There are multiple questions in your prompt, so let's break them down one by one.
How much gravitational potential energy does the goat gain?
The gravitational potential energy gained by the goat can be calculated using the formula:
GPE = mgh
where m is the mass of the goat, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.
Substituting the given values, we get:
GPE = 50 kg x 9.8 m/s^2 x 450 m
GPE = 220500 J
Therefore, the goat gains 220500 J of gravitational potential energy.
How much gravitational potential energy does Evan gain?
The gravitational potential energy gained by Evan can be calculated using the same formula as above:
GPE = mgh
where m is the mass of Evan (including his parachute gear), g is the acceleration due to gravity, and h is the height of the jump.
Substituting the given values, we get:
GPE = 90 kg x 9.8 m/s^2 x 2.0 m
GPE = 1764 J
Therefore, Evan gains 1764 J of gravitational potential energy.
How much kinetic energy does the goat have just before it hits the ground?
The conservation of energy principle tells us that the total energy of the system (in this case, the goat) remains constant. So, the kinetic energy gained by the goat just before it hits the ground is equal to the gravitational potential energy it had at the top of the cliff. Therefore, the kinetic energy of the goat just before it hits the ground is:
KE = GPE = 220500 J
Note that we have assumed that there is no loss of energy due to air resistance or other factors during the goat's fall.
How much GPE does Evan gain given: h = 2.0 m
We have already calculated the gravitational potential energy gained by Evan earlier. Using the same formula, we get:
GPE = mgh
GPE = 90 kg x 9.8 m/s^2 x 2.0 m
GPE = 1764 J
What is the kinetic energy of the aircraft at a height of 5000.00 m?
We cannot calculate the kinetic energy of the aircraft with the given information. The kinetic energy of an object depends on its mass and velocity, but we only have information about its height. If we assume that the aircraft is stationary at a height of 5000.00 m, then its kinetic energy would be zero.
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You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 1515
lb and was traveling eastward. Car B weighs 1125
lb and was traveling westward at 41.0
mph. The cars locked bumpers and slid eastward with their wheels locked for 18.5
ft before stopping. You have measured the coefficient of kinetic friction between the tires and the pavement to be 0.750
.
What speed
(in miles per hour) was car A traveling just before the collision? (This problem uses English units because they would be used in a U.S. legal proceeding.)
Answer:
Solve for force:
Ff = UFn
Ff = 0.75(Fn)
Ff = 0.75(1515 + 1225 * g)
Ff = 20550N
Solve for acceleration:
F= ma
20550N = (1515 + 1225) a
a = 7.5m/s^2
solve for time:
a = d / t^2 ---> 7.5m/s^2 = 18.5/ t^2 ----> t = 0.85s
solve for velocity final
Impulse = F * t = 20550N * 0.85s
mv^2 = Impulse = 17467.5
(1515 + 1125)v^2 = 17467.5
vf = 2.5m/s
Plug in stuff:
1515 * v1 + 1125 * (-18.3m/s) = (1515 + 1125) * 2.5m/s
v1 = 9.23
Note: I converted 41mph(v2) to 18.3m/s, which is negative because "westward" is in the negative direction.
Explanation: Inelastic collision
I'm not sure but my guess is we can solve for the force of friction using the coefficient of friction. With that, we can solve for the acceleration in F = ma, and use that to solve for the time the two cars slide. And using that we can solve for the impulse, which is just the Force of friction times that time, which is also our momentum. Since we know the momentum, we can solve for the velocity of the two objects after the collision. Using that velocity, we can use the equation( m1v1 + m2v2 = (m1+m2)vf ), plug in the known quantities and solve for v1.(Note: don't forget to convert mph to mps and 18.5ft to meters)
Extra: I'm guessing because the two cars slide, the only force acting on them is the force of friction(so it's our net force), hence the Fnet = ma.
In which of the following cases is the largest force exerted on an object by electromagnetic radiation? a) The radiation is absorbed by the object. b) Nearly all of the radiation is transmitted through the object because it is transparent. C) The radiation strikes the surface at a large angle with respect to the normal to the surface. (d) The radiation is reflected back along its incident path e) In all of the above cases the force will be the same since it is the same light striking the object.
The largest force exerted on an object by electromagnetic radiation is d) The radiation is reflected back along its incident path.
What is electromagnetic radiation?The electromagnetic (EM) field's waves, which travel across space carrying momentum and electromagnetic radiant energy, make up electromagnetic radiation (EMR). It consists of X-rays, gamma rays, microwaves, infrared, visible light, ultraviolet, and radio waves. These waves are all a component of the electromagnetic spectrum.
Electromagnetic waves, which are synchronised oscillations of the electric and magnetic fields, are the traditional form of electromagnetic radiation. The electromagnetic spectrum is created at various wavelengths depending on the oscillation frequency. Electromagnetic waves move at the speed of light, in a vacuum. The oscillations of the two fields create a transverse wave in homogeneous, isotropic media when they are perpendicular to each other, perpendicular to the direction of energy and wave propagation, and perpendicular to each other.
What is electromagnetic spectrum?The range of electromagnetic radiation's frequencies, along with their corresponding wavelengths and photon energies, is known as the electromagnetic spectrum.
The electromagnetic spectrum includes electromagnetic waves with frequencies between one hertz and above 10²⁵ hertz, or wavelengths between thousands of kilometres and a small portion of the size of an atomic nucleus. The electromagnetic waves that are contained within each of these bands have different names; starting at the low-frequency (long wavelength) end of the spectrum, these are radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. This frequency range is divided into separate bands.
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) at the instant 7.6 s after the switch is closed, calculate the charge on the capacitor. (2) substitute numerical values into q(t)
The charge on the capacitor at 7.6 s after the switch is closed is 54.87 µC.
The charge on the capacitor can be calculated using the formula,
Q = Q₀(1-e^(-t/RC))
where Q₀ is the initial charge on the capacitor,
t is the time elapsed,
R is the resistance and
C is the capacitance.
Substituting the given values
Q₀ = 60 µC,
R = 10kΩ,
C = 2 µF, and
t = 7.6 s,
we get
[tex]Q = 60 µC(1-e^(-7.6/(10 \times 10³ \times 2\times 10^-6))[/tex]
= 54.87 µC
Thus, the charge on the capacitor at 7.6 s after the switch is closed is 54.87 µC.
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Review For each initial position choose the correct sketch of the mostly path of the shark toward the center of the dipole in
In the given figure, the dipole electrode is represented by the two circles one is red and other is green, and the three initial positions of the shark are represented by the three blue circles.
For the initial position of the shark represented by the top blue circle 1, the most likely path of the shark toward the center of the dipole would be a curved path, as the equipotential lines bend and curve around the dipole electrode. The shark would start by following the equipotential lines to the left, then gradually curve downward and to the right before eventually reaching the center of the dipole.
For the position at the bottom left blue circle 2, the most likely path of the shark would be same as path 1 since the shark would start by following the equipotential lines upward and to the right, then gradually curve downward and to the left before eventually reaching the center of the dipole.
For the position at the bottom right blue circle 3, the most likely path of the shark would be same as path 1 since the shark would start by following the equipotential lines downward and to the left, then gradually curve upward and to the right before eventually reaching the center of the dipole.
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complete question: In experimental tests, sharks have shown the ability to locate dipole electrodes (simulating the dipole fields of the heartbeats of prey animals) buried under the sand. In a test with young bonnethead sharks, sharks that detected the presence of a dipole usually swam toward the center of the dipole by following equipotential lines. Figure P21.35 shows a dipole electrode and three initial positions of a bonnethead shark. For each initial position, sketch the most likely path of the shark toward the center of the dipole.
Help me fast!!
I need help
Answer is what?
Answer:
both are only physical changes
Explanation:
Physical changes are changes that do not alter the identity of a substance.
The liquid soap is still liquid soap when mixed into water.
The dry ice is still dry ice when it changes state from solid to gas.
moving water can be used as an energy source. select all the characteristics of this energy source that apply.
The above-listed characteristics apply to moving water as an energy source. Thus, moving water can be used as an energy source.
The following are the characteristics of moving water as an energy source:
It is a renewable energy source. It is a clean energy source. It is available in many different forms. It is the least expensive energy source to generate.Water is an excellent resource for producing electricity since it is clean, renewable, and is available in many different forms. When water moves, it has the potential to generate energy, which can be harnessed in several ways to produce electricity. As a result, moving water is an excellent source of renewable energy, as it is available in many different forms and can be used in a variety of ways.The above-listed characteristics apply to moving water as an energy source. Thus, moving water can be used as an energy source.
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1.- What is net net charge on the sweater? Why?
2.- What is the net charge on the balloon? Why?
ASAP pls and thank you!!
When students brush balloons against their wool sweaters or hair, electrons are moved from the wool or hair to the balloon. As a result, the balloon has a net negative charge, whereas the garment or hair, having shed negative charges, has a net positive charge.
What is net charge?The term "net" refers to the sum after both positive and negative costs have been deducted. So, if something has 321 positive charges and 319 negative charges, the overall charge is 321 - 319 = +2. The overall charge is 37 - 42 = -5 if it includes 37 positive charges and 42 negative charges.
Electrons are negatively charged, whereas protons are favourably charged. Atoms have an identical amount of electrons and protons and have a net charge of zero. This makes atoms always neutral.
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which statement most accurately captures what current evidence tell us about the habitability of mars?
"Mars may once have met the requirements for livability, such as having liquid ocean, but at the moment, it top orbit is too thin so it lacks the huge magnetic field needed to support life as we know it.
What being magnetic entails?having great aptitude or power to attract. a magnetic personality; of or pertaining to the a magnet or even to magnetism; of, pertaining to, and characterized by earth's magnetism; magnetized or able to be magnetized.
How can a magnet become more powerful?Yet, some substances have a high magnetic field, meaning that the majority of its electrons spin opposite direction. The strongest magnets are made of these materials because of their great magnetic permeability. They include the elements nickel, cobalt, and iron. The most potent type of magnet is one made of neodymium iron boron (NdFeb).
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One end of a massless, 30-cm-long spring with a spring constant of 15 N/m is attached to a 250 g stationary air-track glider; the other end is attached to the track. A 600 g glider hits and sticks to the 250 g glider, compressing the spring to a minimum length of 22 cm . What was the speed of the 600g glider just before impact?
tThe speed of the 600 g glider just before impact was approximately 0.4 m/s.
What is the speed of the glider?To solve this problem, we need to use the conservation of mechanical energy, which states that the initial mechanical energy is equal to the final mechanical energy in a system.
Before the collision, the 250 g glider is stationary, so its kinetic energy is zero. The 600 g glider has an initial kinetic energy of:
KEi = ½ mv²
where;
m is the mass of the 600 g glider and v is its initial velocity.After the collision, the two gliders move together as a single system, and the spring is compressed to a minimum length of 22 cm. At this point, all of the kinetic energy of the system has been converted into potential energy stored in the compressed spring.
The potential energy stored in a spring is given by:
PE = ½ kx²
where;
k is the spring constant and x is the displacement of the spring from its equilibrium position.In this case, the spring is compressed by 30 cm - 22 cm = 8 cm = 0.08 m
from its equilibrium position, so the potential energy stored in the spring is:
PE = ½ kx² = ½ (15 N/m) (0.08 m)² = 0.048 J
Since the total mechanical energy is conserved, we can equate the initial kinetic energy of the 600 g glider to the final potential energy stored in the spring:
KEi = KEf + PE
where;
KEf is the final kinetic energy of the system after the collision.Substituting the expressions for KEi, KEf, and PE, we get:
½ mv² = 0 + 0.048 J
Solving for v, we get:
v = √(2PE/m) = √(2(0.048 J)/(0.6 kg)) = 0.4 m/s
Therefore, the speed of the 600 g glider just before impact was approximately 0.4 m/s.
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A 65 kg-mass person stands at the end of a diving board, 1.5 m from the board's pivot point. Determine the torque the person is exerting on the board with respect to the pivot point. Show your work.
Answer:
Explanation:
To calculate the torque exerted by the person on the diving board, we need to know the force exerted and the lever arm.
The force exerted by the person is the weight of their body, which can be calculated as:
F = mg
F = 65 kg x 9.81 m/s^2
F = 637.65 N
note: The acceleration of gravity "g" is therefore the result of gravitation (gravitational attraction) between the Earth and other celestial bodies, and of the centrifugal acceleration, due to the movement of the earth's rotation and its average global value is 9.81 ms -2.
The lever arm is the distance from the person to the pivot point, which is given as 1.5 m.
The torque (τ) can then be calculated as:
τ = F x d
τ = 637.65 N x 1.5 m
τ = 956.47 Nm
Therefore, the torque exerted by the person on the diving board with respect to the pivot point is 956.47 Nm.
The torque exerted by a force F at a distance r from the pivot point is given by the formula:
τ = F x r x sin(θ)
where θ is the angle between the force vector and the vector from the pivot point to the point where the force is applied.
In this case, the person's weight is the force being exerted on the board, and its magnitude is:
F = m x g = 65 kg x 9.8 m/s^2 = 637 N
The distance from the pivot point to the person is r = 1.5 m. Since the person is standing vertically, the angle between the weight vector and the vector from the pivot point to the person is 90 degrees, so sin(θ) = 1. Substituting the values into the torque formula, we get:
τ = 637 N x 1.5 m x 1 = 955.5 Nm
Therefore, the person is exerting a torque of 955.5 Nm on the diving board with respect to the pivot point.
What is the frequency of blue light that has a wavelength of 448 nm?
Answer:
The frequency of light can be calculated using the following formula:
frequency = speed of light / wavelength
where the speed of light is approximately 299,792,458 meters per second.
First, we need to convert the given wavelength from nanometers to meters:
448 nm = 448 × 10^-9 m
Now we can plug in the values and solve for frequency:
frequency = (299,792,458 m/s) / (448 × 10^-9 m)
frequency = 6.69 × 10^14 Hz
Therefore, the frequency of blue light with a wavelength of 448 nm is approximately 6.69 × 10^14 Hz.
a. what are the physical processes by which atoms rearrange during phase transformations in the solid state (how do atoms rearrange in the solid state)?
The physical processes by which atoms rearrange during phase transformations in the solid state involve changes in the arrangement of the atoms in the lattice, which can be caused by changes in temperature, pressure, or both.
The physical processes by which atoms rearrange during phase transformations in the solid state involve changes in the arrangement of the atoms in the lattice.
This is typically done by changing the number of nearest neighbours of each atom or by introducing new lattice points in the solid structure. In some cases, atoms may even have to move from one position to another.
Common examples of phase transformations in the solid state include melting, recrystallization, and solidification.
Melting occurs when the thermal energy of the solid is increased and the atoms become mobile enough to break the bonds between them. This causes the solid to transition into a liquid phase.
Recrystallization occurs when the thermal energy of the solid is decreased, causing the atoms to return to their original positions and form a new, more ordered lattice.
Lastly, solidification is the reverse process of melting, where thermal energy is removed and the atoms return to their original positions in the lattice.
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imagine that the blue light and orange light from the source were blocked. what color would how be present in the spectrum of light observed
Everything but blue & orange would now be present in the spectrum of light observed.
Spectrum refers to a range of different wavelengths of electromagnetic radiation. Electromagnetic radiation is a form of energy that travels through space and includes different types such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of electromagnetic radiation has a different wavelength and frequency, and together they make up the electromagnetic spectrum.
The concept of spectrum is used in a variety of fields, including physics, astronomy, and telecommunications. The spectrum of electromagnetic radiation is essential for many technologies, such as radios and televisions, cell phones, and medical imaging devices, as they all rely on the transmission and reception of specific wavelengths of electromagnetic radiation.
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Complete Question: -
Imagine that the blue light and orange light from the source were blocked. What color(s) would now be present in the spectrum of light observed?
think back to what you've done so far - what are the factors that affect the temperature of the earth?
Greenhouse gases, Albedo , Orbital variations ,Solar radiation and Volcanic activity these are the factors that affect the temperature of the earth.
There are many factors that affect the temperature of the Earth, including the following:
Greenhouse gases: Certain gases, such as carbon dioxide, methane, and water vapor, trap heat in the Earth's atmosphere and cause the planet to warm up. As greenhouse gas emissions increase due to human activity, such as burning fossil fuels, the Earth's temperature is expected to continue to rise.
Albedo: This is a measure of how much light the Earth reflects back into space. When the Earth's surface is covered in snow or ice, it has a high albedo and reflects more light. When the Earth's surface is covered in dark vegetation or water, it has a low albedo and absorbs more light, which causes it to warm up. Changes in land use, such as deforestation, can also affect the Earth's albedo.
Orbital variations: The Earth's orbit around the sun changes over time due to gravitational interactions with other planets. These variations can affect the amount of sunlight that reaches different parts of the Earth and cause climate patterns to shift. For example, changes in the tilt of the Earth's axis can lead to changes in the seasons.
Solar radiation: The amount of energy the Earth receives from the sun varies over time due to changes in the sun's output and the Earth's position in its orbit. This can affect the Earth's climate, especially over long periods of time. For example, changes in solar radiation are thought to have contributed to past ice ages.
Volcanic activity: When a volcano erupts, it releases large amounts of gases and particles into the atmosphere. This can cause the Earth's temperature to drop temporarily by blocking sunlight. However, over longer periods of time, volcanic activity can also release greenhouse gases and cause the Earth to warm up.
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a banked curve is safer than a flat curve because the ___ force required to keep the car from skidding is supplied by the horizontal component of the ___ force instead of friction.
Answer:
centripetal, normal
A 0.35-kg piece of putty is dropped from a height of 2.5 m above a flat surface. When it hits the surface, the putty comes to rest in 0.30 s. What is the average force exerted on the putty by the surface?
The average force exerted on the putty by the surface is 0 N this means that the putty experiences no net force and does not accelerate during the 0.30 s it takes to come to rest.
To answer this problem, we may apply the average force equation, which states that average force equals momentum change divided by the period during which the force occurs.
Initially, we must determine the putty's starting momentum. We may employ the momentum equation, which asserts that momentum equals mass times velocity. Because the putty is dropped from rest, its initial velocity is zero, as is its initial momentum.
The ultimate momentum of the putty must then be determined. The putty's final velocity is also zero since it comes to rest. As a result, the putty's ultimate momentum is similarly zero.
Finally, we can substitute the values we found into the equation for average force:
Average force = change in momentum/time interval
= 0 / 0.30
= 0 N
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Two pieces of clay, one white and one gray, are thrown through the air. The
m
white clay has a momentum of 25 kg, and the gray clay has a
S
momentum of -30 kg immediately before they collide.
What is the magnitude and direction of their final momentum immediately
after the collision?
Your answer should have one significant figure.
h
kg.
m
-
m
S
S
we can't give a specific direction for the final momentum.
What is momentum?
Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. Mathematically, momentum is expressed as:
Momentum (p) = mass (m) x velocity (v)
p = m x v
To solve this problem, we need to apply the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.
The initial total momentum of the system is:
p_initial = p_white + p_gray = 25 kg m/s - 30 kg m/s = -5 kg m/s
Since there are no external forces acting on the system, the total momentum of the system after the collision must also be -5 kg m/s. Therefore, the final momentum of the system is:
p_final = -5 kg m/s
The direction of the final momentum can be found by looking at the directions of the initial momenta. Since the white clay has positive momentum and the gray clay has negative momentum, we can say that the white clay is moving to the right and the gray clay is moving to the left before the collision.
During the collision, the two clays will exert forces on each other, causing them to change direction and possibly even break apart. Without more information about the collision, we can't say for sure what the direction of the final momentum will be. It could be to the left or to the right, or some combination of the two. Therefore, we can't give a specific direction for the final momentum.
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Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 27.5 m/s (about 62 mph ) around the turn, what is the race car's centripetal (radial) acceleration? What is the Coefficient of friction?
Answer:
Explanation:
The centripetal acceleration of the race car is given by the formula:
a = v^2 / r
where v is the speed of the race car and r is the radius of the turn.
Substituting the given values, we get:
a = (27.5 m/s)^2 / 57.0 m = 13.3 m/s^2
So the centripetal acceleration of the race car is 13.3 m/s^2.
To find the coefficient of friction, we need to use the formula:
f = μN
where f is the force of friction, μ is the coefficient of friction, and N is the normal force.
The normal force is equal to the weight of the car, which we can calculate as:
N = mg
where m is the mass of the car and g is the acceleration due to gravity (9.81 m/s^2).
Assuming the mass of the car is 1500 kg, we get:
N = 1500 kg × 9.81 m/s^2 = 14,715 N
The force of friction is equal to the centripetal force required to keep the car moving in a circle:
f = ma = (1500 kg)(13.3 m/s^2) = 19,950 N
Substituting the values of N and f into the formula for friction, we get:
19,950 N = μ(14,715 N)
Solving for μ, we get:
μ = 1.35
So the coefficient of friction is 1.35.
A driver notices that her 1400-kg car, when in neutral, slows down from 95 km/h to 65 km/h in about 7.0 s on a flat horizontal road. Approximately what power (watts) is needed to keep the car traveling at a constant 80 km/h? Express your answer using two significant figures.
The magnitude of power needed to keep the car traveling at a constant speed of 80 km/h would be 7 × [tex]10^4[/tex] watts.
Power calculationThe initial speed of the car is 95 km/h = 26.39 m/s, and the final speed is 65 km/h = 18.06 m/s. The change in speed over the 7.0 s interval is:
Δv = vf - vi = 18.06 m/s - 26.39 m/s = -8.33 m/s
The acceleration of the car can be found using:
a = Δv/t = -8.33 m/s / 7.0 s = -1.19 m/s^2
This is the deceleration of the car when it's in neutral. The force of friction acting on the car is:
F = ma = (1400 kg)(1.19 m/s^2) = 1666 N
To keep the car traveling at a constant 80 km/h = 22.22 m/s, a force equal in magnitude but opposite in direction to the force of friction must be applied. The power required to maintain this speed is:
P = Fv = (1666 N)(22.22 m/s) = 37000 W ≈ 3.7 × [tex]10^4[/tex] W
Therefore, the power needed to keep the car traveling at a constant 80 km/h is approximately 7 × [tex]10^4[/tex] watts.
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Calculate the mass in kg of a ball at a height of 3m above the ground with a potential energy of 120J.
The mass of the ball at a height of 3m above the ground with a potential energy of 120J can be calculated using the equation:
Mass = Potential Energy/Gravity * Height
Mass = 120J/(9.81m/s² * 3m)
Mass = 4.1 kg
Answer:
4 kg
Explanation:
Using,
Energy/ Work done = Force x Distance (Height)
E = F • s
But recall, that F = mg
Therefore,
E = m • g • s
Making mass (m), the subject of the formula
m = E / (g • s)
m = 120 / (10 • 3)
m = 120 / 30
m = 4 kg
But if g = 9.8 ms-¹
Then,
m = 120 / (9.8 • 3)
m = 120 / 29.4
m = 4.08 kg
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If a person steps on a scale in an elevator that is accelerating at a rate -1.100 m/s^2 (negative means downward while positive means upwards) and sees a scale reading of 598.900 Newtons what would the scale read if the elevator were not moving?
answer with correct units
Answer:
Explanation:
When the elevator is accelerating downwards, the apparent weight of the person is reduced, and when the elevator is accelerating upwards, the apparent weight is increased.
First, we need to determine the actual weight of the person. We can do this by using the formula:
Weight = mass x gravity
where mass is the mass of the person and gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2.
Weight = (598.900 N) / (9.81 m/s^2) = 61.048 kg
Now, when the elevator is not moving, the person is only experiencing the force due to gravity, which is:
Weight = mass x gravity = (61.048 kg) x (9.81 m/s^2) = 598.78 N
Therefore, the scale would read approximately 598.78 Newtons when the elevator is not moving.
on the grid below sketch at least one complete cycle of a transverse wave with a 4.0 centimeter amplitude a freuqncy of 5.0 hertz
Draw the complete cycle of the wave by repeating the pattern of the peak, the equilibrium position, and the trough, with a distance of λ between each consecutive peak or trough. The number of cycles per second, or the frequency, should be 5.0 hertz.
What is Wave?
A wave is a disturbance that propagates through space and time, often transferring energy from one location to another without the physical transfer of matter. Waves can take many different forms, including sound waves, electromagnetic waves, and mechanical waves.
Draw a horizontal axis representing time, labeled in seconds or milliseconds.
Draw a vertical axis representing displacement or amplitude, labeled in centimeters or meters.
Choose a starting point for the wave, which represents the equilibrium position of the medium.
Draw the peak of the wave, which represents the maximum displacement of the medium from its equilibrium position. This should be 4.0 centimeters above the equilibrium position.
Draw the trough of the wave, which represents the minimum displacement of the medium from its equilibrium position. This should be 4.0 centimeters below the equilibrium position.
Determine the wavelength of the wave, which is the distance between two consecutive peaks or troughs. This can be calculated using the formula λ = v/f, where λ is the wavelength, v is the velocity of the wave, and f is the frequency. For a transverse wave on a string, the velocity is given by v = √(T/μ), where T is the tension in the string and μ is the linear mass density of the string.
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The back emf in a motor is 72 V when operating at 1800 rpm. What would be the back emf at 2500 rpm if the magnetic field is unchanged?
The back emf at 2500 rpm if the magnetic field is unchanged is 100 V for the back emf in a motor is 72 V when operating at 1800 rpm.
The back emf in a motor is proportional to the speed of the motor. Therefore, we can use the following formula to determine the back emf at 2500 rpm:
E2 = E1 × (N2 / N1)
where E1 is the back emf at 1800 rpm, N1 is the speed at which the back emf was measured, E2 is the back emf at 2500 rpm, and N2 is a new speed.
Plugging in the values we get:
E2 = 72 V × (2500 rpm / 1800 rpm)
E2 = 100 V
Therefore, the back emf at 2500 rpm of the motor would be 100 V if the magnetic field is unchanged.
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Determine the absolute pressure on the bottom of a swimming pool 28.0 m by 8.5 m whose uniform depth is 1.8 m .
Express your answer using two significant figures.
The absolute pressure on the bottom of a swimming pool 28.0 m by 8.5 m whose uniform depth is 1.8 m is 287 kPa
the absolute pressure on the bottom of the pool is 17.6 kPa.
Pressure is defined as the amount of force per unit area applied to an object's surface. Pressure may also be defined as a scalar amount of stress exerted on a surface that is perpendicular to the direction of the force. Pressure is frequently represented by the symbol p, which stands for pressure.
Given,
Length of the pool, l = 28 m
Width of the pool, w = 8.5 m
Depth of the pool, h = 1.8 m
The density of water,
p = 1000 kg/m³
g = 9.81 m/s²
Absolute pressure formula:
p = ρgh
Absolute pressure p is given by,
p = ρgh
p = 1000 kg/m³ × 9.81 m/s² × 1.8 mp
= 17604 Pa
Then, Converting the answer to kPa,
1 Pa = 1 × 10⁻³ kPa⇒ 17604 Pa = 17.6 kPa
Therefore, the absolute pressure on the bottom of the pool is 17.6 kPa rounded to two significant figures.
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You are pulling water with a constant velocity from a well using a crank of lengthL . If the length of the crank was doubled, you could ...A: pull up the water with the same work, but less forceB: pull up the pail with half the number of revolutionsC: exert double the torque while pulling up the pail with half the workD: pull up the pail with half the work and half the forceE: pull up double the amount of water with the same workF: exert four times the torque while pulling up the pail with the same work
The correct option is A, If the length of the crank was doubled, you could pull up the water with the same work, but less force.
The term "crank" can have various meanings depending on the context. In the context of machinery or engines, a crank is a mechanical device that converts rotational motion into linear motion or vice versa. It typically consists of a rod with a crankpin that connects to a piston or other reciprocating part.In a different context, the term "crank" can refer to a person who holds unconventional or extreme views and insists on expressing them in a forceful or annoying way.
Such a person may be described as a "crank" or "crankpot." The term can also refer to someone who is mentally unbalanced or eccentric. Furthermore, in the context of illegal drugs, "crank" is a slang term for methamphetamine, a highly addictive stimulant that can cause serious health problems and addiction. It is usually sold in crystalline form and can be smoked, snorted, or injected.
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Complete Question: -
You are pulling water with a constant velocity from a well using a crank of lengthL . If the length of the crank was doubled, you could ...
A: pull up the water with the same work, but less force
B: pull up the pail with half the number of revolutions
C: exert double the torque while pulling up the pail with half the work
D: pull up the pail with half the work and half the force
E: pull up double the amount of water with the same work
F: exert four times the torque while pulling up the pail with the same work
b) what is the probability that an average of 22 shields will absorb more than 17.1 j/kg? use 4 decimal places.
The probability that an average of 22 shields will absorb more than 17.1 J/kg is approximately 0.3085.
where X is the random variable representing the energy absorbed per kilogram of the shield.
To calculate this probability, we need to know the distribution of X.
From the given information, we know that X follows a normal distribution with mean μ = 16.8 J/kg and standard deviation σ = 0.6 J/kg.
Thus, we can standardize X as follows:
Z = (X - μ)/σZ ~ N(0, 1)
P(X > 17.1) = P((X - μ)/σ > (17.1 - μ)/σ)
= P(Z > (17.1 - 16.8)/0.6)
= P(Z > 0.5)
Using a standard normal table, we can find the probability that Z > 0.5 to be 0.3085 (rounded to 4 decimal places).
Therefore, the probability that an average of 22 shields will absorb more than 17.1 J/kg is approximately 0.3085.
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The disruption of which of the following interactions directly contributes towards removing 2,3-BPG from HB? His 146 - Asp 94 Tyr-145 - His 146 His 146 - Lys 40 Tyr 145 - Val 98 QUESTION 5 Hemoglobin has a binding affinity at pO2
=20
Torr and binding affinity at
pO2=100
Torr. High; High High; Low Low; Low Low; High
The disruption of His 146 - Lys 40 interaction directly contributes towards removing 2,3-BPG from HB. This interaction has a low binding affinity (Kd) when pO2 is at 100 Torr compared to when pO2 is at 20 Torr, where it has a higher affinity (Kd).
This means that at a higher pO2, 2,3-BPG is more likely to be removed, allowing HB to bind oxygen with higher affinity.
When answering questions on Brainly, you should always be factually accurate, professional, and friendly, be concise and not provide extraneous amounts of detail, and provide a step-by-step explanation in your answer. The disruption of His 146 - Lys 40 interactions directly contributes towards removing 2,3-BPG from HB.
This is because the 2,3-bisphosphoglycerate (2,3-BPG) molecule interacts with hemoglobin by creating salt bridges with specific amino acid residues, resulting in oxygen unloading in tissues at high altitudes.
The residue lysine 40, which forms a salt bridge with the carboxylate groups of 2,3-BPG, is one of the most important 2,3-BPG-binding residues in hemoglobin.To remove 2,3-BPG from hemoglobin, it is necessary to disrupt the salt bridge between lysine 40 and 2,3-BPG. This can be accomplished by modifying the lysine residue or by increasing the oxygen tension of the blood. Increasing oxygen tension can displace 2,3-BPG from hemoglobin, making it available for oxygen transport.
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An illustration of a circle with an arrowhead on the circle pointing counterclockwise. at a point near the top of the circle is a dot with 4 vectors from it. Vector A is circular counterclockwise along the circle, vector c toward the center of the circle, a vector tangent to the circle and counterclockwise labeled B and a vector away from the center of the circle labeled D and a vector halfway between vectors B and D labeled C.
Aldis is swinging a ball tied to the end of a string over his head. Suddenly, the string breaks and the ball flies away.
Arrow
✔ B
best represents the path the ball follows after the string breaks.
Correct awnser is B
Given the fact that the linear velocity of the ball is tangential to the circle then it is shown by vector B
What is the direction of the tangential velocity of a ball that flies out of a circular path?When a ball flies out of a circular path, the direction of its tangential velocity is tangent to the point at which it leaves the circular path.
To visualize this, imagine a ball tied to a string and whirled around in a circle. As the ball is released, it will move away from the center of the circle in a straight line. At the moment it leaves the circular path, its velocity vector will be tangent to the circle, pointing in the direction of its motion.
If the ball is flying out of the circle in a clockwise direction, then its tangential velocity vector will point to the right. If it is flying out of the circle in a counterclockwise direction, then its tangential velocity vector will point to the left.
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A diesel engine of a 400-Mg train increases the train's speed uniformly from rest to 10 m/s in 100 s along a horizontal track. Determine the average power developed.
The average power developed by a diesel engine of a 400-Mg train increases the train's speed uniformly from rest to 10 m/s in 100 s along a horizontal track = 200 kW.
How to calculate average power?The first kinematic equation is v=v0+at , where v is the final velocity, v0 is the initial velocity, a is the constant acceleration, and t is the time
According to given information:
v = 10, v0= 0 , t= 100s, m=400
v=v0+at
10= 0+a(100)
a= 0.1 m/s²
∑ F =ma <==> F= 400(10 ³ )(0.1) = 40(10 ³)N
Pavg = F. Vavg = 40(10 ³)(10/2) = 200 kW
It represents the typical quantity of work completed or energy converted per unit of time. When the context clearly indicates it, the average power is frequently referred to as "power".
The instantaneous power overrides the average power as time interval t gets closer to zero.
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if ao is 50 feet, find the perimeter of the pool. (o is the center of the sector aob. oa and ob are the diameters of two semi-circles.)
The perimeter of the pool is approximately 206.85 feet if we use 3.14 as the approximation of the value of π.
In this case, the angle AOB is 360 degrees, so the arc length is:
arc length = (360/360) x 2π(25) = 50π feet
Finally, we can find the perimeter of the pool by adding up the lengths of the two semicircles and the arc AB:
perimeter = 2πr + 2r + arc length
perimeter = 2π(25) + 2(25) + 50π
perimeter = 50π + 50
Perimeter is a measurement of the distance around the edge of a two-dimensional shape, such as a square, rectangle, or circle. It is the sum of the lengths of all the sides that make up the shape. The perimeter is an important concept in geometry and is used to determine the amount of material needed to enclose or surround a shape, as well as to calculate the distance around a given route or path.
To find the perimeter of a shape, you simply add up the lengths of its sides. For example, if you have a square with sides that are each 5 units long, the perimeter would be 5 + 5 + 5 + 5 = 20 units. Similarly, if you have a circle with a radius of 10 units, the perimeter (also known as the circumference) would be 2πr or approximately 62.8 units.
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Complete Question: -
If AO is 50 feet, find the perimeter of the pool. (O is the center of the sector AOB. OA and OB are the diameters of two semi-circles.)
