A jetliner can fly 8.0 hours on a full load of fuel. Without any wind it flies at a speed of 2.42 x 102 m/s. The plane is to make a round-trip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a 40.7-m/s wind from the jet stream, which blows from west to east. What is the maximum distance (in kilometers) that the plane can travel due west and just be able to return home

Answer:

W = 24 J

Explanation:

Given that,

Applied force, F = 60 N

Distance moved, d = 40 cm = 0.4 m

We need to find the work done by the carpenter. We know that,

Work done, W = Fd

Put all the values,

W = 60 N × 0.4 m

= 24 J

Hence, the required work done is equal to 24 J.

Explanation:

these are quantities that have magnitude but no direction

Examples include : speed, mass, volume, density, everything, time

Answer:

new PE at top=original PE - energy lost

mgh=.2(9.8)20-30

Explanation:

mgh=.2(9.8)20-30 = 9.2

Answer:

See Explanation

Explanation:

The frequency of sound waves received by the microphone influences the output or pitch of the sound obtained from the microphone.

The higher the frequency of the sound received by the microphone, the higher the output of the microphone and vice versa. This is because, the higher the frequency of sound, the higher the oscillations produced and the greater the output of the microphone.

The rise and fall in the pitch of sound waves as the frequency of sound waves varies is called inflection.

Answer:

b

Explanation:

cuz im smart

Answer:

592000 J

Explanation:

We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:

1 Pa = 1 Kg/ms²

Therefore,

3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²

Next, we shall determine the workdone.

Workdone is given by the following equation:

Workdone (Wd) = pressure (P) × change in volume (ΔV)

Wd = PΔV

With the above formula, the work done can be obtained as follow:

Pressure (P) = 3.7×10⁵ Kg/ms²

Change in volume (ΔV) = 1.6 m³

Workdone (Wd) =?

Wd = PΔV

Wd = 3.7×10⁵ × 1.6

Wd = 592000 Kgm²/s²

Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:

1 Kgm²/s² = 1 J

Therefore,

592000 Kgm²/s² = 592000 J

Therefore, the Workdone is 592000 J.

Answer:

Explanation:

First off, we need the mass in kg and it's in g so we have to convert it. Then we can do the problem. 200 g = .200 kg. Moving on.

The equation used to find the tension in the string is the same one we use to find the centripetal force, because the tension is what is upplying the centripetal force needed to keep the stone moving in a circular manner. The formula for that is

[tex]F_c=T=\frac{mv^2}{r}[/tex] where ma is the mass in kg, v is the velocity in m/s, and r is the radius of the circle about which the stone spins in meters.

Filling in:

[tex]T=\frac{(.200)(2)^2}{2}[/tex] which gives us

T = .4 N

Answer:

0.18 m/s²

Explanation:

The total time taken to cover a 10 km race is 27 min, 43.6 seconds.

At 25 min, Pre was at 7.71 km mark. Therefore the average speed = 7.71 km / 25 min = 7710 m / (25 * 60) s = 5.14 m/s

The distance remaining = 10 km - 7.71 km = 2.29 km = 2290 m

The remaining time = 27 min, 43.6 seconds - 25 min = 2 min 43.6 second = 163.6 seconds

She accelerates for 60 seconds, therefore the distance covered (S) during the acceleration (a) is:

S₁ = 5.14(60) + 0.5a(60)² = 308.4 + 1800a

She maintains the speed for the remaining distance (S₂). The remaining time = 163.6 seconds - 60 seconds = 103.6 seconds. The final speed after the acceleration = (5.14 + 60a) m/s

S₂ = (5.14 + 60a)* 103.6 = 532.5 + 6216a

S₁ + S₂ = 2290 m

(308.4 + 1800a) + (532.5 + 6216a) = 2290

8016a + 840.9 = 2290

8016a = 1449.1

a = 0.18 m/s²

Pressure will decrease whenever the surface area increases, and when the weight of the object is reduced.

[tex] \color{green} {\huge \circ \degree \degree} \boxed{\normalsize{ \mathrm{ \underline{ \color{red}pressure \: \: will \: \: decrease}}} } \: \: \huge \color{green}\degree \degree \circ[/tex]

We know that,

[tex]\large \boxed{ \mathrm{pressure = \frac{mass}{area \: \: of \: \: surface}} }[/tex]

Now, we can observe that the area of surface is inversely proportional to the pressure, Therefore pressure will change opposite to the change in surface area in contact.

So, if we increase the surface area then there would be decrease in magnitude of pressure.

[tex] \large { \mathfrak{hope \: \:i t \: \: helps \: \: you..... }}[/tex]

Answer:

Explanation:

The formula for the magnitude of this resultant vector, which is in Q1, btw, is:

[tex]B_{mag}=\sqrt{6.18^2+4.43^2}[/tex] which gives us, to 3 sig fig's:

7.60 m. Since the resultant vector is in Q1, we don't need to add anything to the angle once we find it to 3 sig fig:

[tex]tan^{-1}(\frac{4.43}{6.18})[/tex] gives us an angle of 35.6 degrees

Substance:-

Answer:

0.66

Explanation:

Follow the Density Formul d = m/v

so

d = 5.29/8

= 0.66 Density

Just correct me if I'm wrong, I mean like literally :> Thank you! ^^

Answer:

4.88 K.

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 5 moles

Pressure (P) = 1 atm

Volume (V) = 2 L

Gas constant (R) = 0.082 atm.L/Kmol

Temperature (T) =?

The temperature of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

1 × 2 = 5 × 0.082 × T

2 = 0.41 × T

Divide both side by 0.41

T = 2 / 0.41

T = 4.88 K

Therefore, the temperature of the gas is 4.88 K.

Answer:

electrons i think

Explanation:

Answer:

h = 0.2 m

Explanation:

Given that,

A pendulum is moving 2.0 m/s at the bottom of its swing.

We need to find the height high it swing back. Let the height is h.

Using the conservation of energy such that,

[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}[/tex]

Put all the values,

[tex]h=\dfrac{(2)^2}{2\times 10}\\\\h=0.2\ m[/tex]

So, it will reach to a height of 0.2 m.

Answer:

The screw gauge is an instrument used for measuring accurately the diameter of a thin wire or the thickness of a sheet of metal. It consists of a U-shaped frame fitted with a screwed spindle which is attached to a thimble.

Explanation:

Measure the length of the coil with the help of a meter scale. The thickness of the wire can be found by dividing the length of the coil by the number of turns. Measure the diameter with callipers. Place an electrical wire between the jaws of a set of Vernier callipers. Slide the movable jaw around the cable without compressing the insulation and read the measurement where the line from the moving indicator meets the stationary scale for a diameter.

Answer:

Moment is the product of force and its perpendicular distance from a point along its line of action.

The net moments on clockwise and anticlockwise is zero at a point.

The net force applied on a spanner handle is equal to the moment of the rotation

Answer:

Explanation:

You didn't fill in the proper masses which is why you never got an answer to this. But that's ok...I got you. I happen to know what they are! We will use the universal law of gravitation and the gravitational constant to solve this.

[tex]F_g=\frac{Gm_1m_2}{r^2}[/tex] and filling in:

[tex]F_g=\frac{(6.67*10^{-11})(5.98*10^{24})(7.36*10^{22})}{(3.84*10^8)^2}[/tex] The denominator is the radius of the earth plus the radius of the moon plus the distance between their surfaces, just FYI.

That gives us that

[tex]F_g=1.99*10^{20}N[/tex] Not sure what your choices entail, but I'd have to say, taking into consideration that maybe your problem didn't figure in the distance between the surfaces, you'd be at choice B.

Answer:

YOUR answer is given below:

Explanation:

Drug B will retain the highest percentage of initial concentration.

First order degradation means that both solution will degrade by same amount in same time because first order is directly proportional relationship between given both aqueous solution.

Given that Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes.

Since, initially concentration of Drug B is more. Therefore, at all instant concentration of Drug will be highest.

Learn more:

brainly.com/question/17029235

Answer:

35%

Explanation:

win

The amount of work required to lift the 230 kg to a height of 3.5 m at  84% efficiency is 9391.67 J

This can be defined as the capacity to achieve a given task with little or no waste. Mathematically, it can be expressed as

Efficiency = (output / input) × 100

Work output = mgh

Work output = 230 × 9.8 × 3.5

Work output = 7889 J

Efficiency = (output / input) × 100

84% = 7889 / input

Cross multiply

84% × input = 7889

Divide both side by 84%

Input = 7889 / 84%

Input = 7889 / 0.84

Input = 9391.67 J

Learn more about efficiency:

https://brainly.com/question/2009210

#SPJ2

Answer:

b

Explanation:

Answer:

(C) 250

Explanation:

Given the following data;

Mass = 10 kg

Distance = 50 m

Force applied = 10 N

Angle = 60°

To find the work done on the box, we would first of all find the horizontal component of the force applied.

[tex] Horizontal force, Fx = mgCosd[/tex]

Where;

Fx represents the horizontal force.

m is the mass of an object.

g is the acceleration due to gravity.

d is the angle of inclination (theta).

mg = weight = 10 N

Substituting into the equation, we have;

[tex] Fx = 10 * Cos60 [/tex]

[tex] Fx = 125 * 0.5 [/tex]

Fx = 5 Newton

Next, we find the work done.

Mathematically, workdone is given by the formula;

[tex] Workdone = force * distance[/tex]

Substituting into the formula, we have;

[tex] Workdone = 5 * 50 [/tex]

Workdone = 250 Nm

Answer:

a) actual reading=2mm+(0.1×8)=2.8 mm=0.28 cm

b)actual reading=5 mm+(0.1×7)=5.7mm=0.57 cm

c)actual reading=9 mm=0.9 cm

d)actual reading=0 mm+(0.1×7)=0.7 mm=0.07 cm

e)actual reading=19 mm+(0.1×9)=19.9 mm=1.99 cm

f)actual reading=15 mm+(0.1×3)=15.3 mm=1.53 cm

g)actual reading=11 mm(0.1×5)=11.5 mm=1.15 cm

Answer:

v_f = 2.9m/s

Explanation:

v_f = v_I + a(t)

v_f = 0.6m/s + 1.2m/s²(1.9s)

v_f = 2.88m/s

v_f = 2.9m/s

Yeah, hand signals are important in officiating games. The hand signals are given by the referee who first signals the fault and then indicates which team has won the point. A point is indicated by one finger at the side of the court to indicate the winner of the rally.

Answer:

Electricity is the set of physical phenomena associated with the presence and motion of matter that has a property of electric charge. Electricity is related to magnetism, both being part of the phenomenon of electromagnetism, as described by Maxwell's equations.

Answer:

increasing wavelength near beach

Explanation:

When wavelength increases, frequency of these waves decreases and the waves suddenly stop.

This is also called damped oscillation.

Answer:

According to the law of conservation of energy, energy is neither created nor destroyed but changes from one form to another

The energy in the light bulb comes from the movement of electrons through the resistance of the coil of the bulb, therefore, the energy in the bulb is changed from electric energy to heat and light energy as follows;

The friction between the moving electrons and the resistive filament of the light bulb results in the slowing down of the rapidly moving electrons

The part change in the (kinetic) energy of the electrons moving through the filament of the bulb as they slow down is observed as sensible heat which causes the bulb to be hot

Another part of the change in energy is given seen as the light given off by the bulb filament in an incandescent bulb as the filament becomes very hot from the movement of the electrons which causes the bulb to glow (produce light), due to the incandescent characteristics of the filament

Explanation:

Answer:

36000

Explanation:

1/2mv²=0.5×500×12²=36000j