A proton moves along the x-axis with v_x=1.0×10^7m/s. As it passes the origin, what are the strength and direction of the magnetic field at the (0 cm, 1 cm, 0 cm) position? Give your answer using unit vectors.

Answers

Answer 1

Here ya go! i think this will help!

A Proton Moves Along The X-axis With V_x=1.010^7m/s. As It Passes The Origin, What Are The Strength And
A Proton Moves Along The X-axis With V_x=1.010^7m/s. As It Passes The Origin, What Are The Strength And

Related Questions

A spring of spring constant k=8.25N/m is displaced from equilibrium by a distance of 0.150 m. What is the stored energy in the form of spring potential energy?

Answers

PE is the potential energy stored in the spring, k is the spring constant, and x is the  PE is the potential energy stored in the spring, k is the spring constant, and x is the displacement from equilibrium.

What is a displacement?

Displacement is a vector quantity that describes the overall change in position of an object from its initial position to its final position. It is a vector because it has both magnitude (the distance between the initial and final positions) and direction (the direction from the initial position to the final position).

For example, if an object moves from point A to point B, its displacement is the vector that points from A to B, regardless of the path taken to get there. Displacement can be positive, negative, or zero, depending on the direction of the vector.

Displacement is often used in kinematics, which is the study of motion without considering the forces that cause the motion. It is a key concept in describing the motion of objects in one, two, or three dimensions.

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What would the best cost to each person in the United States given that the total cost is •10^14 dollars

Answers

Answer:

3,012,955.71 USD per person

Explanation:

The U.S. as of 2021 had 331.9 million inhabitants

Total cost of 10^14 USD to be divided by 331.9m inhabitants to obtain the cost per person

3,012,955.71 USD per person

5. In the diagram below, Aircraft A is flying East and maintaining a groundspeed of 340 kt (a kt = speed of 1 NM / hr). Aircraft B is flying in the same direction as aircraft A but 210 NM ahead, maintaining a ground speed of 280 kt. Aircraft A will catch Aircraft B at Point ‘X’. What distance will Aircraft B have travelled when this event occurs?

Answers

For the event to occur, Aircraft B will have travelled a distance of 980 NM.

How to calculate distance?

Since Aircraft A is flying East, we can assume that the positive direction is to the East and negative direction is to the West. Let's assume that the position of Aircraft A is x and position of Aircraft B is x + 210 NM.

Let t be the time it takes for Aircraft A to catch up with Aircraft B. At that moment, both aircraft will be at the same position, so:

distance traveled by Aircraft A = distance traveled by Aircraft B

Ground speed x time = Ground speed x time + 210

Using the given ground speeds, we can set up the equation as:

340t = 280t + 210

60t = 210

t = 3.5 hours

Therefore, Aircraft B will have traveled a distance of:

distance = ground speed x time

distance = 280 kt x 3.5 hr

distance = 980 NM

So, Aircraft B will have traveled 980 NM when Aircraft A catches up with it at Point X.

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Which correctly describes a different evolutionary stage of a star like the sun?

A) it’s forms from a cold, dusty molecular cloud

B) During a yellow giant stage, it burns carbon in its core and helium in the shell surrounding the core.

C) After leaving the main sequence, its core is stable due to electron degeneracy

D) It becomes a white dwarf after exploding as a supernova

E)During a red giant stage, its core contracts and cools

Answers

Answer:

Explanation:

The correct option that describes a different evolutionary stage of a star like the sun is:

D) It becomes a white dwarf after exploding as a supernova

This is because a star like the sun does not have enough mass to undergo a supernova explosion. After it has exhausted all the fuel in its core, it will evolve into a red giant and then a planetary nebula, leaving behind a small, hot, dense remnant known as a white dwarf. Supernovae occur in much more massive stars that have cores that can collapse to form a neutron star or black hole.

true/false. A nuclear family includes a pair of adults, their children, and any grandparents who live in the family.

Answers

The nuclear family is considered the most essential family unit because it is the family unit with the most fundamental relationships. that's why the Given statement is False.

In a nuclear family, parents and their children live in a household. A nuclear family is a type of family structure that consists of a pair of adults and their children, but not grandparents who live in the family.

It is also called the traditional family, and it is considered to be the basic family unit.A nuclear family is a small family consisting of two parents and their children.

A nuclear family is often known as the basic family unit since it is a family structure consisting of two parents and their children. It is also considered the most prevalent family structure in many countries around the world.

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Problem 23.13 One type of antenna for receiving AM radio signals is a square loop of wire, 0.16 m on a side, that has 20 turns. Part A If the magnetic field from the radio waves changes at a rate of 8.4 × 10-4 T/s and is perpendicular to the loop, what is the magnitude of the induced emf in the loop? Express your answer to two significant figures and include appropriate units. Value Units Submit My Answers Give Up back Continue

Answers

The induced emf by the formula that we have can be obtained as 4.3 * 10^-4 V.

What is the induced emf?

The induced emf (electromotive force) is the voltage that is generated in a conductor when there is a change in the magnetic field that surrounds the conductor. This phenomenon is known as electromagnetic induction and was discovered by Michael Faraday in the 19th century.

The induced emf is created by the interaction between the magnetic field and the moving charges in the conductor. When the magnetic field changes, it creates an electric field that pushes the charges in the conductor, creating a current flow.

Using emf = NAdB/dt

= 20 * (0.16)^2 *  8.4 × 10-4 T/s

4.3 * 10^-4 V

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At one instant an object in free fall is moving downward at 50 meters per second. One second later its speed is about
A) 25 m/s. B) 50 m/s. C) 55 m/s. D) 60 m/s. E) 100 m/s.

Answers

The correct answer is C) 55 m/s. An object in free fall accelerates due to gravity, which means its speed increases by about 9.8 m/s2 every second. So in one second, its speed increased from 50 m/s to 50 + 9.8 = 59.8 m/s. Since it is impossible for the object to have a speed of 59.8 m/s, the closest answer is C) 55 m/s.


Given,An object in free fall is moving downward at 50 meters per second.At one-second later its speed is about.To find: The speed of the object at one second laterSolution:Let us assume that the object moves with an acceleration of ‘g’.Given, Initial velocity, u = 50 m/s

Time taken, t = 1sWe know that the velocity of an object in freefall is given by:v = u + gtFrom the above equation, we can calculate the final velocity of the object after one secondv = u + gtv = 50 + 9.8 × 1v = 50 + 9.8v = 59.8 ≈ 60 m/sTherefore, the final velocity of the object after one second is 60 m/s.Hence, the correct option is (D) 60 m/s.

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If pulse 1 were reflected from a wall, which one of the patterns above would represent the reflected pulse? A) 1 B) 2 C) 3 D) 4 E) 5

Answers

If pulse 1 is reflected from a wall, pattern 2 would represent the reflected pulse. This is because when a wave is reflected from a fixed end, its amplitude is inverted. So, pattern 2 represents the reflection of pulse 1 from a fixed end.

A pulse is a short burst of energy that travels through space or matter. These bursts of energy can come in many different forms, including sound waves, light waves, and even electromagnetic radiation. In the context of waves, a pulse refers to a single disturbance that propagates through a medium. The reflection of waves refers to the behavior of waves that encounter a barrier or a discontinuity in a medium that causes them to return to their original medium. When waves are reflected, their direction of motion changes, and they experience a change in amplitude, phase, and polarization.

The amplitude of the reflected wave is related to the amplitude of the incident wave, as well as to the reflectivity of the medium. The reflection of waves is an essential phenomenon in many fields of science and engineering. For example, it is essential in optics, where it is used to form images in mirrors and lenses. It is also important in acoustics, where it is used to analyze the characteristics of sound waves. In addition, the reflection of waves is a critical aspect of the design of structures such as bridges and buildings, where it can help to reduce the impact of seismic waves during an earthquake.

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a battleship simultaneously fires two shells at enemy ships. if the shells follow the parabolic trajectories shown, which ship gets hit first?

Answers

A battleship simultaneously fires two shells in parabolic projectile motion and no information about initial speeds at enemy ships. The ship B got hit first. So, the correct choice for answer is option (c).

Here is we have a battleship Which fires two shells simultaneously at the enemy ship along the two paths. The initial speed of projection may be same or different. See the above figure carefully, the angle of projection for ship A is more than ship B. Time of flight for ship A is

[tex]T_A = \frac{ 2u_{A} sinθ_{A}}{g }[/tex]

For ship B, [tex]T_B = \frac{2u_B sinθ_{B}}{g }[/tex]

We have no idea about the initial speed of projection, so we cannot consider it for comparison. As we know from above,

[tex]θ_{A} > θ_{B}[/tex]

=> [tex]sinθ_{A} > sinθ_{B}[/tex]

So, [tex]T_{A} > T_{B}[/tex]

That is time of flight for ship A is greater than for the ship B. Therefore, ship B gets hit first.

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Complete question:

A battleship simultaneously fires two shells at enemy ships. if the shells follow the parabolic trajectories shown, which ship gets hit first?

a) A

b) both simultaneously

c) B

d) None

What is the
equivalent
capacitance of this
combination?
(Remember, μ means 10-6.)
HHH
25 μF 15 μF
[?] × 10²¹ F
X

Answers

The equivalent capacitance of this combination is 9.375 μF, or 9.375 × 10⁻⁶ F in scientific notation.

What is capacitor ?

A capacitor is an electronic component that stores electrical energy in an electric field. It consists of two conductive plates separated by a non-conductive material, called a dielectric. When a voltage is applied to the capacitor, electric charge builds up on the plates, creating an electric field between them. The amount of charge that can be stored on the plates depends on the capacitance of the capacitor, which is determined by the size and spacing of the plates, as well as the properties of the dielectric material.

When capacitors are in series, their effective capacitance is given by:

1/C_series = 1/C_1 + 1/C_2 + ...

In this case, we have two capacitors in series, with capacitances of 25 μF and 15 μF:

1/C_series = 1/25μF + 1/15μF

1/C_series = (15 + 25)/(1525μF²)

1/C_series = 40/(375*μF²)

C_series = 375*μF²/40

C_series = 9.375 μF

Therefore, the equivalent capacitance of this combination is 9.375 μF, or 9.375 × 10⁻⁶ F in scientific notation.

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Given a = 31+4j- k and b= 1 - 3j+ k,
find a unit vector n normal to the plane
containing a and b such that a, b and n in that form a right handed system

Answers

Unit vector n is (7/√6206)i - (30/√6206)j - (97/√6206)k and is a right handed system because of its positive value.

How to determine unit vector?

To find a unit vector n normal to the plane containing a and b, we need to take the cross product of a and b:

a × b =

| i j k |

| 31 4 -1 |

| 1 -3 1 |

= (4×1 - (-1)×(-3))i - (31×1 - (-1)×1)j + (31×(-3) - 4×1)k

= 7i - 30j - 97k

To make this a unit vector, we need to divide it by its magnitude:

|n| = √(7² + (-30)² + (-97)²) = √(6206)

n = (7/√6206)i - (30/√6206)j - (97/√6206)k

To check that this forms a right-handed system with a and b, we can take their dot product:

a · (b × n) =

(31+4j-k) · (7i-30j-97k) =

31×7 + 4×(-30) + (-1)×(-97) = 505

Since this is a positive value, we can conclude that a, b, and n form a right-handed system.

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center of mass vs gravity ​

Answers

In most mechanics problems the gravitational field is assumed to be uniform. The center of gravity is then in exactly the same position as the center of mass. The terms center of gravity and center of mass tend to often be used interchangeably since they are often at the same location

This hair-dryer has a plastic case. It is connected to a mains socket by a 3-pin plug.
The cable connecting the hair-dryer to the plug contains only two wires.
Write down the colour of the insulation on the wires.
Wire 1
Wire 2
(ii)
Which of the usual three wires is not needed?
=
This hair-dryer is safe to use without the third wire. Explain why.

Answers

Wire 1 and Wire 2 are typically insulated with one of three standard colors: black, white, or red.

The wire that is not needed is the earth wire, which is typically green or yellow with green stripes. The earth wire is used for safety purposes to provide a path for current to flow to the ground in case of a fault or short circuit, but is not strictly necessary for the operation of the hair-dryer.

The hair-dryer is safe to use without the earth wire because it is double-insulated. This means that the hair-dryer has two layers of insulation between the live and neutral wires and the outer casing, which provides an extra level of protection against electrical shocks. Double-insulated appliances are designed to operate safely without the need for an earth wire, and are marked with a symbol consisting of a square inside another square to indicate this.

What is an earth wire?

An earth wire, also known as a ground wire or protective earth (PE) wire, is a safety wire used in electrical wiring systems. It is designed to provide a path for electrical current to flow to the ground in the event of an electrical fault, such as a short circuit or a surge.

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I actually have 3 questions. >33

1. Write about a time when you felt very cold and did something to make yourself feel warm, or a time when you felt hot and did something to cool yourself down. What caused the heat to transfer from one place to another place? How did this transfer of heat cause a change in temperature?

2. Why is the temperature of the liquid in the flask on the previous page measured when the liquid in the thermometer has stopped rising?

3. How can the thermometer in the flask on the previous page be used to demonstrate the relationship between heat transfer and kinetic energy? Explain.

Answers

When you contact anything hot, the heat is transmitted from the object to your hand, making it feel hot. When you contact something cold, heat is transmitted from your hand to the object, making it feel chilly.

When heated the molecules of the liquid move faster causes them to get a little further apart?

when heated, the molecules of the liquid in the thermometer move faster, causing them to get a little further apart. this results in movement up the thermometer. when cooled, the molecules of the liquid in the thermometer move slower, causing them to get a little closer together.

When the liquid in the thermometer is heated, the molecules move quicker, forcing them to move wider apart. This causes the thermometer to rise. When the liquid in the thermometer is chilled, the molecules travel slower, leading them to get closer together.

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A person with a mass of 55.0 kg jumps straight upwards, gaining 820.0 J of gravitational potential energy. How high did the person jump?

Answers

m=55.0 D=820 so were are looking for the velocity ? v= m\d V = 55.0*820 =45100 ...

Two long parallel wires placed side by side on a horizontal table carry the same currents in opposite directions. The wire on your right carries current toward you, and the wire on your left carries current away from you. Determine the direction of the magnetic field at the point exactly midway between the two wires from your point of view. Explain your answer with the aid of labelled diagram. [5 marked​

Answers

To find:-

Magnetic field at the centre between the wires.

Answer:-

We are here given that two long current carrying wires are having same current. We need to find out the magnetic field at the centre between the wires .

We know that for a point between two ends of a wire , magnetic field is given by,

[tex]\implies B =\dfrac{\mu_0}{4\pi}\dfrac{2i}{d}\\[/tex]

where ,

B is magnetic field.i is the current.d is the distance .

Now since magnetic field is a vector quantity we need to find out the direction of the field . We can do so by using Right Hand thumb rule .

Right hand thumb rule :-

Hold the wire , in your hand with thumbs towards the direction of the current, then the curling of the fingers would give you the direction of the magnetic field.

For wire AB :-

The direction comes to be down the page .

For wire CD :-

The direction comes to be down the page .

Calculating net magnetic field:-

The net magnetic field will be the sum of both the fields .

[tex]\implies B_{net}=\dfrac{\mu_0}{4\pi}\dfrac{2i}{d}+\dfrac{\mu_0}{4\pi}\dfrac{2i}{d} \\[/tex]

[tex]\implies B_{net}=\dfrac{\mu_0}{4\pi}\dfrac{4i}{d}\\[/tex]

[tex]\implies \underline{\underline{\green{ B_{net}=\dfrac{\mu_0i}{ \pi d}}}}\\[/tex]

The direction is down the page .

and we are done!

For small bodies with high thermal conductivity, the features surrounding the medium that favor lumped system analysis
The medium should be a poor conductor of heat
The medium should be motionless

Answers

Small bodies with high thermal conductivity, the medium should be a poor conductor of heat and should be motionless in order to favour lumped system analysis.

For small bodies with high thermal conductivity, the features surrounding the medium that favor lumped system analysis are that the medium should be a poor conductor of heat and the medium should be motionless.

In other words, for small bodies with high thermal conductivity, the thermal energy will stay confined within the boundaries of the medium if it is a poor conductor of heat and the medium is not moving. This allows the energy to be spread evenly throughout the system, which is why lumped system analysis can be used.

Lumped system analysis is a method used to analyse heat transfer and energy flow within a system. It assumes that thermal energy is transferred across a body of homogeneous material and can be used to calculate the temperature of an object at different points in the body.

The effectiveness of this method relies on the heat capacity of the medium and its thermal conductivity, which is why it is most suitable for small bodies with high thermal conductivity.

For large bodies, or bodies with low thermal conductivity, distributed system analysis is typically used instead of lumped system analysis. This method assumes that the body has different thermal properties at different points, and calculates the temperature at those points based on their respective thermal properties.

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A tiny solid ball (I = (2/5)Mr^(2)) rolls without slipping on the inside surface of a hemisphere as shown in Fig. 10-12. (The ball is much smaller than shown.) If the ball is released at A, how fast is it moving as it passes (a) point-B, and (b) point-C? Ignore friction losses. [Hint: Study the two previous questions. When it comes to the ball’s descent, its own radius is negligible.]

Answers

At point B, the ball is moving at a speed of around 2.05 m/s. At point C, the ball is moving at a speed of roughly 3.67 m/s.

Is velocity the same as speed?

Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion.

(a) The ball has plummeted to a height at point B of h = r(1 - cos), where r is the hemisphere's radius and is the angle formed by the vertical and the line connecting A and B.

The ball loses as much potential energy as it gains in kinetic energy:

mgh = (1/2)mv² + (1/2)Iω²

Since the ball is rolling without slipping, we have v = rω. Also, for a solid sphere or ball, I = (2/5)mr^2.

By simplifying and substituting these formulas, we obtain:

mgh = (7/10)mv²

Solving for v, we get:

v = √((10/7)gh)

Substituting the given values, we get:

v = √((10/7) x 9.8 m/s² x 0.5 m x (1 - cos(30°)))

≈ 2.05 m/s

(b) The ball has dropped through a height of h = 2r at point C. Applying the same simplifications and conservation of energy equation as before, we arrive at:

mgh = (7/5)mv²

Solving for v, we get:

v = √((5/7)gh)

By simplifying and substituting these formulas, we obtain:

v = √((5/7) x 9.8 m/s² x 1.0 m)

≈ 3.67 m/s.

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When a water heater is rated to operate at 240 volts but is operated at 208 volts, the water heater will take___ time to heat the water.Select one:a. moreb. the samec. less

Answers

a. more When a water heater is rated to operate at 240 volts but is operated at 208 volts, the lower voltage means that the heating element in the water heater will not receive as much power as it is designed.

What is a power ?

Power is the rate at which work is done or energy is transferred, typically measured in watts or horsepower. It represents the amount of energy used or transferred per unit time.

Mathematically, power is defined as the product of force and velocity, or the product of current and voltage. The unit of power is the watt (W), which is equal to one joule of energy per second.Power is an important concept in physics, engineering, and technology. It is used to describe the output of engines, motors, generators, and other devices that convert energy from one form to another. In everyday life, power is used to measure the rate at which electricity is consumed by appliances and electronics, and to compare the performance of different machines and tools.

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Please do help me. Nonsense answers will be reported.

An object is thrown horizontally with a speed of 30 m/s from the top of a building. Complete the table below for the indicated time interval. Use g≈ 10 m/s²)​

Answers

The time that was taken for the movement of the item is observed as 3 seconds.

How do you use the equations of motion?

The equations of motion describe the motion of objects in terms of their position, velocity, acceleration, and time.

For the equation;

v = u + at

This equation relates the final velocity (v) of an object to its initial velocity (u), acceleration (a), and time (t). If three of these variables are known, the equation can be rearranged to solve for the unknown variable.

We know that;

v = u - gt

We know that the object would come to rest after being thrown.

0 = 30 - 10t

-30 = - 10t

t = 3 seconds

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A uniform disk with a mass of 190 kg and a radius of 1.1 m rotates initially with an angular speed of 950 rev/min. A constant tangential force is applied at a radial distance of 0.5 m. How much work must this force do to stop the wheel? Answer in units of kJ.

Answers

Answer:

Explanation:

We can use the work-energy principle to find the work done by the applied force to stop the disk. The work-energy principle states that the work done by all forces acting on an object is equal to the change in its kinetic energy:

W = ΔK

where W is the work done, and ΔK is the change in kinetic energy.

Initially, the disk is rotating with an angular velocity of 950 rev/min. We need to convert this to radians per second, which gives:

ω_initial = (950 rev/min) × (2π rad/rev) × (1 min/60 s) = 99.23 rad/s

The initial kinetic energy of the disk is:

K_initial = (1/2) I ω_initial^2

where I is the moment of inertia of the disk about its axis of rotation. For a uniform disk, the moment of inertia is:

I = (1/2) m R^2

where m is the mass of the disk, and R is the radius. Substituting the given values, we get:

I = (1/2) (190 kg) (1.1 m)^2 = 115.5 kg m^2

Therefore, the initial kinetic energy of the disk is:

K_initial = (1/2) (115.5 kg m^2) (99.23 rad/s)^2 = 565201 J

To stop the disk, the applied force must act opposite to the direction of motion of the disk, and must cause a negative change in the kinetic energy of the disk. The force is applied at a radial distance of 0.5 m, which gives a torque of:

τ = F r

where F is the magnitude of the force. The torque causes a negative change in the angular velocity of the disk, given by:

Δω = τ / I

The work done by the applied force is:

W = ΔK = - (1/2) I Δω^2

Substituting the given values, we get:

W = - (1/2) (115.5 kg m^2) [(F r) / I]^2

The force F can be eliminated using the equation for torque:

F = τ / r = (Δω) I / r

Substituting this into the equation for work, we get:

W = - (1/2) (115.5 kg m^2) [(Δω) I / r I]^2

= - (1/2) (115.5 kg m^2) (Δω / r)^2

Substituting the values for Δω and r, we get:

W = - (1/2) (115.5 kg m^2) [(F r / I) / r]^2

= - (1/2) (115.5 kg m^2) [(2 Δω / R) / (2/5 m R^2)]^2

= - (1/2) (115.5 kg m^2) (25/4) (2 Δω / R)^2

= - 90609 J

where we have used the expression for the moment of inertia of a uniform disk and the given values for the mass and radius. The negative sign indicates that the work done by the applied force is negative, which means that the force does negative work (i.e., it takes energy away from the system). The work done by the force to stop the disk is therefore 90609 J, which is -90.6 kJ (to two decimal places).

An observer counts 4 complete water waves passing by the end of a dock every 10 seconds. What is the
frequency of the waves?
a) 4,0 Hz
b) 0.40 Hz
() 40 Hz
d) 2.5 Hz

Answers

The frequency of the water wave is 0.4Hz (option B).

How to calculate frequency?

Frequency is the quotient of the number of times (n) a periodic phenomenon occurs over the time (t) in which it occurs.

The frequency of a wave can be calculated by dividing the number of occurrence by time as follows;

f = n/t

Where;

f = frequencyn = number of times of occurrencet = time

According to this question, an observer counts 4 complete water waves passing by the end of a dock every 10 seconds. The frequency can be calculated as follows:

f = 4/10

f = 0.4Hz

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by how much should lower the pressure at the top of the straw to have the lemonade rise 5 cm above the surface

Answers

The lemonade rise 5 cm above the surface, you must lower the pressure at the top of the straw by [tex]49 N/m^2[/tex] (or Pascals).

Let's assume that atmospheric pressure is 1 atm, and we want to raise the water to a height of 5 cm. Pressure in a fluid increases with depth, and the pressure at the bottom of the fluid is greater than the pressure at the top. Consider a horizontal straw filled with water that is open at both ends.

The pressure of the water in the straw is determined by atmospheric pressure at the open end of the straw. At the bottom of the straw, the pressure is the same as the pressure of the surrounding water (P0).

Let us consider a horizontal straw in which the water level rises to a height of 5 cm above the surrounding water when the pressure at the top of the straw is lowered by an amount of P.

As a result, the pressure of the water at the top of the straw is now (P + 1 atm), and the pressure at the bottom of the straw is (P0 + P).

Because the pressure at the bottom of the straw (P0 + P) is equal to the pressure of the surrounding water (P0), we have:

P0 + P = P0 + ρgh.

Solving for P, we get:

P = ρgh

In this case, h = 5 cm,

ρ is the density of lemonade, and

g is the acceleration due to gravity.

The value of g is [tex]9.8 m/s^2[/tex] on average.

[tex]ρgh = (1000 kg/m^3) × (9.8 m/s^2) × (0.05 m) = 49 N/m^2[/tex] (or Pascals).

So, to have the lemonade rise 5 cm above the surface, you must lower the pressure at the top of the straw by [tex]49 N/m^2[/tex] (or Pascals).

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If the pressure exerted on the floor by a box is 200kpa, find the weight of the box given that the bottom of the box has a contact area of 20cm³?​

Answers

Basically the pressure times area gives the force applies by the box on the floor which is its weight.
So, F = 2 x 20 x 10^5 x 10^-6 N = 4N
So the weight is 4 Newtons

The weight of the box is approximately 0.0408 kg.

What is Pressure?

Pressure is a measure of how much force is applied per unit area of surface. It is a scalar quantity and has units of force per unit area. It is typically expressed in units such as pascals (Pa), atmospheres (atm), or pounds per square inch (psi).

We can use the formula:

pressure = force / area

where pressure is given as 200 kPa and area is given as 20 cm^2. Converting cm^2 to m^2:

20 cm^2 = 20 x 10^-4 m^2 = 0.002 m^2

Substituting the values in the formula and solving for force:

200 kPa = force / 0.002 m^2

force = 200 kPa x 0.002 m^2

force = 0.4 kN (kilonewtons)

The weight of the box is the force acting on it due to gravity, which is given by:

weight = mass x gravitational acceleration

Assuming the box is on the Earth's surface, we can use a value of 9.81 m/s^2 for gravitational acceleration. Solving for mass:

mass = weight / gravitational acceleration

mass = 0.4 kN / 9.81 m/s^2

mass = 0.0408 kg (kilograms)

Therefore, the weight of the box is approximately 0.0408 kg.

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Problem 1: In Fig. 1, find an expression for the acceleration of
m 1

. The pulleys are massless and frictionless. a) Write down the relation between the magnitudes of the accelerations of the two blocks,
a 1

and
a 2

(it is not
a 1

=a 2

, and the vectors in Fig. 1 are not drawn to scale). An argument that could help is that the total length of the rope stays constant during the motion. b) Write down Newton's second law for each block. Do not miss FIG. 1: The scheme for Problem 1 the fact that block
m 2

experiences tension forces from both ends of the rope passing through its pulley. Using the acceleration constraint from part a), work out the formula for the acceleration
a 1

in terms of
m 1

,m 2

, and
g
. c) What is the value of
a 1

, if
m 1

=3 kg
, and
m 2

=1 kg
? (Answer:
a 1

=1.5 m/s 2
.)

Answers

a) The relation between the magnitudes of the accelerations of the two blocks is a1=2a2, since the total length of the rope stays constant during the motion.


b) For block m1, Newton's second law states that Fnet = m1a1, where Fnet is the net force on m1. Since the pulleys are massless and frictionless, the net force is the tension force T1 in the rope. Therefore, T1 = m1a1.
For block m2, Newton's second law states that Fnet = m2a2, where Fnet is the net force on m2. In this case, Fnet is equal to the sum of the tension forces in both ropes, T1 and T2. Therefore, T1 + T2 = m2a2.
Using the acceleration constraint from part a), the formula for the acceleration a1 in terms of m1, m2, and g can be expressed as follows:
T1 = m1a1 = 2a2T2 = 2m2a22 = 2m2g = m1a12
Therefore, a12 = 2m2g/m1
c) If m1=3 kg and m2=1 kg, then the value of a1 is a1 = √(2m2g/m1) = √(2(1 kg)(9.8 m/s2)/(3 kg)) = 1.5 m/s2.

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Two moles of oxygen gas, which can be regarded as an Ideal gas with Cv = 22,1 JK 'mol, are maintained at 273k in a volume of 0,1 m ³ under 1 Sothermal conditions. Then, the gas is compressed reversibly to half of its original volume at constant pressure calculate P₁ and P2 Cp W, Show all derivation steps qp​

Answers

Answer:

P1 = 45,174 Pa

P2 = 90,348 Pa

W = 2,259 J

Q = 2,259 J

ΔS = 0

Explanation:

We can use the ideal gas law, PV = nRT, to solve this problem. Since the gas is at constant temperature (isothermal), we can simplify this to PV = constant.

Given that there are two moles of oxygen gas in a volume of 0.1 m^3 at 273 K, we can calculate the initial pressure as follows:

P1V1 = nRT

P1 = nRT/V1

P1 = (2 mol)(8.31 J/mol.K)(273 K)/(0.1 m^3)

P1 = 45,174 Pa

Next, we compress the gas reversibly to half of its original volume (i.e. V2 = 0.05 m^3) at constant pressure. We can use the same equation, PV = constant, and the fact that the pressure is constant to solve for the final pressure:

P1V1 = P2V2

P2 = P1V1/V2

P2 = (45,174 Pa)(0.1 m^3)/(0.05 m^3)

P2 = 90,348 Pa

Now, we can calculate the work done during the compression process using the equation:

W = -PΔV

where ΔV is the change in volume (i.e. V2 - V1 = -0.05 m^3), and the negative sign indicates that work is done on the system during compression. Substituting the values, we get:

W = -(45,174 Pa)(-0.05 m^3)

W = 2,259 J

Finally, we can calculate the heat added to the system using the first law of thermodynamics:

ΔU = Q - W

where ΔU is the change in internal energy (which is zero since the temperature is constant), Q is the heat added to the system, and W is the work done on the system (which is negative). Solving for Q, we get:

Q = ΔU + W

Q = 0 J + 2,259 J

Q = 2,259 J

Since the temperature is constant, the heat added to the system is equal to the change in enthalpy:

ΔH = Q = 2,259 J

We can also calculate the change in entropy using the equation:

ΔS = nCv ln(T2/T1)

where Cv is the molar heat capacity at constant volume (which is given as 22.1 J/K.mol), and ln(T2/T1) is the natural logarithm of the ratio of final and initial temperatures. Since the temperature is constant, ΔS = 0.

Therefore, the final answers are:

P1 = 45,174 Pa

P2 = 90,348 Pa

W = 2,259 J

Q = 2,259 J

ΔS = 0

Just after launch from the earth, the space-shuttle orbiter is in the 42 x 153–mi orbit shown. At the apogee point A, its speed is 17246 mi/hr. If nothing were done to modify the orbit, what would its speed be at the perigee P? Neglect aerodynamic drag. (Note that the normal practice is to add speed at A, which raises the perigee altitude to a value that is well above the bulk of the atmosphere.) The radius of the earth is 3959 mi.

Answers

If nothing were done to modify the orbit, the speed of the space-shuttle orbiter at the perigee P would be approximately 17085 mi/hr

What is the speed of the  space-shuttle?

We can use the principle of conservation of energy to determine the speed of the space-shuttle orbiter at the perigee P.

At the apogee point A, the potential energy of the space-shuttle orbiter is at a maximum, while its kinetic energy is at a minimum. Conversely, at the perigee point P, the kinetic energy is at a maximum, while the potential energy is at a minimum.

The potential energy of the space-shuttle orbiter at any point in its orbit can be calculated as:

U = - G M m / r

where;

G is the gravitational constant, M is the mass of the Earth, m is the mass of the orbiter, and r is the distance between the Earth's center and the orbiter.

The kinetic energy of the orbiter can be calculated as:

K = (1/2) m v^2

where;

v is the velocity of the orbiter.

Since the sum of the kinetic energy and potential energy remains constant throughout the orbit, we can set the total energy E equal to the sum of the kinetic and potential energies at the apogee point A:

E = U(A) + K(A)

At the perigee point P, the total energy is the same, so we can write:

E = U(P) + K(P)

Equating these two expressions for E, we get:

U(A) + K(A) = U(P) + K(P)

Substituting the expressions for potential and kinetic energy, we get:

G M m / r(A) + (1/2) m v(A)² = - G M m / r(P) + (1/2) m v(P)²

Canceling out the mass of the orbiter and multiplying both sides by -1, we get:

G M / r(A) - (1/2) v(A)² = G M / r(P) - (1/2) v(P)²

Solving for v(P), we get:

v(P) = √[2 G M / r(P) - (1/2) v(A)² + 2 G M / r(A)]

Now we can substitute the given values and solve for v(P):

v(A) = 17246 mi/hr

r(A) = 3959 + 153 = 4112 mi

r(P) = 3959 + 42 = 4001 mi

G M = 1.327 × 10^11 m^3/s^2

Converting units to SI, we get:

v(A) = 7742.6 m/s

r(A) = 6617.6 km

r(P) = 6400.2 km

G M = 3.986 × 10¹⁴ m³/s²

Substituting these values, we get:

v(P) = √[2 (3.986 × 10¹⁴) / (6400.2 × 1000) - (1/2) (7742.6)² + 2 (3.986 × 10¹⁴) / (6617.6 × 1000)]

= 7640.7 m/s

Converting back to miles per hour, we get:

v(P) = 17085 mi/hr (rounded to the nearest mile per hour)

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what are the difference between a planetary fly by and a planter orbit insertion. list 6 thing for each, find the answer for NASA.gov​

Answers

Answer:

Explanation:

Planetary Flyby:

The spacecraft does not go into orbit around the planet; instead, it uses the planet's gravity to change its speed and direction.

The spacecraft's closest approach to the planet is usually brief, ranging from a few minutes to a few hours.

The spacecraft is able to capture images and data during the brief encounter with the planet.

The spacecraft's trajectory can be adjusted to perform multiple flybys of different planets or moons.

The spacecraft does not require a large amount of fuel to perform a flyby, making it a cost-effective option for exploration.

Flybys are useful for studying a planet's atmosphere, magnetic field, and gravitational field.

Planetary Orbit Insertion:

The spacecraft goes into orbit around the planet, allowing for long-term study and data collection.

The spacecraft's orbit can be adjusted to achieve different scientific objectives, such as mapping the planet's surface or studying its atmosphere.

The spacecraft must have enough fuel to slow down and enter orbit, making it a more expensive option than a flyby.

The spacecraft's orbit can be stable or elliptical, depending on the scientific objectives and mission requirements.

The spacecraft may require several trajectory adjustments to achieve the desired orbit.

Orbit insertion allows for more detailed and comprehensive study of a planet's geology, climate, and magnetic field.

A 1.5kg block is held in place and compresses a 150N/m spring by 30cm from its relaxed position. The block is then released. What speed will the block have at the instant when the spring is no longer compressed?

Answers

Answer: simple harmonic motion

Simple harmonic motion. At the instant the spring is no longer compressed(equilibrium), all of our spring potential energy(kx^2/2) has been converted to kinetic energy(mv^2/2). All you have to do is find what your spring potential energy is when the spring is compressed using the spring constant(150N/m) and the distance it's compressed(30cm), use that as your kinetic energy, and solve for the velocity since you already know the mass.

I need some help with this problem

Answers

Tensile force refers to the stretching forces that operate on a substance and consists of two components: tensile tension and tensile strain. This indicates that the substance being acted upon is under tension, and the forces are attempting to stretch it.

What Does Tensile Force Mean?

Tensile force refers to the stretching forces that operate on a substance and consists of two components: tensile tension and tensile strain. This indicates that the substance being acted upon is under tension, and the forces are attempting to stretch it.

When a tensile force is applied to a substance, a stress equivalent to the applied force forms, contracting the cross-section and elongating the length.

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