Answer:
molar mass of copper = 63.55 g/mol
( 1 mol of copper)
6.19 g copper × ( 63.55g copper )
0.0975 moles
complete and balanced the following equations by predicting the products of each reaction pair.
NA + LiCI -> _ + _
Explanation:
this is a single Replacement Reaction, so Na and Cl will form a bond.
Course Home P Acceptable units x + courseld=16709491&OpenVellumHMAC=f5c9929f4e4da0b5529475e262c91d79=10001 1 Review art A alculate the heat change in calories for condensation of 11.0 g of steam at 100°C. xpress your answer as a positive value using three significant figures and inc 2 MIKIN M HA Value CS
Answer:
The heat change in calories for condensation of 11.0 g of steam at 100°C is 5930 calories
Explanation:
Latent heat of condensation is the heat released when one mole of steam or water vapor condenses to form liquid droplets. The heat of condensation of water at 100° C is about 2,260 kJ/kg, which is equal to 40.68 kJ/mol. Since condensation of steam and vaporization of water occur at the same temperature and require the same amount of energy to occur, the heat of condensation is exactly equal to the heat vaporization, but has the opposite sign. In the vaporization, heat energy is absorbed by the substance, whereas in condensation heat energy is released by the substance.
The specific latent heat of vaporization of steam at 100° C = 40.68 kJ/mol
Number of moles of moles of water in 11.0 g of steam = mass/ molar mass
Molar mass of water = 18.0 g/mol
Number of moles of steam = 11.0 g / 18.0 g/mol = 0.61 moles
Heat released = 40.68 K/mol × 0.61 moles = 24.815 kJ
Converting to kcal by dividing 24.815 kJ by 4.184 = 5.93 kcal or 5930 calories
Therefore, the heat change in calories for condensation of 11.0 g of steam at 100°C is 5930 calories
For each amino acid, the name, three-letter abbreviation, or one-letter abbreviation is given. Complete the missing information name: proline three-letter abbreviation: one-letter abbreviation: Select the class (side chain) for proline. name: three-letter abbreviation: Phe name: three-letter abbreviation: Phe one-letter abbreviation: Select the class (side chain) for Phe. name: three-letter abbreviation: name: three-letter abbreviation: one-letter abbreviation: D Select the class (side chain) for D. nathe: lysine three-letter abbreviation: latihan aidantului one-letter abbreviation: Select the class (side chain) for lysine. name: three-letter abbreviation: Gin one-letter abbreviation: Select the class (side chain) for Gln.
Question 1
Consider the following reaction:
Cl2(g) + 3 F2(g) —> 2 CIF3 (8)
How many moles of product will form if 0.115 moles of fluorine gas react?
Answer:
0.077 mole of ClF₃.
Explanation:
The balanced equation for the reaction is given below:
Cl₂ + 3F₂ —> 2ClF₃
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of ClF₃.
Finally, we shall determine the number of mole of ClF₃ produced by the reaction of 0.115 mole of F₂. This can be obtained as follow:
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of ClF₃.
Therefore, 0.115 mole of F₂ will react to to produce = (0.115 × 2)/3 = 0.077 mole of ClF₃.
Thus, 0.077 mole of ClF₃ was obtained from the reaction.
A 100.0-g sample of water at 27.0oC is poured into a 71.0-g sample of water at 89.0oC. What will be the final temperature of the water? (Specific heat capacity of water = 4.184 J/goC.)
Answer: The final temperature will be [tex]52.74^oC[/tex]
Explanation:
Calculating the heat released or absorbed for the process:
[tex]q=m\times C\times (T_2-T_1)[/tex]
In a system, the total amount of heat released is equal to the total amount of heat absorbed.
[tex]q_1=-q_2[/tex]
OR
[tex]m_1\times C\times (T_f-T_1)=-m_2\times C\times (T_f-T_2)[/tex] ......(1)
where,
C = heat capacity of water = [tex]4.184J/g^oC[/tex]
[tex]m_1[/tex] = mass of water of sample 1 = 100.0 g
[tex]m_2[/tex] = mass of water of sample 2 = 71.0 g
[tex]T_f[/tex] = final temperature of the system = ?
[tex]T_1[/tex] = initial temperature of water of sample 1 = [tex]27^oC[/tex]
[tex]T_2[/tex] = initial temperature of the water of sample 2 = [tex]89.0^oC[/tex]
Putting values in equation 1, we get:
[tex]100.0\times 4.184\times (T_f-27)=-71.0\times 4.184\times (T_f-89)\\\\171T_f=9019\\\\T_f=\frac{9019}{171}=52.74^oC[/tex]
Hence, the final temperature will be [tex]52.74^oC[/tex]
You have been observing an insect that defends itself from enemies by secreting a caustic liquid. Analysis of the liquid shows it to have a total concentration of formate plus formic acid (Ka =1.8 x 10^-4) of 1.45 M; the concentration of formate ion is 0.015 M. What is the pH of the secretion?
Answer:
pH = 1.76
Explanation:
The mixture of formate and formic acid produce a buffer. The pH of the buffer is obtained using H-H equation as follows:
pH = pKa + log [A-] / [HA]
Where pH is the pH of the buffer:
pKa = -log Ka = 3.74
[A-] is molar concentration of conjugate base (Formate) = 0.015M
[HA] is molar concentration of weak acid (Formic acid) = 1.45M - 0.015M = 1.435M
Replacing:
pH = 3.74 + log [0.015M] / [1.435M]
pH = 1.765-Analysis of a 12.04-g sample of a liquid compound composed of carbon, hydrogen, and nitrogen showed it to contain 7.34 g C, 1.85 g H, and 2.85 g N. What is the percent composition of this compound
Answer:
%C = 60.9%; %H = 15.4%; %N = 23.7%
Explanation:
Step 1: Given data
Mass of the sample (m): 12.04 gMass of Carbon (mC): 7.34 gMass of Hydrogen (mH): 1.85 gMass of Nitrogen (mN): 2.85 gStep 2: Calculate the percent composition of this compound
To calculate the percent by mass of any element (E), we will use the following expression.
%E = mE/m × 100%
%C = 7.34 g/12.04 g × 100% = 60.9%
%H = 1.85 g/12.04 g × 100% = 15.4%
%N = 2.85 g/12.04 g × 100% = 23.7%
Compare the solubility of silver iodide in each of the following aqueous solutions:
a. 0.10 M AgCH3COO
b. 0.10 M NaI
c. 0.10 M KCH3COO
d. 0.10 M NH4NO3
1. More soluble than in pure water.
2. Similar solubility as in pure water.
3. Less soluble than in pure water.
Answer:
Compare the solubility of silver iodide in each of the following aqueous solutions:
a. 0.10 M AgCH3COO
b. 0.10 M NaI
c. 0.10 M KCH3COO
d. 0.10 M NH4NO3
1. More soluble than in pure water.
2. Similar solubility as in pure water.
3. Less soluble than in pure water.
Explanation:
This can be explained based on common ion effect.
According to common ion effect the solubility of a sparingly soluble salt decreases further in a solution which has a common ion to it.
The solubility of AgI(s) silver iodide in water is shown below:
[tex]AgI(s) <=> Ag^{+}(aq)+I^{-}(aq)\\[/tex]
a. a. 0.10 M AgCH3COO has a common ion Ag+ with AgI.
So, AgI is less soluble than in pure water in this solution.
b. 0.10 M NaI has a common ion I- with AgI.
So, AgI is less soluble than in pure water in this solution.
c. 0.10 M KCH3COO:
This solution has no common ion with AgI.
So, AgI has similar solubility as in pure water.
d. 0.10 M NH4NO3:
In this solution, AgI can be more soluble than in pure water.
Anew fictitious element was discovered. It is a metal named jolmium, J,and it has three valence electrons. If it combineswith iodine it forms jolmium iodide. Answer the following questions.a.Is this compound ionic or covalent
a. Is this compound ionic or covalent?
b. What is the formula of Jolmium iodide?
c. What is the charge on the metal J in this compound?
d. Explain how you know that is the charge?
Answer:
A new fictitious element was discovered.
It is a metal named jolmium, J, and it has three valence electrons.
If it combines with iodine it forms jolmium iodide. Answer the following questions.
a.Is this compound ionic or covalent
b. What is the formula of Jolmium iodide?
c. What is the charge on the metal J in this compound?
d. Explain how you know that is the charge?
Explanation:
It is given the element jolmium J is a metal with three valence electrons.
Since metals are highly electropositive, they lose electrons easily and form cations (Ions with a positive charge).
[tex]J^{3+}[/tex] ion will be formed.
b) The formula of jolmium iodide is shown below:
[tex]J^{+3} I^{-1}\\The formula becomes:\\JI_{3}[/tex]
a) The compound is ionic in nature.
Since the compound formed between a metal atom and a nonmetal atom will take place by transfer of electrons.
Hence, it is ionic in nature.
c) The charge on the metal J in this compound is +3.
d) Given J has three valence electrons.
That means it can lose three electrons to form a bond.
So, its valency is three.
Write briefly on carbohydrates
Answer:
carbohydrates are simple sugars which can be broken down to form 3 sugars.
which are , (maltose) (fructose) & (glucose)
Diazomethane has the molecular formula CH2N2. Draw the preferred Lewis structure for diazomethane and assign formal charges to all atoms, if any.
Answer:
See explanation
Explanation:
We define the formal charge on an atom in a molecule as the charge it carries assuming that electrons in all chemical bonds of the molecule were shared equally between atoms irrespective of the electronegativity of each atom.
The formula for calculating the formal charge on an atom in a molecule is;
Formal Charge = [number of valence electrons on neutral atom] – [(number of lone electron pairs) + (½ number of bonding electrons)] ·
The formal charge on the two nitrogen atoms in diazomethane is obtained as follows;
Middle nitrogen atom = 5 – 8/2 – 0 = +1
Last nitrogen atom = 5 – 4/2 – 4 = –1
The Lewis structure of the molecule is shown in the image attached.
Cellulose and starch are examples of:
Select one:
a. monosaccharides
b. disaccharides
c. lipids
d. polysaccharides
Answer:
The choose (d)
d. polysaccharides
Write a balanced equation for the combination reaction described, using the smallest possible integer coefficients. When methane (CH4) combines with carbon tetrachloride , dichloromethane (CH2Cl2) is formed.
Answer:
C H₄ + C Cl₄ = 2 (C H₂ Cl₂)
What are the two types of addition compounds
Answer:
electrophilic addition and
nucleophilic addition.
Answer:
the two types of addition compoundsare:
1.electrophilic addition
2. nucleophilic addition.
A recipe calls for 1/4 cup of butter. One ounce (oz) of butter is equivalent to 2 tablespoons (T), and there are 8 oz of butter in 1 cup. Which of the following statements correctly interpret the information provided?
a. The information provided gives the conversion factor 8oz/2T.
b. The information provided gives the conversion factor 8oz/1 cup.
c. The recipe requires 64 T of butter.
d. The recipe requires 4T of butter.
Answer:
D
Explanation:
8oz=1cup
Xoz=1/4cup
cross multiply
Xoz=8×1/4=2
2oz=1/4cup
1oz=2T
2oz=x
cross multiply
×=2×2=4T
The cup of butter, number of tablespoons and ounces of butter are all in direct proportion with one another. The interpretation of the information provided is:
(b). The information provided gives the conversion factor 8oz/1 cup.
Given that:
[tex]1\ recipe = \frac{1}{4}\ cup[/tex]
[tex]1\ oz = 2T[/tex]
[tex]8\ oz = 1\ cup[/tex]
Multiply both sides of [tex]1\ oz = 2T[/tex] by 8
[tex]8 \times 1oz = 8 \times 2T[/tex]
[tex]8 oz = 16T[/tex]
Substitute 8oz for 1 cup in: [tex]1\ recipe = \frac{1}{4}\ cup[/tex]
[tex]1\ recipe = \frac{1}{4} \times 8oz[/tex]
Substitute [tex]8 oz = 16T[/tex]
[tex]1\ recipe = \frac{1}{4} \times 16T[/tex]
[tex]1\ recipe = 4T[/tex]
The interpretations are as follows:
[tex]1\ recipe = 4T[/tex] means that 1 recipe requires 4T of butter [tex]8\ oz = 1\ cup[/tex] means that the information provided gives a conversion of 8oz/1 cupHence, (b) is correct
Read more about direct proportions at:
https://brainly.com/question/1266676
Give reason: The maximum covalence of boron is 4.
Answer:
true
Explanation:
Answer:
true
Explanation:
What is the concentration of HNO3 if 5.00×10−2 mol are present in 905 mL of the solution?
Answer:
0.05525 M or 55.25 mM
Explanation:
Concentration = moles/volume
*Note that volume is expressed in L so you will need to convert mL > L here
[tex]C= \frac{n}{V}\\C= \frac{0.05}{0.905}\\C=0.05525[/tex]
What is the IUPAC name of the following compound?
OH
s
Answer:
2-isopropyl-4-methylphenol.
Explanation:
Hey there!
In this case, according to the given information, it turns out possible for us to assign the appropriate IUPAC name of the given compound, by considering that the phenol stands for the parent chain and we have isopropyl methyl radicals which the former is called first due to the alphabet consideration.
In such a way, the name would be 2-isopropyl-4-methylphenol.
Regards!
Determine the molality and molarity of a sodium chloride solution prepared by adding 52.80 g of solid NaCl to 150.0 g of water. The density of the saline solution is 1.1972 g mL . Molality
Answer:
6.02 m5.334 MExplanation:
First we convert 52.80 g of NaCl to moles, using its molar mass:
52.80 g ÷ 58.44 g/mol = 0.9035 molTo determine the molality, we convert 150.0 g of water to kg:
150.0 g / 1000 = 0.150 kgmolality = 0.9035 mol / 0.150 kg = 6.02 mAs for the molarity, we determine the total mass of solution:
52.80 g + 150.0 g = 202.8 gAnd calculate the volume, using the density:
202.8 g ÷ 1.1972 g/mL = 169.39 mL169.39 mL / 1000 = 0.16939 LFinally we calculate the molarity:
0.9035 mol / 0.16939 L = 5.334 MWhat does Etching , Stratches and sample size impact hardness results of metals
Answer:
Etching is used to reveal the microstructure of the metal through selective chemical attack. It also removes the thin, highly deformed layer introduced during grinding and polishing. ... The specimen is etched using a reagent.
Explanation:
hope it was helpful.....
22)
)
Limestone can form as a result of
A)
metamorphosis of conglomerate rock
B)
cooling of molten rock under the oceans
C)
precipitation from evaporating water
D)
radioactive decay of dolostone
Answer:
tge answer is a
Explanation:
I'm smart like that
Which statement
about Niels Bohr's atomic model is true?
Higher orbits have lower energies.
Each orbit has a specific energy level.
&
Electrons can exist in any energy level.
Orbits close to the nucleus have no energy.
Answer:
b. each orbit has a specific energy level
Explanation:
edge
A certain shade of blue has a frequency of 7.16x10^14Hz. What is the energy of exactly one photon of this light? Planck’s constant h=6.626x10^-34 j•s.
Explanation:
the answer is in the image above
If 7.90 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction?
C5H12+8O2=6H2O+5CO2
Answer:
moles CO₂ produced from combustion of 7.9 mole of C₅H₁₂ = 39.5 moles CO₂
Explanation:
C₅H₁₂ + 8O₂ => 6H₂O + 5CO₂
Given: 7.9moles excess _____ ? moles
From Equation, 1 mole C₅H₁₂ =============> 5 moles CO₂
Given 7.9 mole C₅H₁₂ =============> X
Solving for 'X' using ratio and proportion ...
1mole C₅H₁₂ / 7.9mole C₅H₁₂ = 5mole CO₂ / X
=> X = 5 mole CO₂ x 7.9mole C₅H₁₂ / 1mole C₅H₁₂ = 39.5 moles CO₂
≅ 40 moles CO₂ (2 sig. figs.)
An ideal gas is made up of gas particles that...
(A) ...have volume.
(B) ... attract each other.
(C)...can be liquified.
(D) ... are in random motion.
Answer:
Its D Are in random motion
i hope it will help you if not soo sorry :)
A sample of drinking water was tested for Pb2 and was found to have a Pb2 concentration of 17.50 ppb. A 9.00 mL sample of the drinking water was spiked with 1.00 mL of a 2.29 ppb Pb2 standard. Analysis of the spiked sample gave a concentration of 15.93 ppb Pb2 . Find the percent recovery of the spike.
Answer:
[tex]X=75\%[/tex]
Explanation:
From the question we are told that:
Concentration [tex]C_1=17.50ppb[/tex]
Volume [tex]v=9mL[/tex]
Spike Volume [tex]V_s=1.00mL[/tex]
spike Conc [tex]C_2=2.29 ppb[/tex]
Analysis Conc [tex]C_s=15.93 ppb[/tex]
Generally the equation for percent recovery is mathematically given by
[tex]X=\frac{C_s'-C_1'}{C_2'}[/tex]
Where
Concentration of spiked sample C_s'
[tex]C_s'=C_s*(v+v_s)[/tex]
[tex]C_s'=15.92*(9+1)[/tex]
[tex]C_2=159.2[/tex]
Concentration of unspiked sample C_1'
[tex]C_1'=17.50*9mL[/tex]
[tex]C_1'=157.5[/tex]
Concentration of spike sample C_2'
[tex]C_2=2.29*1[/tex]
[tex]C_2=2.29[/tex]
Therefore
[tex]X=\frac{159.2-157.5}{2.29}[/tex]
[tex]X=75\%[/tex]
Which of the following ions is formed when an acid is dissolved in a solution? (5 points) H+
O−
OH−
SO42+
Answer:
Hence, option B is correct. 1 and 2
Explanation:
NH 4 Cl is a weak base-strong acid salt.
NaCN is a salt of a strong base (NaOH) and weak acid (HCN).In water,
1. NH 4 Cl produces acidic solution
2. KHSO 4 produces acidic solution
because the neutral salt of strong base KOH and strong acid H 2 SO 4 is K 2 SO 4
3. NaCN produces basic solution
4. KNO
3 produces neutral solution
I think this is right but I hope its help ,ur welcome ♥️♥️
Answer:
H+
Explanation:
I took the test :)
Toothpastes containing sodium hydrogen carbonate (sodium bicarbonate) and hydrogen peroxide are widely used. Write Lewis structures for the hydrogen carbonate ion and hydrogen peroxide molecule, with resonance forms where appropriate.
Answer:
See explanation and images attached
Explanation:
The first image shows the structure of hydrogen peroxide. It does not exist as resonance structures. The structure and properties of the molecule can wholly be explained on the basis of a single Lewis structure.
However, the structure of the bicarbonate ion in sodium bicarbonate can not be completely described by a single Lewis structure. Hence, two resonance structures are shown for the bicarbonate ion. In each case, Na^+ is the counter ion.
A certain alkyl halide is reacted with OH- to form an alcohol. The alkyl halide is optically active but the product(s) is/are optically inactive. Which of the following could be the reactant?a) 3-bromo-3-methylhexane.b) 1-chlorobutane.c) 2-bromo-2-methylbutane.d) 3-bromo-2,3,4-trimethypentane.
Answer:
a. 3-brumo - 3-methylhexane
Explanation:
Alkyl Halides can undergo substitution reactions. Nucleophiles are electron rich species and has negative charge while Electrophiles are electron deficient species which carry positive charge. Alkyl halide which have polar carbon atom are electrophiles.
* Use the periodic table
How many grams of O2 are in a 5.0 mol of the element?
80 g
16 g
160 g
