A gas has a volume of 4.25 m3 at a temperature of 95.0°C and a pressure of 1.05 atm. What temperature will the gas have at a pressure of 1.58 atm and a volume of 2.46 m3

Answers

Answer 1

Answer:

[tex]\boxed {\boxed {\sf 82.7 \textdegree C}}[/tex]

Explanation:

We are asked to find the temperature of a gas given a change in pressure and volume. We will use the Combined Gas Law, which combines 3 gas laws: Boyle's, Charles's, and Gay-Lussac's.

[tex]\frac {P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

Initially, the gas has a pressure of 1.05 atmospheres, a volume of 4.25 cubic meters, and a temperature of 95.0 degrees Celsius.

[tex]\frac {1.05 \ atm * 4.25 \ m^3}{95.0 \textdegree C}= \frac{P_2V_2}{T_2}[/tex]

Then, the pressure increases to 1.58 atmospheres and the volume decreases to 2.46 cubic meters.

[tex]\frac {1.05 \ atm * 4.25 \ m^3}{95.0 \textdegree C}= \frac{1.58 \ atm *2.46 \ m^3}{T_2}[/tex]

We are solving for the new temperature, so we must isolate the variable T₂. Cross multiply. Multiply the first numerator by the second denominator, then multiply the first denominator by the second numerator.

[tex](1.05 \ atm * 4.25 \ m^3) * T_2 = (95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)[/tex]

Now the variable is being multiplied by (1.05 atm * 4.25 m³). The inverse operation of multiplication is division, so we divide both sides by this value.

[tex]\frac {(1.05 \ atm * 4.25 \ m^3) * T_2}{(1.05 \ atm * 4.25 \ m^3)} = \frac{(95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)}{(1.05 \ atm * 4.25 \ m^3)}[/tex]

[tex]T_2=\frac{(95.0 \textdegree C)*(1.58 \ atm * 2.46 \ m^3)}{(1.05 \ atm * 4.25 \ m^3)}[/tex]

The units of atmospheres and cubic meters cancel.

[tex]T_2=\frac{(95.0 \textdegree C)*(1.58* 2.46 )}{(1.05 * 4.25 )}[/tex]

Solve inside the parentheses.

[tex]T_2= \frac{(95.0 \textdegree C)*3.8868}{4.4625}[/tex]

[tex]T_2= \frac{369.246}{4.4625} \textdegree C}[/tex]

[tex]T_2 = 82.74420168 \textdegree C[/tex]

The original values of volume, temperature, and pressure all have 3 significant figures, so our answer must have the same. For the number we calculated, that is the tenths place. The 4 in the hundredth place to the right tells us to leave the 7 in the tenths place.

[tex]T_2 \approx 82.7 \textdegree C[/tex]

The temperature is approximately 82.7 degrees Celsius.


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Answer:

9.1093837015 × 10^−31 kg

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Answer:

The food coloring mixes through the hot water faster than it mixes with the cold water. The reason for this is because  in hot water, the water molecules have more energy and are moving faster than the molecules of cold water. This makes it way more easier for the dye to get mixed throughout the hot water.

Explanation:

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D. To design an experimental setup to synthesize molecules

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Answer:

Freezing water and cracking limestone are physical changes.

WILL MARK BRAINLEST IF CORRECT!
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Answers

Answer:

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Vapor pressure of any liquid _______. A. increases with increases in temperature B. increases with decreases in temperature C. is not affected by changes in temperature D. increases with increases in volume of the liquid E. None of the Above

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please mark me brainleast

Which of the following are decomposition reactions?
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B. N2 (9) + 3H2 (9) ► 2NH3 (9)
C. CaCO3 (s) - Cao (s) + CO2 (9)
D. 2H20 (1) ► 2H2 (9) + O2 (9)

Answers

Answer:

C and D

Explanation:

A reaction is said to be decomposed, if the reactant is broken down to liberate single element.

Classify vodka (composed of 50% water and 50% alcohol).

Answers

Answer:

Liquor

Explanation:

A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200 joules, what is the approximate final temperature of the water?
75 °C
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Answers

Answer:

81 °C

Explanation:

This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:

q = heat added/released by a sample

m = mass of sample

c=specific heat of sample

ΔT = change in temperature

from here we can rearrange the equation to state:

q/(mc) = ΔT

1200J/((20.0g)(4.2J/g•°C)) = ΔT

14°C = ΔT

If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.

Answer:

C. 81 c

Explanation:

took the test :)

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Answers

The number of moles of reactants and products can be used to obtain the mass of products formed. The results obtained are as follows;

The mass of hydrogen produced is 0.0174 gramsThe mass of zinc produced is  0.5688 gramsThe percentage by mass of zinc in the brass alloy is 47.3 %

The question says that HCl was in excess. It means that after the reaction, we will have unreacted HCl(aq) and  ZnCl2(aq) in the remaining solution.

Hence;

Mass of ZnCl2(aq) formed = 36.309g - 35.123g  = 1.186g

Number of moles ZnCl2(aq) formed = [tex]\frac{mass of ZnCl2(aq) formed}{molar mass of ZnCl2}[/tex]

[tex]\frac{1.186g}{136.286 g/mol}[/tex] = 0.0087 moles

From the reaction equation;

[tex]Zn (s) + 2HCl(aq) - > H2(g) + ZnCl2 (aq)[/tex]

To obtain the amount of Zn reacted

1 mole of Zn yields 1 mole of ZnCl2

x moles of Zn yields 0.0087 moles of ZnCl2

x = 0.0087 moles of Zn

a) 1 mole of Zn yields 1 mole of H2

0.0087 moles of Zn yields 0.0087 moles of H2

Mass of H2 = 0.0087 moles of H2 * 2 g/mol = 0.0174 grams

b)

Mass of Zn reacted =  0.0087 moles of Zn * 65.38 grams/mole = 0.5688 grams

c)

Percentage of Zn in the alloy = 0.5688 grams/1.203g * 100 = 47.3 %

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WHATS THE FREEZING POINT FOR WATER

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HELP! Fill in the blanks:
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Answers

Answer:

I don't know

Explanation:

is today your test

1. If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion. If it loses an electron, it becomes positively charged and is known as a cation.

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Answer:

3). C

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When inter-nuclear distance [ atomic radius ] is smaller, the nuclear attraction has a greater magnitude.

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Answers

Explanation:

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Answer:

There arre two main parts of the atom, the nucleus and the orbital rings. The three subatomic particles are contained in each of these, the proton and neutron together in the nucleus and the electrons orbiting in the rings.

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(Pls)

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big ablsolty long pp

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dong

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Answers

Answer:

Hi, There! :)

If you change the number of protons an atom has, you change the type of element it is. If you change the number of neutrons an atom has, you make an isotope of that element.

Answer:

If you change the number of protons an atom has, you change the type of element it is. If you change the number of neutrons an atom has, you make an isotope of that element. All known elements are arranged on a chart called the Periodic Table of Elements.

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that's what I found buddy

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2

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2×2

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soooo

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Answers

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Answers

[tex] \huge \boxed{\mathfrak{Formulas} \downarrow}[/tex]

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2 ka A. nitrogen, oxygen, Carbon dioxide

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Answers

The correct answer to the question is Rubidium (Rb)

Rubidium (Rb) is a group 1 element and as such, it can form bond by losing it's valence electron (i.e 1 electron) easily.

Gallium (Ga) is a group 13 element. It can only form bond by losing it's 3 valence electrons.

Argon is a group 18 element. This group has completely filled outermost shell and are very stable. They do not involve in bond formation.

Iodine (I) is a group 17 element. It is more difficult for this group to lose its 7 valence electrons hence, they form bond by accepting 1 electron.

With the above information, we can conclude that Rubidium will most likely lose electron to form bond.

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Answer:

(Question 1)Which element would most likely lose electrons to form positive ions when bonding with other elements?

(Answer) rubidium (Rb)

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(Answer) nitrogen (N) and oxygen (O)

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(Answer) the relative strength with which an element attracts electrons in a chemical bond

(Question 5) Based on the information in the table, which pair of elements would likely form the least polar bonds with each other?

(Answer) bromine and nitrogen

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just finished the quick check enjoy UwU

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