A coniferous forest that runs along the west coast of Canada and the United States, due to the moist winds off the Pacific, is called the

Answers

Answer 1
Is called the = temperate rain forest

Related Questions

DNA and RNA are structurally similar in some ways, but different in others. Identify whether each of the following statements applies to DNA, RNA. both or neither.
1. It can contain the purine adenine.
2. It can contain the pyrimidine uracil.
3. This contains the pyrimidine thymine.
4. In terms of base composition, the %T = %G.
5. This contains the sugar ribose.
6. The sugars are connected with a 3'-5' phosphodiester link.
7. It contains equal amounts of guanine and cytosine.
8. Bases are attached to sugars in an alpha N-glycosides linkage.

Answers

Answer:

DNA

It can contain the purine adenine

This contains the pyrimidine thymine

The sugars are connected with a 3'-5' phosphodiester link.

It contains equal amounts of guanine and cytosine. The percentage of A-T ,C-G are the same in DNA,,they are linked by hydrogen bonds.But varies in RNA.

Explanation:

.RNA

It can contain the purine adenine.

It can contain the pyrimidine uracil

This contains the sugar ribose. This is a 5C sugar with one oxygen atom deficient.The forms the lever for holding the bases and phosphate group

The sugars are connected with a 3'-5' phosphodiester link.This is the backbone of both DNA and RNA.It is formed between the sugars and the phosphate groups in both DNA and RNA.

None is made of  base composition, the %T = %G. This is wrong because purines must pair with pyrimidine,but not two purines or pyrimidine  pairing  as shown,

Bases are attached to sugars in an alpha N-glycosides linkage.This is wrong the beta N-glycisidic bonds are the linkages

Suppose you want to make a new connection to species in the concept map. Which of the terms below could fill in the blank in this new connection: "_____ is a mechanism that defines the separation between species." Select all that apply.

Answers

Answer:

Hello. You did not enter answer options, but some terms that can be used to fill in the blank are:

Hybrid infertility, Hybrid inviability, Behavioral isolation, Sympatric isolation, Habitat isolation, Hybrid breakdown, Allopatric isolation.

Explanation:

All of the above terms represent situations that cause separation between species. This separation can occur physically or molecularly, but it always results in genetic modifications that end up separating one species genetically from the other, causing evolution and generating different species, to the point that it is not possible to establish mating between its members.

S100A8 sex chromosome? yes or no

Answers

Answer:

yes !!

Explanation:

because it's yes !!

Answer:

YES

Explanation:

I know this because i looked it up

In prokaryotic cells, regulator proteins bind to a section of DNA called alan (1 point)
O repressor
o promoter
O chromatin.
o operon.

Answers

Answer:

promoter

Explanation:

Answer: Operon

Explanation:

Consider that a certain gene is a maternal effect gene and that the allele for dark brown pigment is incompletely dominant to the allele for no pigment (white). The incomplete dominant phenotype is light tan. If a white female is crossed with dark brown male, what will be the phenotypic ratio of the progeny?
A) all white
B) all dark brown
C) all light tan
D) either all white or all light tan
E) either all light tan or all dark brown
F) none of the above choices (cannot be determined)

Answers

Answer:

The correct answer is C. All light tan        

Explanation:

You will find the answer and explanation in the attached file due to technical problems.

You believe that the cytosolic protein p007 is involved in mediating growth hormone-stimulated proliferation in cells. You wish to establish a cell model using your cultured fibroblasts. Provide clear explanations to the following, each worth 2.5 pts each. a) Describe how you would transfect the growth hormone receptor DNA into your cells to create stable cell lines, and include a description of the benefits of using stable cell lines versus transiently transfected cell line. b) Describe how you would measure specific receptor binding of GH to your stable cell line. c) Describe how you would measure growth hormone-induced proliferation in your stable cell line. Make sure to include controls. d) Describe how you would use RNAi to demonstrate the requirement for p007 in growth-hormone stimulated proliferation. Make sure to include controls.

Answers

Answer:

Following are the answer to this question:

Explanation:

In option a:

There are many ways, which can be defined as follows:  

It keeping cells "qualified," use heat shock and handle ions like Ca and ice incubating.It uses Micro-injection with DNA.  It uses the biolistics or even the process of gene-gun.  

The stable cell charts indicate simple and definitive outcomes when their relationship to specific results. Moreover, relative to temporary cell lines, findings are more reliable and error-free. These lines also easily break and much less.

In option b:

Radio tests including linking tests could be used  

The Ligand Binding Assays is an analysis, that is based on the binding of ligands to antibodies, or other macromolecules. Its existence and distance of formed ligand-receptor complexes are defined using a system of measurement that is usually electrical or fluorescent.

In option c:

The method for measuring the levels of cell growth is accessible and the  Another way is to measure the metabolism within the same cell. So many color pigments were also accessible that can permeate an organism as well as react with some proteins as well as other factors, and that can effectively identify a color final product.  

Throughout relation to the amount of metabolism exercise, cell proliferation could be evaluated by researching one or even more cell markings. The BrdU limited liability assessment is a very well-published illustration.  

Its specific antibody can detect BrdU and high BrdUincorporations levels are linked to high levels of cell proliferation.  Command cell without DNA receptor growth hormone.

In option d:

The cell growth will stop after each use of RNA interference ( RNAi). The p007 formation as well as the effect on growth caused by the intrusion will be a goal. If development is delayed effectively, the theory will be tested successfully to a cell without any of the required DNA. The RNAi is the free cell

You decide to focus first on Mutation 1 and Mutation 2.
The F' plasmid appears to "rescue" mutant strain 1 by restoring wild-type inducible expression.
The F' plasmid does not change the phenotype of mutant strain 2; there is still no expression of the lac operon.
There are three possible mutations that could lead to lack of expression: a super-repressor (Is), a promoter mutation (P-) or a mutation in the lacZ gene (Z- ). To determine the effect of introducing a wild-type F' plasmid into a bacterial cell with each of these mutations, you draw out the three possible scenarios.
F' l+ cap+
Determine the expression of the lac operon for each possible partial diploid and for the "unknown" mutation partial diploids (Mutation 1 and Mutation 2).
1. F' lac+/ ts
2. F' lac+/ P
3. F' lac+/ Z
4. F' lac+/ Mutation 1
5. F lac+/ Mutation 2
A. Inducible (wild type)
B. No expression (mutant)

Answers

Answer:

Super-repressor (Is) - Uninducible dominant

Binding region is modified by the protein called repressor which prevents the lactose to bind with it. Thus, even the lactose is present the repressor protein is bound to the promoter and can not be detach from it. Transcription is not inducible.

Promoter mutation (P)- - Uninducible recessive

Mutated promoter region inhibits the binding of RNA polymerase that leads to trranscription.

The lacZ gene ( Z-) is mutated - recessive while the normal LacZ gene (Z +) -  dominant .

                   Inducible (Wild type)        No expression (Mutant)

F' lac+/ Is             No                                Yes

F' lac + / P-            Yes                                 No

F' lac + / Z-            Yes                                 No

F' lac +/ Mutation1     Yes                                 No

F' lac+ / Mutation2      No                                 Yes

Mutation 1 and F' plasmid - Inducible wild type

Mutation 2 and F' plasmid - Mutant no expression

In pea plants there is a dominant allele (A) for green pods and a recessive allele (a) for yellow pods. Suppose a heterozygous plant is crossed with a plant that has yellow pods. Complete the sentences about this cross with the correct terms.
1. The phenotype of the heterozygous plant is_________.
2. The genotype of the heterozygous plant is_________.
3. The genotype of the plant with yellow pods is________.
4. The genotypes of gametes produced by a heterozigous plant is______.
5. The genotypes of gametes produced by a yellow plant is_______.
A. Green pods
B. 75% AA and 25% Aa
C. AA
D. 100% A
E. Yellow pods
F. 50%
G. 25%
H. 100% a
I. 50% A and 50% a
J. Aa
K. 0%
L. 75%
M. 75% A and 25% a

Answers

Answer:

1. Green

2. Aa

3. aa

4. A and a

5. a and a

Explanation:

1. The phenotype of the heterozygous plant (Aa) would be green since the allele responsible for green color (A) is dominant over the allele responsible for yellow color (a).

2. The genotype of a heterozygous plant would be Aa. Heterozygous individuals have different alleles for the same gene.

3. The genotype of the plant with a yellow pod would be aa. Since the allele for green color (A) is dominant over the allele for yellow color (a), the yellow color can be expressed only in the absence of the (A) allele. Hence, the genotype fo yellow color has to be aa.

4. The genotypes of gametes produced by a heterozygous plant would be (A) and (a) because heterozygous individuals have two different alleles for a gene.

5. The genotypes of gametes produced by a yellow plant would be (a) and (a) because a yellow plant has the genotype (aa).

Please answer ASAP, the assignments in due really soon :) 30 Points!!! The image below shows the lac operon, which breaks down lactose in bacteria. Which statement correctly describes the expression of this gene?

Answers

Answer:

B. Gene expression is influenced by high lactose levels in the environment.

Explanation:

The lactose operon (lac operon) functions for the metabolism and transport of lactose in several bacteria.

Gene expression is influenced by high lactose levels in the environment as genes are expressed in the presence of high level lactose and absence of glucose. High level lactose carry an activator protein called catabolite activator protein (CAP), which let the RNA polymerase do transcription of the operon.

Hence, the correct option is "B".

Answer:

C

Explanation:

^he said it was right^

have an amazing day! :)

4. Unlike a scientific theory, a scientific law describes an observed pattern in nature without
attempting to explain it.
O true
Ofalse​

Answers

Answer:

False

Any discovery must first be tested and have an explanation

y= -14x + 1.2 5 can be x or y

Answers

Answer:

Slope= 2.0002.400=1.200

x−intercept=−60​=−0.00000

y−intercept=50​=0.00000

Hoped I helped

In quiet breathing, muscular effort is used mainly in inspiration, and expiration is largely passive, due to elastic recoil of the lung. It results in a pattern change between expiratory and inspiratory flow. Explain changes you observed in the recordings you obtained.

Answers

Answer:

The summary of something like the particular question is demonstrated in the following portion on either the clarity.

Explanation:

Inspiration depends on either the diaphragm contracting, as well as the influence including its external intercostal has been limited throughout normal breathing. Maximum inhalation or even just expiration time depth, as well as rate, are fairly directly proportional to one another because.We may link the whole observation to something like the sequence of expiratory versus inspiratory movement as it takes much longer than either the inspiratory speed throughout our sample since expiration becomes passive yet requires having to return to something like the steady levels.

Outside the lining of the alveolus is blood, which is at a gauge pressure of 5 mmHg, while air is contained inside the alveolus. What is the absolute pressure inside the alveolus

Answers

Answer:

765 mmHg

Explanation:

The gauge pressure = 5 mmHg

To get the absolute pressure we use the relationship

[tex]P_{ab}= P_{g}+ P_{atm}[/tex]

where [tex]P_{ab}[/tex] is the absolute pressure = ?

[tex]P_{g}[/tex] is the gauge pressure = 5 mmHg

[tex]P_{atm}[/tex] = atmospheric pressure = 760 mmHg

substituting, we have

[tex]P_{ab}[/tex] = 5 mmHg + 760 mmHg = 765 mmHg

DIHYBRID CROSSES
In all of the examples we have only been concerned with one trait. It is possible, however, to track the inheritance of more than one trait at a time. When one is investigating the inheritance of two traits at once the cross is called a dihybrid cross. Strictly speaking, a dihybrid cross is one between two individuals that are heterozygous for two traits, meaning that they are hybrids in two senses. For example, in humans eye color is determined by multiple factors, but if we compare only blue eyes to brown eyes, brown is dominant (R) and blue acts as a recessive allele (r). If a man heterozygous for both eye color and bent little finger has a child with a woman who also heterozygous for both traits, this would be a dihybrid cross. Which is/are possible genotypes for a person with bent little finger and blue eyes?
1. bbrr
2. BBRR
3. BBrr
4. Bbrr
Referring to the previous question, which is/are possible genotypes for a person with straight little finger and blue eyes?
1. bbrr
2. BbRr
3. Bbrr
4. bbRr

Answers

Answer:

Question 1: bbrr

Question 2: bbRr

Explanation:

To address the first question, the possible genotype for someone with bent little finger and blue eyes would be bbrr.

Since brown eye (B) is dominant over blue eyes (b), in order for the blue eye color to be expressed, it has to be in bb condition. The only option with bb genotype is option 1.  

For the second question, the possible genotype for a person with a straight little finger and blue eyes would be bbRr.

Blue eye genotype is bb as explained in the first question while straight little finger would be Rr since the bent little finger has been represented by the genotype rr in the first question.

g Riboswitch is a mechanism of gene activity regulation by mRNA conformation. Riboswitch can regulate ______.

Answers

Answer: c. both transcription and translation

Explanation:

Riboswitchs are mRNA elements that influence the activity of genes certain genes by regulating same and are found in other organisms apart from humans such as bacteria, plants and fungi.

They regulate activity by binding to specific small molecules known as ligands thus causing a structural rearrangement that enables either transcription or translation to be modulated in the gene.

How do animals survive along the deeper parts of the seafloor? A They feed at the surface. B They feed on each other. C They photosynthesize.

Answers

Answer:

They photosynthesize..

Explanation:

There are several ways deep ocean animals survive in such an enviournment..Food is scare in much of the deep sea, in parts because photosynthesis only thakes place at the ocean's surface where there's sunlight. Most animals cope with this by begin very small and meeding less to eat of by growoing very slow..

Answer:

the answer is They photosynthesize..

Explanation:

Select the scenarios that describe an abiotic factor that is density independent. Select the TWO answers that are correct.

a. Fir trees grow in number, increasing the amount of food available for moose
b. Heavy and continuous rains flood the land, submerging habitats.
c. Lightning strikes a tree and begins a fire that clears the land.
d. Ticks infesting moose weaken the moose's health and reproductive success.
e. Frigid temperatures flow into the area, causing hypothermia and death.

Answers

Answer: Option B and C.

Heavy and continuous rains flood the land, submerging habitats.

c. Lightning strikes a tree and begins a fire that clears the land.

Explanation:

Heavy and continuous rains flood the land, submerging habitats.

Lightning strikes a tree and begins a fire that clears the land.

The above are example of density independent abiotic factors because rainfall and lightning affect the population size of the environment by decreasing it's population sizes.

Abiotic factors are the non living part of the environment and they include rain fail, temperature,lightning, humidity e.t.c.

Density independent abiotic factors are factors that decrease or increase the population size of the ecosystem.

Therefore, Heavy and continuous rains flood the land, submerging habitats.

cLightning strikes a tree and begins a fire that clears the land are density independent factor because they decrease the population size.

The scenarios that describe an abiotic factor that is density independent are ; ( B and C )

Heavy and continuous  rains flood the land, submerging habitats ( B )Lightning strikes a tree and begins a fire that clears the land ( C )

Abiotic factors are Nonliving components of an ecosystem that has a significant effect on the ecosystem such as ; Rain, rocks, Temperature and humidity. Density Independent factors are factors in an ecosystem that can cause the decrease or increase of the population size of an ecosystem.

Heavy and continuous rainfall is an abiotic factor that has the ability to decrease the population of an ecosystem by submerging organisms habitats.

Lightning striking a tree and setting it ablaze which clears the land also reduces the population of the ecosystem because the fire will lead to loss of habitats and death of some organisms .

Hence we can conclude that The scenarios that describe an abiotic factor that is density independent are Heavy and continuous  rains flood the land, submerging habitats and Lightning strikes a tree and begins a fire that clears the land .

Learn more : https://brainly.com/question/19180443

Which is incorrect descriptions of the genetic event initiated by the HIV reverse transcriptase (RT) upon the HIV infection?
a. RT catalyzes initial synthesis of ssDNA using viral genomic RNA as the template.
b. The first RNA template is degraded after ssDNA synthesis.
c. The whole process is completed after synthesis of dsDNA.
d. tRNAs are adopted as the first primers.
e. None of these

Answers

Answer:

e. None of these

Explanation:

The immune deficiency viruses (HIV) are retroviruses that use a reverse transcriptase (RT) enzyme to produce a single-stranded DNA (ssDNA) from an RNA template. The reverse transcription allows retroviruses to replicate their genetic material, which is integrated into the host's genome as a double-stranded linear DNA molecule in a similar way to the mechanism of insertion used by endogenous retrotransposons. The synthesis of DNA is started by cellular tRNAs (tRNA3Lys) that are packaged into the virion. After reverse transcription, the HIV DNA enters the nucleus of CD4 immune cells (also known as CD4+ T cells), and then it integrates into the genome to coopt the host's cell machinery for its own replication.

Which is the best way to describes the Biodiversity of an areas

Answers

Answer:

Biodiversity is defined as “the variability among living organisms from all sources including, inter alia, terrestrial, marine and other aquatic ecosystems and the ecological complexes of which they are part; this includes diversity within species, between species and of ecosystems.” The importance of this definition ...

Two of the many cycles in nature's web of life are the carbon cycle and the A. energy cycle B. water cycle C. food cycle D. heat cycle

Answers

━━━━━━━☆☆━━━━━━━

▹ Answer

B. water cycle

▹ Step-by-Step Explanation

Water is something that is dependent on amongst living things. Without the water cycle, there wouldn't be a source of water and living things wouldn't be able to survive.

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

How can particle interactions explain the properties and behavior of dry ice?

Answers

Answer:

Dry ice is the solid form of carbon dioxide (CO2). The particle interaction in dry ice is due to collision between inter-particles which results in agglomeration and shows the properties and behavior of dry ice.

The inter-particle collision in dry ice keeps the high temperature of dry-ice and make it sublimate (solid to gas) at room temperature and normal pressure.

The collision of carbon atoms in dry ice also makes it highly reactive and shows chemical properties of dry ice. When dry ice is added with magnesium, it left black powder, which is carbon

Is zinc renewable or not?

Answers

Answer:  Zinc is  non renewable.

Explanation:

Non-Renewable resources are resources that cannot be replenished easily through natural process. These are the sources which are used in wise manner so that they do not get depleted. For example: coal, petroleum etc.

Renewable resources are resources that can be replenished overtime through natural process.These are the sources which never depletes completely. For example: bio mass energy, solar energy etc.

As zinc cannot be replenished easily through natural process, it is  non renewable.

Animal migration on savannas is often governed by

distance
reproduction
rainfall
fire

Answers

Answer:

The answer would be rainfall.

Explanation:

The reason why this is the answer is because rain is essential for survival in such a hot and dry climate. Droughts are quite frequent in the savanna and the lack of water leads to the death of many organisms.

Answer:

Rainfall is what often governs animal migration on savannas.

Explanation:

Brainlies please

on terms of genetic similarity, which list is ordered from most similar to least similar b. cousin, uncle, mother, non twin sibling, identical twin

Answers

Answer:

Identical Twin, non twin sibling, Mother, Cousin, Then Uncle

Explanation:

When a liquid becomes a gas, _____

The molecules move closer together
The molecules move farther apart
The molecules are unchanged
There are no molecules

Answers

Answer:

The molecules move farther apart.

According to kirk smith a professor of environmental health at the university of california berkley indoor fires increase risks of pneumonia tuberculosis lung cancer and low birth weight in babies born of women expose during pregnancy. What simple solution is being widely promoted to reduce the risk of death?
a) preparing meals using solar cookers.
b) switching from wood to burning crop waste as a fuel source.
c) adding more windows to houses as a source of ventilation.
d) passing a green tax to make homeowners pay for their pollution.
e) providing asthma inhalers to children under the age of 12 years.

Answers

Answer:

preparing meals using solar cookers.

Explanation:

solar cookers  radiates at low rates.Therefore the most of the nutrients in the foods are conserved.Thus most micro nutrients for biochemical activities are retained. Vitamins which can not withstand high temperature are preserved.

Most importantly carcinogens which are usually associated with high heat foods are avoided ,when cook with low heat of solar cookers

The solar cooker is smoke free,therefore irritation of the lungs,lung cancer associated with high heat  cookers is avoided.

Specifically,local Mayan women exposed to high heat smoke cookers, suffers lung cancer,and those with pregnancy gives to infants with low birth weights. Children exposed to theses high heat also experienced acute lower respiratory infections.

Thus the smokeless,low heat solar cooker is safer.

Given the gene sequence GGACCGTCGATCTTC, which of the following choices would
represent an inversion mutation?
A. CCACCGTCGATCTTC
B. GGACCG TCGATC TTC
C. GGACCGTCGATCCTT
D. GGAC TCGATC TTC

Answers

Answer:

I would go with A maybe,am not really sure though.

Under normal conditions glomerular filtration depends on three main pressures. What pressures is a pressure that favors the process of filtration?

Answers

Answer:

Glomerular Hydrostatic pressure .

Explanation:

The basic function of the kidney is the formation of urine for elimination through the urinary excretory system. Two different processes determine this formation: the filtration of fluid through the glomerular capillaries into Bowman's space and the modification of the volume and composition of the glomerular filtrate in the renal tubules.  The fluid passes from the glomerular capillaries to Bowman's capsule due to the existence of a pressure gradient between these two areas. This process is favored by two structural characteristics that make renal corpuscles particularly effective filtration membranes: glomerular capillaries have a much higher number of pores than other capillaries, and the efferent arteriole has a smaller diameter than the afferent arteriole, causing greater resistance to outflow of blood flow from the glomerulus and increasing glomerular hydrostatic pressure. Increased glomerular hydrostatic pressure (due to increased blood flow through the glomerulus) increases filtration, while increases in Bowman's hydrostatic pressure or urinary space (which remains constant, unless there is disease at that level, usually due to fibrosis) and plasma P. oncotic (determined by proteins, which tend to "drag" plasma into the glomerulus) decrease filtering. Resulting in a filtering pressure of 10 mmHg.

Saprobic microorganisms are important decomposers of plant litter, animal matter, and dead microbes. This is an example of a(n) ______________.

Answers

Answer:

The correct answer would be - heterotrophs (chemoheterotrophs)

Explanation:

Heterotrophs are the living organisms that are directly or indirectly depend on the autotrophs or the organisms that can make their own food for energy and growth.

Saprobic microorganism are free living organisms that get their energy from decomposing rotten or dead organic matter such as plant litter, animal matter and dead microbes. It is performed with the help of enzymes or chemicals they release to decompose such matter. they also known as chemoheterotrophs.

Thus, the correct answer would be - heterotrophs (chemoheterotrophs).

The ion composition of perilymph is like that of interstitial fluid; high sodium and low potassium levels. If someone ruptured the vestibular membrane, the membrane between the vestibular duct (Scala vestibuli) and the cochlear duct (Scala media), what would be the effect of such a rupture on the concentration of potassium in the endolymph in the cochlear duct

Answers

Answer:

The concentration of potassium will decrease

Explanation:

The cochlear ducts are composed of two distict types of fluids: 1-perilymph, rich in sodium (140 mM) and low in potassium (5 mM), and 2- endolymph, rich in potassium (1 mM) and low in sodium (150 mM). The perilymph fluid has a similar composition to the rest of the extracellular fluids, while endolymph present a unique ion composition that is not found in other fluids of the body. It is believed that the cochlea can regulate potassium flow without using energy (i.e.,  without use ATP), since potassium enters into the cells through passive pathways, while this ion ion leaves the cells by an active mechanism.

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