a disk rotates at 7200 rpm. it has 500 sectors of 512 bytes around the outer cylinder. how long does it take to read a sector? group of answer choices about 4.167 usec about 8.33 msec about 0.2 msec about 16.67 usec

The function that accepts a c-string as an argument and converts the string to a long integer is the strtol() function.

The strtol() function is part of the C standard library and is declared in the <cstdlib> header file. It is used to convert a C-string (character array) representing an integer value into a long int value.

Here's the general syntax of the strtol() function:

#include <cstdlib>

long int strtol(const char* str, char** endptr, int base);

   str is the C-string to be converted.

   endptr is a pointer to a char* object that will be set by the function to the character immediately following the converted number.

   base is the number base (radix) to interpret the string (e.g., 10 for decimal numbers, 16 for hexadecimal numbers).

The strtol() function parses the input string and returns the converted long int value. If the conversion fails, it returns 0. You can check for conversion errors by examining endptr or by using errno if you have included the <cerrno> header.

Here's an example of using strtol() to convert a C-string to a long int:

#include <cstdlib>

#include <iostream>

int main() {

   const char* str = "12345";

   char* endptr;

   long int num = strtol(str, &endptr, 10);

   if (endptr == str) {

       std::cout << "Invalid input.";

   } else {

       std::cout << "Converted number: " << num;

   }

   return 0;

}

In this example, the C-string "12345" is converted to the long int value 12345, and it is printed to the console.

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In this code, the is_even function checks if the inputted number is divisible by 2 without any remainder. If it is, the function returns True, indicating that the number is even. Otherwise, it returns False, indicating that the number is odd.

Python function that takes an integer as a parameter and returns True if the inputted integer is even, and False if it is odd:

def is_even(number):

   if number % 2 == 0:

       return True

   else:

       return False

# Test the function with integers 5 and 10

number1 = 5

number2 = 10

result1 = is_even(number1)

result2 = is_even(number2)

print(f"The number {number1} is even: {result1}")

print(f"The number {number2} is even: {result2}")

output:

The number 5 is even: False

The number 10 is even: True

We then call the function with the integers 5 and 10 and store the results in result1 and result2 variables, respectively. Finally, we print out the results indicating whether each number is even or not.

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