Answer:
Option A:
Dig into the zone of aeration
Explanation:
Within the lithosphere of the earth's surface, the zone of aeration is the zone directly above the water table, with a lot of pore spaces within the rocks. These pore spaces contain air and water, which can be used to water the cows.
Once the zone of aeration has been dug into, the farmer can tap into the underground reserve of water, which is stored within the pores of rocks. This water can now sip into the hole that was dug up by the farmer, forming a pond for the cows.
Please answer all of the examples below!
Answer:
The first one is balanced. The second one is not.
Explanation:
The first one is balanced because there are the same amount of elements on the reactant side as there are on the product side. The second one is not balanced because there are not the same amount of elements on the reactant side as there are on the product side. Therefore, it is not balanced
More Detailed: first example
Reactant side (left of arrow)
H: 2
C: 1
O: 3
Product side (right of arrow)
H: 2
C: 1
O: 3
More detailed: second example
Reactant side:
Na: 1
O: 1
H: 1
C: 1
Product side:
Na: 2
O: 4
H: 2
C: 1
the variables needed to balance this equation is 2,1, 1, 1.
How much water should be added to 5.00 g of KCl to prepare a 0.500 m
solution? *
Molality = moles of solute
Kg of solvent
100 g
38g
500 g
134 g
Other
Answer:133.4
c
m
3
Explanation: Explanation:
Molarity is number of moles of solute divided by number of litres of solution.
M
=
n
V
Rearrange for V to give
V
=
n
M
Number of moles of KCl is the mass divided by the molar mass of KCl which is 75.5 g/mol, so (5/75.5) = 0.0667 moles.
Now plug in the numbers:
V
=
n
m
=
0.0667
0.5
=
0.1334
litres
So you need to add 0.1334 litres of 133.4
c
m
3
of water.
(NB: symbol for molarity is upper case M. m is metres).
Sample A has a mass of 40g and a volume of 10cm^3. Sample B has a volume of 15cm^3 and a mass of 45g. Which sample has a greater density? Show your work.
The Answer Is Sample A
Density -
[tex]density = \frac{mass}{volume} [/tex]
Input The Formula For Both Equations To Find Density.
Sample A -
[tex]d = \frac{40}{10} [/tex]
[tex]d = 4[/tex]
Sample B -
[tex]d = \frac{45}{15} [/tex]
[tex]d = 3[/tex]
A greater force is required to move an object with a larger mass than one with a smaller
mass.
Answer:
Explanation:
what do u need to know
you have a coin with a volume of 10cm3 and a mass of 23g. What is the density of the coin
Answer:
2.3 grams per cubic cm
Explanation:
Density is equal to mass over volume, so
23/10=2.3
in which of these compounds are there twice as many oxygen atoms as hydrogen atoms?
Answer:
G - H2SO4
Explanation:
two hydrogen atoms and 4 oxygen atoms
How many grams of oxygen are present in 10g of H2 SO4?
An aqueous solution has a hydroxide-ion concentration of 1.0x10^-3M. What is the pH of the solution?
a.11
b.3
c.-3
d.7
Which statement explains why carbon-14 dating cannot be used to date ancient rocks?
O Carbon-14 decays at a varying rate.
O Carbon-14 decays quickly leaving the amount too small to measure.
O Carbon-14 can be used only to date the remains of organisms.
O Carbon-14 has a half-life that is much longer than potassium.
Answer: Carbon-14 decays quickly leaving the amount too small to measure.
Explanation:
Answer:
b
Explanation:
i did it
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O How many moles of oxygen gas (O2) are needed to create EXACTLY 6 moles of Carbon dioxide(CO2)?.
Which two moon phases can occur while the
relative positions of the sun, Earth, and moon
form a straight line?
Answer:
its the lunar and solar eclipse
Explanation:
the solar eclipse happens when the moon is in between the sun and earth
If 4.04g of h2 gas react with oxygen gas to create 36.36g of water, how many grams of oxygen reacted?
Answer:
gO₂ = 32.32 g
Explanation:
In this case, let's write the general equation:
2H₂ + O₂ -------> 2H₂O
In this case, we can use the 1° law, which is mass conservation. If the product has 36.36 g of water, then in the reactants we should have the same 36.36 g.
According to this, we already have 4.04 of hydrogen, then the remaining to reach the 36.36 g would be:
gO₂ = 36.36 - 4.04
gO₂ = 32.32 gHope this helps
What is a precipitation
reaction?
Answer:
A precipitation reaction is one in which substances in solution are mixed and an insoluble product is made. The insoluble product is called a precipitate and can be seen as a solid forming in the reaction mixture.
*
14. An AREA which drains into a common river system.
watershed
tributary
drainage divide
riparian zone
What is the purpose of a buffer?
Answer: A buffer solution is a solution made to prevent the pH level of something from changing when you add a base or an acid to it. For example, if you put a buffer solution in a pool, and then you put chlorine in it, the chlorine's effect on the PH level will be suppressed.
Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con 1 g de H2O.
Answer:
0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.
Explanation:
¡Hola!
En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:
[tex]Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3[/tex]
Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:
[tex]2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3[/tex]
De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.
¡Saludos!
In order to expand agriculture and urban areas to meet increased demand for growing populations, water supplies often have to be diverted. In three to five sentences, construct a potential chain of consequences for what could happen when water is diverted from large bodies like lakes and rivers
Answer:
Decrease occur in the amount and flow of water bodies.
Explanation:
There is decrease in the amount and flow of water from water bodies such as rivers and lakes etc occur when the river is diverted from large water bodies because the water flows to the diverted sides and decrease occurs in the amount of water in the rivers and lakes. Those regions from where this river passes can also be negatively affected due to low amount of water they receives for their daily needs or for cultivation of crops so we can say that this diversion has adverse effect on other populations.
¿
Que es la materia y qué es el volumen que ocupa la materia?
Todo en un estado sólido de materia tiene una forma y una longitud distintas. El volumen de un objeto es la cantidad de espacio que ocupa. Un sólido es un bloque de madera que conserva su forma y volumen cuando se coloca sobre una mesa.
Hope that helps!!!
¡Espero que ayude!
which of the following is true about these diagrams
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Ca(NO3)2 wht is the mass
Answer:
164.088 g/mol
Explanation: hope this helps
Answer:
Calcium nitrate
Explanation:
164.088 g/mol
give me the brainliest plss
What three temperature measurements Inust you make to calculate the specific heat of a sample using a calorimeter?
Answer:
Explanation:
Heat and temperature are two different but closely related concepts. Note that they have different units: temperature typically has units of degrees Celsius ( ∘ C ^\circ\text C ∘Cdegrees, start text, C, end text) or Kelvin ( Kstart text, K, end text), and heat has units of energy, Joules ( Jstart text, J, end text).
what is the physical change of a liquid to a solid by the removal of heat?
Consider the following balanced equation:
3 H2 + N2 --> 2 NH3
What volume of hydrogen gas will react in a perfect ratio
with 3 liters of nitrogen gas?
Answer:
[tex]from \: avogadros \: hypothesis \\ 1 \: mole \: of \: nitrogen \: reacts \: with \: 3 \: moles \: of \: hydrogen \\ 3 \: litres \: of \: nitrogen \: react \: with \: ( \frac{3 \times 3}{1} ) \\ 9 \: litres \: of \: hydrogen[/tex]
how much heat is required to increase the temperature of 20 grams of water by 26 degrees celsius?
Answer: 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.
Explanation:
Given: Mass = 20 g
Change in temperature = [tex]26^{o}C[/tex]
The standard value of specific heat of water is [tex]4.184 J/ g^{o}C[/tex]
Formula used to calculate the heat energy is as follows.
[tex]q = m \times C \times \Delta T[/tex]
where,
q = heat energy
m = mass of substance
C = specific heat of substance
[tex]\Delta T[/tex] = change in temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times \Delta T\\= 20 g \times 4.184 J/g ^{o}C \times 26^{o}C\\= 2175.68 J[/tex]
Thus, we can conclude that 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.
Si la masa de una muestra de un compuesto Y es de 196 gramos y contiene 2 mol, la masa molar de Y es
Answer:
98 g/mol
Explanation:
La masa molar de un compuesto es la cantidad de materia (medida como masa) que hay en 1 mol de dicho compuesto. Por lo tanto, puede calcularse como sigue:
masa molar = masa/número moles
Tenemos los siguientes datos del compuesto Y:
masa Y = 196 g
número de moles de Y = 2 mol
Entonces, podemos calcular la masa molar de Y de la siguiente manera:
masa molar Y = (masa Y)/(número de moles de Y) = 196 g/2 mol = 98 g/mol
9.49.8 grams of Kl is dissolved in 1.00 kg of solvent. What is the molality?
Answer:
Molality = 9.498 mol k g − 1
Explanation:
A final way to express the concentration of a solution is by its molality. The molality ( m ) of a solution is the moles of solute divided by the kilograms of solvent. A solution that contains 1.0 mol of NaCl dissolved into 1.0 kg of water is a “one-molal” solution of sodium chloride.
molality = number of moles of solute/ mass of solvent in kg
number of moles of KI = mass of KI / molar mass of KI
number of moles of KI = 9.49.8 g / 1.00 g m o l − 1
number of moles of KI = 9.498 moles
molality = 9.498 moles / 1kg
molality = 9.498 mol k g − 1
i hate chemistry but someone help please, no links or you’ll be reported
Answer:
A, D, E
Explanation:
How many calories of heat were added to 167.9 g of water to raise its temperature from 25oC to 55oC?
Answer:
Q = 5036.9 calories
Explanation:
Given that,
Mass, m = 167.9 g
The temperature raises from 25°C to 55°C.
The specific heat of water,c = 4.184 J/g °C
We need to find the heat added to water. We know that,
[tex]Q=mc\Delta T\\\\=167.9 \times 4.184\times (55-25)\\\\=21074.8\ J[/tex]
or
Q = 5036.9 calories
So, 5036.9 calories of heat is added.
HELP!!! WILL MARK BRAINLIEST!!!
picture attached below
Answer:
0.2 cm
Explanation:
looking at the ruler, you can see that the diameter is 0.4 cm. to get the radius, just divide by two, which gets 0.2 cm as the radius