 6 - 4x + 5 \\ 4 {x}^{3} + 5 {x}^{2} - 7x - 1[/tex]

Answer:

562,354 votes

Step-by-step explanation:

1/11 of 6,185,894

=>1/11 x 6,185,894

=>562,354

Answer: (X-12)(x+4)

The middle number is -8 and the last number is -48.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -8

Multiply together to get -48

Can you think of the two numbers?

Try 4 and -12:

4+-12 = -8

4*-12 = -48

Fill in the blanks in

(x+_)(x+_)

with 4 and -12 to get...

(x+4)(x-12)

Answer:

(x+4)(x−12)

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { (x - 12)(x + 4 )}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] {x}^{2} - 8x - 48[/tex]

[tex] = {x}^{2} + 4x - 12x - 48[/tex]

Taking [tex]x[/tex] as common from first two terms and [tex]12[/tex] from last two terms, we have

[tex] = x \: (x + 4) - 12 \: (x + 4)[/tex]

Taking the factor [tex](x+4)[/tex] as common,

[tex] = (x - 12)(x + 4)[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

A1/ the difference of 3 and x divided by 7

A2/ 3e - 5

A3/ -1

A4/ g + (g - 8)

A5/ One half the difference between eight and a number y

I'm not sure, but I hope it helps :)

Answer:

B

Step-by-step explanation:

Let the number = x

2/5 (x - 1)

<

3/5 (x + 1)

2/5 (x - 1 ) < 3/5(x+ 1)      Multiply both sides  by 5

2(x - 1) < 3 ( x + 1)            Remove the brackets.

2x - 2 < 3x + 3                Add 2 to both sides

2x < 3x + 5                     Subtract 3x from both sides

2x - 3x < 5              

- x < 5                            Here's the tricky part . Divide by - 1

x > -5                             Notice what happened. The < become > That happens because you have divided (or multiplied) by a negative number.

The original question 2/5 (x - 1 ) < 3/5(x+ 1)    was graphed. The red part is every value that satisfies the inequality. You should be using a y and x together to find a more suitable answer using this program. But if you just look along the x axis, you will see that the < has been turned around.

B The second one from the top.

Answer:

15 mph

Step-by-step explanation

i used a calculator but correct me if im wrong pls

Step-by-step explanation:

jnx-avkj-uup p.l.z join

Answer:

2, 3, 5, 8, 13 missing number is 18.

Answer:

Step-by-step explanation:

-1<x<3.   I hope it helpful!

Answer:

4.53

Step-by-step explanation:

Given the data :

4, 5, 10, 11, 15

The mean = 9

The standard deviation of a sample :

s = √[Σ(x - mean)²/(n-1)]

s = √[((4-9)² + (5-9)²+(10-9)² + (11-9)² + (15-9)²) / (5-1)]

s = √(25+16+1+4+36)/4

s = √20.5

s = 4.527

s = 4.53

Answer:

4.5

Step-by-step explanation:

5.1.3

Answer:

2nd one is the answer if it's the question

Answer:

[tex]PR = 37[/tex]

Step-by-step explanation:

Given

[tex]PQ = 25[/tex]

[tex]PQ = 2x +1[/tex]

[tex]QR = x[/tex]

Required

PQ

Since Q is between the given points, then:

[tex]PR = PQ + QR[/tex]

This gives:

[tex]PR = 2x + 1 + x[/tex]

Collect like terms

[tex]PR = 2x + x+ 1[/tex]

[tex]PR = 3x + 1[/tex]

Next, solve for x

We have:

[tex]PQ = 25[/tex]

[tex]PQ = 2x +1[/tex]

This gives:

[tex]2x + 1 = 25[/tex]

Collect like terms

[tex]2x = 25 -1[/tex]

[tex]2x = 24[/tex]

Divide by 2

[tex]x = 12[/tex]

So:

[tex]PR = 3x + 1[/tex]

[tex]PR = 3 * 12 + 1[/tex]

[tex]PR = 37[/tex]

x^2 + y^2 = 12.25

The above equation is the equation for a circle. The formula for the equation of a circle is (x - h)^2 + (y - k)^2 = r^2.

Looking at the given equation, x and y, otherwise known as the center, are not shifted at all. This mean that the center of our circle is at (0,0).

To find the radius, we take the square root of 12.25, which is 3.5. Therefore, go 3.5 units up, down, left, and right (to make a + sort of shape) from the center and then connect the points to make the circle.

Hope this helps!! :)

Answer:

Step-by-step explanation:

The graph of x^2 + y^2 = 12.25 will be a circle with centre at (0, 0) and radius will be √12.25 = 3.5.

2x + y = 1  is a straight line

y = -2x + 1 so it will pass through the y axis at y = 1 and also through the point

(-1/2, 0).

Where the line passes through the circle will be the solutions to the system.

Hope this helps. Please mark brainliest

Answer: 20

let the number be x

1/4 x = 5

x=5*4

x=20

Answer:

x=20

Step-by-step explanation:

[tex]\frac{1}{4}x=5\\x=20[/tex]

divide [tex]\frac{1}{4}[/tex] on both sides, which gives you 20.

Answer

No solution

Step-by-step explanation:

4y + 2x = 18

3x + 6y = 26

You need either the x's or the y's to have the same coefficients.

let's line things up first.

4y + 2x = 18   (multiply by 3)

6y + 3x = 26  (multiply by 2)

to keep numbers relatively small we will multiply the top equation by 3 and the bottom equation by 2. Multiply all terms. This will make the coefficients equal.

12y + 6x = 54

12y + 6x = 52

So, if you subtract them from each other you get :

0 = 2

When this happens the solution set is : no solution

Answer:

Impossible

Step-by-step explanation:

Ok, so we first rearrange for convenience:

2x+4y=18

3x+6y=26

We multiply the two equations to eliminate x:

2x+4y=18 * -3

3x+6y=26 * 2

So:

-6x-12y=-54

6x+12y=52

And now we add the two equations:

0+0= -2

Try multiplying the two equations by any other number which will lead to them cancelling, (eg. -9, 6), still the equation will not work.

Answer:

2a.

Step-by-step explanation:

6 = 2 * 3

8 = 2 * 2 * 2   - 2 is common to both sets of factors.

So the GCF of 6 and 8 is 2.

For the 2 a's it is a.