Answer:
Yes they can type about 130 each minute
Step-by-step explanation:
I learned this in a book
Answer:
the person can type
80 wpm
parabola
Given that tanθ= [tex]-\frac{9}{4}[/tex] and [tex]\frac{\pi }{2\\}[/tex]<θ<π , find the exact values of the trigonometric functions.
9514 1404 393
Answer:
sin(θ) = (9√97)/97cos(θ) = (-4√97)/97csc(θ) = (√97)/9sec(θ) = (-√97)/4cot(θ) = -4/9Step-by-step explanation:
The angle is in the 2nd quadrant, where the sine is positive and the cosine is negative.
tan^2(θ) +1 = sec^2(θ) = (-9/4)^2 +1 = 97/16 ⇒ sec = -(1/4)√97
cot(θ) = 1/tan(θ) = -4/9
csc^2(θ) = cot^2(θ) +1 = (-4/9)^2 +1 = 97/81 ⇒ csc = (1/9)√97
sin(θ) = 1/csc(θ) = (9√97)/97
cos(θ) = 1/sec(θ) = (-4√97)/97
Rounding in the calculation of monthly interest rates is discouraged. Such rounding can lead to answers different from those presented here. For long-term loans, the differences may be pronounced.
Assume that you take out a $2000 loan for 30 months at 8% APR. How much of the first month's payment is interest? (Round your answer to the nearest cent.)
$
Answer:
13.33
Step-by-step explanation:
Because it's only payment one we can easily figure out the interest portion
we first need the effective rate
.08/12= .006666667
We the just mulitply this by loan amount
2000*.006666667= 13.33
Step-by-step explanation:
its your answer
I hope it's help you
How to Factor 4n^3-49n
Answer:
n (2n-7) (2n+7)
Step-by-step explanation:
Fyi you can use the app photo math you just take a pic of the problem and it gives you the answer and explains the steps and it is free.
Dr. Lum teaches part-time at two community colleges, Hilltop College and Serra College. Dr. Lum can teach up to 5 classes per semester. For every class he teaches at Hilltop College, he needs to spend 3 hours per week preparing lessons and grading papers. For each class at Serra College, he must do 4 hours of work per week. He has determined that he cannot spend more than 18 hours per week preparing lessons and grading papers. If he earns $6,000 per class at Hilltop College and $7,500 per class at Serra College, how many classes should he teach at each college to maximize his income, and what will be his income?
To maximize his income, Dr. Lum should teach_______classes for Hilltop College and __________classes for Serra College. His maximum income would be________.
Answer:
z (max) = 34500 $
x₁ = 2
x₂ = 3
Step-by-step explanation:
Hilltop College
3 hours per week preparing lessons and grading papers
Serra College
4 hours per week preparing lessons and grading papers
Total hours to spend per week preparing lessons 18
Let´s call x₁ numbers of class at Hilltop College
and x₂ numbers of class at Serra College then:
Objective function
z = 6000*x₁ + 7500*x₂
Constraints:
1.- x₁ + x₂ ≤ 5 the total number of class
2.- 3*x₁ + 4*x₂ ≤ 18
3. General constraints x₁ ≥ 0 x₂ ≥ 0 integers
After 6 iteration optimal solution is: From on-line solver
z (max) = 34500 $
x₁ = 2
x₂ = 3
please help thx steps too
Step-by-step explanation:
IN first triangle multiplier factor is 4
and IN second triangle multiplier factor is
[tex] \frac{3}{2} [/tex]
Consider random samples of size 86 drawn from population A with proportion 0.43 and random samples of size 60 drawn from population B with proportion 0.15
(a) Find the standard error of the distribution of differences in sample proportions A - B Round your answer for the standard error to three decimal places. Standard error=
(b) Are the sample sizes large enough for the Central Limit Theorem toa
Yes or No?
Answer:
a) The standard error is s = 0.071.
b) Yes, as both sample sizes are above 30.
Step-by-step explanation:
To solve this question, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
Samples of size 86 drawn from population A with proportion 0.43
This means that [tex]n = 86, p = 0.43[/tex]. So:
[tex]s_A = \sqrt{\frac{0.43*0.57}{86}} = 0.0534[/tex]
Samples of size 60 drawn from population B with proportion 0.15:
This means that [tex]n = 60, p = 0.15[/tex]. So:
[tex]s_B = \sqrt{\frac{0.15*0.85}{60}} = 0.0461[/tex]
(a) Find the standard error of the distribution of differences in sample proportions A - B Round your answer for the standard error to three decimal places. Standard error=
This is:
[tex]s = \sqrt{s_A^2 + s_B^2}[/tex]
[tex]s = \sqrt{(0.0534)^2 + (0.0461)^2}[/tex]
[tex]s = 0.071[/tex]
The standard error is s = 0.071.
(b) Are the sample sizes large enough for the Central Limit Theorem. Yes or No?
Yes, as both sample sizes are above 30.
As preparation for designing a new line of business wear, a clothing manufacturer asked a large sample of department store customers, "What is your favorite
color of dress shirt?" The ple chart below summarizes their responses.
(a) Which color was chosen by approximately one fourth of
the customers?
Answer:
white
Step-by-step explanation:
if you cut the shape in half both ways it makes white take up a fourth.
Consider the following data representing the price of plasma televisions (in dollars).
1325, 1266, 1123, 1233, 1387, 1249, 1120, 1140, 1347, 1337, 1402, 1259, 1421, 1351, 1452, 1277, 1309, 1232, 1112, 1243, 1429
Copy Data Price of Plasma Televisions (in Dollars) Class Frequency Class Boundaries Midpoint Relative Frequency Cumulative Frequency
1067–1126 1127–1186 1187–1246 1247–1306 1307–1366 1367–1426
Determine the class width of the classes listed in the frequency table.
Answer:
[tex]Width = 59[/tex]
Step-by-step explanation:
Given
The above data
Required
The class width
To do this, we simply calculate the difference between the class limits of any one of the classes.
Taking 1187–1246 as a point of reference, the class width is:
[tex]Width = 1246 - 1187[/tex]
[tex]Width = 59[/tex]
Can someone please help me out?
The difference between two numbers is 16. The first number is three times the other number. What are the numbers?
A. 8 and 25
B. 8 and 24
C. 9 and 24
D. 9 and 25
No links or fake answers pls
9514 1404 393
Answer:
B. 8 and 24
Step-by-step explanation:
There are a number of approaches you can use here. One of them is to choose the only answer that makes any sense in the problem.
The problem tells you the numbers have a ratio of 3, so numbers like 8 and 25, 9 and 24, 9 and 25 cannot be the answer.
The only answer choice that makes any sense is B: 8 and 24.
__
If you want to work the problem, there are different ways you can do that. One of my favorite is to consider ratio units. The ratio of the two numbers is 3:1. The difference of the two numbers is 3-1 = 2 ratio units, which we are told is 16. Then each ratio unit represents 16/2 = 8. Then the numbers are ...
3×8 and 1×8 = 24 and 8.
Or, you can let a variable represent one of the numbers. If x is the first number, then the other number is 1/3x, and their difference is ...
x -1/3x = 16
2/3x = 16
x = 16(3/2) = 24
The numbers are 24 and 24/3 = 8.
__
Additional comment
You need to talk to your teacher about this question. The answer choices list the smaller number first, but the problem statement tells you the first number is 3 times the second number. The correct answer would be 24 and 8.
Will mark BRAINLIEST!! This is pt.2
Answer:
See below.
Step-by-step explanation:
Problem 3.
1. <3, <4
Given
2. <1, <2
Given
3. KG
Congruence of segments is reflexive.
4. HKG, LKG
ASA
Problem 4.
1. MR, OR
Given
2. PR, NR
Given
3. <2
Vertical angles are congruent.
4. MPR, ONR
SAS
Ana vende productos de limpieza .Por cada $100 que venda le dan de comisión $30 .¿Cuánto ganará si vende $600?
Answer:
$180
Step-by-step explanation:
$600/$100 = 6
$600 es 6 veces $100.
Por vender $600 gana 6 veces mas que por vender $100.
6 * $30 = $180
Respuesta: $180
HELP MATH ANSWER QUESTION
Answer:
Last one.
Step-by-step explanation:
[tex]\sqrt{3}[/tex] is used in 30-60-90 triangles
[tex]\sqrt{2}[/tex] is used in 45-45-90 triangles
Base is x, leg is x[tex]\sqrt{3}[/tex], hypotenuse is 2x
Answer:
x = 20 ; y= 10√3
Step-by-step explanation:
30, 60 , 90 triangle ratio is
Side opposite to 30 is a
a = AC = 10
Side opposite to 60 is a[tex]\sqrt{3}[/tex]
AB = a[tex]\sqrt{3}[/tex] = 10√3
Side opposite to 90 is 2a
BC = 2a = 2* 10 = 20
If 5^3b-1 = 5^b-3, what is the value of b?
-2
-1
1
2
Answer:
3b-1 = b-3
2b = 4
b = 2
Step-by-step explanation:
ASAP!!! There are three marbles in a bag. One is red and two are black. What is the probability of picking a red marble first, putting it back in the bag and then picking a black marble? Use the following probably need to find the answer.
Answer:
The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)
Step-by-step explanation:
Hey there!
The probability of first getting a red marble is 1/3 since we have 1 red marble out of 2 + 1 = 3 total.
We put the marble back. The probability of then choosing a black marble is 2/3, since we have 2 black marbles out of 3 total.
So we get 1/3 * 2/3 = 2/9
The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)
Hope this helps, please mark brainliest if possible. Have a nice day. :)
Quadrilateral FGHI is similar to quadrilateral JKLM. Find the measure of side JK. Round your answer to nearest tenth if necessary,
Answer:
JK ≈ 12.3
Step-by-step explanation:
Since the figures are similar then the ratios of corresponding sides are equal, that is
[tex]\frac{FI}{JM}[/tex] = [tex]\frac{FG}{JK}[/tex] , substitute values
[tex]\frac{59}{26}[/tex] = [tex]\frac{28}{JK}[/tex] ( cross- multiply )
59 JK = 728 ( divide both sides by 59 )
JK ≈ 12.3 ( to the nearest tenth )
What is the future value of a R 75 000 deposit made every 6 months for 3 years using an annual rate of 10% compounded semi-annually?
Answer:
The future value is: RS 132867.075
Step-by-step explanation:
Given
[tex]PV = 75000[/tex] --- present value
[tex]r = 10\%[/tex] --- annual rate
[tex]n = 6[/tex] --- number of times compounded (3 years/ 6 months)
Required
The future value
This is calculated as:
[tex]FV =PV * (1 + r)^n[/tex]
[tex]FV = 75000 * (1 + 10\%)^6[/tex]
[tex]FV = 75000 * (1 + 0.10)^6[/tex]
[tex]FV = 75000 * (1.10)^6[/tex]
[tex]FV = 132867.075[/tex]
Hence, the future value is: RS 132867.075
Choose the equation of the line that is parallel to the x-axis.
x = 4
x + y = 0
x = y
y = 4
NO LINKS OR ELSE YOU'LL BE REPORTED! Only answer if you're very good at Math.No guessing please.
The sample space,S,of a coin being tossed three times is shown below, where H and T denote the coin landing on heads and tails respectively.
Answer: Bottom left corner
=======================================================
Explanation:
There are only four possible outcomes here
A) we get all tails, ie getting 0 headsB) we get exactly one head (the rest tails)C) we get exactly 2 headsD) we get all three headsBased on this so far, the answer is either the table in the bottom left corner or in the top right corner. It's not possible for X = 4 since we only flipped 3 coins.
The probability of case A happening is 1/8 since we have 1 scenario that's all tails (TTT) out of 8 items in the sample space. Similarly, the probability for case D is the same probability. We only have one HHH out of 8 total items.
The probabilities of cases B and C are the same. Both are 3/8. Note that for case B, we have HTT, THT, TTH which is three occurrences in which we get exactly 1 head. So that explains the 3/8.
An College student complained that the cost of textbooks was too high. She randomly surveyed 36 other students and found that the mean amount of money spent for textbooks was $121.60. If the standard deviation of the population was $6.36, find the best point estimate. Show your work.
Answer:
The best point estimate for the mean amount of money spent for textbooks for all students at the College is of $121.60.
Step-by-step explanation:
Best point estimate:
The best point estimate of a population mean is the sample mean.
In this question:
The sample mean amount of money spent for textbooks was $121.60, which means that the best point estimate for the mean amount of money spent for textbooks for all students at the College is of $121.60.
A bag contains 9 red marbles, 6 white marbles, and 8 blue marbles. You draw 4 marbles out at random, without replacement. Find the following probabilities and round to 4 decimal places.
a. The probability that all the marbles are red is
b. The probability that none of the marbles are red is
Step-by-step explanation:
here are the answers bae. Feel free to ask for more
The function is f(x) is shown on the graph.
What is f(0)
•12 only
•2 and 3 only
•-2, -1, 1, and 2 only
•-2, -1, 1, 2 and 12
Answer:
12 only
Step-by-step explanation:
The function is given on the graph.
What is f(0)?
This is the value of y when x = 0.
Looking at the horizontal axis, when x = 0, the vertical axis is at y = 12, and at no other point the horizontal axis is at x = 0, which means that the correct answer is given by:
12 only
Use the limit definition of the derivative to find the instantaneous rate of change of
f(x)=5x^2+3x+3 at x=4
[tex]f'(4) = 43[/tex]
Explanation:
Given: [tex]f(x)=5x^2 + 3x + 3[/tex]
[tex]\displaystyle f'(x)= \lim_{h \to 0} \dfrac{f(x+h) - f(x)}{h}[/tex]
Note that
[tex]f(x+h) = 5(x+h)^2 + 3(x+h) + 3[/tex]
[tex]\:\:\;\:\:\:\:= 5(x^2 + 2hx + h^2) + 3x + 3h +3[/tex]
[tex]\:\:\;\:\:\:\:= 5x^2 + 10hx + 5h^2 + 3x + 3h +3[/tex]
Substituting the above equation into the expression for f'(x), we can then write f'(x) as
[tex]\displaystyle f'(x) = \lim_{h \to 0} \dfrac{10hx + 3h + 5h^2}{h}[/tex]
[tex]\displaystyle\:\:\;\:\:\:\:= \lim_{h \to 0} (10x +3 +5h)[/tex]
[tex]\:\:\;\:\:\:\:= 10x + 3[/tex]
Therefore,
[tex]f'(4) = 10(4) + 3 = 43[/tex]
What is 2+2-35x62+88-1x675
[tex]\longrightarrow{\blue{ -2753}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex]2 + 2 - 35 \times 62 + 88 - 1 \times 675[/tex]
[tex] = 2 + 2 - 2170 + 88 - 675[/tex]
[tex] = 92 - 2170 - 675[/tex]
[tex] = 92 - 2845[/tex]
[tex] = - 2753[/tex]
Note:-[tex]\sf\pink{PEMDAS\: rule.}[/tex]
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]
The list price on slacks is $22, and the list price on jumpers is $37. If Petit’s Clothing Store orders 30 pairs of slacks and 40 jumpers at a discount rate of 11%, what is the trade discount on the purchase?
Answer: $235.4
Step-by-step explanation:
Given
Price list on slacks is $22
Price list on jumpers is $37
Store ordered 30 pairs of slacks and 40 Jumpers
Total price becomes
[tex]\Rightarrow 22\times 30+37\times 40\\\Rightarrow \$2140[/tex]
for a discount of 11%
Trade discount is [tex]2140\times 11\%[/tex]
[tex]\Rightarrow 2140\times 0.11\\\Rightarrow \$235.4[/tex]
What is the domain of the function y=3 sqrt x?
Answer:
Step-by-step explanation:
y=3√x
domain : all real values≥0
Can someone please help me
Answer:
8,889
Step-by-step explanation:
1 twig = 10 leaves
1 branch = 10 twigs = 100 leaves
1 trunk = 10 branches = 1000 leaves
1 tree = 10 trunks = 10,000 leaves
The complete tree has 10,000 leaves
The woodcutter cut off:
1 trunk = 1000 leaves
1 branch = 100 leaves
1 twig = 10 leaves
1 leaf
Total number of leaves that were cut:
1000 + 100 + 10 + 1 = 1111
Leaves left on tree:
10,000 - 1,111 = 8,889
|x| =3 means that the distance between x and 0 is 3 / true or false
Answer:
True
Step-by-step explanation:
if |x| is 3 then x is either -3 or 3. Either way, the distance from 0 is 3.
Hole this helps! :)
On a coordinate plane, Rectangles A B C D and E F G H are shown. The length of side A B is 6 units and the length of side B C is 3 units. The length of side E F is 8 units and the length of side F G is 4 units.
Is rectangle EFGH the result of a dilation of rectangle ABCD with a center of dilation at the origin? Why or why not?
Yes, because corresponding sides are parallel and have lengths in the ratio Four-thirds
Yes, because both figures are rectangles and all rectangles are similar.
No, because the center of dilation is not at (0, 0).
No, because corresponding sides have different slopes.
Answer:
im doing the same one, i believe it is D
Step-by-step explanation:
Answer:
a- yes because corresponding sides are parallel and have lengths in the ration 4/3
Step-by-step explanation:
just did the test
Pls solve this question:
it is about Square and square roots
if u answer, then I will mark you as brilliant
[tex]\sqrt{2.3} multiplied \sqrt{2.3[/tex]
Answer:
2.3
Step-by-step explanation:
if you mean √2.3×√2.3 then the answer is 2.3 because √2.3×√2.3= (√2.3)² and that square cuts the square root and what remains is 2.3 which is the answer.
A plane flies 420 miles with the wind and 350 miles against the wind in the same length of time. If the speed of the wind is 15 mph, find the speed of the plane in still air.
Answer:
161 speed of plain in still air
Mark in brainlist
