A gas-filled balloon having a volume of 1.00 L at 1.2 atm and 25°C is allowed to rise to the stratosphere (about 30 km above the surface of Earth), where the temperature and pressure are -23°C and 3.00 10-3 atm, respectively. Calculate the final volume of the balloon.

Answers

Answer 1

Answer: The final volume of the balloon is 335.6 L

Explanation:

To calculate the final volume of the balloon, we use the equation given by combined gas law:

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = Initial pressure = 1.2 atm

[tex]P_2[/tex] = Final pressure = [tex]3.00\times 10^{-3}[/tex] atm

[tex]V_1[/tex] = Initial volume = 1.00 L

[tex]V_2[/tex] = Final volume = ?

[tex]T_1[/tex] = Initial temperature = [tex]25^oC=[25+273]=298K[/tex]

[tex]T_2[/tex] = Final temperature = [tex]-23^oC=[-23+273]=250K[/tex]

Putting values in above equation, we get:

[tex]\frac{1.2atm\times 1.00L}{298K}=\frac{3.00\times 10^{-3}atm\times V_2}{250K}\\\\V_2=\frac{1.2\times 1.00\times 250}{298\times 3.00\times 10^{-3}}\\\\V_2=335.6L[/tex]

Hence, the final volume of the balloon is 335.6 L


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Answers

Answer: [tex]136.2\times 10^{23}[/tex] molecules

Explanation:

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Taking into account the definition of Avogadro's number, 1.36×10²⁵ molecules of C₃H₃N are in 1200 g.

Avogadro's Number

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Mass molar

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

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You have 1200 g of C₃H₃N. So, knowing its molar mass, you can calculate the number of moles that contain a mass of 1200 g as:

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Then you can apply the following rule of three: If by definition of Avogadro's number 1 mole of C₃H₃N contains 6.023×10²³ molecules, 22.64 moles of C₃H₃N contains how many molecules?

amount of molecules of C₃H₃N= (22.64 moles × 6.023×10²³ molecules)÷ 1 mole

amount of molecules of C₃H₃N= 1.36×10²⁵ molecules

Finally, 1.36×10²⁵ molecules of C₃H₃N are in 1200 g.

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Avogadro's Number:brainly.com/question/11907018?referrer=searchResultsbrainly.com/question/1445383?referrer=searchResultsbrainly.com/question/1528951?referrer=searchResultsMolar mass:brainly.com/question/12695086?referrer=searchResults

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