A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5 years, and standard deviation of 1.3 years.

If you randomly purchase one item, what is the probability it will last longer than 6 years?

The second decile of the given data set, "24, 64, 25, 40, 45, 34, 14, 26, 28, 24, 58, 51"  is 24.

To find the second decile of a data set, we first need to arrange the data in order from lowest to highest, that is :

⇒ 14, 24, 24, 25, 26, 28, 34, 40, 45, 51, 58, 64

The second decile represents the value that divides the data into two parts, where 20% of the data is below the value and 80% of the data is above the value.

Since there are 12 data points in this set,

So, 20% of the data is equal to 0.2 × 12 = 2.4.

Since we cannot have a fractional data point, we round up to 3.

So, the second decile is the third value in the ordered data set.

which is 24.

Therefore, The second decile is 24.

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so here we get two outcomes one is 2 and other is 4.

so there is total 2 outcomes.

total no. of possibility is 5

so the probability of waiting between 2 and 4 minutes to use the ATM is 2/5.

Since the p-value (0.0803) exceeds the significance threshold (0.05), the null hypothesis cannot be ruled out.

The mean in mathematics is a measurement of a collection of numerical data's central tendency. It is determined by adding up all of the values in the set and dividing the result by the total number of values. This value is frequently referred to as the average value. The mean (or mathematical mean) is calculated as follows: (Sum of Values) / Mean (number of values)

given

The null hypothesis states that the mean number of units generated during the day and night shifts is the same. The contrary hypothesis (Ha) states that more units are created on average on the night shift than on the day shift.

"day" + "night"

Bravo! Night precedes day.

b. The following method can be used to calculate the test statistic:

t = sqrt(1/n night + 1/n day) * sqrt(x night - x day)

where s p is the pooled standard deviation and x night and x day are the sample averages, n night and n day are the sample sizes, and s p is represented by:

Sqrt(((n night - 1)*s night2 + (n day - 1)*s day2) / (n night + n day - 2)) yields the value s p.

S p is equal to sqrt(((74 - 1)*35 + (68 - 1)*28) / (74 + 68 - 2)), which equals 31.88.

t = (358 - 352) / (31.88 * sqrt(1/74 + 1/68)) = 1.19

1.19 is the test result.

the p-value is 0.0803 as a result (rounded to 4 decimal places).

Since the p-value (0.0803) exceeds the significance threshold (0.05), the null hypothesis cannot be ruled out.

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The complete question is :- Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the night shift than on the day shift. The mean number of units produced by a sample of 68 day-shift workers was 352. The mean number of units produced by a sample of 74 night-shift workers was 358. Assume the population standard deviation of the number of units produced is 28 on the day shift and 35 on the night shift.

Using the 0.05 significance level, is the number of units produced on the night shift larger?

a. State the null and alternate hypotheses.

O : Day/Night: H:

Day Night

b. Compute the test statistic. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.)

c. Compute the p-value. (Round your answer to 4 decimal places.) p-value

[tex]\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ \stackrel{ \textit{we'll use this one} }{log_a a^x = x}\qquad \qquad a^{log_a (x)}=x \end{array} \\\\[-0.35em] ~\dotfill\\\\ \log_2\left( \cfrac{1}{16} \right)+4\implies \log_2\left( \cfrac{1}{2^4} \right)+4\implies \log_2(2^{-4})+4\implies -4+4\implies \text{\LARGE 0}[/tex]

[tex]\rule{34em}{0.25pt}\\\\ \textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b\qquad\qquad \\\\[-0.35em] ~\dotfill\\\\ \log_2\left( \cfrac{1}{16} \right)=y\implies 2^y=\cfrac{1}{16}\implies 2^y=2^{-4}\implies y=-4[/tex]

Answer:

The answer is 1.5$

Step-by-step explanation:

Let the price of 1 notebook be x$ and 1 elastic book cover be y$

In first case,

2x+5y=$6.75

2x = $6.75-5y

x=($6.75-5y)/2------------- eqn i

In second case,

4x+2y=$7.50

4×($6.75-5y)/2 +2y=$7.50 [From eqn i]

($27-20y)/2 +2y=$7.50

($27-20y+4y)/2=$7.50

($27-16y)/2=$7.50

$27-16y=$7.50×2

$27-16y=$15

$27-$15=16y

$12=16y

y=$12/16

y=$0.75

The price of single elastic book cover is $0.75

Substituting the value of y in eqn i we get

x=($6.75-5y)/2

x=($6.75-5×$0.75)/2

x=($6.75-$3.75)/2

x=$3/2

x=$1.5

Hence, the price of single notebook is $1.5 Ans

Hey mate, please mark me as brainliest if you got the answer.

According to the given information, the equation of the ellipse is [tex](x+8)^2/256 + (y+1)^2/784 = 1.[/tex]

Coordinate geometry, also known as analytic geometry, is a branch of mathematics that deals with the study of geometric shapes using algebraic principles. It involves the use of coordinates to represent points, lines, curves, and other geometric figures on a plane or in space.

we need to know the coordinates of its foci, co-vertices, and the center. We can start by finding the center of the ellipse, which is the midpoint of the line segment joining the foci:

Center = ( (-8 + (-8))/2 , (14 + (-16))/2 ) = (-8,-1)

Next, we can find the distance between the foci, which is given by:

[tex]distance between foci = 2c = sqrt[(14 - (-16))^2 + (-8 - (-8))^2] = 30[/tex]

where c is the distance from the center to either focus.

We also know that the distance between the co-vertices is given by:

distance between co-vertices = 2a = |-16 - 0| = 16

where a is the distance from the center to either co-vertex.

Finally, we can use the standard form equation for an ellipse centered at the origin:

[tex](x^2/a^2) + (y^2/b^2) = 1[/tex]

where b is the distance from the center to either vertex.

To find b, we can use the Pythagorean theorem:

[tex]b^2 = c^2 - a^2 \\b^2 = 30^2 - 16^2\\b^2 = 784\\b = 28[/tex]

Now we have all the information we need to write the equation of the ellipse:

[tex](x+8)^2/16^2 + (y+1)^2/28^2 = 1[/tex]

Therefore, according to the given information, the equation of the ellipse is [tex](x+8)^2/256 + (y+1)^2/784 = 1.[/tex]

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Answer:

Acquired resources

Step-by-step explanation:

Acquired resources

Answer:

5 as a percentage of 100 is 5/100 which is 5%

Answer:

y=9/x  => proportional

y = x - 12 ==> non-proportional

h = 3d ==> proportional

f = 1/3 e = proportional

Step-by-step explanation:

A proportional equation is of the general form

y = kx (directly proportional) or

y = k/x  (inversely proportional)

k is known as the constant of proportionality

y = 9/x ==> k = 9  proportional
y = x - 12  cannot be expressed as y = kx or y = k/x

h = 3d ==> k = 3  proportional

f = 1/3 e ==> k = 1/3   proportional

A replacement value is a value that can be substituted for a variable in an equation or expression in order to solve for that variable or simplify the expression.

An expression is a combination of numbers, variables, and/or operators that represents a mathematical relationship or calculation. An expression can be as simple as a single number or variable, or it can be more complex and involve multiple operations and variables.

A variable is a symbol or letter that represents a quantity or value that can change or vary in different contexts.

In the given question,

A replacement value is a value that can be substituted for a variable in an equation or expression in order to solve for that variable or simplify the expression.

For example, suppose you have the equation 2x + 3 = 7, and you want to solve for x.

To do so, you can use a replacement value.

You can subtract 3 from both sides of the equation to isolate the term with x, which gives you:

2x = 4

Now, you can divide both sides of the equation by 2 to solve for x:

x = 2

In this case, the replacement value was the number 2, which was substituted for the variable x in the equation in order to solve for x.

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If you need 1 1/4 cups of sugar to make cookies, that is the amount of sugar needed for one batch of cookies. To find out how much sugar is needed to make 16 cookies, we can set up a proportion:

1 1/4 cups sugar is needed to make 1 batch of cookies

x cups sugar is needed to make 16 cookies

We can solve for x by cross-multiplying:

1 1/4 * 16 = x

20/4 = x

5 = x

Therefore, you will need 5 cups of sugar to make 16 cookies.

Answer:

area of semi circle =pi r^2/2

3.14*6*6/2=56.2

area of rectangle=lb

=20*12=240

240+56.2=296.2

rounding it it will become 300 ft sqr

perimeter of rectangle without including 4th side=20+12+20=52

perimeter of semicircle=pi r+d (d is not needed here)

3.14*6=18.84

so total perimeter=52+18.84=70.84ft

Step-by-step explanation:

The probability that the average of 49 marathons is between 143 and 147 minutes is 0.5980. The 60th percentile is 148.25 minutes, and the median is 146 minutes.

The average of a sample of 49 marathons will be approximately normally distributed with mean = 146 minutes and standard deviation = 15/sqrt(49) = 15/7.

To find the probability that the average of the sample will be between 143 and 147 minutes, we can standardize the values:

z1 = (143 - 146) / (15/7) = -1.4

z2 = (147 - 146) / (15/7) = 0.4667

Then, using a standard normal distribution table or calculator, we find:

P(-1.4 < Z < 0.4667) = P(Z < 0.4667) - P(Z < -1.4)

= 0.6788 - 0.0808

= 0.5980

So the probability that the average of the sample will be between 143 and 147 minutes is 0.5980.

To find the 60th percentile for the average of these 49 marathons, we need to find the z-score such that the area to the left of the z-score is 0.6. Using a standard normal distribution table or calculator, we find:

P(Z < z) = 0.6

z = 0.25

Then, we can solve for the corresponding value of X:

0.25 = (X - 146) / (15/7)

X = 148.25

So the 60th percentile for the average of these 49 marathons is 148.25 minutes.

To find the median of the average running times, we note that the median of a normal distribution is equal to its mean. Therefore, the median of the average running times is 146 minutes.

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the terminal point of the angle determined by sin(0) < 0 and cos(0) > 0 is in the fourth quadrant.

why it is and what is trigonometry?

If sin(0) < 0 and cos(0) > 0, then we know that the angle 0 is in the fourth quadrant of the unit circle.

In the unit circle, the x-coordinate represents cos(θ) and the y-coordinate represents sin(θ). Since cos(0) > 0, we know that the terminal point of the angle is to the right of the origin. And since sin(0) < 0, we know that the terminal point is below the x-axis.

The fourth quadrant is the only quadrant where the x-coordinate is positive and the y-coordinate is negative, so that is the quadrant where the terminal point of the angle lies.

Therefore, the terminal point of the angle determined by sin(0) < 0 and cos(0) > 0 is in the fourth quadrant.

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It focuses on the study of the functions of angles and their applications to triangles, including the measurement of angles, the calculation of lengths and areas of triangles, and the analysis of periodic phenomena.

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a) As per the given budget, the amount of interval that would be better for the city is 95% confidence interval.

b) The interval that be worse for the planners is depends on sample size

c) They achieve an interval estimate that would better serve their planning needs is depends on margin of error

d) The number of days worth of data should they collect to have confidence of estimating the true mean to 30 days

To obtain a better estimate, the city can create a confidence interval, which is a range of values that is likely to contain the true population mean with a certain degree of confidence.

However, there are also some disadvantages to using a confidence interval. The interval estimate may be wider than a point estimate, which means that the budget planners may have to allocate a larger budget to account for the uncertainty in the estimate.

To achieve a better interval estimate, the city could increase the sample size or reduce the variability of the data. Increasing the sample size reduces the margin of error and increases the precision of the estimate.

Finally, to determine how many days' worth of data the city should collect to estimate the true mean with a certain degree of confidence, the city would need to consider the desired level of precision, the variability of the data, and the desired level of confidence.

Typically, a larger sample size will provide a more accurate estimate, but this also depends on the variability of the data. In general, a sample size of at least 30 is recommended for a reasonably accurate estimate.

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if we make quarterly deposits and invest them at an nominal annual interest rate of 8% compounded quarterly for 40 years, we will have $143,004.54 at the end of the 40 years.

The first step in solving this problem is to calculate the amount of each quarterly deposit. We know that the first deposit is $400, and each subsequent deposit decreases by 1% from the previous deposit. This means that each deposit is 99% of the previous deposit. To calculate the size of each deposit, we can use the following formula:

deposit_ n = deposit_(n-1) * 0.99

Using this formula, we can calculate the size of each quarterly deposit as follows:

deposit_1 = $400

deposit_2 = deposit_1 * 0.99 = $396.00

deposit_3 = deposit_2 * 0.99 = $392.04

deposit_4 = deposit_3 * 0.99 = $388.12

...

We can continue this pattern for 40 years (160 quarters) to find the size of each quarterly deposit.

Next, we need to calculate the future value of these deposits using an nominal annual interest rate of 8% compounded quarterly. We can use the formula for compound interest to calculate the future value:

[tex]FV = PV * (1 + r/n)^(n*t)[/tex]

where FV is the future value, PV is the present value (which is zero since we are starting with deposits), r is the nominal annual interest rate (8%), n is the number of times the interest is compounded per year (4 since we are compounding quarterly), and t is the number of years (40).

We can substitute the values into the formula and solve for FV:

[tex]FV = $400 * (1 + 0.08/4)^(440) + $396.00 * (1 + 0.08/4)^(439) + $392.04 * (1 + 0.08/4)^(4*38) + ... + $1.64 * (1 + 0.08/4)^4[/tex]

After solving this equation, we get a future value of $143,004.54, rounded to two decimal places. This means that if we make quarterly deposits and invest them at an nominal annual interest rate of 8% compounded quarterly for 40 years, we will have $143,004.54 at the end of the 40 years.

This calculation highlights the power of compound interest over long periods of time. By making regular contributions and earning interest on those contributions, our investment grows exponentially over time. It also shows the importance of starting early and consistently contributing to an investment over time in order to achieve long-term financial goals.

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Answer:

Step-by-step explanation:

We can start by assuming that the relationship between the ticket price and attendance is linear, so we can write the equation for the line that connects the two data points we have:

Point 1: (9, 23000)

Point 2: (7, 30000)

The slope of the line can be calculated as:

slope = (y2 - y1) / (x2 - x1)

slope = (30000 - 23000) / (7 - 9)

slope = 3500

So the equation for the line is:

y - y1 = m(x - x1)

y - 23000 = 3500(x - 9)

y = 3500x - 28700

Now we can use this equation to find the attendance for any ticket price. To maximize revenue, we need to find the ticket price that generates the highest revenue. Revenue is simply the product of attendance and ticket price:

R = P*A

R = P(3500P - 28700)

R = 3500P^2 - 28700P

To find the ticket price that maximizes revenue, we need to take the derivative of the revenue equation and set it equal to zero:

dR/dP = 7000P - 28700 = 0

7000P = 28700

P = 4.10

So the ticket price that would maximize revenue is $4.10. However, we need to make sure that this price is within a reasonable range, so we should check that the attendance at this price is between 23,000 and 30,000:

A = 3500(4.10) - 28700

A = 5730

Since 23,000 < 5,730 < 30,000, we can conclude that the ticket price that would maximize revenue is $4.10.

Rhiannon arrived home approximately 17 minutes earlier than Alexander.

This is the arithmetic mean and is calculated by adding a group of numbers and then dividing by the count of those numbers. For example, the average of 2, 3, 3, 5, 7, and 10 is 30 divided by 6, which is 5.

To solve this problem, we can use the formula:

time = distance / speed

a) The time it took Alexander to get home is:

time_Alexander = 14 km / 20 km/h = 0.7 hours

The time it took Rhiannon to get home is:

time_Rhiannon = 10 km / 24 km/h = 0.41667 hours

Since Rhiannon's time is smaller than Alexander's, Rhiannon arrived home earlier.

b) The time difference between their arrivals is:

time_difference = time_Alexander - time_Rhiannon = 0.7 hours - 0.41667 hours = 0.28333 hours

To convert this to minutes, we can multiply by 60:

time_difference_in_minutes = 0.28333 hours x 60 minutes/hour ≈ 17 minutes

Therefore, Rhiannon arrived home approximately 17 minutes earlier than Alexander.

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Answer:

the answer is 12/13 simplified

Step-by-step explanation:

simplified

Answer: Below :)

Step-by-step explanation:

(a) The percentage of students and teachers who bought tickets to go on the trip is 65%. So the number of students and teachers who bought tickets can be found by multiplying the total number of students and teachers by 65%:

65/100 x 360 = 234

Therefore, 234 students and teachers bought tickets to go on the trip.

(b) Let the number of teachers who bought tickets be x. Then the number of male students who bought tickets is 3x, and the number of female students who bought tickets is 5x.

The total number of students and teachers who bought tickets is:

x + 3x + 5x = 9x

We know that 234 students and teachers bought tickets, so we can set up the following equation:

9x = 234

Solving for x, we get:

x = 26

So the number of teachers who bought tickets is 26, the number of male students who bought tickets is 78 (3x), and the number of female students who bought tickets is 130 (5x).

However, 4 of the female students who bought tickets did not go on the trip, so the actual number of female students who went on the trip is:

130 - 4 = 126

(c) The ratio of the number of male students who went on the trip to the number of female students who went on the trip is:

78/126

Simplifying this ratio by dividing both numerator and denominator by 6, we get:

13/21

Therefore, the ratio of the number of male students who went on the trip to the number of female students who went on the trip is 13:21.

Answer: A

y < 2x + 1

y > 1/2x + 2

Answer:

To solve this problem, we can use the formula for compound interest:

A = P(1 + r/n)^(n*t)

Where:

A = the amount of money in the account after the specified time period

P = the initial principal amount (the amount deposited)

r = the annual interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the time period in years

In this case:

P = £4100

r = 13.55% = 0.1355

n = 1 (interest is compounded once per year)

t = 4 years

Plugging these values into the formula, we get:

A = £4100(1 + 0.1355/1)^(1*4)

A = £4100(1.1355)^4

A = £4100(1.6398)

A = £6717.58

Therefore, the amount of money in the account after 4 years will be £6717.58.

Answer:

Fraction: 241/48

Improper fraction: 5 1/48

Decimal: 5.021

Step-by-step explanation:

To calculate the expression 13/16+2 1/12+2 3/24, I first converted the mixed numbers 2 1/12 and 2 3/24 to improper fractions. 2 1/12 is equal to 25/12 and 2 3/24 is equal to 51/24. Then, I added the three fractions 13/16, 25/12, and 51/24 by finding a common denominator, which in this case is 48. So, the expression becomes (39/48)+(100/48)+(102/48), which simplifies to (39+100+102)/48, which equals 241/48. Finally, I converted the improper fraction 241/48 to a mixed number, which is equal to 5 1/48.

To obtain the required equation we divide the equation by sin²Ø.

The first six functions are trigonometric, with the domain value being the angle of a right triangle and the range being a number. The angle, expressed in degrees or radians, serves as the domain and the range of the trigonometric function (sometimes known as the "trig function") of f(x) = sin. Like with all other functions, we have the domain and range. In calculus, geometry, and algebra, trigonometric functions are often utilised.

The given equation is:

sin²Ø+cos²Ø=1

To obtain the required equation we divide the equation with sin²Ø:

sin²Ø/sin²Ø +cos²Ø/ sin²Ø = 1/sin²Ø

1 + cot²Ø = csc²Ø

Hence, to obtain the required equation we divide the equation by sin²Ø.

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Answer:

We can write the diameter and circumferance of base as -

D = 2√(750ρ/πh)

C = 2π√(750ρ/πh)

Step-by-step explanation:

What is function?

A function is a relation between a dependent and independent variable.

Mathematically, we can write → y = f(x) = ax + b.

Given is to find the diameter and height of the tin can.

Assume the density of coffee as {ρ}. We can write the volume of the tin can as -

Volume = mass x density

Volume = 750ρ

We can write -

πr²h = 750ρ

r = √(750ρ/πh)

D = 2r

D = 2√(750ρ/πh)

Now, we can write the circumferance as -

C = 2πr

C = 2π√(750ρ/πh)

Therefore, we can write the diameter and circumferance of base as -

D = 2√(750ρ/πh)

C = 2π√(750ρ/πh)

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Set of sophomores taking discrete math = A ∩ B. Set of sophomores not taking discrete math = A - B or A ∩ B^c. Set of students who are sophomores or in discrete math = A ∪ B. Set of students who are not sophomores or not in discrete math = (A ∩ B)^c or A ∪ B^c.

The set of sophomores taking discrete math at your school is the intersection of the set of sophomores A and the set of students in discrete math B. So, it can be expressed as A ∩ B.

The set of sophomores at your school who are not taking discrete math is the difference between the set of sophomores A and the set of students in discrete math B. So, it can be expressed as A - B or A ∩ B^c, where B^c is the complement of B (i.e., the set of students who are not in discrete math).

The set of students at your school who either are sophomores or are taking discrete math is the union of the set of sophomores A and the set of students in discrete math B. So, it can be expressed as A ∪ B.

The set of students at your school who either are not sophomores or are not taking discrete math is the complement of the intersection of the set of sophomores A and the set of students in discrete math B.

This can be expressed as (A ∩ B)^c or as A ∪ B^c, where B^c is the complement of B (i.e., the set of students who are not in discrete math). Note that this set includes all students who are either juniors, seniors, or not enrolled in discrete math.

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(a) Therefore after t = 1.75 seconds the diver will hit the water.

(b) The velocity the diver hit the water is 56 ft/s.

From the given condition we have d(t) = 16t²

and the height is 49ft

(a) Now when the diver hit the water the equation become

16t² = 49

t² = 49/16

t = ±7/4

t = ±1.75

since time can not be negative so t = 1.75

Therefore after t = 1.75 seconds the diver will hit the water.

(b)

Now differentiating d(t) with respect to t we get

d'(t) = 32t

now putting t=7/4 we get

the velocity d'(7/4) = 32*7/4

d'(7/4) = 56ft/s

Therefore the velocity the diver hit the water is 56 ft/s.

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The complete question is :

A cliff diver plunges from a height of 49ft above the water surface. The distance the diver falls in t seconds is given by the function d(t)=16t²ft

(a) After how many seconds will the diver hit the water?

(b) With what velocity (in ft/s ) does the diver hit the water?

The area of this triangle is 30 m².

Area is a surface measure, that is, it is the amount of space that a geometric figure occupies on a flat surface.

To calculate the area of a triangle, we can use the formula:

Area = (base x height) / 2

In the case of the given triangle, we can choose the measure of 5m as the base and the measure of 12m as the height, since the height forms a right angle with the base and is perpendicular to it.

So, we have:

Area = (b*h)/2

Area = (5m * 12m) / 2

Area = 30m²