A couple is planning a wedding and they need to decide how many guests on the bride’s side
as well as on the groom’s side to invite. The couple has agreed that the bride can invite at
most 60 guests. Since the bride’s friends and family are very fancy it costs N$300 per guest
on her side while it only costs N$150 per guest on the groom’s side and they have a budget
of N$30000. Each guest on the bride’s side will receive 4 drink tickets and each guest from
the groom’s side will receive 3 drink tickets and no more than 500 drink tickets can be given.
Keeping in mind that both the bride and groom must have guests (neither of them can attend
the wedding without any of their friends or family present).
Draw a graph and use it to answer the following questions:
i. What is the maximum number of guests that can attend the wedding?
ii. How many guests will the bride and the groom each invite?
Question 2 [

Answers

Answer 1

Answer:

- The graph of this linear programming question is presented in the first attached image to this solution.

i) The maximum number of guests that can attend the wedding = 150 guests

ii) Bride can invite 50 guests and the groom can invite 100 guests to maximize the available resources.

Explanation:

Let x represent the number of guests that the bride invites.

Let y represent the number of guests that the groom invites.

- The bride can invite at most 60 guests

x ≤ 60

- I costs N$300 per guest on her side while it only costs N$150 per guest on the groom’s side and they have a budget of N$30000.

300x + 150y ≤ 30,000

- Each guest on the bride’s side will receive 4 drink tickets and each guest from the groom’s side will receive 3 drink tickets and no more than 500 drink tickets can be given.

4x + 3y ≤ 500

- Keeping in mind that both the bride and groom must have guests (neither of them can attend the wedding without any of their friends or family present).

x > 0

y > 0

This is a linear programming question. Combining all the equations as ontained above

x ≤ 60

300x + 150y ≤ 30,000

4x + 3y ≤ 500

x > 0

y > 0

The graph of this linear programming question is presented in the first attached image to this solution.

The second attached image to this solution shows each of the graphs plotted on the linear programming graph and the representative colours to recognize each of them.

i) From the acceptable region of values, we have the pairs. This is shown on the third attached image to this solution.

(60, 80)

(50, 100)

(0, 200)

(0, 166.67)

(60, 86.67)

The most correct pairs that satisfy all the conditions include

(60, 80), sum of guests In this case = 140

(50, 100), sum of guests In this case = 150

(60, 86.67), sum of guests In this case = 146.67

Of the 3 possible answers, the maximum number of guests is 150.

ii) From the most optimal solution, (50, 100), the bride can invite 50 guests and the groom can invite 100 guests to maximize the available resources.

Hope this Helps!!!

A Couple Is Planning A Wedding And They Need To Decide How Many Guests On The Brides Side As Well As
A Couple Is Planning A Wedding And They Need To Decide How Many Guests On The Brides Side As Well As
A Couple Is Planning A Wedding And They Need To Decide How Many Guests On The Brides Side As Well As

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The idea of a
"two-track mind" is central
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A. introspection
B. sensory attention
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Answers

Answer:

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Explanation:

The idea of a “two-track mind” is central to dual processing theory.

What is dual processing theory?

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C)
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Answer:

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Explanation:

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply

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Ode to the west wind Which statement best completes the blank in this graphic organizer?
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The speaker is desperately hopeful.
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Answers

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Explanation:

correct on edg2020

Answer:

b. The speaker is desperately hopeful

Explanation:

Antique Accents tracks their daily profits and has found that the distribution of profits is approximately normal with a mean of $17,700.00 and a standard deviation of about $900.00. Using this information, answer the following questions. For full marks your answer should be accurate to at least three decimal places.

Answers

Answer:

a) 0.434

b) 0.983

c) 0.367

Explanation:

The exact question with the given parameters wasn't obtained online, but the same question, albeit with different parameters is then obtained. Hopefully, this Helps to solve the complete question with the required parameters.

Antique Accents tracks their daily profits and has found that the distribution of profis is approximately normal with a mean of $17,700.00 and a standard deviation of about $900.00. Using this information, answer the following questions For full marks your answer should be accurate to at least three decimal places. Compute the probability that tomorrow's profit will be

a) less than $16,791 or greater than $18,231

b) greater than $15,783

c) between $17,997 and $20,130

Solution

This is a normal distribution problem with

Mean = μ = $17,700

Standard deviation = σ = $900

a) less than $16,791 or greater than $18,231. P(x < 16,791) or P(X > 18,231) = P(X < 16,791) + P(x > 18,231)

We first standardize 16,791 and 18,231

The standardized score for any value is the value minus the mean then divided by the standard deviation.

For 16791

z = (x - μ)/σ = (16791 - 17700)/900 = - 1.01

For 18231

z = (x - μ)/σ = (18231 - 17700)/900 = 0.59

To determine the required probability

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59)

We'll use data from the normal probability table for these probabilities

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59)

P(z < -1.01) = 0.15625

P(z > 0.59) = 1 - (z ≤ 0.59) = 1 - 0.7224 = 0.2776

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59) = 0.15625 + 0.2776 = 0.43385 = 0.434 to 3 d.p

b) greater than $15,783. P(x > 15783)

We standardize 15783

z = (x - μ)/σ = (15783 - 17700)/900 = -2.13

To determine the required probability

P(x > 15783) = P(z > -2.13)

We'll use data from the normal probability table for this probability

P(x > 15783) = P(z > -2.13) = 1 - P(z ≤ - 2.13)

= 1 - 0.01659 = 0.98341 = 0.983 to 3 d.p.

c) between $17,997 and $20,130.

P(17,997 < x < 20,130)

We first standardize 17,997 and 20,130

The standardized score for any value is the value minus the mean then divided by the standard deviation.

For 17,997

z = (x - μ)/σ = (17,997 - 17700)/900 = 0.33

For 20,130

z = (x - μ)/σ = (20,130 - 17700)/900 = 2.70

To determine the required probability

P(17,997 < x < 20,130) = P(0.33 < x < 2.70)

We'll use data from the normal probability table for these probabilities

P(17,997 < x < 20,130) = P(0.33 < x < 2.70)

= P(z < 2.70) - P(z < 0.33)

= 0.99653 - 0.62930

= 0.36723 = 0.367 to 3 d.p.

Hope this Helps!!!

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