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Answer:
59, 56, 53, 50
Step-by-step explanation:
Use n = 1 through 4 and evaluate.
a1 = 59 -3(0) = 59
a2 = 59 -3(1) = 56
a3 = 59 -3(2) = 53
a4 = 59 -3(3) = 50
The first four terms are 59, 56, 53, 50.
A journal article reports that 34% of fathers take no responsibility for child care. A group of fathers believes that this estimate is too high. In a random sample of 80 fathers, it was found that 23 of those fathers take no responsibility for child care. Is there significant evidence at the 1% significance level that less than 34% of fathers take no responsibility for child care
Answer:
The p-value of the test is 0.1611>0.01, which means that there is not significant evidence at the 1% significance level that less than 34% of fathers take no responsibility for child care
Step-by-step explanation:
A journal article reports that 34% of fathers take no responsibility for child care. A group of fathers believes that this estimate is too high.
At the null hypothesis, we test if the proportion is of at least 34%, that is:
[tex]H_0: p \geq 0.34[/tex]
At the alternative hypothesis, we test if the proportion is less than that, that is:
[tex]H_1: p < 0.34[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
0.34 is tested at the null hypothesis:
This means that [tex]\mu = 0.34, \sigma = \sqrt{0.34*0.66}[/tex]
In a random sample of 80 fathers, it was found that 23 of those fathers take no responsibility for child care.
This means that [tex]n = 80, X = \frac{23}{80} = 0.2875[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{0.2875 - 0.34}{\frac{\sqrt{0.34*0.66}}{\sqrt{80}}}[/tex]
[tex]Z = -0.99[/tex]
P-value of the test and decision:
The p-value of the test is the probability of finding a sample proportion below 0.2875, which is the p-value of Z = -0.99.
Looking at the Z-table, Z = -0.99 has a p-value of 0.1611.
The p-value of the test is 0.1611>0.01, which means that there is not significant evidence at the 1% significance level that less than 34% of fathers take no responsibility for child care
What would be the correct answer for this
Answer:
The answer is B
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
0.99218
Match the system of linear equations, to its graph.
Answer:
The answer is the second graph, Option 2
A car travels 22 km due south and
then 28 km in a direction 60° east of
south. Find the magnitude of the
car's resultant vector.
Answer:
Step-by-step explanation:
elimination was used to solve a system of equations. one of the intermediate steps led to the equation 2x= 8. which of the following systems could have led to this equation?
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Answer:
C
Step-by-step explanation:
The step shown indicates that y was eliminated from the equations. For choices A, B, D, this is done by adding the equations together (the y-coefficients are opposites). The result of doing that gives x-terms of 4x, 0x, and 0x, respectively. These x-terms do not match the one given: 2x.
For choice C, the y-term is eliminated by subtracting twice the second equation from the first. Doing that gives ...
(4x +2y) -2(x +y) = (14) -2(3)
4x +2y -2x -2y = 14 -6 . . . . eliminate parentheses
2x = 8 . . . . . . . . . . . . . . collect terms
GIVING OUT BRAINLIEST HELP MEEE PLSS!!
Answer:
x=7
Step-by-step explanation:
take 30 degree as reference angle
using sin tan rule
tan 30=opposite/adjacent
[tex]\frac{1}{\sqrt{3} }[/tex]=x/[tex]7\sqrt{3}[/tex]
[tex]\frac{1}{\sqrt{3} }[/tex] *[tex]7\sqrt{3}[/tex]
[tex]7\sqrt{3} /\sqrt{3}[/tex]
7=x
which net represents the pyramid with the greatest surface area
Answer:
the top one that's orange
How many 1/6 cup servings of. Rice are in 2/3 cup of rice
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Answer:
4
Step-by-step explanation:
2/3 = 4/6
There are four 1/6-cup servings of rice in 4/6 cups of rice.
Find Use proportion
24 =18/15
21
b
18
20
16
Answer:
Step-by-step explanation:
I need help with this question I wanna say the answers B
Answer:
hi, yes the option B is the correct answer
A college savings account pays 8.2% annual interest compounded semiannually. What is the balance of an account after 12 years if $21,000 was initially deposited?
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Answer:
$55,085.44
Step-by-step explanation:
The formula for the account balance is ...
A = P(1 +r/n)^(nt)
where principal P is invested at annual rate r compounded n times per year for t years. Using the given values, we find the balance to be ...
A = $21,000(1 +0.082/2)^(2·12) = $21,000(1.041^24) ≈ $55,085.44
The balance is $55,085.44 after 12 years.
You buy a used car for $9,000. The car depreciates 9% per year. Find the value of the
car after 10 years.
Answer:
$19,000.Step-by-step explanation:
#hopeithelpsbrainliest me.what is the row of sum 8192 in Pascal's triangle?
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Answer:
row 13
Step-by-step explanation:
The sum of row n is 2^n, so the row number with a particular sum is ...
2^n = sum
n·log(2) = log(sum)
n = log(sum)/log(2)
The row with sum 8192 is ...
n = log(8192)/log(2) = 13
The row of Pascal's triangle that has a sum of 8192 is row 13.
Find the median and mean of the data set below:
10, 43, 20, 11
Which system of equations represents the matrix shown below?
Answer:
c
Step-by-step explanation:
Consider two x distributions corresponding to the same x distribution. The first x distribution is based on samples of size n = 100 and the second is based on samples of size n = 225. Which x distribution has the smaller standard error?
Answer:
Hence the correct option is the distribution with n = 225 will have a smaller standard error.
Step-by-step explanation:
Now the standard deviation is
[tex]S.E=\frac{\sigma }{\sqrt{n}}[/tex]
If n = 100 then consider [tex]\sigma =6[/tex]
[tex]S.E=\frac{6}{\sqrt{100}}=0.6[/tex].
If n= 225 then consider [tex]\sigma =6[/tex]
[tex]S.E=\frac{6}{\sqrt{225}}=0.4[/tex].
Here the distribution with n = 225 will have a smaller standard error.
A stadium's normal ticket price is $78. As a special promotion they offer 15% off. What is the price of the discounted
ticket?
Answer:
$66.3
Step-by-step explanation:
price of a ticket without discount = $78
discount % = 15%
discount amount = ?
price of a discounted ticket = ?
discount amount = discount% of price of a original ticket
=15/100 * $78
=$1170/100
=$ 11.7
price of the discounted ticket = $78 - $11.7
=$66.3
The discounted price of the stadium's normal ticket is $66.3
What is the percentage?A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.
Given, A stadium's normal ticket price is $78 and As a special promotion they offer 15% off.
Therefore, The discounted price of the ticket should be (100 - 15)% = 85% of the original price which is,
= (85/100)×78.
= $66.3 is the discounted price.
learn more about percentages here :
https://brainly.com/question/24159063
#SPJ6
Determine whether the sampling method described below appears to be sound or is flawed. In a survey of 511 human resource​ professionals, each was asked about the importance of the age of a job applicant. The survey subjects were randomly selected by pollsters from a reputable market research firm.
a) it is flawed because it is a census.
b) it is flawed because it is not statistically significant.
c) it appears to be sound because the data are not biased in anyway.
d) it is flawed because it is a voluntary response sample.
Answer:
c) it appears to be sound because the data are not biased in anyway.
Step-by-step explanation:
From the information given regarding the sample selection method , the size, the larger sample from which the survey subject were selected, we can conclude that the data is sound and not in anyway biased. The subject were selected from a reputable market research firm, which means the subjects were chosen from a larger sample which is reliable and not just a voluntary pool of subjects. Also, the selection process is randomized. Based on these, there are no flaws which are likely to cause the introduction of bias into the sample selected. Hence, the data is sound and not in any way biased.
Nathaniel has $2 worth of dimes and quarters. He has 6 more dimes than quarters. By following the steps below, determine the number of dimes,x, and the number of quarters,y, that Nathaniel has.
Determine three ways to have 6 more dimes than quarters:
Answer:
10 dimes and 4 quartersStep-by-step explanation:
Number of dimes = d, each d = 10 cNumber of quarters = q, each q = 25 cTotal = $2 = 200 cEquations according the given:
10d + 25q = 200d = q + 6Solve for q by substitution:
10(q + 6) + 25q = 20010q + 60 + 25q = 20035q = 140q = 140/35q = 4Find the value of d:
d = 4 + 6 = 10Nathaniel has 10 dimes and 4 quarters
[tex]\frac{(csc x+1)(csc x-1)}{csc^2x}\\[/tex]
cscθ·cos^2θ+sinθ= cscθ
Step-by-step explanation:
[tex]\frac{( \csc x+1)( \csc x-1)}{ \csc ^2x} = \frac{ { \csc }^{2} x - 1}{ \csc^{2} x} \\ = 1 - \sin^{2} x = \cos^{2} x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
b. Since csc theta = 1/sin theta, we can multiply both sides by sin theta and you will end up with
[tex] \cos^{2} \theta + \sin^{2} \theta = 1[/tex]
which is an identity.
Need help practice problem please
Answer:
I think there is no solution.
Step-by-step explanation:
Substitute:
Z = -3y-5x+25
X = 3y-2z-13
Put into the last formula:
14(3y-2z-13)-2y+3(-3y-5x+25) = 48
Then:
14(3y-2(-3y-5x+25)-13)-2y+3(-3y-5(3y-2z-13)) = 48
So:
14(3y-2(-3y-5(3y-2z-13)+25)-13)-2y+3(-3y-5(3y-2(-3y-5x+25)-13)) = 48
And so on.
What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE
Given:
The equation of a line is:
[tex]2y+3x=10[/tex]
The line is dilated by factor 3.
To find:
The result of dilation.
Solution:
The equation of a line is:
[tex]2y+3x=10[/tex]
For [tex]x=0[/tex],
[tex]2y+3(0)=10[/tex]
[tex]2y+0=10[/tex]
[tex]y=\dfrac{10}{2}[/tex]
[tex]y=5[/tex]
For [tex]x=2[/tex],
[tex]2y+3(2)=10[/tex]
[tex]2y+6=10[/tex]
[tex]2y=10-6[/tex]
[tex]2y=4[/tex]
Divide both sides by 2.
[tex]y=\dfrac{4}{2}[/tex]
[tex]y=2[/tex]
The given line passes through the two points A(0,5) and B(2,2).
If the line dilated by factor 3 with origin as center of dilation, then
[tex](x,y)\to (3x,3y)[/tex]
Using this rule, we get
[tex]A(0,5)\to A'(3(0),3(5))[/tex]
[tex]A(0,5)\to A'(0,15)[/tex]
Similarly,
[tex]B(2,2)\to B'(3(2),3(2))[/tex]
[tex]B(2,2)\to B'(6,6)[/tex]
The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-15=\dfrac{6-15}{6-0}(x-0)[/tex]
[tex]y-15=\dfrac{-9}{6}(x)[/tex]
[tex]y-15=\dfrac{-3}{2}x[/tex]
Multiply both sides by 2.
[tex]2(y-15)=-3x[/tex]
[tex]2y-30=-3x[/tex]
[tex]2y+3x=30[/tex]
Therefore, the equation of the line after the dilation is [tex]2y+3x=30[/tex].
A school cafeteria wants to survey a random sample of 50 students about the quality of food. During one lunch period, every 5th student who walks through the cafeteria door is surveyed until 50 students are selected. Which of the following statements is true about this sample?
Answer:
B
Step-by-step explanation:
Answer:
B EDGE
Step-by-step explanation:
In ABC, c=66,m∠A=3230', and m∠C=11140'. Find the length of side a to the nearest tenth.
g(x)=x²+5
.
Find g(a+1)-g(a-1)
Answer:
g(a + 1) - g(a - 1) = 4a
Step-by-step explanation:
g(x) = x^2 + 5,
when x = a+1, g(a+1) = (a+1)^2 + 5.
when x = a-1, g(a-1) = (a-1)^2 +5.
g(a+1)-g(a-1) = (a+1)^2 + 5 - [(a-1)^2 + 5]
= a^2 + 2a + 1 + 5 - [a^2 - 2a + 1 + 5]
= 4a
Find the equation of a line perpendicular to x+5y=−2 that contains the point (3,0).
Perpendicular Definition:
[tex] \large \boxed{m_1m_2 = - 1}[/tex]
Slopes of two different equations multiply each others and must equal to -1. We can also say that the perpendicular occurs only if both equations are negative reciprocal to each others. For example, we are given the equation of y = 2x. The perpendicular to y = 2x would be y = (-1/2)x. See how both are reciprocal to each others.
From the equation below:
[tex] \large{x + 5y = - 2}[/tex]
Since the equation is in the form of Ax+By = C. It is better to use the another slope formula which is:
[tex] \large \boxed{m = - \frac{A}{B} }[/tex]
From the equation above, use the slope formula to find the slope.
[tex] \large{m = - \frac{1}{5} }[/tex]
Therefore the equation has a slope of -1/5. Next to find the perpendicular equation to the original equation. Since our slope is -1/5 - that means the negative reciprocal of -1/5 is 5. Therefore the slope of perpendicular line is 5.
Next we will be using the point-slope form below:
[tex] \large \boxed{y - y_1 = m(x - x_1)}[/tex]
Given the y1 and x1 or (x1,y1) are the points. Our perpendicular slope is 5 which passes through the point (3,0). Substitute both slope and the point in.
[tex] \large{y - 0 = 5(x - 3)}[/tex]
Simplify in the slope-intercept form as we get:
[tex] \large{y = 5x - 15}[/tex]
Answer
y = 5x-15 is perpendicular to x+5y = -2Hope this helps and let me know if you have any doubts!
2. The set {0,1,-1} is closed under the operation of?
When do creative people get their best ideas? USA Today did a survey of 966 inventors (who hold U.S. patents) and obtained the following information.
Time of Day When Best Ideas Occur
Time Number of Inventors
6 A.M.-12 noon
12 noon-6 P.M.
6 P.M.-12 midnight
12 midnight-6 A.M. 295
138
311
222
Assuming that the time interval includes the left limit and all the times up to but not including the right limit, estimate the probability that an inventor has a best idea during each time interval: from 6 A.M. to 12 noon, from 12 noon to 6 P.M., from 6 P.M. to 12 midnight, from 12 midnight to 6 A.M. (Enter your answers to 3 decimal places.)
6AM-12PM 12PM-6PM 6PM-12AM 12AM-6AM
Answer:
[tex]P(6am-12\ noon) = 0.305[/tex]
[tex]P(12\ noon - 6pm) = 0.143[/tex]
[tex]P(6pm-12\ midnight) = 0.322[/tex]
[tex]P(12\ midnight - 6am) =0.230[/tex]
Step-by-step explanation:
Given
[tex]\begin{array}{cc}{Time} & {Inventors} & {6am - 12\ noon} & {295} & {12\ noon -6pm} & {138} & {6pm - 12\ midnight} & {311} & {12\ midnight - 6am} & {222} & {Total} & {966} \ \end{array}[/tex]
Required
The probability of each time interval
To do this, we simply divide the number of inventors in the interval by the total inventors (966)
So, we have:
[tex]P(6am-12\ noon) = \frac{6am-12\ noon}{Total}[/tex]
[tex]P(6am-12\ noon) = \frac{295}{966}[/tex]
[tex]P(6am-12\ noon) = 0.305[/tex]
[tex]P(12\ noon - 6pm) = \frac{12\ noon - 6pm}{Total}[/tex]
[tex]P(12\ noon - 6pm) = \frac{138}{966}[/tex]
[tex]P(12\ noon - 6pm) = 0.143[/tex]
[tex]P(6pm-12\ midnight) = \frac{6pm-12\ midnight}{Total}[/tex]
[tex]P(6pm-12\ midnight) = \frac{311}{966}[/tex]
[tex]P(6pm-12\ midnight) = 0.322[/tex]
[tex]P(12\ midnight - 6am) =\frac{12\ midnight - 6am}{Total}[/tex]
[tex]P(12\ midnight - 6am) =\frac{222}{966}[/tex]
[tex]P(12\ midnight - 6am) =0.230[/tex]
8,11,14,17 and you have to find the 74th term
Answer:
227 is the 74th term of your question.
A triangular prism has a base area of 12 square centimeters, and a height of 15 centimeters. What is the volume?
