A cylindrical specimen of some metal alloy having an elastic modulus of 124 GPa and an original cross-sectional diameter of 4.2 mm will experience only elastic deformation when a tensile load of 1810 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.46 mm.

Answers

Answer 1

Answer:

the maximum length of the specimen before deformation is 0.4366 m

Explanation:

Given the data in the question;

Elastic modulus E = 124 GPa = 124 × 10⁹ Nm⁻²

cross-sectional diameter D = 4.2 mm = 4.2 × 10⁻³ m

tensile load F = 1810 N

maximum allowable elongation Δl = 0.46 mm = 0.46 × 10⁻³ m

Now to calculate the maximum length [tex]l[/tex] for the deformation, we use the following relation;

[tex]l[/tex] = [ Δl × E × π × D² ] / 4F

so we substitute our values into the formula

[tex]l[/tex] = [ (0.46 × 10⁻³) × (124 × 10⁹) × π × (4.2 × 10⁻³)² ] / ( 4 × 1810 )

[tex]l[/tex] = 3161.025289 / 7240

[tex]l[/tex] = 0.4366 m

Therefore, the maximum length of the specimen before deformation is 0.4366 m


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Answer:

equal amounts of inversion and retention at the center undergoing substitution

Explanation:

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Answers

I believe most likely: (C) least likely: (B)

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Answers

Answer:

In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component. ... In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.

Explanation:

For automobile engines, identify the best choice of motor oil.
A. High viscosity for Maine in the winter and low viscosity for Florida in the summer.
B. Low viscosity for Maine in the winter and low viscosity for Florida in the summer.
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D. High viscosity for Maine in the winter and high viscosity for Florida in the summer.
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Answers

Answer:

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Explanation:

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3
د3
lic
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Answers

Answer:

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Answers

Answer:

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Explanation:

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