A penny is thrown from the top of a 26.6-meter building and hits the ground 3.59 seconds after it was thrown. The penny reached its maximum height above the ground 0.77 seconds after it was thrown.

1. Define a quadratic function, h, that expresses the height of the penny above the ground (measured in meters) as a function of the number of seconds elapsed since the penny was thrown, t.

2.What is the maximum height of the penny above the ground?

Answers

Answer 1

Answer:

it is at 200 mph

Step-by-step explanation:

bc i did the test

Answer 2

The quadratic function which models the motion of the penny is h(t) = -4.9t² + 10.18t + 26.6 and the maximum height reached is 31.53 meters

The relationship can be expressed in the form :

h(t) = - 0.5gt² + vt + h (downward motion)

g = 9.8 m/s²

h = 26.6 m

v = ?

We can obtain v thus ;

h(t) = -0.5gt² + vt + 26.6

h(t) = - 4.9t² + vt + 26.6

Time when penny hits the ground ; t = 3.59

h(3.59) = 0

0 = -4.9(3.59)² + v(3.59) + 26.6

− 63.15169 + 3.59v + 26.6 = 0

3.59v = 36.55169

v = 36.55169 /3.59

v = 10.181 m/s

Equation becomes :

h(t) = -4.9t² + 10.18t + 26.6

2.) The maximum height of the penny above the ground ;

t = 0.77 seconds

h(0.77) = -4.9(0.77^2)+ 10.18(0.77) + 26.6

Maximum height reached = 31.53 meters

Therefore, the maximum height reached is 31.53 meters

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Answer: Choice D

[tex](f \circ g)(x) = x+12[/tex]

Domain = [-3, infinity)

==================================================

Work Shown:

[tex]f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\[/tex]

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Answer:

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The fourth one IAMS

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Answer:

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Step-by-step explanation:

Answer:  3000

Ask yourself this: "Is 3148 closer to 3000, or is it closer to 4000?"

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Put another way, we round 3148 to 3000 since the next digit after the thousands place is not a 5 or larger. So we just drop the 148 and replace those digits with 0s.

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Recall that the base angles of an isosceles ∆ are equal to each other.

This means that:

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Thus,

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Answers

Step-by-step explanation:

Given parameters:

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Unknown:

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Step-by-step explanation:

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