Answer: [tex]317.2\ ft[/tex]
Step-by-step explanation:
Given
Angle of elevation [tex]\theta=65^{\circ}[/tex]
Length of string [tex]L=350\ ft[/tex]
Suppose the height of kite from the ground level is h
from the figure, we can write
[tex]\Rightarrow \sin \theta=\dfrac{h}{L}\\\\\Rightarrow \sin 65^{\circ}=\dfrac{h}{350}\\\\\Rightarrow h=350\sin 65^{\circ}\\\Rightarrow h=317.2\ ft[/tex]
Someone Please help‼️‼️‼️
Hi there!
[tex]\large\boxed{m = 2}[/tex]
Since the line is increasing (the y-values are increasing as x increases), we can automatically eliminate any answer choice containing a negative slope.
Thus, the only correct answer choice would be m = 2.
We could also solve using the slope formula:
m = y2-y1/x2-x1
Plug in given points:
m = 3-1 / 0 - (-1)
m = 2 / 1 = 2
please answer this!!
Helpppp Please! Please!
The solution of this equation has an error. Which of the following steps has an error?
Step 1: -2x + 8 - 3x = 7
Step2:–5x+8=7
Step3:-5x = 15
Step4:
x = -3
O Step 2
O Step 1
O Step 3
3rd step
Solution:-
[tex]\\ \sf\longmapsto -2x+8-3x=7[/tex]
[tex]\\ \sf\longmapsto -2x-3x+8=7[/tex]
[tex]\\ \sf\longmapsto -5x+8=7[/tex]
[tex]\\ \sf\longmapsto -5x=7-8[/tex]
[tex]\\ \sf\longmapsto -5x=-1[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-1}{-5}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{1}{5}[/tex]
Solve the following equation using
distribution.
2 (4x – 12) = 5
(3) (4x) – (*) (12) = 5
2x - 6 = 5
+6
+6
2x = 11
.. i need help asap look at pics please i need this class done completely in two hours
Answer: 5.5
Step-by-step explanation: It is basically already solved the only thing I did was isolate x by itself my moving the 2 over and doing 11 divided by 2 which equals 5.5. This means that x equals 5.5
Finding an irrational number between which given pair of numbers supports the idea that irrational numbers are dense in real numbers? 3.14 and pi 3.33 and 1/3 e squared and square root of 5 square root of 64 over 2 and square root of 16
Answer:
So, we need to find irrational numbers between the given pairs.
Remember that the sum between an irrational number and an rational number is irrational.
For example, for the first case, we want a irrational number between:
3.14 and pi:
pi = 3.14159265.... is irrational
pi - 0.0001 = 3.14159265... - 0.0001 = 3.14149265...
So this number:
3.14149265...
is an irrational number larger than 3.14 and smaller than pi.
Second cacse:
3.33 and 1/3
(here the range would be actually:
1/3 = 0.33 and 3.33
So we want an irrational number larger tan 0.33 and smaller than 3.33
here we can just use pi = 3.141592...
third case:
e^2 and √5
Firs let's write these numbers so we can see how they look.
e^2 =7.389...
√5 = 2.236
So we want a number larger than 2.236... and smaller than 7.389...
Again, here we can use pi = 3.141592...
2.236... < 3.141592... < 7.389...
final case:
√(64/2) and √16
we have:
√(64/2) = 5.65
√16 = 4
So we want an irrational number larger than 4 and smaller than 5.65
Again, let's use our beloved number pi.
we have that:
pi + 1 is an irrational number:
pi + 1 = 3.14159265... + 1.0 = 4.14159265....
This number, 4.14159265..., is irrational, is larger than 4 and is smaller than 5.65, so we found the irrational number between the given pair of numbers.
Answer:
3.33 and 1/3
Step-by-step explanation:
f(x) = x2 – 12x – 29
f(3) = (x+ ?)+ ?
Answer:
-6 and - 65
Step-by-step explanation:
X-12x-29, by completing the square we get (x-6)^2-65
Help please, I need with the question
Answer: [tex]\frac{4}{3}[/tex]
Step-by-step explanation:
tangent of ∠PLM = [tex]\frac{opposite}{adjacent} =\frac{4}{3}[/tex]
Answer:
PLM=4/3
Step-by-step explanation:
[tex]2 |3 \sqrt{2} - 2 \sqrt{3} | + |3 \sqrt{8} - 8 \sqrt{3} | + 2 \sqrt{12} [/tex]
.......................
Answer:
hope it helps
Step-by-step explanation:
Answer:
SEE THE IMAGE FOR SOLUTION..
Evaluate 1/243 ( base must be 1/9)
PLEASE I NEED THIS FAST!
Answer:
(1/9)^2 x 1/3
Step-by-step explanation:
1/243
=> 1 / 3 x 3 x 3 x 3 x 3
=> 1 / 9 x 9 x 3
=> (1/9)^2 x 1/3
please answer this
simplify it too
Answer:
x^2 +3x
Step-by-step explanation:
The outer rectangle has an area of
A = l*w = (4x)*(x+2) = 4x^2 +8x
The inner rectangle has an area of
A = (3x+5)*x = 3x^2 +5x
Subtract the inner rectangle from the outer rectangle
Shaded area = 4x^2 +8x - ( 3x^2 +5x)
Distribute the minus sign
=4x^2 +8x - 3x^2 -5x
Combine like terms
= x^2 +3x
Please help a-e I will rate and like response. Thank u
Answer:
VOLUME OF RIGHT CIRCULAR CONE=≈74.93136cm^3
VOLUME OF SPHERE: ≈523.6cm^3
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION WHILE ANSWERING THE QUESTION!!
A data set with less variation will have a smaller ____________________.
A. minimum
B. median
C. mean
D. interquartile range
Answer:
c. mean
Step-by-step explanation:
the data set that has less variation will have smaller distribution over a large area or variation measures.
Answer:
D. Interquile Range
Step-by-step explanation:
The datasets that have less variation are those that have smaller dispersion or variation measures.
Some of these measures of variance are variance, standard deviation, mean absolute deviation, range and interquartile range. Among the options shown, the only one that is used as a measure of variation is the interquartile range. The interquartile range is the difference between the third quartile and the first quartile of a data distribution. In other words, the interquartile range measures the range between the central 50% of the data.
The curve y=(k-6)x^2-8x+k cuts the x-axis at two points and has a minimum point. Find the range of values of k.
Answer:
Hello,
answer: -2 < k < 8
Step-by-step explanation:
As there are 2 roots: Δ>0
As there is a mininum, k-6 <0 ==> k<6,
minimum :y'=0 ==> (k-6)*2x-8=0 ==> x=4/(k-6)
[tex]\Delta=8^2-4*k*(k-6)\\=64-4k^2+24k\\=-4(k^2-6k+9)+36+64\\=100-4(k-3)^2\\=4(8-k)(k+2)\\\\\Delta\ is\ positive\ for\ -2 < k < 8[/tex]
help me...............
Answer:
Brainliestgive o020201000
What is the value of the expression below when y = 8 y=8? 2 y + 7 2y+7
Answer:
23
Step-by-step explanation:
[tex]2 y + 7[/tex]
Replace y with 8
[tex]= 2 (8) + 7\\= 16+ 7\\= 23[/tex]
Therefore, the value of the expression when y=8 is 23.
I hope this helps!
For each pair of equations, write the letter of the equation that expresses an equal value.
1. a. L = 1 dm3 b. 1 L = 1 cm3
2. a. 1 mL = 1 cm3 b. 1 cm3 = 1 L
3. a. 0°C = –273 K b. 0 K = −273°C
4. a. 1 kg = 100 g b. 1,000 g = 1 kg
5. a. 400 cm = 4.0 m b. 400 cm = 0.40 m
6. a. 1 dm = 10 m b. 1 dm = 0.10 m
7. a. 100°C = 373 K b. 373 K = 10°C
We must understand that certain standards has been layed down for the conversions of measuring units. A summary of such standards are discussed below:
1. Option A. 1 L = 1 dm³
2. Option A. 1 mL = 1 cm³
3. Option B. 0 K = −273 °C
4. Option B. 1000 g = 1 kg
5. Option A. 400 cm = 4.0 m
6. Option B. 1 dm = 0.10 m
7. Option A. 100°C = 373 K
1. Option A. 1 L = 1 dm³
Option B. 1 L = 1 cm³
From standard measurement,
1 L = 1 dm³
1 L = 1000 cm³
From the measuring standard, we can see that 1 L ≠ 1 cm³.
Hence, option A gives the correct answer.
2. Option A. 1 mL = 1 cm³
Option B. 1 cm³ = 1 L
Hence, option A gives the correct answer.
From standard measurement,
1 mL = 1 cm³
1000 cm³ = 1 L
Thus, option A gives the correct answer.
3. Option A. 0°C = –273 K
Option B. 0 K = −273 °C
Recall:
T (K) = T(°C) + 273
T (K) = Temperature in Kelvin
T(°C) = Temperature in decree celcius
Next, we shall convert 0°C to K
T(°C) = 0°C
T (K) = T(°C) + 273
T (K) = 0 + 273
T (K) = 273 K
Thus, 0°C is equivalent to 273 K
Next, we shall convert 0 K to °C
T(K) = 0
T (K) = T(°C) + 273
0 = T(°C) + 273
Collect like terms
0 – 273 = T(°C)
T(°C) = –273°C
Thus, 0 K is equivalent to –273°C
Therefore, option B gives the correct answer.
4. Option A. 1 kg = 100 g
Option B. 1000 g = 1 kg
From standard measurement,
1 Kg = 1000 g
1000 g = 1 Kg
Hence, Option B gives the right answer
5. Option A. 400 cm = 4.0 m
Option B. 400 cm = 0.40 m
From standard measurement,
100 cm = 1 m
Converting 400 cm to m, we have:
[tex]400 cm = 1 m\\400 cm = \frac{400 cm * 1 m }{100 cm}\\400 cm = 4 m[/tex]
Thus, option A gives the correct answer.
6. Option A. 1 dm = 10 m
Option B. 1 dm = 0.10 m
From standard measurement,
10 dm = 1 m
Thus,
[tex]1 dm = \frac{1 dm * 1 m}{10 dm}\\1 dm = 0.1 m[/tex]
Therefore, option B gives the correct answer.
7. Option A. 100°C = 373 K
Option B. 373 K = 10°C
Recall:
T (K) = T(°C) + 273
T (K) = Temperature in Kelvin
T(°C) = Temperature in decree celcius
Next, we shall convert 100°C to K
T(°C) = 100°C
T (K) = T(°C) + 273
T (K) = 100 + 273
T (K) = 373 K
Thus, 100°C is equivalent to 373 K
Next, we shall convert 373 K to °C
T(K) = 373
T (K) = T(°C) + 273
373 = T(°C) + 273
Collect like terms
373 – 273 = T(°C)
T(°C) = 100°C
Thus, 373 K is equivalent to 100°C
Therefore, option A gives the correct answer.
SUMMARY:
1. Option A. 1 L = 1 dm³
2. Option A. 1 mL = 1 cm³
3. Option B. 0 K = −273 °C
4. Option B. 1000 g = 1 kg
5. Option A. 400 cm = 4.0 m
6. Option B. 1 dm = 0.10 m
7. Option A. 100°C = 373 K
Learn more:
https://brainly.com/question/11650994
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Factor out the greatest common factor from 4x4 + 12x2 + 8x.
4(x4 + 3x2 + 2x)
2x(2x3 + 6x + 4)
4x(x3 + 3x + 2)
2(2x4 + 6x2 + 4x)
Answer:
4x( x^3 +3x+2)
Step-by-step explanation:
4x^4 + 12x^2 + 8x
Factor out 4x
4x( x^3 +3x+2)
if the hypotenuse of an isosceles right triangle has a length of 5 centimeters what is the length of one of the legs
Answer:
a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]
Step-by-step explanation:
[tex]a^{2} +b^{2} = 5 ^{2}[/tex]
a = b
[tex]2a^{2} = 5 ^{2}[/tex]
[tex]2a^{2} = 25\\[/tex]
[tex]a^{2} = \frac{25}{5}[/tex]
a = [tex]\frac{5}{\sqrt{5} }[/tex]
must rationalize...
a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]
Given that the point (-2,8) is on the graph of an equation that is symmetric with respect to the x-axis, what other point is on the graph?
(Type an ordered pair)
Number 13 I don’t get it
===========================================
Explanation:
The two equations given to us are
ab = 3ab^2 = 18Divide the second equation over the first equation and that would lead to b = 6
Notice how the 'a' terms divide to 1 and go away, i.e. cancel out.
The b terms divide to (b^2)/b = b
The right hand side values divide to 18/3 = 6
So that's how we end up with b = 6
-------------------------
Now if b = 6, then we can say,
ab = 3
a*6 = 3
a = 3/6
a = 1/2
Or we could say
ab^2 = 18
a*6^2 = 18
a*36 = 18
a = 18/36
a = 1/2
what is the answer to this equation?
Answer:
4i
Step-by-step explanation:
apply (a+b)^2 formula
Please help explanation if possible
Answer:
Hello,
Step-by-step explanation:
slope of the line=3/7
slope of the perpendicular = -7/3
equation of the perpendicular:
y-3=(x-3)*(-7/3)
or
y=-7/3*x +7+3
or
y=-7/3*x+10
Simultaneous equation 2x-Y= -1 x-2y=4
Answer:
x + y = -5
Step-by-step explanation:
2x - x - y + 2y = -1 - 4
x + y = -5
Find the value of z.
Answer:
Option D, 110
Step-by-step explanation:
first we find x
10x+20-80=2(2x+15)
or, x=15
now, 10x+20 = 170
so, z = 360-170-80 = 110
I need help solving this
Answer:
E. 248
Step-by-step explanation:
1 to 500 in set A, 250 to 750 in set B
500 - 250 = 250
100 and 200 are divisible by 100.
250 - 2 = 248
Thank you so much thank y’all
The volume of a sphere is 3,000π m3. What is the radius of the sphere to the nearest meter?
Answer:
13m
Step-by-step explanation:
volume of sphere = [tex]\frac{4}{3} * pi * r^{3}[/tex] = 3000π
4r^3/3 = 3000
r^3 =2250
r = ∛2250 = 13.10370 = 13
Answer:
Radius of the sphere is 13.1 m.
Step-by-step explanation:
Volume:
[tex]{ \boxed{ \pmb{volume = { \bf{ \frac{4}{3}\pi {r}^{3} }}}}}[/tex]
Substitute:
[tex]{ \tt{3000\pi = \frac{4}{3} \times \pi \times {( {r}^{3}) } }} \\ \\ { \tt{ {r}^{3} = \frac{3000 \times 3}{4} }} \\ \\ { \tt{r = \sqrt[3]{ \frac{3000 \times 3}{4} } }} \\ { \tt{r = 13.1 \: m}}[/tex]
.....................
Answer:
2nd option is the correct one
log|x|-f(x)+k
(3 -/ 5) power 10 divided (3 -/ 5) power 8
simplify and express in exponential form