Step-by-step explanation:
1. draw the parallelogram with side 20cm and 25cm respectively and also the diagonal as well.
2.Clearly it forms a triangle in the parallelogram with three known lengths of side.
3.Using the cosine rule : c^2=b^2+c^2 -2bc cos c to find the obtuse angle.
9514 1404 393
Answer:
114.8°
Step-by-step explanation:
The angles can be found using the Law of Cosines. It tells you ...
c² = a² +b² -2ab·cos(C)
Then angle C can be found to be ...
C = arccos((a² +b² -c²)/(2ab)) = arccos((20² +25² -38²)/(2·20·25))
C = arccos(-419/1000) ≈ 114.77°
The measure of the obtuse angle is about 114.8°.
What is the sum of the interior angles of a regular polygon with 13 sides?
giving 20 points!!
Answer:
1980
Step-by-step explanation:
13 sides
Number of sides n=13
The sum of interior angles of polygon =(2n−4)×90o
=(2×13−4)×90o
=(26−4)×90o
=22×90o
We get,
=1980
I need help finding y
to solve for y, we must multiply by t on both side to get ride of the t in the denominator. By doing this, we will get:
[tex] {t}^{3} [/tex]
on the right side.
Subtracting 3, and we have successfully isolated y.
It would be impossible to get a quantitative value for y if we don't know the value of t.
respuesta listsdafddfssdffd
Look at this rectangular prism:
If the height is quadrupled, then which of the following statements about its volume will be true?
Answer:
the new volume Will be 4 times the old volume
Step-by-step explanation:
I have put the photo 3
Find the area of the shaded region.
8 in
24 in
Answer:
96 in^2
Step-by-step explanation:
area of rectangle: 24*8=192
Area of triangle: (1/2)*base*height
= .5 * 8 * 24
=192/2
=96
area of shaded=rectangle - triangle
= 192-96
which is also just 192/2
so it is 96
what is the length of the third side triangle?
Answer:
x = 8cm
Step-by-step explanation:
17² = 15² + x²
289 = 225 + x²
- x² = 225 - 289
x² = 64
x = √64
x = 8
Good Luck! :)[tex]{ \boxed{ \sf \color{blue}{answer}}}[/tex]
x = 8 cm
Step-by-step explanation:
17² = 15² + x²
289 = 225 + x²
x² = 225 - 289
x² = 64
x = √64
x = 8
___________________Teorema pythagoras
Which of the following is a monomial?
9/x and 20x⁹ are the monomials.
The correct option A and D.
What is a polynomial?An expression that consists of variables, constants, and exponents that is combined using mathematical operations like addition, subtraction, multiplication, and division is referred to as a polynomial.
A monomial is a polynomial with just one term.
From the given choices:
9/x and 20x⁹ are the monomials.
11x - 9 and 20x⁹ -7x are the binomial.
Therefore, A and D are the monomials.
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A boat travels 12 km upstream and 40 km downstream in 8 hours. It can go 16 km upstream and 32 km downstream in the same time. Find the speed of the boat in still water and the speed of the stream.
the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h
Let's define the variables:
B = speed of the boat in still water.
S = speed of the stream.
When the boat travels downstream, the total speed of the boat will be equal to the sum of the speed of the stream and the speed of the boat in still water:
speed = B + S
When the boat goes downstream, the speed will be:
speed = B - S
Now, also remember the relation:
speed*time = distance.
The given information is:
In 8 hours the boat can:
go 12 km upstream and 40km downstream.
We now need to define another variable, T, as the time that the boat travels upstream.
Then we can write this as:
12km = (B - S)*T
If the boat travels T hours upstream, and travels for a total of 8 hours, then the amount of time that travels downstream is 8h - T, then we can write:
40km = (S + B)*(8h - T)
Similarly, when we have:
"it can go 16 km upstream and 32 km downstream in the same time."
we can define a new variable T', and write:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
Then we have a system of 4 equations:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
40km = (S + B)*(8h - T)
12km = (B - S)*T
And we need to solve this for S and B.
To do it, we need to isolate one of the variables in one of the equations.
Let's isolate T in the last equation:
T = 12km/(B - S)
now we can replace that in the third equation to get:
40km = (S + B)*(8h - 12km/(B - S))
So now we have 3 equations:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
40km = (S + B)*(8h - 12km/(S - B))
Now we need to do the same thing, this time let's isolate T' in the first equation and replace it in the second one:
T' = 16km/(B - S)
Replacing it in the second equation we get:
32km = (S + B)*(8h - T')
32km = (S + B)*(8h - 16km/(B - S))
So now we have two equations:
40km = (S + B)*(8h - 12km/(B - S))
32km = (S + B)*(8h - 16km/(B - S))
Let's simplify these:
40km = 8h*(S + B) - 12km*(S + B)/(B - S)
32km = 8h*(S + B) - 16km*(S+ B)/(B - S)
Now we can multiply both equations by (B - S) to get:
40km*(S - B) = 8h*(S + B)*(B - S) - 12km*(S + B)
32km*(S - B) = 8h*(S + B)*(B - S) - 16km*(S+ B)
Let's keep simplifying this:
40km*(B - S) + 12km*(S + B) = 8h*(S + B)*(B - S)
32km*(B - S) + 16km*(S+ B) = 8h*(S + B)*(B - S)
Now we get:
52km*B - 28km*S = 8h*(S^2 + B^2)
48km*B - 16km*S = 8h*(S^2 + B^2)
Notice that the right side of these equations is the same thing, then we can write:
52km*B - 28km*S = 48km*B - 16km*S
(52km - 48km)*B = (28km - 18km)*S
4km*B = 10km*S
B = (10/4)*S
B = (5/2)*S
Now we can replace this in one of our two equations, let's use the first one:
48km*B - 16km*S = 8h*(S^2 + B^2)
48km*(5/2)*S - 16km*S = 8h*( S^2 + ( (5/2)*S)^2)
Now we can solve this for S
104km*S = 8h*( S^2 + 25/4*S^2)
104km*S = 8h*(29/4*S^2) = 48h*S^2
104km*S = 48h*S^2
dividing at both sides by S we get:
104km = 48h*S
104km/48h = S = 2.167 km/h
And using B = (5/2)*S
We can find the speed of the boat:
B = (5/2)*2.167 km/h = 5.418 km/h
Then:
the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h
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In circle O, the length of OB is 6 inches, and the measure of ∠AOB is 120°. What is the length of arc AB, in inches (show your answer in terms of π)? *
Answer:
4π inches
Step-by-step explanation:
Formula for finding length of arc AB = θ/360*2πr
Where,
Central angle (θ) = 120°
Radius (r) = 6 inches
Length of arc AB = 120/360*2*π*6
Length for arc AB = ⅓*12π
= 4π inches
4. What is the domain?
Erynn glued k seashell on a photo frame. She made 5 such photo frames. How many seashells did she use?
Seashells glued on 1 photo frame = k
So, seashells glued on 5 photo frame
= Seashells glued on 1 photo frame × 5
= k × 5
= 5k
So, Erynn used 5k seashells.
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112 A. Median: 102, Q1: 87, Q3: 113, IR: 28, outliers: none B. Median: 102, Q1: 87, Q3: 115, IR: 28, outliers: 68 C. Median: 102, Q1: 87, Q2: 115, IR: 28, outliers: none D. Median: 102, Q1: 87, Q3: 115, IR: 27, outliers: none
Answer:
Q1 = 87 ;
Q2 = 102 ;
Q3 = 115 ;
IQR = 28
OUTLIER = None
Step-by-step explanation:
Given the data:
111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112
Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152
Sample size, n = 15
The first quartile, Q1 = 1/4(n+1)th term
Q1 = 1/4(15+1)th term
Q1 = 1/4(16) = 4th term
Q1 = 87
The Median , Q2 = 1/2(n+1)th term
Q2 = 1/2(15+1)th term
Q2 = 1/2(16) = 8th term
Q2 = 102
The third quartile, Q3 = 3/4(n+1)th term
Q3 = 1/4(15+1)th term
Q3 = 3/4(16) = 12th term
Q3 = 115
The interquartile range, IQR = Q3 - Q1
IQR = (115 - 87) = 28
Q1 = 87 ;
Q2 = 102 ;
Q3 = 115 ;
IQR = 28
OUTLIER = None
40÷1+3‐(3×7)+7-5 use pedams to answer the following question
Hey there!
40 / 1 + 3 ‐ (3 * 7) + 7 - 5
= 40 + 3 - (3 * 7) + 7 - 5
= 43 + 7 - 5 - 3 * 7
= 50 - 5 - 3 * 7
= 45 - 3 * 7
= 45 - 21
= 24
Answer: 24
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
An angle measures 75.2° more than the measure of its complementary angle. What is the measure of each angle?
Answer:
x = complement
x + 5.2 = first angle (5.2 more than complement)
measure of two complementary angles add up to 90.
x + x+ 5.2 = 90
2x = 84.8
x = 42.4
other angle = x + 5.2 = 42.4 + 5.2 = 47.6
hope it's help you.....!!!!!
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Step-by-step explanation:
Hope it will help you .
.
.
.
Given the function f(x) = -2c+cx-x^2, and f^-1(5) = -1, find c
Answer:
[tex]c=-2[/tex]
Step-by-step explanation:
We are given the function:
[tex]f(x) = -2c + cx - x^2[/tex]
And that:
[tex]\displaystyle f^{-1} (5) = -1[/tex]
And we want to determine the value of c.
Recall that by definition of inverse functions:
[tex]\displaystyle \text{If } f(a) = b, \text{ then } f^{-1}(b) = a[/tex]
So, since f⁻¹(5) = -1, then f(-1) = 5.
Substitute:
[tex]f(-1) = 5 = -2c + c(-1) - (-1)^2[/tex]
Simplify:
[tex]5 = -2c - c - (1)[/tex]
Combine like terms:
[tex]6 = -3c[/tex]
And divide. Hence:
[tex]c = -2[/tex]
In conclusion, the value of c is -2.
Does anyone know how to do these. Its due in the morning. Pls help
Answer:
15)Given equation:
y = 2/5x - 3To plot the line first find two points:
1. x = 0 ⇒ y = -32. x = 5 ⇒ y = -1Plot (0, -3) and (5, -1) and connect the points with a line. This will be the required line.
16)Use Pythagorean to find the missing leg:
[tex]x = \sqrt{13^2 - 5^2} = \sqrt{144} = 12[/tex] unitsI NEEEDDDD HELPPPP ITS URGENTTTTT!!!!!! I’ll mark you brainliest
Answer:
(x+2)^2 + (y-15)^-1 = 64
Step-by-step explanation:
plz mark brainlist
Correct answer gets brainliest and 5 stars
Answer:
A is false
Step-by-step explanation:
notice how in both diagrams, there are 4 triangles with lengths a, b, c, but in each diagram the triangles are just rotated and positioned differently. if there are the same amount of triangles in both diagrams, and the have equal lengths then the area of the remaining figure, should both match up.
basically the area of the big square in Step 2, is equal to both of the shaded squares, combined area, in Step 1.
Consider the formula 4(h-3k)= h+7.
(a) Make k the subject of the above formula.
(b) If the value of h is decreased by 8, write down the change in the value of k.
guys I really need help
plzzzzzz
Answer:
=k=0.25h-7/12
Step-by-step explanation:
4(h-3k)=h+7
=4h-12k=h+7
collecting like terms and leaving characters with k on 1 side, we get;
12k=3h-7
=k=0.25h-7/12
What error did Leah make?
Answer:
the lines arent parallel, so you cant use corresponding angles theorem
The error is corresponding property does not apply.
What are parallel lines?Parallel lines are those lines that are equidistant from each other and never meet, no matter how much they may be extended in either directions. For example, the opposite sides of a rectangle represent parallel lines.
We know that when two lines are parallel they the following property:
Alternate interior angleCorresponding angleco- interior angles.As, there is no parallel lines line.
So, the measurement if <1 = 88 can't be true because corresponding doesn't apply.
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PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!
A charity is holding a benefit at an Italian restaurant. The owner of the restaurant offers to donate $200 in addition to $4 for each person that attends. Write an equation where d is the total donation and p in the number of people that attend.
A. d=4p+200
B. d=4+200p
C. p=4+200d
D. p=4d+200
Answer:
A. d=4p+200
Step-by-step explanation:
The reason why this is, is because d is the total amount, equaling to 4 times p due to the fact that it is $4 for each person that attends.
Given angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.
Answer:
y = 3
Step-by-step explanation:
*As seen in the photo, the fact that EF = GF and the bisector being there makes EH = HG.
5y + 10 = 28 - y
*Add y to both sides.
6y + 10 = 28
*Subtract 10 from both sides.
6y = 18
*Divide both sides by 6.
y = 3
In triangle EFG, with angle bisector FH and equal lengths for EF and GF, the value of y is 3.
Use the concept of a triangle defined as:
A triangle is a 3-sided polygon, which has three vertices and three angles which has a sum of 180 degrees.
Given that,
Angle EFG has an angle bisector FH.
EF = GF (the lengths of the corresponding sides of triangle EFG are equal).
EH = 5y + 10 (length of segment EH).
HG = 28 - y (length of segment HG).
To find the value of y,
Start by applying the angle bisector theorem in triangle EFG.
According to the theorem,
The ratio of the lengths of the segments formed by the angle bisector to the corresponding sides should be equal.
Since EF = GF,
Set up the following equation:
EH / HG = EF / FG
Substituting the given values, we have:
[tex]\dfrac{(5y + 10)}{ (28 - y)} = \dfrac{1} { 1}[/tex]
Cross-multiplying, we get:
5y + 10 = 28 - y
Combining like terms, we have:
6y = 18
Dividing both sides by 6, we find:
y = 3
Therefore, the value of y is 3.
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Select the point that is a solution to the system of inequalities.
y< x2 + 6
y> x2 - 4
The only point that is a solution to the system of inequalities is (C) (2, 6).
How to determine inequalities?To solve this problem, substitute each of the points into the inequalities.
For point (A), y < (4)² + 6 and y > (4)² − 4.
This simplifies to y < 22 and y > 12.
However, 2 is not greater than 12, so (A) is not a solution.
For point (B), y < (0)² + 6 and y > (0)² − 4.
This simplifies to y < 6 and y > −4.
However, 8 is not less than 6, so (B) is not a solution.
For point (C), y < (2)² + 6 and y > (2)² − 4.
This simplifies to y < 10 and y > 0.
6 is less than 10 and greater than 0, so (C) is a solution.
For point (D), y < (−2)² + 6 and y > (−2)² − 4.
This simplifies to y<2 and y>−8.
-4 is not greater than -8, so (D) is not a solution.
Therefore, the only point that is a solution to the system of inequalities is (C).
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A circle has a radius of \sqrt{45} 45 square root of, 45, end square root units and is centered at (-2.4,-4.8)(−2.4,−4.8)left parenthesis, minus, 2, point, 4, comma, minus, 4, point, 8, right parenthesis.
What is the equation of this circle?
Answer:
(x + 2.4)² + (y + 4.8)² = 45Step-by-step explanation:
Circle equation:
(x - h)² + (y - k)² = r², where (h, k) is the center, r - radiusSubstitute the values to get the equation:
(x - (- 2.4))² + (y - (-4.8))² = (√45)²(x + 2.4)² + (y + 4.8)² = 45Answer:
(x+2.4)^2 + (y+4.8)^2 =45
Step-by-step explanation:
Determine the LCM of the following monomials listed below.
[tex]\boxed{\sf 60x^6y^4}[/tex]
Option d is correctPlease hurry I will mark you brainliest
Identify the function given y= -9/4
Answer:
the function is a y-intercept
Step-by-step explanation:
y=mx+b is the slope intercept formula, m being the slope and b being the y-intercept, meaning y=b, so b=-9/4.
Because it says y=-9/4, we can assume that m, or the slope equals 0.
so when you plug it in, you get
y=0x-9/4
y=-9/4
A piece of land is 20cm by 5cm. A portion of the land by size 10cm by 2cm was used to cultivate tomatoes. what is the area of the land?
Answer:
80cm^2
Step-by-step explanation:
20*5=100
10*2=20
100-20=80
the volume of a cube that is 6 units on an edge in exponential form
Answer:
[tex] {6}^{3} = 216[/tex]
Which of the following is equivalent to the expression below?
Answer:
4
Step-by-step explanation:
ln(e)=1 since ln= log_e
log(x^y)=y*log(x) so ln(e^4)=4*ln(4)=4*1=4
Answer:
D
Step-by-step explanation:
ln(e^4)
The 4 comes down in front of the natural log (ln). You get 4 ln(e)
The natural log of e (ln e ) is 1.
So the answer is 4 * 1 = 4
That may not be clear to you. We could try it another way.
e = 2.718281828
ln (2.718281828) = 1
ln(2.718281828)^4 = 4. The calculator gags until you get it right. You need the y^x key (or the x^y key of ^) It does come back with 4.
You have to monkey around with the calculator to get this to happen.
5. Simplify: 2/5 +3/7+(-6/5)+ (-13/7)
Answer: -78 / 35
Step-by-step explanation:
Given
2/5 + 3/7 + (-6/5) + (-13/7)
Combine terms that have the same denominator
= 2/5 + (-6/5) + 3/7 + (-13/7)
= -4/5 - 10/7
Convert denominator by Least Common Multiple (LCM)
= (-4 × 7) / (5 × 7) - (10 × 5) / (7 × 5)
= -28/35 - 50/35
= -78 / 35
Hope this helps!! :)
Please let me know if you have any questions
Answer:
[tex] \frac{2}{5} + \frac{3}{7} + ( - \frac{6}{5} ) + ( - \frac{13}{7} ) \\ \frac{2}{5} + \frac{3}{7} - \frac{6}{5} - \frac{13}{7} \\ ( \frac{2}{5} - \frac{6}{5} ) + ( \frac{3}{7} - \frac{13}{7} ) \\ \frac{2 - 6}{5} + \frac{3 - 13}{7} \\ \frac{ - 4}{5} + \frac{ - 10}{7} \\ \frac{ - 4}{5} - \frac{10}{7} \\ \frac{ - 28 - 50}{35} \\ \frac{ - 78}{35} \\ - \frac{78}{35} [/tex]