A display case of toy rings are marked 5 for $1. If Zach wants to buy 50 toy rings, how much will Zach spend (not including tax)

Answer:

the magnitude of a real number without regard to its sign.

Step-by-step explanation:

For example, |-3| would just be a 3 in general, no negative sign in the front.

hope this answers your confusion.

Answer:

A. ¼

Step-by-step explanation:

Rate of change (m) = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Using two points on the line, (4, 1) and (-4, -1), find the rate of change using the formula stated above:

Where,

[tex] (4, 1) = (x_1, y_1) [/tex]

[tex] (-4, -1) = (x_2, y_2) [/tex]

Plug in the values

Rate of change (m) = [tex] \frac{-1 - 1}{-4 - 4} [/tex]

= [tex] \frac{-2}{-8} [/tex]

= [tex] \frac{1}{4} [/tex]

Rate of change = ¼

Answer:

A

Step-by-step explanation:

the first one in the picture

Answer:

a)  c) μ = 16.4.

b)  d) μ > 16.4.

c) a) μ < 16.4.

d) c) μ ≠ 16.4.

e)  d) right; left; both.

Step-by-step explanation:

Question a:

Test if it is getting worse, so at the alternative hypothesis we test if the mean is of greater than 16.4 inches, but at the null hypothesis we test if it is still of 16.4 options, so option C.

Question b:

At the alternative hypothesis we test if the mean is of greater than 16.4 inches, as said above, so the answer is given by option d.

Question c:

Dying down, so if the mean is lower than 16.4 inches, so option a.

Question d:

Don't know, so just test if it is different, which includes both lower or greater, so the correct answer is given by option c.

Question e:

Test if more -> right, so on question b) is a right tailed test.

Test if less -> left, so on question c) is a left tailed test.

Different -> both sides, so on question d) it is a two-tailed test.

Thus the correct answer is given by option d.

Answer:

A is that answer

A) y<2x-3

Answer:

3

Step-by-step explanation:

From the diagram

AD = 9 units and AB = 3 units , then

[tex]\frac{AD}{AB}[/tex] = [tex]\frac{9}{3}[/tex] = 3

Answer:

Speed of the river = [tex]\frac{4}{3}[/tex] km per hour

Step-by-step explanation:

Speed of the boat in still water = 4 km per hour

Let the speed of the river = v km per hour

Speed of the boat upstream = (4 - v) km per hour

Time taken to cover 6 km = [tex]\frac{\text{Distance}}{\text{Speed}}[/tex]

                                           = [tex]\frac{6}{4-v}[/tex] hours

Speed of the boat downstream = (4 + v) km per hour

Time taken to cover 12 km = [tex]\frac{12}{4+v}[/tex] hours

Since, time taken by the boat in both the cases is same,

[tex]\frac{6}{4-v}= \frac{12}{4+v}[/tex]

6(4 + v) = 12(4 - v)

24 + 6v = 48 - 12v

12v + 6v = 48 - 24

18v = 24

v = [tex]\frac{24}{18}[/tex]

v = [tex]\frac{4}{3}[/tex] km per hour

9514 1404 393

Answer:

  d = kw/p

Step-by-step explanation:

When d varies directly with w, the equation is ...

  d = kw

When d varies inversely with p, the equation is ...

  d = k/p

When d does both, the equation is ...

  d = kw/p

Answer:

x2-4

Step-by-step explanation:

Answer:

hope it helps

Hello!

3a = 7b =>

=> 3 × a = 7 × b =>

=> a/b = 7/3

Good luck! :)

Answer:

[tex]Q(a+h)-Q(a-h)=8ah+10h[/tex]

Step-by-step explanation:

We are given the function:

[tex]Q(x)=2x^2+5x-3[/tex]

And we want to find and simplify:

[tex]Q(a+h)-Q(a-h)[/tex]

Substitute:

[tex]=[2(a+h)^2+5(a+h)-3]-[2(a-h)^2+5(a-h)-3][/tex]

Expand:

[tex]\displaystyle =[2(a^2+2ah+h^2)+5a+5h-3]-[2(a^2-2ah+h^2)+5a-5h-3][/tex]

Distribute:

[tex]=[2a^2+4ah+2h^2+5a+5h-3]-[2a^2-4ah+h^2+5a-5h-3][/tex]

Distribute:

[tex]=(2a^2+4ah+2h^2+5a+5h-3)+(-2a^2+4ah-2h^2-5a+5h+3)[/tex]

Rewrite:

[tex]=(2a^2-2a^2)+(4ah+4ah)+(2h^2-2h^2)+(5a-5a)+(5h+5h)+(-3+3)[/tex]

Combine like terms:

[tex]=8ah+10h[/tex]

Hence:

[tex]Q(a+h)-Q(a-h)=8ah+10h[/tex]

Answer:

60%

Step-by-step explanation:

20,000

we can move the decimal place one to the left to find 10 percent

2,000

multiply 10 x 2 to find twenty percent or 4,000

we add this to the original total. 24,000

then add the 8,000

32,000

we know find one percent of the original total

200

and find the difference between the two totals

32000-20000 = 12,000

12000 divided by 200 which is 6

multiply six by ten to get

60 percent

Answer:

The slant height of the cone affected is two times the slant height of original cone

Step-by-step explanation:

we know that

If the height and base radius of a cone are increased by a factor of  to create a similar cone

then

the scale factor is equal to  

therefore

the slant height of the cone affected is equal to the slant height of the original cone multiplied by the scale factor

Find the slant height of the original cone

Let

l-----> slant height of original cone

la-----> slant height of the cone affected

Applying the Pythagoras theorem

so

The slant height of the cone affected is two times the slant height of original cone

(I GOT THIS FROM SOMEONE ELSES ANSWER IN 2017 SO I HOPE THIS HELPS)

The slant height of the larger cone is double the slant height of the smaller cone.

Option B is the correct answer.

It is a shape of a Christmas tree where there is a base of radius r and a top point called the apex.

The volume of a cone is 1/3 πr²h

We have,

The slant height of the cone is affected by a factor of 2.

When the height and base radius of a cone are multiplied by 2, the dimensions of the new cone are doubled.

Therefore,

The slant height of the larger cone is double the slant height of the smaller cone.

Learn more about cones here:

https://brainly.com/question/13798146

#SPJ5

Answer:

41 feet

Step-by-step explanation:

12 +12 + [tex]\sqrt{144+144}[/tex]

Answer:

Perfilar. Comienza por delimitar la forma y dimensión del macizo. ...

Cavar y abonar. ...

Enmarcar y rastrillar. ...

Distribuir y plantar.

Step-by-step explanation:

Answer:

A=W, B=X, C=Y, D=Z, AB=WX, BC=XY, CD=YZ, AD=WZ

(The second answer down)

Step-by-step explanation:

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{3^3 \times 5^4}[/tex]

[tex]\mathsf{3^3}[/tex]

[tex]\mathsf{= 3\times3\times3}[/tex]

[tex]\mathsf{= 9\times3}[/tex]

[tex]\mathsf{= \bf 27}[/tex]

[tex]\mathsf{5^4}[/tex]

[tex]\mathsf{= 5\times 5\times5\times 5}[/tex]

[tex]\mathsf{= 25\times25}[/tex]

[tex]\mathsf{= \bf 625}[/tex]

[tex]\mathsf{27 \times625}[/tex]

[tex]\mathsf{= \bf 16,875}[/tex]

[tex]\mathsf{2\times5^3\times11}[/tex]

[tex]\mathsf{5^3}[/tex]

[tex]\mathsf{= 5\times 5\times5}[/tex]

[tex]\mathsf{= 25\times 5}[/tex]

[tex]\mathsf{\bf = 125}[/tex]

[tex]\mathsf{2\times125\times11}[/tex]

[tex]\mathsf{= 250\times11}[/tex]

[tex]\mathsf{\bf = 2,750}[/tex]

[tex]\large\textsf{Find the Greatest Common Factor (GCF) of 16,875 \& 2,750}[/tex]

[tex]\large\textsf{16,875: 1, 3, 5, 9, 15, 25, 27, 45, 75, 125, 135, 225, 375, 625, 675, 1,125,}\\\\\large\textsf{1,875, 3,375, 5,625, \& 16,875}[/tex]

[tex]\large\textsf{2,750: 1, 2, 5, 10, 11, 22, 25, 50, 55, 110, 125, 250, 275, 550, 1,375, \& 2,750}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: the GCF is \bf 125 }}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

916.67 (corrected to 2 decimal places)

Hope I'm right, fingers crossed

Step-by-step explanation:

[tex]55 \times 50 = 2750 \div \frac{3}{4 } = 916.6666667[/tex]

Answer:

39

Step-by-step explanation:

you just put it in a calculator

Answer:

The expression is not factorable with rational numbers.

2x^2+19x+12

Step-by-step explanation:

Answer:

x = -3 +/- square root(22)

Step-by-step explanation:

x = -b +/- square root(b^2 - 4ac) / 2a

ax^2 + bx + c = 0

these are both the quadratic formula but one is solved for the x and another for 0

a= 1

b= 6

c = -13

x= -6 +/- square root( 6^2 - 4(1)(13)) / 2(1)

x = -6 +/- sqrt( 36 + 52) / 2

x= -6 +/- sqrt (88) / 2

sqrt of 88 = 2 x sqrt (22)

divide 2 on each

x= -3 +/- sqrt (22)

Answer:

(x-4) (x-5)

Step-by-step explanation:

* means multiply

first you figure out what 2 numbers

when added make 9

when multiplied make 20

those are 4 and 5

(x  4) (x  5)

in this case

-4 -5 make -9

-4 * -5 make 20

(x-4) (x-5)

Answer:

(x-4)(x-5)

Step-by-step explanation:

Firstly you need to use the second equation formula to get the value of x.

x= [tex]\frac{-(-9)+- \sqrt{(-9)^{2}-4*1*20 } }{2*1}[/tex]

x= [tex]\frac{9+- \sqrt{81-80 } }{2}[/tex]

x= [tex]\frac{9+-1}{2}[/tex]

so,

x=[tex]\frac{9+1}{2}[/tex]      x=5

and

x=[tex]\frac{9-1}{2}[/tex]      x=4

When writing the factor, we have to change signs of 5 and 4. So it will be -5 and -4.

That's why the awnser is (x-4)(x-5)

Hope it helps!

Answer:

La suma de las dos matrices cuadradas de dimensión 2 es [tex]\vec U = \left[\begin{array}{cc}-1&11\\2&5\end{array}\right][/tex].

Step-by-step explanation:

Considerando que se tratan de dos matrices de igual dimensión y cuyos elementos son números reales, conocemos que la adición entre dos matrices consiste en las sumas de los elementos de igual posición, esto es, los elementos que están localizados en las mismas filas y columnas, entonces, la suma es:

[tex]\vec A = \left[\begin{array}{cc}1&2\\-1&0\end{array} \right][/tex], [tex]\vec B = \left[\begin{array}{cc}-2&9\\3&5\end{array}\right][/tex]

[tex]\vec U = \vec A + \vec B = \left[\begin{array}{cc}1 + (-2)&2+9\\-1 + 3&0 + 5\end{array}\right][/tex]

[tex]\vec U = \left[\begin{array}{cc}-1&11\\2&5\end{array}\right][/tex]

La suma de las dos matrices cuadradas de dimensión 2 es [tex]\vec U = \left[\begin{array}{cc}-1&11\\2&5\end{array}\right][/tex].

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that [tex]n = 16[/tex]

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that [tex]p = 0.5[/tex]

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0[/tex]

[tex]P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002[/tex]

[tex]P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018[/tex]

[tex]P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085[/tex]

Then

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105[/tex]

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Answer:

Option A

Step-by-step explanation:

If the quadrilateral ABCD is dilated by a scale factor 'k' to form quadrilateral A'B'C'D',

Scale factor = [tex]\frac{\text{Length of one side of the Image}}{\text{Length of one side of the original}}[/tex]

k = [tex]\frac{BA'}{BA}[/tex]

Distance between B(2, -5) and A(-1, -1) = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

                                                               = [tex]\sqrt{(2+1)^2+(-5+1)^2}[/tex]

                                                               = 5 units

Distance between B(2, -5) and A'(-5.5, 5) = [tex]\sqrt{(-5.5-2)^2+(5+5)^2}[/tex]

                                                                    = [tex]\sqrt{(-7.5)^2+(10)^2}[/tex]

                                                                    = 12.5 units

Scale factor 'k' = [tex]\frac{12.5}{5}[/tex]

k = [tex]\frac{5}{2}[/tex]

Therefore, ABCD is dilated by a scale factor [tex]\frac{5}{2}[/tex] about point B.

BA and it's image BA' are on the same line and passes through center of dilation B.

Similarly, lines CD and C'D' will be parallel because they do not pass through center of dilation.

Therefore, Option (A) will be the correct option.

Answer:

I don't know the answer to ur question. LOL

Answer:

stop being desperate

nobody is gonna fall in love with some desperate weirdo

16:52

Hope this helps! :)