The net realizable value οf the inventοry is the anticipated sale price in the nοrmal cοurse οf business less the prοjected cοsts fοr cοmpletiοn, destructiοn, and transpοrtatiοn after the LCM adjustment has been made.
What dοes a math's unit mean?The rightmοst place in an integer οr the number οne can be cοnsidered a unit in mathematics. The unit number inside the number 6713 in this case is 3. The standard measuring units can alsο be referred tο as a unit.
1. We must evaluate the price per piece and selling price per unit and select the lesser οf the twο in οrder tο get the lοwer οf price οr marketplace (LCM) fοr each item. The calculatiοns lοοk like this:
Speakers: LCM = min($105, $113) = $105 per unit
Stereοs: LCM = min($116, $126) = $116 per unit
Amplifiers: LCM = min($101, $110) = $101 per unit
Subwοοfers: LCM = min($57, $67) = $57 per unit
Alarms: LCM = min($155, $165) = $155 per unit
Lοcks: LCM = min($98, $108) = $98 per unit
Cameras: LCM = min($327, $337) = $327 per unit
Tripοds: LCM = min($89, $99) = $89 per unit
Stabilizers: LCM = min($110, $120) = $110 per unit
2. We must evaluate the entire cοst οf inventοry as well as the tοtal selling price οf inventοry in οrder tο determine whether an LCM adjustment is required. We must change the value οf the inventοry tο reflect the lesser οf the cοst οr market if indeed the market value falls shοrt οf the cοst. The calculatiοns lοοk like this:
Tοtal cοst οf inventοry = (350 x $105) + (265 x $126) + (331 x $101) + (209 x $67) + (485 x $165) + (296 x $108) + (217 x $327) + (190 x $89) + (175 x $110)
= $70,657
Tοtal market value οf inventοry = (350 x $113) + (265 x $116) + (331 x $110) + (209 x $57) + (485 x $155) + (296 x $98) + (217 x $327) + (190 x $99) + (175 x $110)
= $70,273
We must make an LCM mοdificatiοn tο the Merchandise Accοunting system because the market price is lοwer than the cοst. The distinctiοn amοng the tοtal cοst and the tοtal market value is the adjustment amοunt, which is:
$70,657 - $70,273 = $384
The LCM adjustment's jοurnal entry is as fοllοws:
Merchandise Inventοry 384
LCM Adjustment 384
The LCM adjustment reduces the inventοry value tο its net realizable value, which is the estimated selling price in the οrdinary cοurse οf business, less the estimated cοsts οf cοmpletiοn, dispοsal, and transpοrtatiοn.
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Consider the function h(x) = a(−2x + 1)^5 − b, where a does not=0 and b does not=0 are constants.
A. Find h′(x) and h"(x).
B. Show that h is monotonic (that is, that either h always increases or remains constant or h always decreases or remains constant).
C. Show that the x-coordinate(s) of the location(s) of the critical points are independent of a and b.
Answer:
A. To find the derivative of h(x), we can use the chain rule:
h(x) = a(-2x + 1)^5 - b
h'(x) = a * 5(-2x + 1)^4 * (-2) = -10a(-2x + 1)^4
To find the second derivative, we can again use the chain rule:
h''(x) = -10a * 4(-2x + 1)^3 * (-2) = 80a(-2x + 1)^3
B. To show that h is monotonic, we need to show that h'(x) is either always positive or always negative. Since h'(x) is a multiple of (-2x + 1)^4, which is always non-negative, h'(x) is always either positive or negative depending on the sign of a. If a > 0, then h'(x) is always negative, which means that h(x) is decreasing. If a < 0, then h'(x) is always positive, which means that h(x) is increasing.
C. To find the critical points, we need to find where h'(x) = 0:
h'(x) = -10a(-2x + 1)^4 = 0
-2x + 1 = 0
x = 1/2
Thus, the critical point is at x = 1/2. This value is independent of a and b, as neither a nor b appear in the calculation of the critical point.
Which is correct answer?
a
b
c
When g be continuous on [1,6], where g(1) = 18 and g(6): = 11. Does a value 1 < c < 6 exist such that g(c) = 12
Yes, because of the intermediate value theoremWhat is intermediate value theorem?The intermediate value theorem is a fundamental theorem in calculus that states that if a continuous function f(x) is defined on a closed interval [a, b], and if there exists a number y between f(a) and f(b), then there exists at least one point c in the interval [a, b] such that f(c) = y.
According to the intermediate value theorem,
since g(x) is a continuous function on the closed interval [1, 6]
since g(1) = 18 is greater than 12, and
g(6) = 11 is less than 12,
there must be at least one value c between 1 and 6 where g(c) = 12.
Therefore, we can conclude that a value of c does exist such that g(c) = 12.
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Construct an example of a function that satisfies the following conditions:
a) Its domain and range are both all real numbers except 5.
b) Its domain is all positive numbers greater than 1, including 1.
c) Its domain is all positive numbers greater than 1, but not including 1.
Answer:
f(x) = (x^2 - 25) / (x - 5)
Step-by-step explanation:
Note that this function is undefined at x=5, which satisfies condition (a). Also, the function is defined for all other real numbers, which satisfies the domain and range requirement of (a).
For condition (b), note that the function is defined for all positive numbers greater than 1, including 1, since the denominator (x-5) will be positive for these values of x.
For condition (c), note that the function is undefined at x=1, since the denominator (x-5) will be negative for x slightly less than 1. Therefore, the function is defined for all positive numbers greater than 1, but not including 1.
Which of the following is a true statement?The area under the standard normal curve between 0 and 2 is twice the area between 0 and 1.The area under the standard normal curve between 0 and 2 is half the area between -2 and 2.For the standard normal curve, the IQR is approximately 3.For the standard normal curve, the area to the left of 0.1 is the same as the area to the right of 0.9.
For the standard normal curve, the area to the left of 0.1 is the same as the area to the right of 0.9 is true . So, the correct answer is D.
The standard normal curve is a normal distribution with a mean of 0 and a standard deviation of 1. This curve is often used in statistics to model natural phenomena, and it has many important properties.
Option A is incorrect because the area under the standard normal curve between 0 and 2 is not twice the area between 0 and 1. The area under the curve increases as we move away from the mean, so the area between 0 and 2 will be greater than the area between 0 and 1.
Option B is also incorrect because the area under the standard normal curve between 0 and 2 is not half the area between -2 and 2. The area between -2 and 2 covers more of the curve than the area between 0 and 2, so the area between 0 and 2 will be smaller than half the area between -2 and 2.
Option C is incorrect because the standard normal curve does not have a fixed IQR (interquartile range). The IQR depends on the quartiles of the distribution, which can vary depending on the sample size and the distribution's shape.
Option D is the correct answer because the standard normal curve is symmetric around the mean of 0. This means that the area to the left of any point on the curve is the same as the area to the right of its negative counterpart. Therefore, the area to the left of 0.1 is equal to the area to the right of 0.9.
Therefore, Correct option is D.
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Question is in the image, please help
On solving the question we can say that so the other side of triangle is [tex]B = \sqrt324[/tex], therefore the angle will be [tex]cos^{-1} (0.38)[/tex].
What precisely is a triangle?A triangle is a closed two-dimensional geometric object consisting of three line segments, called edges, that intersect at three places called vertices. Triangles are distinguished by their sides and angles. A triangle can be equilateral (all sides equal), isosceles, or odd, depending on the sides. Triangles are classified as acute (any angle less than 90 degrees), right (angles equal to 90 degrees), or obtuse (any angle greater than 90 degrees). The area of a triangle can be calculated using the formula A = (1/2)bh. where A is the area, b is the base of the triangle, and h is the height of the triangle.
here two sides of the triangle are given that are 19.5 and 7.5
so by
[tex]A^2 = B^2 + C^2\\B^2 = 19.5^2 - 7.5^2\\B^2 = 380.25 - 56.25\\B^2 = 324\\B = \sqrt324[/tex]
so the other side is [tex]B = \sqrt324[/tex], therefore the angle will be [tex]cos^{-1} (0.38)[/tex].
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Please see attached question
Using graphs, we can see that the point (4,2) can be a coordinate where y will represent x.
What are graphs?The graph is simply a structured representation of the data. The numerical information gathered through observation is referred to as data.
If there is just one value of y (output) for every value of x, the relationship between x and y is said to be a function (input).
In other words, there can only be one value of y for each value of x.
Determine each plotted point's coordinates first:
(-4,4)
(-2,3)
(0,1)
(2, -1)
(3,0)
The following point cannot have any of the x-coordinates of the displayed points, which are -4, -2, 0, 2, and 3.
Options include:
A (0,1) →The relationship cannot be regarded as a function at this stage as the x-coordinate zero already has a corresponding value of y.
B (2,2) →Although there is already a value of y for the location x=2, the relationship cannot be regarded as a function at this point.
C (3,4) →Although there is already a value of y for the location x=3, the relationship cannot be regarded as a function at this point.
D (4,2) → The relationship will still be regarded as a function even though there are no points on the graph with the coordinates x=4 displayed.
Therefore, option D (4,2) is the point where y will represent x.
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The complete question:
Please see attached question
A baseball team has home games on Thursday and Sunday. The two games together earn $4064.50 for the team. Thursday's game generates $400.50 less than Sunday's game. How much money
was taken in at each game?
The Sunday game brought in $2232.50, while the Thursday game brought in $1832.00.
What does this gain and loss mean?A company's income, costs, and profit are compiled in a profit and loss (P&L) statement, a financial report. It provides information to investors and other interested parties about a company's operations and financial viability.
The issue informs us that the combined revenue from the two games was $4064.50.
S + (S - 400.50) = 4064.50
Simplifying the left side, we get:
2S - 400.50 = 4064.50
Adding 400.50 to both sides, we get:
2S = 4465
Dividing both sides by 2, we get:
S = 2232.50
So the Sunday game generated $2232.50, and the Thursday game generated $2232.50 - $400.50 = $1832.00.
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Divide 240g in the ratio 5 4 3
Step-by-step explanation:
240g divided in ratios.
divide 240g in the ratio 5:4:3
To divide 240g in the ratio 5:4:3, we need to determine the amount of each part of the ratio.
First, we need to find the total number of parts in the ratio, which is 5 + 4 + 3 = 12.
Next, we divide the total amount (240g) by the total number of parts (12) to find the value of one part:
240g ÷ 12 = 20g
Therefore, one part of the ratio is equal to 20g.
To find the amount of each part of the ratio, we can multiply the value of one part by the corresponding number in the ratio.
The amounts are:
5 parts: 5 × 20g = 100g
4 parts: 4 × 20g = 80g
3 parts: 3 × 20g = 60g
Therefore, to divide 240g in the ratio 5:4:3, we need 100g, 80g, and 60g for each part of the ratio, respectively.
Answer
100g , 80g , 60g
Step-by-step explanation:
Ratio:Ratio = 5 : 4 : 3
Let the unit share be 'x'.
So, three shares are 5x, 4x and 3x.
Total weight = 240 g
Total shares = 5x + 4x + 3x = 12x
Sum of all the shares equal to the total weight.
12x = 240g
x = 240 ÷ 12 = 20
The value of unit share is 20 g. From this we can find the weight of each share.
5x = 5 * 20 = 100g
4x = 4 * 20 = 80 g
3x = 3 * 20 = 60 g
Suppose the current cost of gasoline is $2.93 per gallon. Find the current price index number, using the 1975 price of 56.7 cents as the reference value.
Answer:
Step-by-step explanation:
To find the current price index number using the 1975 price of 56.7 cents as the reference value, we can use the formula:
Price Index = (Current Price / Base Price) x 100
Where "Current Price" is the current cost of gasoline, and "Base Price" is the 1975 price of 56.7 cents.
Substituting the values given in the problem, we get:
Price Index = ($2.93 / $0.567) x 100
Price Index = 516.899
Therefore, the current price index number, using the 1975 price of 56.7 cents as the reference value, is 516.899.
The graph represents a relation where x represents the independent variable and y represents the dependent variable. a graph with points plotted at negative 5 comma 1, at negative 2 comma 0, at negative 1 comma 3, at negative 1 comma negative 2, at 0 comma 2, and at 5 comma 1 Is the relation a function? Explain. No, because for each input there is not exactly one output. No, because for each output there is not exactly one input. Yes, because for each input there is exactly one output. Yes, because for each output there is exactly one input.
No, the relation is not a function, because for each input there is not exactly one output.
What is graph?A graph is a visual representation of data that shows the relationship between variables or sets of data. It consists of a set of points, called vertices or nodes, which are connected by lines or curves, called edges or arcs. Graphs are commonly used to display numerical information, such as trends, patterns, or relationships, and can be used to analyze and interpret data.
The relation is not a function because for the input x = -1, there are two different output values, y = 3 and y = -2. A function is a relation where each input has exactly one output, but in this case, the input -1 has two different outputs, violating the definition of a function.
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The distribution of pitches thrown in all the at-bats in a baseball game is as follows
The probability of a pitcher throwing exactly 5 pitches in an at-bat is 0.1 or 10%.
What is probability and how is it calculated?
Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain. The probability of an event A is calculated as the ratio of the number of outcomes that correspond to event A to the total number of possible outcomes.
Calculating probability of a pitcher throwing exactly 5 pitches :
To calculate the probability of a pitcher throwing exactly 5 pitches in an at-bat, we need to add up the frequencies of all the at-bats that have exactly 5 pitches. From the given table, we see that there are 8 at-bats that have exactly 5 pitches.
The total number of at-bats is the sum of the frequencies of all pitch counts.
Total number of at-bats = 12+16+32+12+8 = 80
Therefore, the probability of a pitcher throwing exactly 5 pitches in an at-bat is:
P(5) = Frequency of 5-pitch at-bats / Total number of at-bats
P(5)= 8/80 = 0.1 or 10%
Hence, the probability that a pitcher will throw exactly 5 pitches in an at-bat is 10%.
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Find all relative extrema of the function. Use the Second-Derivative Test when applicable. (If an answer does not exist, enter DNE.) f (x) = x^4 ? 8x^3 + 4relative minimum (x, y) =( )relative maximum(x, y) =( )
The relative maximum of the function is (0, 4), and the relative minimum is (6, -152).
To find the relative extrema of the function f(x) = x^4 - 8x^3 + 4, we first take the derivative of the function:
f'(x) = 4x^3 - 24x^2
Then we set f'(x) = 0 to find the critical points:
4x^3 - 24x^2 = 0
4x^2(x - 6) = 0
This gives us two critical points: x = 0 and x = 6.
Next, we find the second derivative of f(x):
f''(x) = 12x^2 - 48x
We can use the Second-Derivative Test to determine the nature of the critical points.
For x = 0, we have:
f''(0) = 0 - 0 = 0
This tells us that the Second-Derivative Test is inconclusive at x = 0.
For x = 6, we have:
f''(6) = 12(6)^2 - 48(6) = 0
Since the second derivative is zero at x = 6, we cannot use the Second-Derivative Test to determine the nature of the critical point at x = 6.
To determine whether the critical points are relative maxima or minima, we can use the first derivative test or examine the behavior of the function around the critical points.
For x < 0, f'(x) < 0, so the function is decreasing.
For 0 < x < 6, f'(x) > 0, so the function is increasing.
For x > 6, f'(x) < 0, so the function is decreasing.
Therefore, we can conclude that the critical point at x = 0 is a relative maximum and the critical point at x = 6 is a relative minimum.
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nction value. n=4 -1,4, and 2+2i are zeros; f(1)=-30
The polynomial function with the given zeros and numeric value at x = 1 is given as follows:
f(x) = x^4 - 7x³ + 16x² - 8x - 32
How to define the polynomial function?The zeros of the polynomial function are given as follows:
x = -1.x = 4.x = 2 + 2i.x = 2 - 2i. -> complex-conjugate theorem, when a complex number is a root of a polynomial function, it's conjugate also is.Then the linear factors of the function are given as follows:
x + 1.x - 4.x - 2 - 2i.x - 2 + 2i.According to the Factor Theorem, the function with leading coefficient a can be defined as a product of it's linear factors are follows:
f(x) = a(x + 1)(x - 4)(x - 2 - 2i)(x - 2 + 2i).
f(x) = a(x² - 3x - 4)(x² - 4x + 8)
f(x) = a(x^4 - 7x³ + 16x² - 8x - 32).
When x = 1, y = -30, hence the leading coefficient a is obtained as follows:
-30 = a(1 - 7 + 16 - 8 - 32)
-30a = -30
a = 1.
Hence the function is:
f(x) = x^4 - 7x³ + 16x² - 8x - 32
Missing InformationThe problem asks for the polynomial function with the given zeros and numeric value at x = 1.
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A type of wood has a density of 250 kg/m3. How many kilograms is 75,000 cm3 of the wood? Give your answer as a decimal.
Zeros: −9, multiplicity 1; −1, multiplicity 2; degree 3
Form a polynomial whose zeros and degree are given.
Answer:
Step-by-step explanation:
If the zeros and their multiplicities are given, we can write the polynomial as the product of linear factors corresponding to each zero.
For this problem, the polynomial has zeros of -9 (multiplicity 1) and -1 (multiplicity 2), so the linear factors are:
(x + 9) and (x + 1)^2
To find the third factor, we use the fact that the degree of the polynomial is 3. We can multiply the linear factors together and then simplify:
(x + 9)(x + 1)^2 = (x^2 + 10x + 9)(x + 1)
= x^3 + 11x^2 + 19x + 9
Therefore, the polynomial with zeros of -9 (multiplicity 1), -1 (multiplicity 2), and degree 3 is:
f(x) = x^3 + 11x^2 + 19x + 9
For ever 100 clovers that Lucy picked 22 of them had four leaves while the others only had three leave in total Lucy picked 1,000 clovers if her pattern continued, how many three - leaf and four leaf would Lucy have how many of each clover would she have if she picked 2,000 clovers
Answer:
a)220 4 leaf clovers, 780 3 leaf clovers b)440 four leaf clovers, 1560 3 leaf clovers
Step-by-step explanation:
100:1000=1:10 22:x=1:10 x=220
220x2=440
1000-220=780
780x2=1560
find surface area of cilinder with the radius of 9 and height of 14. make sure to put the correct exponents with answer.
The surface area is 1305. 96 square units
How to determine the surface areaIt is important to note that the formula for calculating the surface area of a cylinder is expressed with the equation;
SA = 2πrh + 2πr²
Given that the parameters are;
SA represents the surface area.r represents the radius of the cylinderh represents the height of the cylinderπ takes the value of 3.14Now, substitute the values, we have;
Surface area = 2 × 3.14 × 9 ×14 + 2 × 3.14 × 9²
Multiply the values
Surface area = 791. 28 + 508. 68
add the values
Surface area = 1305. 96 square units
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Please help! Use the properties of exponents to simplify the expression.
Answer:
[tex] {y}^{6} {x}^{ - 2} [/tex]
Step-by-step explanation:
4 will get multiplied to the exponents of x and y inside the bracket.
Find the zeros of the function. Then graph the function
y= (x+1)(x-2)(x-6)
Answer:
Step-by-step explanation:
To find the zeros of the function, we set y to zero and solve for x:
y = (x+1)(x-2)(x-6) = 0
Setting each factor equal to zero and solving for x gives us the zeros:
x+1 = 0 or x-2 = 0 or x-6 = 0
x = -1, x = 2, x = 6
So the zeros of the function are -1, 2, and 6.
To graph the function, we can use the zeros and the leading coefficient to sketch a rough graph. The leading coefficient is positive, so the graph will open upward. The zeros are -1, 2, and 6, so the graph will intersect the x-axis at those points. We can also find the y-intercept by plugging in x = 0:
y = (0+1)(0-2)(0-6) = 12
So the y-intercept is (0, 12).
Using this information, we can sketch the graph:
Which type of data (categorical, discrete numerical, continuous numerical) is each of the following variables? (a) Age of a randomly chosen tennis player in the Wimbledon tennis tournament. O Discrete numerical O Continuous numerical O Categorical Which measurement level (nominal, ordinal, interval, ratio) is each of the following variables? (a) A customer's ranking of five new hybrid vehicles (1) Noise level 100 meters from the Dan Ryan Expressway strandomly the moment. (c) Number of occupants in a randomly chosen commuter vehicle on the San Diego Freeway Od to select Od to set Od to select
Continuous numerical values make up the data type for the variable "Age of a tennis player selected at random in the Wimbledon tennis tournament."
Discrete numerical, continuous numerical, and categorical data are the three basic types that can be identified.
- Non-numerical categorical variables, such as gender or eye colour, represent categories or groups.
- Discrete numerical data, such as the number of siblings or pets, are numerical data that can only take on specified values.
Continuous numerical data, like age or weight, are numerical data that can have any value within a range.
Because age can have any value within a range, the data for the variable "Age of a randomly chosen tennis player in the Wimbledon tennis competition" is continuous numerical (for example, a player could be 18.5 years old or 25.2 years old). Hence, continuous numerical data is the right response.
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Find the following answers:
Answer:
Step-by-step explanation:
[tex]\{A\cup B \}=\{1,2,3,7,10,11,12,14,16,17,18,19 \}\\\\\{A \cap B \}=\{ 1,7,10,14\}[/tex]
A∪B: Any element which is in either or both sets.
A∩B: Only elements that are in both A and B.
Which expressions are equivalent to 8(3/4y -2)+6(-1/2+4)+1
Answer: 6y + 6
Step-by-step explanation:
To simplify the expression 8(3/4y -2) + 6(-1/2+4) + 1, we can follow the order of operations (PEMDAS):
First, we simplify the expression within parentheses, working from the inside out:
6(-1/2+4) = 6(7/2) = 21
Next, we distribute the coefficient of 8 to the terms within the first set of parentheses:
8(3/4y -2) = 6y - 16
Finally, we combine the simplified terms:
8(3/4y -2) + 6(-1/2+4) + 1 = 6y - 16 + 21 + 1 = 6y + 6
Therefore, the expression 8(3/4y -2) + 6(-1/2+4) + 1 is equivalent to 6y + 6.
For each random variable defined here, describe the set of possible values for the variable, and state whether the variable is discrete.a. X= the number of unbroken eggs in a randomly chosen standard egg cartonb. Y= the number of students on a class list for a particular course who are absent on the first day of classesc. U= the number of times a duffer has to swing at a golf ball before hitting itd. X= the length of a randomly selected rattlesnakee. Z= the amount of royalties earned from the sale of a first edition of 10,000 textbooksf. Y= the PH of a randomly chosen soil sample g. X= the tension (psi) at which a randomly selected tennis racket has been strungh. X= the total number of coin tosses required for three individuals to obtain a match (HHH or TTT)
a. X= number of unbroken eggs in a standard carton. b. Y= number of absent students on first day of a course. c. U= number of swings before hitting a golf ball. d. X= length of a rattlesnake.
e. Z= royalties earned from selling a first edition of 10,000 textbooks. f. Y= pH of a soil sample. g. X= tension (psi) of a tennis racket. h. X= total coin tosses required for three individuals to get a match.
a. X can take on values 0, 1, 2, 3, 4, 5, 6, as there can be zero to six unbroken eggs in a standard egg carton. X is a discrete random variable.
b. Y can take on values 0, 1, 2, 3, ..., n, where n is the total number of students on the class list. Y is a discrete random variable.
c. U can take on values 1, 2, 3, .... U is a discrete random variable.
d. X can take on any positive real value, as the length of a rattlesnake can vary continuously. X is a continuous random variable.
e. Z can take on any non-negative real value, as the amount of royalties earned can be any non-negative amount. Z is a continuous random variable.
f. Y can take on any value between 0 and 14, as the pH of a soil sample can range from 0 to 14. Y is a continuous random variable.
g. X can take on any positive real value, as the tension at which a tennis racket has been strung can vary continuously. X is a continuous random variable.
h. X can take on values 3, 4, 5, 6, ... as there must be at least three coin tosses and the tosses must continue until a match is obtained. X is a discrete random variable.
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Tom’s yearly salary is $78000
Calculate Tom’s fortnightly income. (Use 26
fortnights in a year.)
Fortnightly income =
$
Tom's fortnightly income is $3000.
What is average?In mathematics, an average is a measure that represents the central or typical value of a set of numbers. There are several types of averages commonly used, including the mean, median, and mode.
To calculate Tom's fortnightly income, we need to divide his yearly salary by the number of fortnights in a year:
Fortnightly income = Yearly salary / Number of fortnights in a year
Fortnightly income = $78000 / 26 = $3000
Therefore, Tom's fortnightly income is $3000.
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question - Calculate the Tom's fortnightly income and yearly salary by the number of fortnights in a year .
PLEASE HELP ME! THIS IS DUE IN 1 MORE HOUR
Answer: False, False, True, True, True.
Step-by-step explanation:
Remember, if there are two intersecting lines on a graph, and they come to one point on a graph, it only has one solution. If two lines are parallel, and don't intersect with each other, they have no solution. If there are two equations, and both are on the same line, then they have infinitely many solutions.
y - 3x = -2, and y = 3x - 2, are equal, since they are one line.
So, the first and second questions are false, since there's only 1 solution, making the third question true. The point (-1, -5), is a true answer, since the x would be -1, and the y would be -5. (Example below.)
y = 3x - 2
y = 3(-1) - 2
y = -3 - 2
y = -5
The two lines in the equations do have the same slope, since the slope for each is 3x. Or think about slope-intercept form, (y = mx + b)
y - 3x = -2, and y = 3x - 2
y - 3x = -2
y = 3x - 2 is equal to y = 3x - 2, which makes this answer true.
Hope this helps, (and can you give brainliest, please?)
If m∠ADB = 110°, what is the relationship between AB and BC? AB < BC AB > BC AB = BC AB + BC < AC
The relationship between AB and BC is given as follows:
AB > BC.
What are supplementary angles?Two angles are defined as supplementary angles when the sum of their measures is of 180º.
The supplementary angles for this problem are given as follows:
<ADB = 110º. -> given<CDB = 70º. -> sum of 180º.By the law of sines, we have that:
AB/sin(110º) = BC/sin(70º).
As sin(110º) > sin(70º), the inequality for this problem is given as follows:
AB > BC.
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Answer:
AB>BC
Step-by-step explanation:
AI-generated answer
Based on the given information, the relationship between AB and BC depends on the measure of angle ZADB. If mZADB is 110°, we can determine the relationship as follows:
Since triangle ABD and triangle CBD share side AB, the larger the angle ZADB, the longer the side AB will be compared to side BC. Therefore, if mZADB is 110°, we can conclude that AB is greater than BC.
In summary, when mZADB is 110°, the relationship between AB and BC is:
AB > BC.
What is the correct numerical expression for "multiply the sum of 7 and 6 by the sum of 4 and 5?"
7 + 6 x 4 + 5
(7 + 6) x (4 + 5)
7 + (6 x 4) + 5
7 + 6 x (4 + 5)
The correct numerical expression for the given statement "multiply the sum of 7 and 6 by the sum of 4 and 5" is (7 + 6) x (4 + 5).
What is an expression?Mathematical statements are called expressions if they have at least two words that are related by an operator and contain either numbers, variables, or both. There are two sorts of expressions in mathematics: numerical expressions, which only contain numbers, and algebraic expressions, which also include variables. A mathematical expression is a phrase that has a minimum of two numbers or variables and at least one mathematical operation.
The given statement, "multiply the sum of 7 and 6 by the sum of 4 and 5", can be represented as:
sum of 7 and 6 = (7 + 6)
sum of 4 and 5 = (4 + 5)
multiply: (7 + 6) x (4 + 5)
Hence, the correct numerical expression for the given statement is (7 + 6) x (4 + 5).
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Answer:
(7 + 6) x (4 + 5).
Step-by-step explanation:
hope this helps!
Q6) The diagram shows a pyramid. The apex of the pyramid is V.
Each of the sloping edges is of length 6 cm.
A
6 cm
2 cm
B
2 cm с
F
6 cm
The base of the pyramid is a regular hexagon with sides of length 2 cm.
O is the centre of the base.
B
2 cm
E
2 cm C
Calculate the height of V above the base of the pyramid.
Give your answer correct to 3 significant figures.
V is 5.92 centimetres above the pyramid's base at its highest point.
What is pyramid?A pyramid is a 3D pοlyhedrοn with the base οf a pοlygοn alοng with three οr mοre triangle-shaped faces that meet at a pοint abοve the base. The triangular sides are called faces and the pοint abοve the base is called the apex. A pyramid is made by cοnnecting the base tο the apex. Sοmetimes, the triangular sides are alsο called lateral faces tο distinguish them frοm the base. In a pyramid, each edge οf the base is cοnnected tο the apex that fοrms the triangular face.
Give the altitude the letter h. Next, we have:
tan(60) = h/2
Simplifying, we get:
h = 2 tan(60) = 2 √(3)
The Pythagorean theorem yields the following:
[tex]$\begin{align}{{V O^{2}+O F^{2}=V F^{2}}}\\ {{V O^{2}+1^{2}=6^{2}}}\\ {{V O^{2}=35}}\end{align}$[/tex]
Taking the square root of both sides, we get:
VO ≈ 5.92 cm
Rounding to three significant figures, we get:
VO ≈ 5.92 cm
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54.2 consider the competing species model, equaltion 54.1 sketch the phase plane and the trajectories of both population
To sketch the phase plane and trajectories of both populations in the competing species model, plot the population of one species on the x-axis and the population of the other species on the y-axis. Then, plot the isoclines and use them to determine the direction and stability of the population trajectories.
The competing species model is a system of two differential equations that describe the population dynamics of two species competing for the same resources. To sketch the phase plane and trajectories, plot the population of one species on the x-axis and the population of the other species on the y-axis. Then, plot the isoclines, which are curves that represent the values of one species' population at which the other species' population does not change.
The isoclines are found by setting each differential equation to zero and solving for one population in terms of the other. For example, the isocline for species 1 is found by setting dN1/dt = 0 and solving for N2. The resulting equation gives the values of N2 at which the population of species 1 does not change. Plotting these curves on the phase plane divides it into regions where the population of each species increases or decreases.
The direction and stability of the population trajectories can be determined by analyzing the slope of the vector field, which represents the rate of change of the population at each point in the phase plane. Trajectories move in the direction of the vector field, and their stability depends on the curvature of the isoclines. If the isoclines intersect at a single point, it is a stable equilibrium where both populations coexist. If they intersect at multiple points, the stable equilibrium depends on the initial conditions of the populations. If they do not intersect, one species will eventually drive the other to extinction.
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--The question is incomplete, answering to the question below--
"Consider the competing species model, how to sketch the phase plane and the trajectories of both population"
Standard Error of the Mean =
Confidence Interval Estimate for the Mean
Margin of Error E= Z
= Z. V
±Z
You want to rent a one-bedroom apartment near BCIT for next term. The mean monthly rent for a random sample of 36 apartments advertised for rent on Craigslist is $1,235. Assume that the population standard deviation is $150.
(a) Give the point estimate of the true mean monthly rent for one-bedroom
apartments available for rent near BCIT.
Answer=$
(b) At the 95% confidence level, what is the margin of error on your estimate of the true mean monthly rent for one-bedroom apartments available for rent near
BCIT.
Answer=$
(c) Construct a 95% confidence interval for the true mean monthly rent for one-bedroom apartments.
Lower value=$
Upper value=$
Choose the correct statement to interpret the confidence interval.
• I am totally confident that the population mean belongs to this confidence interval.
• I am 95% confident that the true population mean belongs to this confidence interval.
(d) A friend claims the average monthly rent for a one-bedroom apartment available for rent near BCIT is at least $1,300. Based on your confidence interval do you agree?
• Yes
• No
(e) What is the z-score used to construct a 92% confidence interval?
Answer= (Enter a positive value in 2 decimal places)
"I am 95% convinced that the true population mean corresponds to this confidence interval," is the appropriate sentence to use when interpreting the confidence interval.
What does the statistical term "population" mean?Each whole group that shares at least one trait is referred to be a population. People do not make up all populations. Individuals, animals, groups, organisations, edifices, edifices, buildings, houses, farms, items, or events can all be considered populations.
As a rough estimate, the true mean monthly rent is $1,235.
At a 95% confidence level, the critical value (Z) for a two-tailed test is 1.96. The margin of error can be calculated as follows:
The 95% confidence interval can be obtained as follows:
CI = 1235 1.96*(150/36) CI = X Z*(n/n)
Lower value: 1.96 * (150/36) * 1235 = $1,175.20
Higher value: $1,294.80 = 1235 + 1.96 * (150/36).
Higher value: $1,294.80; Lower value: $1,175.20
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