A popular beach erodes 4 inches per year on average.

An eroding beach.
A. How many years will it take for the coastline to erode one foot?

Answer: See explanation

Step-by-step explanation:

1. Use the five steps of hypothesis testing.

Step 1: The aim of the research is to conduct the five steps of hypothesis testing.

Step 2:

Null hypothesis: H0 u= 4

Population mean: H1 u = 4

Alternate hypothesis: u ≠ 4

Population mean: u ≠ 4

Step 3 and step 4 are attached.

Step 5: Based on the calculation, the calculated value of t is less than the t critical value, therefore, the null hypothesis will be failed to be rejected.

2. Sketch the distributions involved

This has been attached.

3. Explain the logic of what you did to a person who is familiar with hypothesis testing, but knows nothing about t tests of any kind.

The distribution is "t".

The means is tested by using T-test.

Chi-square is used to test the single variance.

Answer:

a) Because this asks about the radius and height, I assume that we are talking about a cylinder shape.

Remember that for a cylinder of radius R and height H the volume is:

V = pi*R^2*H

And the surface will be:

S = 2*pi*R*H + pi*R^2

where pi = 3.14

Here we know that the volume is 1000cm^3, then:

1000cm^3 = pi*R^2*H

We can rewrite this as:

(1000cm^3)/pi = R^2*H

Now we can isolate H to get:

H = (1000cm^3)/(pi*R^2)

Replacing that in the surface equation, we get:

S = 2*pi*R*H + pi*R^2

S = 2*pi*R*(1000cm^3)/(pi*R^2) + pi*R^2

S = 2*(1000cm^3)/R + pi*R^2

So we want to minimize this.

Then we need to find the zeros of S'

S' = dS/dR = -(2000cm^3)/R^2 + 2*pi*R = 0

So we want to find R such that:

2*pi*R = (2000cm^3)/R^2

2*pi*R^3 = 2000cm^3

R^3 = (2000cm^3/2*3.14)

R = ∛(2000cm^3/2*3.14) = 6.83 cm

The radius that minimizes the surface is R = 6.83 cm

With the equation:

H = (1000cm^3)/(pi*R^2)

We can find the height:

H = (1000cm^3)/(3.14*(6.83 cm)^2) =  6.83 cm

(so the height is equal to the radius)

b) The surface equation is:

S = 2*pi*R*H + pi*R^2

replacing the values of H and R we get:

S = 2*3.14*(6.83 cm)*(6.83 cm) + 3.14*(6.83 cm)^2 = 439.43 cm^2

c) Because if we pack cylinders, there is a lot of space between the cylinders, so when you store it, there will be a lot of space that is not used and that can't be used for other things.

Similarly for transport problems, for that dead space, you would need more trucks to transport your ice cream packages.

Answer:

an arithmetic sequence

Step-by-step explanation:

an arithmetic series is wrong also heres an example i found of an arithmetic sequence

The terms in the given sequence represents an arithmetic sequence.

Arithmetic sequence is a sequence of numbers where the numbers are arranged ion a definite order such that the difference of two consecutive numbers is a constant. This constant of difference is called common difference which is commonly denoted by the letter 'd'.

Given sequence of numbers is,

-8, -4, 0, 4, 8, 12, ......

We have to find which sequence does it represent.

This is not a series since they are not represented as the sum.

If the sequence is a geometric sequence, then the ratio of consecutive numbers will be same.

If it is arithmetic sequence, then the difference of consecutive numbers will be same.

Here, ratio is not same.

Difference are same.

-4 - -8 = 4, 0 - -4 = 4, 4 - 0 = 4, 8 - 4 = 4, ........

Common difference is 4.

Hence it is an arithmetic sequence.

Learn more about arithmetic Sequence here :

https://brainly.com/question/15412619

#SPJ3

Answer:

12

Step-by-step explanation:

113.04=3.14 x 3^2 x h/3

Answer:

4x-5=4x-5

Step-by-step explanation:

Answer:

3 sqrt(3) =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj / hyp

cos 30 = x/6

6 cos 30 = x

6 ( sqrt(3)/2) = x

3 sqrt(3) =x

Answer:

a

Step-by-step explanation:

Complete Question:

A soft-drink vendor at a popular beach analyzes his sales records, and finds that if he sells x cans of soda pop in one day, his profit (in dollars) is given by P(x) = -0.001x² + 3x - 1800.

a. What is his maximum profit per day?

b. How many cans must be sold in order to obtain the maximum profit?

Answer:

a. $450

b. 1500 cans

Step-by-step explanation:

Given the following quadratic function;

P(x) = -0.001x² + 3x - 1800  ......equation 1

a. To find his maximum profit per day;

Since P(x) is a quadratic equation, P(x) would be maximum when [tex] x = \frac {-b}{2a} [/tex]

Note : the standard form of a quadratic equation is ax² + bx + c = 0  ......equation 2

Comparing eqn 1 and eqn 2, we have;

a = -0.001, b = 3 and c = -1800

Now, we determine the maximum profit;

[tex] x = \frac {-b}{2a} [/tex]

Substituting the values, we have;

[tex] x = \frac {-3}{2*(-0.001)} [/tex]

Cancelling out the negative signs, we have;

[tex] x = \frac {3}{2*0.001} [/tex]

[tex] x = \frac {3}{0.002} [/tex]

x at maximum = 1500

Substituting the value of "x" into equation 1;

P(1500) = -0.001 * 1500² + 3(1500) - 1800

P(1500) = -0.001 * 2250000 + 4500 - 1800

P(1500) = -2250 + 2700

P(1500) = $450

b. Therefore, the soft-drink vendor must sell 1500 cans in order to obtain the maximum profit.

Answer:

f(3) = g(3)

General Formulas and Concepts:

Algebra I

Functions

Step-by-step explanation:

We can see from the graph that the lines intersect at (3, 6). If this is the case, then that means that when x = 3 for both functions, it outputs f(x) = 6.

Rewriting this in terms of function notation:

f(3) = 6, g(3) = 6

∴ f(3) = g(3)

Answer:

732 samples ;

752 samples

Step-by-step explanation:

Given :

α = 90% ; M.E = 0.03 ; p = 0.58 ; 1 - p = 1 - 0.58 = 0.42

Using the relation :

n = (Z² * p * (1 - p)) / M.E²

Zcritical at 90% = 1.645

n = (1.645² * 0.58 * 0.42) / 0.03²

n = 0.65918769 / 0.0009

n = 732.43076

n = 732 samples

B.)

If no prior estimate is given, then p = 0.5 ; 1 - p = 1 - 0.5 = 0.5

n = (Z² * p * (1 - p)) / M.E²

Zcritical at 90% = 1.645

n = (1.645² * 0.5 * 0.5) / 0.03²

n = 0.67650625 / 0.0009

n = 751.67361

n = 752 samples

Answer:

The answer is "0.1397".

Step-by-step explanation:

[tex]\mu=3511\\\\[/tex]

variance [tex]\ S^2= 253,009\\\\[/tex]

standard deviation [tex]\sigma =\sqrt{253,009}=503\\\\[/tex]

Finding the probability in which the weight will be less than [tex]4617 \ grams\\\\[/tex]

[tex]P(X<4617)=p[z<\frac{4617-3511}{503}]\\\\[/tex]  

                      [tex]=p[z<\frac{1106}{503}]\\\\=p[z< 2.198]\\\\= .013975\approx 0.1397[/tex]

9514 1404 393

Answer:

  C.  h ≥ 1.9 in

Step-by-step explanation:

As the final step, divide both sides of the inequality by 5.3:

  (5.3h)/5.3 ≥ 10/5.3

  h ≥ 1.9

Answer:

13/16 miles per minute

Step-by-step explanation:

Take the miles and divide by the minutes

1/8 ÷ 2/13

Copy dot flip

1/8 * 13/2

13/16 miles per minute

Answer:

[tex]\displaystyle \frac{d}{dx}[x^2] = 2x[/tex]

General Formulas and Concepts:

Calculus

Differentiation

Basic Power Rule:

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle y = x^2[/tex]

Step 2: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

9514 1404 393

Answer:

  A)  (2, ∞) . . . . or C) (-∞, 0) ∪ (2, ∞) if you don't think about it

Step-by-step explanation:

We want ...

  C(x)/x < 100

  (20x +160)/x < 100

  20 +160/x < 100 . . . . . separate the terms on the left

  160/x < 80 . . . . . . . subtract 20

  160/80 < x . . . . . multiply by x/80 . . . . . assumes x > 0

  x > 2 . . . . . . simplify

In interval notation this is (2, ∞).   matches choice A

__

Technically (mathematically), we also have ...

  160/80 > x . . . . and x < 0

which simplifies to x < 0, or the interval (-∞, 0).

If we include this solution, then choice C is the correct one.

_____

Comment on the solution

Since we are using x to count physical items, we want to assume that the practical domain of C(x) is whole numbers, where x ≥ 0, so this second interval is not in the domain of C(x). That is, the average cost of a negative number of items is meaningless.

Answer:

Using the slope intercept formula, we can see the slope of line p is ¼. Since line k is perpendicular to line p it must have a slope that is the negative reciprocal. (-4/1) If we set up the formula y=mx+b, using the given point and a slope of (-4), we can solve for our b or y-intercept. In this case it would be 17.

Complete Question

The quality control manager at a computer manufacturing company believes that the mean life of a computer is 91 months with a standard deviation of 10 months if he is correct. what is the probability that the mean of a sample of 68 computers would differ from the population mean by less than 2.08 months? Round your answer to four decimal places. Answer How to enter your answer Tables Keypad

Answer:

[tex]P(-1.72<Z<1.72)=0.9146[/tex]

Step-by-step explanation:

From the question we are told that:

Population mean \mu=91

Sample Mean \=x =2.08

Standard Deviation \sigma=10

Sample size n=68

Generally the Probability that The  sample mean  would differ from the population mean

P(|\=x-\mu|<2.08)

From Table

[tex]P(|\=x-\mu|<2.08)=P(|z|<1.72)[/tex]

T Test

[tex]Z=\frac{\=x-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]

[tex]Z=\frac{2.08}{\frac{10}{\sqrt{68} } }[/tex]

[tex]Z=1.72[/tex]

[tex]P(|\=x-\mu|<2.08)=P(|z|<1.72)[/tex]

[tex]P(-1.72<Z<1.72)[/tex]

Therefore From Table

[tex]P(-1.72<Z<1.72)=0.9146[/tex]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The graph of g(x) is a vertically scaled version of the graph of f(x). The scale factor is 1/2, so vertical height at a given value of x is 1/2 what it is for f(x). This will make the graph appear shorter and fatter than for f(x).

The graph of g(x) is attached.

Answer:

6

Step-by-step explanation:

We need to evaluate :-

[tex]\rm\implies \displaystyle\rm\sum^4_n (-1)^n (3n + 2 ) [/tex]

Here the [tex]\Sigma[/tex] is the sum operator . And here we need to find the sum from n = 1 to n = 4 . We can write it as ,

[tex]\rm\implies (-1)^1 ( 3*1 +2) + (-1)^2 ( 3*2+2) + (-1)^3(3*3+2) + (-1)^4(3*4+2) [/tex]

Now we know that for odd powers of -1 , we get -1 and for even powers we get 1 . Therefore ,

[tex]\rm\implies -1 ( 3 + 2 ) + 1 (6+2)+-1(9+2)+1(12+2)[/tex]

Now add the terms inside the brackets and then multiply it with the number outside the bracket . We will get ,

[tex]\rm\implies -1 * 5 + 1 * 8 + -1*11 + 1*14 \\\\\rm\implies -5 + 8 - 11 + 14 \\\\\rm\implies\boxed{\quad 6 \quad}[/tex]

Hence the required answer is 6.

Answer:

we need a picture...

Step-by-step explanation:

Answer:

x = 16

Step-by-step explanation:

7(x + 2) = 6(x + 5)

First, to start solving this problem, we have to distribute the "7" to the "x + 2" in the parenthesis and the "6" to the "x + 5" in the parenthesis.

7x + 14 = 6x + 30

Next, let's subtract "6x" from both sides of this equation!

x + 14 = 30

Now, we have to subtract "14" from both sides of the equation.

x = 16

Lastly! Let's make sure our "x=" equation is correct by inputting our value into the "x" values.

7(16 + 2) = 6(16 + 5)

7(18) = 6(21)

126 = 126

Since our equations equal each other we know that our x-value is correct!

Hope this Helps! :)

Have any questions? Ask below in the comments and I will try my best to answer.

-SGO

Answer:

300

Step-by-step explanation:

Answer:

$3240

Step-by-step explanation:

hope it is well understood

Answer: 59300

Step-by-step explanation:

Answer:

Step-by-step explanation:

The formula for this is

[tex]A(t)=P(1+r)^t[/tex] and we have everything but the P. Filling in:

[tex]1469=P(1+.038)^{30[/tex] and

[tex]1469=P(1.038)^{30[/tex] and

1469 = P(3.061403718) so

P = 479.85

Answer:

a.

[tex] log_{5}( {u}^{3 \times {v}^{4} } ) [/tex]

b.

[tex] ln( \frac{1}{( {x}^{2} - 2x + 1 } ) [/tex]

c.

[tex] log_{2}(x { \sqrt{3x - 2} }^{4} ) [/tex]

Answer:

ind the center and radius of the sphere: x2 + y2 +z2-8x + 2y + 62+1 0 2) Find an equation of the sphere that passes through the point (6,-2, 3) and has center (-1,2, 1). Find the curve in which the sphere from #2 intersects the yz-plane. For #4-11, u : ? + j-2k 4) 2u +3v 5) Iv 6) uv and v-3i-2j + k 8) Ivxu 9) comp,v 10) proju 11) Find the angle between u and v 12) Find the scalar triple product of a, b, and c. If a (3, 1,2), b (-1,1,0), and c (0,0,-4) 13) Find the values of x such that (3,2, x) and (2x, 4, x) are orthogonal 14) Find two unit vectors that are orthogonal to both j + 2k and i-2j+3k 15) Find the acute angle between two diagonals of a cube 16) Find a vector perpendicular to the plane through the points A(1,0,0), B(2,0,-1) and C(1,4,3) 17) Find parametric equations for the line through (4,-1, 2) and (1, 1, 5) 18) Find parametric equations for the line through (-2, 2, 4) and perpendicular to the plane 2x-y+5z 12 19) Find an equation of the plane through (2, 1,0) and parallel to x + 4y -3z 1 20) Find an equation of the plane through (3, -1, 1), (4, 0, 2), and (6, 3, 1). 21) Show that the planes x y-z 1 and 2x 3y + 4z 5 are neither parallel nor perpendicular. Find the angle between the planes.

Answer: 25

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

1 : 1 :sqrt(2)

The legs are  in the ratio of 1 to 1

tan 45 = opp side / adj side

tan 45 = 1/1

tan 45 =1

Answer:

Step-by-step explanation: