What is the Scientific name for Ectoparasites?
Ectoparasites are a taxonomically diverse group of organisms that infest the skin of human beings and other animals. Ectoparasitic arthropods and nematodes are similar in that an individual organism can produce skin lesions that are large enough to see with the unaided eye. Ectoparasitic infestations are often intensely itchy, causing considerable annoyance and discomfort. These conditions are often focally hyperendemic in impoverished communities, with a particularly high prevalence in vulnerable families, households, and neighborhoods.
Pediculosis (infestation by head and body lice) and scabies are found to some degree in all human populations, but myiasis (fly larva infestation), tungiasis (sand flea disease), and cutaneous larva migrans occur mainly in tropical and subtropical environments. Except for body lice, the organisms discussed in this article are not vectors of pathogenic microorganisms. In other words, most ectoparasites do not carry disease-causing agents; they are, instead, the direct cause of disease. Mortality is low, but the cumulative morbidity from the direct discomfort, secondary bacterial infections, and sequelae of those infestations and infections is considerable.
Despite the abundant presence of ectoparasitic infestations across human populations, biomedical science lacks firm evidence-based practices to reliably control these organisms. In addition, head lice and scabies are developing resistance to some chemical compounds employed to treat infested individuals, prevent spread, and control outbreaks.
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Question:
A second set of data was obtained using thicker pieces of putty. Both sets of results are shown in graph 2. What is the relationship between the resistance and the thickness of the conducting putty?
The resistance of the thin wire is greater than the resistance of the thick wire because the thin wire has fewer electrons to carry the current. Therefore, for thinner pieces of conducting putty we have the larger resistance and for the thicker pieces of conducting putty we have the lower resistance.
Lichens are not single organisms, but algae and fungi that function together. The algae use photosynthesis to make food for both organisms. The fungi produce digestive chemicals and absorb nutrients for both organisms.
How does the biological activity of lichens cause weathering in rocks?
Answer options with 4 options
A.
Lichens cause friction as they grow, which weathers the rocks.
B.
Lichens produce chemicals, which dissolve and weather the rocks.
C.
Lichens take in water, which freezes in cracks and weathers the rocks.
D.
Lichens absorb heat during photosynthesis, which weathers the rocks.
Answer:
THE ANSWER IS B.
Explanation:
The sandbox of the previous exercises had 10kg of sand. It was initially at 15°C and the specific heat of this sand is 830 j/(kg°C). What will be the final temperature of the sand? (-8100J=|0kg)
Answer:
Sorry I need points [tex] \boxed{}[/tex]
A person travels from C to D. One third of the time travels at v1 = 42km/h, the rest of the time travels at v2 = 36km/h. Find his average speed as he travels from C to D.
Answer:39km/h
Explanation:we know V=(u+v)/2. Here is u=42 and v=36
what is humidity???
Answer:
presence of moisture in air
Humidity is the amount of water vapor in the air.
hope it helps you!!!!!!!!
Please help...
Describe energy transformations in your own words.
How far did Michael Phelps swim, if he swam at a speed of 10m/s in 30 seconds?
Answer: his total speed would be 3 seconds
Explanation: because if you mulimply 10 x 3 you get 30 meaning that your answer would be 3
Explain Beryllium chloride molecule ( Formation of BF3 molecule and NH3 molecule )
Answer:
Here it is!
Explanation:
BeCl2 referred to as Beryllium Chloride, is an inorganic compound. It appears as white or yellow crystal solid at room temperature. It can exist in both monomeric and 1-D polymeric forms. The properties of beryllium chloride are similar to aluminum chloride owing to the diagonal relationship of beryllium with aluminum.
The molar mass and melting point of beryllium chloride are 79.91 g/mol and 399 °C, respectively. The chemical bonding in Beryllium Chloride is studied by writing down its Lewis structure by following the Lewis approach.
After lewis structure, there is a need of understanding its molecular geometry and hybridization of the central atom, Beryllium. The molecular orbital (MO) theory will be used to understand the MO diagram of beryllium chloride.
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Answer:
Beryllium Chloride
[tex]{ \boxed{ \mathfrak{formula : \: { \rm{BeCl _{2} }}}}}[/tex]
Beryllium chloride is formed through ionic / electro-valent bonding. The beryllium atom loses its two valency electrons to the two chlorine atoms each with seven outermost electrons.
As a result, an ionic compound Beryllium chloride is formed.
Boron Fluoride (BF3)
Boron trifluoride is formed through interaction of π bonds with the double alpha bonds of fluorine.
From VESPR, the structure is tetrahedral and non-symmetrical hence polarity is high.
Since, fluorine is highly electronegative, it makes the bond polar
All in all, Boron Fluoride is formed through hybridization.
Ammonia (NH3)
Ammonia is formed through hydrogen bonding.
Hydrogen bonding is a covalent bonding situation where hydrogen bonds with a highly electronegative element such as oxygen, fluorine, nitrogen.
Name three other objects around you now that are displaying a balanced force
Answer:
Examples of balanced forces
Resting against a wall.
Lying down.
Aircraft in a steady-flight.
Floating in water.
Standing in ground.
Tug of war equally balanced teams.
Fruit hanging from a tree.
Ball hanging from a rope.
Do I add squared or not?
Answer: add it
Explanation:
Un bloque de cobre cuya masa es 250 gramos , absorbe calor y su temperatura se eleva de 20 ˚C a 150 `C. ¿Cuál es la cantidad de calor absorbida por el bloque de cobre?. Expresar el resultado en unidades caloríficas y en unidades mecánicas.
Dada la información de la pregunta, el calor absorbido por el cobre es de 12513 J o 2990 calorías.
El calor ganado se obtiene de la relación;
H = mcdt
Dónde;
H = calor absorbido
m = masa
c = capacidad calorífica del cobre
Δt = cambio de temperatura
La capacidad calorífica del cobre es de 385 J / kg / ° C
Entonces;
m = 250 gramos o 0,25 kg
Δt = 150 ° C - 20 ˚C = 130 ˚C
H = 0,25 kg * 385 J / kg / ° C * 130 ˚C
H = 12513 J o 2990 calorías
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In order for energy to be conserved during this process, a
must be released that has an energy of
Answer:
Mechanical energy :)
Explanation:
In order for energy to be conserved, the energy released must be equal to heat energy lost in the process.
What is principle of conservation energy?The principle of conservation of energy states that, the total energy in a system is always conserved.
M = P.E + K.E
where;
P.E is the potential energyK.E is the kinetic energyThus, in order for energy to be conserved, the energy released must be equal to heat energy lost in the process.
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You need low pressure to walk on
snow and ice. True or faulse
Answer:
True
Explanation:
Answer: false please give brainliest
Explanation: Reducing air pressure will not give you more traction and your tires could become seriously underinflated, affecting steering.
why is the answer A and not C?
please help!
Answer:
because it gives a complete thought
What is displacement
Answer:
the moving of something from its place or position
or
he occupation by a submerged body or part of a body of a volume which would otherwise be occupied by a fluid
There are 2 different definitions.
1. The moving of something from its place or position.
2. The occupation by a submerged body or part of a body of a volume which would otherwise be occupied by a fluid.
See screen shot...momentum in collision
Please find attached photographs for your answer.
Hope it helps.
Do comment if you have any query.
When a capacitor is charged, the electric field E, and hence the electric flux Φ, between the plates changes. This change in flux induces a magnetic field, according to Ampère's law as extended by Maxwell: ∮B⃗ ⋅dl⃗ =μ0(I+ϵ0dΦdt). You will calculate this magnetic field in the space between capacitor plates, where the electric flux changes but the conduction current I is zero. A parallel-plate capacitor of capacitance C with circular plates is charged by a constant current I. The radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. Calculate B(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. Express your answer in terms of μ0 and given quantities. B(r) =
The magnitude of the magnetic field B(r) inside the capacitor as a function of distance from the axis is [tex]\mathbf{B(r) =\dfrac{\mu_o I r}{2 \pi a^2} }[/tex]
A charged capacitor usually cause changes between the plates of electric field E and the electric flux Φ
As seen in Ampere's law which is extended by Maxwell:
[tex]\mathbf{\oint B^{\to} .dl^{\to} = \mu_o \Big( I+\dfrac{d \phi }{dt} \Big)}[/tex]
To meet the equilibrium equation of electric charge, Maxwell modified Ampere's law by incorporating the displacement current through into electric current component.
∴
The displacement current can be expressed by the relation;
[tex]\mathbf{I = \varepsilon_o \dfrac{dE}{dt} }[/tex]
From the given information, the displacement current density through area A can now be expressed as:
[tex]\mathbf{I = \varepsilon_o A \dfrac{dE}{dt} }[/tex]
Replacing the value of displacement current density into Maxwell modified Ampere Law, we have:
[tex]\mathbf{\oint B .dl= \mu_o I_{enclosed} }[/tex]
[tex]\mathbf{B \times (2 \pi r) = \mu_o I\Big (\dfrac{\pi r^2}{\pi a^2} \Big) }[/tex]
[tex]\mathbf{B(r) =\dfrac{\mu_o I r}{2 \pi a^2} }[/tex]
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If the force exerted by the intern is doubled and the dis- tance is halved, does the work done by the intern increase, decrease, or remain the same?
If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same. Work done is the force applied to move a body through a distance.
Answer: Remains the same.
A Particular roller coaster has a mass of 3500 kg, a height of 4.0 m, and a velocity of 12 m/s. What is the kinetic energy? If needed, use g = 10. m/s^2
Answer:
=252,000j
or 252j
Explanation:
i don't think 4.0 is supposed to be there
Select the correct answer.
Planet A Planet B
Distance from Sun 0.72 AU 9.54 AU
Planet composition rocky mantle, iron core hydrogen, helium
Gases in atmosphere very dense atmosphere that is 96.5% poisonous carbon dioxide and 3.5% nitrogen mostly hydrogen and helium
Number of moons 0 62
Rings no rings visible rings
Which planet is planet A?
A.
Mars
B.
Saturn
C.
Uranus
D.
Venus
Answer:
D, Venus
Explanation:
Using the facts
solve by formulae method and completing the square method. 4x²-29x+7=0
Answer:
(4x - 1) (x - 7)
Explanation:
4x^2 - 29x + 7 = 0
(4*-7=-28) and: (1*- 1 = -1)
-28 - 1 = -29 and - 1 times -7 = 7
Explain what matter is
Answer:
it doesnt matter
Explanation:
matter is what makes up everything around us; anything takin up space
Explanation:
matter can be defined as anything at all that has weight and occupies space
A 4,000-kg wrecking ball is hoisted 20 m above Earth's surface. What will the wrecking ball's gravitational potential energy be?
Answer:
784,000 JExplanation:
The gravitational potential energy of a body can be found by using the formula
GPE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
GPE = 4000 × 9.8 × 20 = 784,000
We have the final answer as
784,000 JHope this helps you
can someone help me w this ?
Answer:
i can't sorry
Explanation:
I didn't really pay attention in that class
Heat is: *
a Heat transfer by direct contact
b The total kinetic energy in a substance
c The transfer of thermal energy from one object to another
d Heat transfer by a fluid
The total kinetic energy in a substance
Answer:
correct option b
that is the total kinetic energy in a substance
Tommy, who has a mass of 30 kg, sits 4.0 meters from the center of a
merry-go-round that is rotating with a period of 10 seconds. What is the
centripetal force acting on Tommy?
Answer:
Fc= 47.363 N
Explanation:
First, you need tangential velocity because they don't give that to you in the problem.
So, the formula for tangential velocity is υ=2πr/t.
For this problem its v=2π4/10= 2.513 m/s
Then we plug this into our equation for centripetal force
Fc= 30*(2.513)^2/4=47.363 N
Fc=47.363 N
The centripetal force acting on Tommy is 47.36 N if Tommy, who has a mass of 30 kg, sits 4.0 meters from the center of a merry-go-round that is rotating for a period of 10 seconds.
What is mass?A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.
It is given that:
Tommy, who has a mass of 30 kg, sits 4.0 meters from the center of a merry-go-round that is rotating for a period of 10 seconds.
As we know the formula for the centripetal force:
Fc = mv²/r
m = 30 kg
r = 4 meters
First, find the tangential velocity:
The formula for tangential velocity is:
v = 2πr/t
v = 2π4/10
v = 2.513 m/s
Plug the values in the formula:
Fc= 30(2.513)²/4
Fc = 47.36 N
Thus, the centripetal force acting on Tommy is 47.36 N if Tommy, who has a mass of 30 kg, sits 4.0 meters from the center of a merry-go-round that is rotating for a period of 10 seconds.
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this is about the magnet fields. thanks in advance.
What distance does a police car travel if it is going 3.0 m/s for 20 seconds
Answer:
60 meters
Explanation:
If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply
3meters/second*20seconds
cross out the seconds and you have
3 meters*20
60 meters
define longitudinal wave
longitudinal wave, wave consisting of a periodic disturbance or vibration that takes place in the same direction as the advance of the wave. ... Sound moving through air also compresses and rarefies the gas in the direction of travel of the sound wave as they vibrate back and forth.
FORMULA
[tex]y(x,t) = y0 \: cos \: (w(t - \frac{x}{c} ))[/tex]y = displacement of the point on the traveling sound wave
x = distance the point has traveled from the wave's source
y_0 = amplitude of the oscillations
\omega = angular frequency of the wave
t = time elapsed
c = speed of the wave
