The required mass in kg when the power output, time, height are given is 7.63 kg.
We know that, the formula for power output for a motor is
Power P = (m* g*h)/t
where,
m is the mass in kg
g is the acceleration due to gravity in m/s²
h is the height in m
t is the time in sec
Given that,
P = 187 W
g = 9.8 m/s²
h = 13 m
t = 5.2 s
m = ?
Making m as subject in the above equation, we get,
m = (P* t)/(g* h) = (187* 5.2)/(9.8* 13) = 7.63 kg.
Thus, the required mass in kg is 7.63 kg.
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based on its surface temperature of 6,000 k, most photons that leave the sun's surface lie in which region of the electromagnetic spectrum?
Most photons that leave the sun's surface have a surface temperature of 6,000 K, which corresponds to the visible light region of the electromagnetic spectrum.
The electromagnetic spectrum is a continuous range of wavelengths and frequencies that includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The wavelengths and frequencies of these different types of electromagnetic radiation are all different and correspond to different regions of the spectrum.
The visible light region of the electromagnetic spectrum is the portion of the spectrum that can be seen by the human eye. It ranges from about 400 nanometers (nm) to about 700 nm in wavelength, and corresponds to frequencies of about 7.5 x 10^14 Hz to about 4.3 x 10^14 Hz. Photons with wavelengths and frequencies in this range have enough energy to excite the photoreceptors in the human eye, allowing us to see them.
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Use the information and table to answer the following question! A skydiver dives from an airplane. air resistance is measured each second following the skydiver’s jump.
Time After Jump Weight Air Resistance
(seconds) Newtons (N) Newtons (N)
1 seconds 500N 200N
2 seconds 500N 300N
3 seconds 500N 400N
4 seconds 500N 500N
Which statement BEST identifies the skydiver's speed at each second?
a. The skydiver has the slowest speed at 2 seconds
b. The skydiver has the fastest speed at 4 seconds
c. The skydiver has the sloweat speed 1 second
d. The skydiver has the fastest speed at 3 seconds
The skydiver has the fastest speed at 4 seconds, and the correct statement is (b) "The skydiver has the fastest speed at 4 seconds".
To determine the skydiver's speed at each second, we need to consider the forces acting on the skydiver. In this case, the forces acting on the skydiver are the weight of the skydiver and the air resistance. The weight of the skydiver is constant at 500 N, while the air resistance increases with time.
According to Newton's second law of motion, the acceleration of an object is equal to the net force acting on it divided by its mass. In this case, the mass of the skydiver is not given, so we cannot calculate the acceleration directly.
Speed is the rate of change of displacement over time. In this case, the displacement of the skydiver is not given, so we cannot calculate the speed directly. However, we can use the information provided to determine the skydiver's speed at each second.
From the table, we can see that the air resistance increases with time, reaching a maximum of 500 N at 4 seconds. This means that the net force acting on the skydiver is greatest at 4 seconds, which would correspond to the highest acceleration and the fastest speed.
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what are the magnitude and location (with respective to point a) of the resultant force on the horizontal gate? the gate width is w. fluid density is r. you can leave your answer in terms of variables (w, r, and g).
The magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.
What is magnitude?Magnitude is a measure of the size or intensity of a physical quantity. It is usually defined as the absolute value of the numerical value of the physical quantity, and is often expressed in terms of a unit of measurement. Magnitude can refer to a variety of different physical quantities, such as size, intensity, brightness, or energy. Magnitude can also refer to the relative size or intensity of two or more physical quantities, when compared to each other.
The resultant force on the horizontal gate is equal to the sum of the hydrostatic forces acting on the gate.
Since the gate is horizontal, the hydrostatic forces acting on the gate will be equal to the pressure difference between the top and bottom of the gate.
This pressure difference is equal to the product of the fluid density, gravitational acceleration, and the gate width.
Therefore, the magnitude of the resultant force on the gate will be:
F = w * r * g
The location of the resultant force on the gate will be at the center of the gate, which is point A.
Therefore, the magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.
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an airplane flies horizontally at a speed of 351 km/h and drops a crate that falls to the horizontal ground below. neglect air resistance.part (a) if the altitude of the plane was 580 m, then how far, horizontally in meters, did the crate move as it fell to the ground?
Refer to the attached photos. I would appreciate a rate :)
a 9.00-kg hanging block (m2) is connected by a string over a pulley to a 5.00-kg block that is sliding on a flat table (m1). if the coefficient of kinetic friction is 0.200, find the tension in the string.
Kinetic friction coefficient is denoted with µ s. is given by; The Normal force has the same magnitude as the weight.
Newton’s second law for the 5.00kg mass gives
T–f k =(5.00kg)a
Similarly, for the 9.00−kg mass,
(9.00kg)g–T=(9.00kg)a
Adding these two equations gives:
(9.00kg)(9.80m/s −0.200(5.00kg)(9.80m/s
=(14.0kg)a
Which yields a=5.60m/s
2 . Plugging this into the first equation above gives
T=(5.00kg)(5.60m/s 2 )+0.200(5.00kg)(9.80m/s 2 )=37.8N
If the object or plane is inclined at an angle (), the normal force is: where m is the object's mass. And g denotes gravity's acceleration.
How do you find the coefficient of kinetic friction?The coefficient of kinetic friction is the ratio of the kinetic friction force of contacting surfaces to the normal force. Explore the definition and formula for the coefficient of kinetic friction, and learn from calculation examples for friction on an inclined plane.
This is important for understanding the coefficient of kinetic friction, which is the proportion obtained by dividing the pulling force by the pulling force.
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A student wants to make a simple model of the solar system to help him compare how long it would take for a spaceship to travel between different planets.
Which of the following things is essential for him to do in order to think about how long it would take?
this are the opions
He must make sure that the model of each planet looks like the planet it represents, but he does not need to accurately represent the relative distances between the planets because the most important thing is that models look like the thing they are modeling.
He must accurately represent the relative distances between the planets, but he does not need to make sure that the model of each planet looks like the planet it represents because only the relevant aspects of the thing being modeled need to be modeled accurately.
He must accurately represent the relative distances between the planets and also make sure that the model of each planet looks like the planet it represents, because a model should be as much like the thing being modeled as possible.
He does not need to accurately represent the relative distances between the planets, and he does not need to make sure that the model of each planet looks like the planet it represents, because there are always some differences between a model and the thing being modeled.
Answer:
To make a simple model of the solar system that can be used to compare the time it would take for a spaceship to travel between different planets, the student must accurately represent the relative distances between the planets. This is because the time it would take for a spaceship to travel between two planets depends on the distance between those planets, so accurately representing the distances between the planets is essential for thinking about how long it would take for a spaceship to travel between them.
It is not necessary for the student to make sure that the model of each planet looks like the planet it represents, although this may help make the model more understandable. The most important thing is that the model accurately represents the relative distances between the planets.
In summary, the student must accurately represent the relative distances between the planets in order to think about how long it would take for a spaceship to travel between different planets in the solar system.
40 POINTS HELPP
The Anthropocene is still considered an informal designation because International Union of Geological Sciences (IUGS), the international organization that names and defines epochs, has not officially designated it an epoch. Their criteria for the designation of a new epoch are that there should be evidence of human impacts and change in the rock record.
What activities and impact could humans be responsible for that might be reflected in the rock record and thus determine the beginning of the Anthropocene?
(Minimum of two sentences please)
Answer:
One example of an activity that could be reflected in the rock record and contribute to the beginning of the Anthropocene is the widespread use of fossil fuels, which has led to an increase in atmospheric carbon dioxide concentrations and a corresponding shift in the Earth's climate. Another potential contributor to the Anthropocene is the proliferation of plastic and other synthetic materials, which are becoming ubiquitous in the geologic record and may persist for thousands of years.
gravel is being dumped from a conveyor belt at a rate of cubic feet per minute. it forms a pile in the shape of a right circular cone whose base diameter and height are always the same. how fast is the height of the pile increasing when the pile is feet high? recall that the volume of a right circular cone with height and radius of the base is given by .
The fast is the height of the pile increasing when the pile is feet high 0.1989 ft/min.
Calculation:
Here given the rate of change in volume DV/DT = 40 actions and we need the rate of change in height when height h = 16.
Putting all values.
40 = π/4 x (16)² x DV/DT
= DV/DT= 40 x 4/ 1×16×16
0.1989 ft/min.
Rate of change in height when height is 16 H is equal to 0.1989 ft/min.
The goal is to get a text from as many modalities as possible so that models trained on The Pile have broader generalization capabilities. For stakes, experts believe it comes from the Latin word pira. Pila loosely translates to the ball. If you've ever seen inflamed hemorrhoid, you'll understand this moniker better. Many hemorrhoids actually look like small round spheres.
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a 7.00-kg mass is hung from the bottom end of a vertical spring fastened to an overhead beam. the object is set into vertical oscillations having a period of 2.60 seconds. what is the force constant of the spring?
The force constant of the spring is 42.1 m.
What is force?Force is a physical quantity that is related to the interaction between two objects. It is a vector quantity, meaning it has both magnitude and direction. Force can be thought of as a push or a pull between two objects. When one object exerts force on another object, the second object experiences an equal and opposite reaction force. Some of the most common examples of force include friction, gravity, electric fields, and magnetism. Force is a key concept in physics, as it is often used to explain the motion of objects and the behavior of physical systems.
The force constant, or spring constant, of the spring can be calculated using the equation:
k = (4π^2m)/T^2. In this equation, m is the mass of the object and T is the period of oscillation.
Therefore, the force constant of the spring is
k = (4π^2*7.00kg)/(2.60s)^2 = 42.1 N/m.
This means that if a 1 N force is applied to the spring, it will stretch by 42.1 m.
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a vertical spring has a spring constant of 100 n/m. when an object is attached to the bottom of the spring, the spring changes from its unstretched length of 0.50 to a length of 0.65 m. the magnitude of the weight of the object is
Answer: Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.Substituting the values in, we get:F=100*(0.65-0.5)=100*0.15=15N
while riding an open freight elevator upwards at 5.1 m/s, a carpenter drops his hammer off the side. it hits the ground 2.4 s later. how far above the ground was the carpenter when he dropped the hammer?
By making use of equations of motion, we get the Distance from the ground was the carpenter dropped the hammer is 16 m/s.
Given Parameters are
Initial Velocity (u) = 1.5 m/s
Time taken (t) = 2.4 seconds
The final velocity of the elevator after t sec of time can be calculated using one of the equations of motion, so, we have
v = u + at
Putting all the values, we get
v = 1.5 - (9.8)(2.4) = -18.42 m/s
Distance from the ground was the carpenter dropped the hammer is can be calculated using one of the equations of motion,
[tex]v^{2} = u^{2} + 2gh\\\\h = \frac{v^{2}-u^{2} }{2g} \\\\h =\frac{(-18.42)^{2} -(5.1)^{2} }{2(9.8)} = 16 m/s[/tex]
Resolve the cat speed into components,
[tex]v_{x} = (7m/s) cos 49 = 4.59 m/s\\v_{y} = ( 7 m/s ) sin 49 = 5.28 m/s[/tex]
Cat speed with respect to dog is
[tex]v = \sqrt{v_{x} ^{2} - (v_{y} -v_{d} )^{2} } = \sqrt{(4.59)^{2} +(5.28 - 2.4)^{2} } = 5.42 m/s[/tex]
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the leaning tower of pisa is 55 m high and 7.0 m in diameter. the top of the tower is displaced 4.5 m from the vertical. how much more would the top have to be displaced for the tower to be on the verge of tipping? assume the tower is a uniform cylinde
Two parallel circular bases and a curving surface define a cylinder. The height of the cylinder is equal to the angle between the two bases.
What do you meant by uniform cylinde?A cylinder is a three-dimensional solid figure with two identical circular bases connected at a specific distance from the center, which determines the cylinder's height, by a curving surface. Examples of cylinders in real life are toilet paper rolls and beverage cans.
Geometrically speaking, a cylinder is a three-dimensional shape. A cylinder is circular and has a top and bottom with a circled shape. Both the top and bottom are flat and identical in size.
One of the most fundamental curvilinear geometric shapes is the cylinder (from the Greek letter o, romanized as kulindros, meaning "roller" or "tumbler"). It is referred to as a prism with a circle as its base in elementary geometry.
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a uniform thin rod of length 0.50 m and mass 4.0 kg can rotate in a horizontal plane about its center. a 3.0 gram bullet hits the end of the rod (initially at rest) at an angle of 60 degrees and imbeds in the rod. if the angular speed of the rod is 10. rad/s after the bullet strikes, what is the speed of the bullet before it strikes the rod?
The speed of the bullet before it strikes the rod is 67 m/s. To determine the speed of the bullet before it strikes the rod, we need to consider the conservation of angular momentum.
The moment of inertia of a thin rod about its center is given by the following formula:
I = (1/3) * m * L^2where I is the moment of inertia, m is the mass of the rod, and L is the length of the rod.
Substituting the values given in the problem, we find that the moment of inertia of the rod is
(1/3) * 4.0 kg * (0.50 m)^2 = 0.67 kg*m^2.In this case, the bullet strikes the rod, transferring some of its linear momentum to the rod in the form of angular momentum. The change in angular momentum of the rod is equal to the angular momentum of the bullet.
We can use the conservation of angular momentum to write the following equation:
I1 * w1 + J = I2 * w2where I1 is the initial moment of inertia of the rod, w1 is the initial angular velocity of the rod, J is the angular momentum of the bullet, I2 is the final moment of inertia of the rod, and w2 is the final angular velocity of the rod.
Since the initial angular velocity of the rod is zero, we can simplify the equation as follows:
J = I2 * w2
Substituting the values given in the problem, we find that the angular momentum of the bullet is
0.67 kgm^2 * 10 rad/s = 6.7 kgm^2/s.To determine the speed of the bullet before it strikes the rod, we need to consider the bullet's mass and the angle at which it strikes the rod. The mass of the bullet is given as 3.0 grams, which is equivalent to 0.003 kg. The angle at which the bullet strikes the rod is given as 60 degrees.
We can use the following formula to calculate the speed of the bullet before it strikes the rod:
v = (J/m) * sin(theta)Substituting the values given in the problem, we find that the speed of the bullet before it strikes the rod is (6.7 kg*m^2/s / 0.003 kg) * sin(60 degrees) = 67 m/s. This is the final answer.
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compared to radio waves, the velocity of visible light waves in a vacuum is a. less. b. more. c. the same.
In a vacuum, all light goes at the same speed, with no concern about the wavelength or frequency. As we move from gamma rays to radio waves, the frequency drops, and wavelength rises, thereby keeping the product constant. So, velocity is the same but wavelength is changed.
The speed of radio waves and the speed of visible light are exactly the same. Both of them travel at a speed of 3×108 3 × 10 8 meters per second in a vacuum. The visible light that we see with our eyes is a type of electromagnetic radiation.
Light travels at approximately 300,000 kilometers per second in a vacuum, which has a refractive index of 1.0, but it slows down to 225,000 kilometers per second in water (refractive index of 1.3; see Figure 2) and 200,000 kilometers per second in glass
In the vacuum, the light of different colours travels with the same speed. But in mediums like water, light travel with different speeds. In a glass, the red light travels the fastest and the violet light travels the slowest of all the seven colours.
It isn't losing energy; it isn't changing its fundamental, intrinsic properties; it isn't transforming into anything else. All that's changing is the space around it. When that light exits the medium and goes back into vacuum, it goes back to moving at the speed of light in vacuum: 299,792,458 meters per second.
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A car travels down a road at a certain velocity, vcar. The driver slows down so that the car is traveling only a third as fast as before. Which of the following is the correct expression for the resulting velocity?
a. 2vcar
b. 1/3vcar
c. -1/2vcar
d. -2vcar
The correct expression for the resulting velocity is -1/2 vcar. The correct option is c.
What is velocity?
The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.
A car travels down a road at a certain velocity, is Vcar.
Let the initial velocity of the car travel downward be -V car
It is also, given, that the driver slows down so that the car is traveling only half as fast as before.
Resulting velocity = -1/2 vcar
Therefore, the correct option is c. -1/2vcar.
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A 100 kg car starts from 20 m/s and speeds up to 41 m/s in 7 seconds. Determine the car's
acceleration.
Answer: 3 m/s^2
Explanation:
Acceleration equals change in velocity (speed) divided by total time.
a = (v2-v1)/t
a = (41 m/s - 20 m/s) / 7 s
a = 3 m/s^2
Mass is irrelevant in this question.
Which choice below explains what is happening in a liquid as it turns into a gas?
a. The particles speed up and spread apart
b. The particles speed up and come closer together
c. The particles slow down and spread apart
d. The particles slow down and come closer together
Answer:
a
Explanation:
As you add thermal energy the particles spread apart and are moving faster ..... a certain volume of water produces a much larger volume of steam as energy is added.....that is how steam engines work !
a simple pendulum is 4.00 m long. (a) what is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 6.00 m/s2?
The time period of the small oscillations for the simple pendulum is found to be 3.14 seconds.
The pendulum is located in an elevator that is accelerating upwards with an acceleration of 6m/s² and length of the pendulum is 4m.
Because the elevator is accelerating in the upper direction the net acceleration of the pendulum will be (10 + 6)m/s².
The period of small accelerations for this pendulum will be given by the relation,
T = 2π(l/a)
Where, l is the length of pendulum and a is the net acceleration.
Putting values,
T = 2π(4/16)
T = 2π(1/2)
T = π seconds.
T = 3.14 seconds.
So, the time period of this small oscillations for this pendulum is 3.14 second.
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consider the harmonic oscillator with dynamics written as with parameters . if the initial position and velocity of the oscillator are given by , what is the position of the oscillator at seconds?
The position of the oscillator at seconds is ( A cos ( ω t + ϕ ) where A is the amplitude and ϕ is the initial phase and f = 1/T = ω/2π.
What is the mean position in oscillation?Equilibrium or Mean Position: It is a state in which the body is in when there is no net force pushing against it. When a particle is oscillating, it is in its phase This is a representation of the particle's vibrational state at a particular instant.
Is the oscillation period measured in seconds?The period of an oscillating system is the length of time it takes for a cycle to be completed. A system's period is a time measurement, and in physics, it's typically represented by the capital letter T. Although seconds are the most common, period is measured in time units relevant to that system.
What is the equation for an oscillating period?Time, or T, is the oscillation's period, hence ωT = 2π or T = 2π/ω. The formula f = 1/T = ω/2π. gives the reciprocal of the period, or the frequency f, in oscillations per second.
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what is the current through the heating element of an electric toaster oven if the heater has a resistance of 5 ohms and it is connected to 120 volts?
Answer:
24 A
Explanation:
Ohm's Law: V = IR, so I = V/R
I = 120V/5Ω = 24 A
How to be good at basketball
Answer: Practice Makes Perfect
Explanation:
First, you would want to exercise:
Warmups:
Stretch:
10 Toe Touches10 Run Poses with each leg in front one at a time.Stretch your arms for 10 secondsDo these every day:
15 push-ups25 Jumping JacksJog for 10 minutes10 Sit-upsThen:
100 Dribbles50 shots5 laps around the whole court25 layups running from 3-pointDo these in a month, and you will improve a lot in basketball.
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which is a major difference between what we've seen in discovered exoplanets and our own solar system?
The major difference between what we've seen in discovered exoplanets and our own solar system is that extrasolar planet orbits tend to be closer and more eccentric than in our Solar System.
Exoplanet:
Any planet outside of our solar system is an exoplanet. The majority of exoplanets orbit other stars, while rogue planets—free-floating exoplanets that are unattached to any star—orbit the galactic center.
All of the planets in our solar system orbit around the Sun. Planets that orbit around other stars are called exoplanets.
Exoplanets are very hard to see directly with telescopes. They are hidden by the bright glare of the stars they orbit.
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suppose a woman does 550 j of work and 9800 j of heat transfer occurs into the environment in the process. (a) what is the decrease in her internal energy (in kcal), assuming no change in temperature or consumption of food? (that is, there is no other energy transfer.) -10350 kcal (b) what is her efficiency (in percent)? %
W = -500 J is the work, which is why it's negative because a woman is doing it.
Briefing
The heat transfer into the system,
Q = 9500 J, makes it positive.
(a) Heat and work are added to determine the change in internal energy, which is:
ΔU = Q+W
We replace with:
ΔU = 9500 J-500 J
ΔU = 9000 J\s(b) (b) The quantity of useful work completed given a total energy supply is now what is generally referred to as an efficiency. From this, we may divide the woman's labour by the shift in internal energy, giving us
= 500 j / 9000 j.
We get:
ϵ = 0.0556~ 5.56%
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questions 10-11 refer to a ball that is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. the ball rises to a height equal to the asteroid's radius and then falls straight down toward the surface of the asteroid. 10. what forces, if any, act on the ball while it is on the way up?
Only a decreasing gravitational force that acts downward will apply on the ball that is tossed straight up from the surface of a small, spherical asteroid with no atmosphere.
What is gravitational force?All physical things with mass are drawn to the gravitational force, which can be thought of as an attracting force. It is the known natural force that is by far the weakest.The gravitational force, which is what pushes mass-containing objects toward one another. We frequently consider the pull of gravity from the Earth. Your body is kept on the ground by this force. However, all mass-bearing objects are pulled toward each other by gravity.
Hence,
Only a decreasing gravitational force that acts downward will apply on the ball that is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. The ball rises to a height equal to the asteroid's radius and then falls straight down toward the surface of the asteroid.
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1.
KNOW the UNITS!!!!!! SHOW YOUR WORK
What is the net force exerted on a 150.0kg race-car driver while the race car is accelerating from 0 to 58.7m/s i
3.50s?
Answer:
2515.7N
Explanation:
First step is to find the acceleration:
U = 0 and V =58.7 m/s
a = (V-U)/t
where, t = 3.5s
a = 58.7/3.5
so, in order to find the net force,
F= ma
= 150kg × 58.7/3.5
= 2515.7 N
A heavy piece of hanging sculpture is suspended by a 90 cm long 5.0 g steel wire. When the wind blows hard, the wire hums at its fundamental frequency of 95 Hz.What is the mass of the sculpture?
According to the given statement 16.7kg is the mass of the sculpture.
What is a fundamental frequency in physics?The lowest frequency that could be produced by a particular instrument is known as the fundamental frequency. The fundamental frequency is also known as the instrument's first harmonic.
Briefing:Use the string's tautness' fundamental frequency as a formula.
f = (1/2L)*√(T/μ) .... (Eqn1)
Where
f= frequency in Hertz =80Hz
T = The string's tension equals Mg.
M is a symbol for the substance's mass (sculpture)=?
g= 9.8m/s^2
L= Length of the string=90cm=0.9m
μ= string length divided by mass gives the string's density.
mass of string =5g=0.005kg
L=0.9m
μ=0.005/0.9 = 0.0056kg/m
Using (Eqn1)
95= 1/(2*0.9) √(T/0.0056)
171= √(T/0.0056)
Square both sides
29241= T/0.0056
T= 163.74 N
Recall that T =Mg
163.74= M * 9.8
M=163.74/9.8
M= 16.7kg
Consequently, the sculpture weighs 16.7kg.
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light is projected onto a semi-conductive surface. however, no electrons are ejected. if the intensity is held constant but the frequency of light is increased, what will happen?
When the intensity of light is constant, but its frequency is increased, then the number of photons emitted will also increase.
The electrons are emitted from a conductive material when light of sufficient frequency strikes it and causes vibration of electron holes pairs present inside the material. This conductive motion causes the electricity to be generated. There is a minimum frequency which must be reached so that electrons are emitted from the surface. This frequency is called as threshold frequency. Photons are energy packets. The formula which relates energy with frequency is given as:
E = hv,
where, E = energy of photon
h = Planck's constant
v = frequency
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the rope-and-pulley system of negligible mass shown above supports a block of weight w that is at rest. if the tension throughout the rope is uniform, what is the reading on the spring scale?
The rope-and-pulley system of negligible mass shown above supports a block of weight w that is at rest. if the tension throughout the rope is uniform.
To determine the reading on the spring scale, we can apply Newton's Second Law of Motion to the block of weight w. The net force on the block is equal to the block's mass times its acceleration: F net = ma The only force acting on the block is the force of gravity, which is equal to the weight of the block: F net = F gravity = w The acceleration of the block is zero, since it is at rest: w = ma = m * 0 . This equation tells us that the force of gravity on the block is zero, which means that the block is in equilibrium and the tension in the rope is zero. Therefore, the reading on the spring scale is zero.
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Answer:
W/2
Explanation:
The original question does not include a diagram which is necessary for answering the question.
The diagram shows a spring scale attached to the ceiling. Below the spring, 2 pulleys are attached, holding the block at 2 separate points. As a result, there will be 4 ropes (2 attached to the spring scale, and 2 to the ceiling).
Because the tension is dispersed evenly among the 4 points, we can say that the scale will only read half the weight as the rest of the tension will be held by the ceiling.
Therefore, the spring scale will read W/2
I wish that I can upload the diagram, but unfortunately, I cannot. I assume that you will have access to the diagram.
Hope this helped!
newton's second law in 1 dimension: what magnitude net force is required to accelerate a 1200-kg car uniformly from 0 m/s to 27.0 m/s in 10.0 s?
The required force is F = 3240 N.
As a result,
1200 kg is the car's mass.
Initial speed of the vehicle, u = 0.
The car's final speed is 27 meters per second.
Thus we have to first calculate the acceleration and then substitutes its value in the force formula
Taking time, t = 10 s
F = m a, where a represents the vehicle's acceleration, is the formula for the required force.
a= v - u / t
thus a = 27 - 0/ 10
a = 27/ 10
F = 1200 X 27 / 10
F = 3240 N.
Therefore, this is the necessary solution.
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boat moves north at a velocity of 2.5 m/s while the current moves downstream at 6.0 m/s east. What is the resultant velocity of the boat, relative to an observer on the shore?
A) 4.5 m/s, NE
B ) 4.5 m/s, SE
C ) 6.5 m/s, NE
D ) 6.5 m/s, SE
E) 8.5 m/s, NE
Relative to the observer in on the shore, the velocity of the boat is 6.5 m/s, NE.
What is relative velocity?
The velocity of an object in relation to another observer is known as its relative velocity.
We cay say that the relative velocity is equal to the vector difference between the velocities of two objects. The relative velocity of A with respect to B= velocity of the body A – velocity of the body B.
The diagram below shows the calculation where AC is relative speed, AB is speed of the boat and BC is the speed of stream.
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