Answer:
The tank is 10cm high
Step-by-step explanation:
Given
[tex]L=60cm[/tex] -- length
[tex]W=60cm[/tex] -- width
[tex]x = \frac{1}{5}[/tex] --- water lever
[tex]Addition = 24L[/tex]
Required
The height of the tank
Let y represents the remaining fraction before water is added.
So:
[tex]y + x = 1[/tex]
Make y the subject
[tex]y = 1 - x[/tex]
[tex]y = 1 - \frac{1}{5}[/tex]
Solve
[tex]y = \frac{5 - 1}{5}[/tex]
[tex]y = \frac{4}{5}[/tex]
Represent the volume of the tank with v
So:
[tex]y * v = 24L[/tex]
Make v the subject
[tex]v = \frac{24L}{y}[/tex]
Substitute: [tex]y = \frac{4}{5}[/tex]
[tex]v = \frac{24L}{4/5}[/tex]
[tex]v = 30L[/tex]
Represent the height of the tank with h;
So, the volume of the tank is:
[tex]v = lwh[/tex]
Make h the subject
[tex]h = \frac{v}{lw}[/tex]
Substitute values for v, l and w
[tex]h = \frac{30L}{60cm * 50cm}[/tex]
Convert 30L to cm^3
[tex]h = \frac{30*1000cm^3}{60cm * 50cm}[/tex]
[tex]h = \frac{30000cm^3}{3000cm^2}[/tex]
[tex]h = 10cm[/tex]
Point A (6,2) is translated using the vector <-5,2>. Where is the new point located?
======================================================
Explanation:
The notation <-5,2> is the same as writing the translation rule [tex](x,y) \to (x-5,y+2)[/tex]
It says: move 5 units to the left and 2 units up
The point (6,2) moves to (1,2) when moving five units to the left. Then it ultimately arrives at (1, 4) after moving 2 units up. You could move 2 units up first and then 5 units to the left later on, and you'd still arrive at (1, 4). In this case, the order doesn't matter (some combinations of transformations this won't be the case and order will matter).
---------
Or you could write out the steps like so
[tex](x,y) \to (x-5, y+2)\\\\(6,2) \to (6-5, 2+2)\\\\(6,2) \to (1, 4)\\\\[/tex]
We see that (6,2) moves to (1, 4)
Can someone help me with this math homework please!
Answer:
Check off both of the boxes
Step-by-step explanation:
In your reponse you included that most ancient societies didn't have symbols for math operations and didn't have symbols for variables/unknown quantities.
Hope it helps (●'◡'●)
Maths assignment
y^2-36
Answer:
Since both terms are perfect squares, factor using the difference of squares formula,
a ^2 − b ^2 = ( a + b ) ( a − b )
where
a = y
and
b = 6
( y + 6 ) ( y − 6 )
Estimate the answers to the following calculations by carrying out order of magnitude calculations.
a) 0.26 x 890
b) [tex]\frac{1.95}{0.0067}[/tex]
c) 2010 x [tex]10^{-5}[/tex]
d) [tex]\frac{9.98 x 10^{-4} }{9 x 10^{2} }[/tex]
9514 1404 393
Answer:
a) 230
b) 300
c) 2×10^-2
d) 1.1×10^-6
Step-by-step explanation:
a) 0.26 × 890 ≈ 1/4 × 900 ≈ 225 ≈ 230
b) 1.95/(.67×10^-2) ≈ 2/(2/3)×10^2 ≈ 300
c) 2010×10^-5 ≈ 2×10^3×10^-5 = 2×10^-2
d) 9.98×10^-4/(9×10^2) = 9.98/9×10^(-4-2) ≈ 1.1×10^-6
__
YMMV depending on how you do the rounding and approximate multiplication and division.
The first one can be done multiple ways. For most accurate results, increasing one number while decreasing the other is recommended. (You don't want to compute 0.3×900, for example.)
A circular garden is surrounded by a circular path of 7m width.If the area of path is 770m²,find the area of the garden without path.
help me this question ⁉️
Answer:
Answer:
Radius of the circular garden
= 210 sq
=105m
Radius of the region covering the garden and the path =105m+7m
=112m
Area of the region between two concentric circles
with radius of outer circle R, and inner circle r =π(R sq−r sq)
Hence, the area of the path
=π(112sq−105 sq)= 7/22
(12544−11025)
= 33418/7
=4774m sq
HOPE THIS WILL HELP YOU MATE
The function s(t) = t2+2t+5shows the height s(t), in feet, of a water balloon after t seconds. A second water balloon moves in the air along a path represented by p(t)=11+3t where p(t) is the height, in feet, of the balloon from the ground at time t seconds
Part A: Create a table using integers 1 through 4 for the two functions. What is the solution for s(t) = p(t)? How do you know? Include the table in your answer.
Part B: Explain what the solution from Part A means in context of the problem.
Answer:
t =2 , 3
Step-by-step explanation:
s (t) = t^2 + 2 t + 5
p (t) = 11 + 3 t
(a) s (1) = 8
s (2) = 13
s (3) = 20
s (4) = 29
p (1) = 14
p (2) = 17
p (3) = 20
p (4) = 23
Now equate both of them
[tex]t^2 + 2t + 5 = 11 + 3 t \\\\t^2 - t - 6 =0 \\\\t^2 - 3 t + 2t - 6 =0\\\\t(t - 3) + 2 (t - 3) = 0\\\\(t -3)(t-2)=0\\\\t =3, 2[/tex]
(b) It shows that the values are same at = 2 and t = 3.
If U={a,b,c,d,e,f,g,h,} A={a,b,c,d} B={a,e,h}. Then verify the relation AUB
Answer:
U={a,b,c,d,e,f,g,h}
A={a,b,c,d}
now,
AUB= {a,b,c,d,e,f,g,h} U {a,b,c,d}
= {a,b,c,d,e,
ok,this question is wrong btw ,I think I stead of U(universal set) it is B
20 Points- Which of the following is true for f of x equals the quotient of the quantity x squared plus 9 and the quantity x minus 3?
There is a removable discontinuity at x = 3.
There is a non-removable discontinuity at x = 3.
The function is continuous for all real numbers.
Answer:
There is a non-removable discontinuity at x = 3
Step-by-step explanation:
We are given that
[tex]f(x)=\frac{x^2+9}{x-3}[/tex]
We have to find true statement about given function.
[tex]\lim_{x\rightarrow 3}f(x)=\lim_{x\rightarrow 3}\frac{x^2+9}{x-3}[/tex]
=[tex]\infty[/tex]
It is not removable discontinuity.
x-3=0
x=3
The function f(x) is not define at x=3. Therefore, the function f(x) is continuous for all real numbers except x=3.
Therefore, x=3 is non- removable discontinuity of function f(x).
Hence, option B is correct.
Write an
equivalent expression by distributing the
"---"
sign outside the parentheses:
-(3.9d + 10)
Answer of this question
-3.9d-10Which formulas can be used to find the surface area of a right prism where p is the perimeter of the base, h is the height of the prism, BA is the area of bases, and LA is the lateral area? Check all that apply.
A. SA = BA - LA
B. SA = p + LA
C. SA = BA + LA
D. SA = BA + ph
E. SA = 1 / BA + LA
Answer:
SA=BA+LA and SA=BA+ph
Step-by-step explanation:
I just looked it up
The correct formulas to find the surface area of a right prism are:
SA = BA + LA and SA = BA + ph.
Options (A), and (D) are the correct answer.
What is a prism?A prism is a three-dimensional object.
There are triangular prism and rectangular prism.
We have,
The correct formulas to find the surface area of a right prism are:
1)
SA = BA + LA, where SA is the total surface area, BA is the area of the two identical bases, and LA is the lateral area (the sum of the areas of all the rectangular sides).
2)
SA = BA + ph, where SA is the total surface area, B is the area of one base, p is the perimeter of the base, h is the height of the prism, and ph is the area of all the rectangular sides (the lateral area).
Therefore,
The correct formulas to find the surface area of a right prism are:
SA = BA + LA and SA = BA + ph.
Learn more about prism here:
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which of the following are identities? check all that apply.
A. (sinx + cosx)^2= 1+sin2x
B. sin6x=2 sin3x cos3x
C. sin3x/sinxcosx = 4cosx - secx
D. sin3x-sinx/cos3x+cosx = tanx
Answer: (a), (b), (c), and (d)
Step-by-step explanation:
Check the options
[tex](a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x[/tex]
[tex](b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)[/tex]
[tex](c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow 3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x[/tex]
[tex](d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x[/tex]
Thus, all the identities are correct.
A. Not an identity
B. An identity
C. Not an identity
D. An identity
To check whether each expression is an identity, we need to verify if the equation holds true for all values of the variable x. If it is true for all values of x, then it is an identity. Let's check each option:
A. [tex]\((\sin x + \cos x)^2 = 1 + \sin 2x\)[/tex]
To check if this is an identity, let's expand the left-hand side (LHS):
[tex]\((\sin x + \cos x)^2 = \sin^2 x + 2\sin x \cos x + \cos^2 x\)[/tex]
Now, we can use the trigonometric identity [tex]\(\sin^2 x + \cos^2 x = 1\)[/tex] to simplify the LHS:
[tex]\(\sin^2 x + 2\sin x \cos x + \cos^2 x = 1 + 2\sin x \cos x\)[/tex]
The simplified LHS is not equal to the right-hand side (RHS) 1 + sin 2x since it is missing the sin 2x term. Therefore, option A is not an identity.
B. [tex]\(\sin 6x = 2 \sin 3x \cos 3x\)[/tex]
To check if this is an identity, we can use the double-angle identity for sine:[tex]\(\sin 2\theta = 2\sin \theta \cos \theta\)[/tex]
Let [tex]\(2\theta = 6x\)[/tex], which means [tex]\(\theta = 3x\):[/tex]
[tex]\(\sin 6x = 2 \sin 3x \cos 3x\)[/tex]
The equation holds true with the double-angle identity, so option B is an identity.
C. [tex]\(\frac{\sin 3x}{\sin x \cos x} = 4\cos x - \sec x\)[/tex]
To check if this is an identity, we can simplify the right-hand side (RHS) using trigonometric identities.
Recall that [tex]\(\sec x = \frac{1}{\cos x}\):[/tex]
[tex]\(4\cos x - \sec x = 4\cos x - \frac{1}{\cos x} = \frac{4\cos^2 x - 1}{\cos x}\)[/tex]
Now, using the double-angle identity for sine, [tex]\(\sin 2\theta = 2\sin \theta \cos \theta\),[/tex] let [tex]\(\theta = x\):[/tex]
[tex]\(\sin 2x = 2\sin x \cos x\)[/tex]
Multiply both sides by 2: [tex]\(2\sin x \cos x = \sin 2x\)[/tex]
Now, the left-hand side (LHS) becomes:
[tex]\(\frac{\sin 3x}{\sin x \cos x} = \frac{\sin 2x}{\sin x \cos x}\)[/tex]
Using the double-angle identity for sine again, let [tex]\(2\theta = 2x\):[/tex]
[tex]\(\frac{\sin 2x}{\sin x \cos x} = \frac{2\sin x \cos x}{\sin x \cos x} = 2\)[/tex]
So, the LHS is 2, which is not equal to the RHS [tex]\(\frac{4\cos^2 x - 1}{\cos x}\)[/tex]. Therefore, option C is not an identity.
D. [tex]\(\frac{\sin 3x - \sin x}{\cos 3x + \cos x} = \tan x\)[/tex]
To check if this is an identity, we can use the sum-to-product trigonometric identities:
[tex]\(\sin A - \sin B = 2\sin \frac{A-B}{2} \cos \frac{A+B}{2}\)\(\cos A + \cos B = 2\cos \frac{A+B}{2} \cos \frac{A-B}{2}\)[/tex]
Let A = 3x and B = x:
[tex]\(\sin 3x - \sin x = 2\sin x \cos 2x\)\(\cos 3x + \cos x = 2\cos 2x \cos x\)[/tex]
Now, we can rewrite the expression:
[tex]\(\frac{\sin 3x - \sin x}{\cos 3x + \cos x} = \frac{2\sin x \cos 2x}{2\cos 2x \cos x} = \frac{\sin x}{\cos x} = \tan x\)[/tex]
The equation holds true, so option D is an identity.
To know more about identity:
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Celsius to Fahrenheit
Step-by-step explanation:
149......hshdbhdhsbhsjsusvshhs
Solve the equation and enter the value of x below. 9x + 4 + x = 54
Hello!
9x + 4 + x = 54 <=>
<=> 9x + x + 4 = 54 <=>
<=> 10x + 4 = 54 <=>
<=> 10x = 54 - 4 <=>
<=> 10x = 50 <=>
<=> x = 50 : 10 <=>
<=> x = 5 => 9 × 5 + 4 + 5 = 54
Good luck! :)
Answer:
x = 5
Step-by-step explanation:
First, combine like terms. Like terms are terms with the same variables as well as same amount of said variables:
9x + x + 4 = 54
(9x + x) + 4 = 54
10x + 4 = 54
Next, isolate the variable, x. Note the equal sign, what you do to one side, you do tot he other. Do the opposite of PEMDAS.
PEMDAS is the order of operations, and stands for:
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
-
First, subtract 4 from both sides of the equation:
10x + 4 (-4) = 54 (-4)
10x = 54 - 4
10x = 50
Next, divide 10 from both sides of the equation:
(10x)/10 = (50)/10
x = 50/10 = 5
x = 5 is your answer.
~
identify an equation in point slope form for the line perpendicular to y=-1/3x-6 that passes through (-1,5)
find the size of each of the unknown angles.
plz solve this question fast as soon as possible with solution.
Answer:
Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°
Step-by-step explanation:
To find the measure of Angle a, we add 55 and 45, then subtract the sum from 180.
180 - 100 = 80
Angle a is 80°.
Then, we solve for Angle b. Line segment CD is congruent to Line AB, so Angle b is congruent to 55°.
After that, we find Angle c. Line segment AC is congruent to Line segment BD, so Angle c is congruent to 45°.
Lastly, we solve for Angle d using the same method we used for Angle b and Angle c. Angle d is congruent to Angle a, so it measures 80°.
So, Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°.
expand: 4(w - 2)
(with the steps)
Answer:
4w-8
Step-by-step explanation:
4(w-2)
(4*w)-(4*2)
4w-8
Answer:
4w-8
Step-by-step explanation:
4(w - 2)
Distribute
4*w - 4*2
4w-8
The area of a duck enclosure is 300 square feet, with 100 square feet occupied by a pond. Each duck in the enclosure needs more than 20 square feet of space on dry land. If x ducks can be put in the enclosure, which is the simplest inequality that represents this situation?
Answer: x = 100 duck
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Question 2: use the image and your knowledge of the isosceles triangle to find the value of x
Answer:
x is 66 degrees
Step-by-step explanation:
since its a isosceles, two of the angles should be the same.
Which of the following inequalities matches the graph?
Answer:
the answer is C, comment if you need explanation
Step-by-step explanation:
− 0.32 + 0.18 = 0.25 − 1.95
Answer:
Step-by-step explanation:
0.18-0.32 = .25-1.95
-0.14 = 1.70
obviously that equation above is not true, I suspect that there were some "x" variables on some of those numbers?
If Clare earns $75 the next week from delivering newspapers and deposits it in her account, What will her account balance be then?\
answer pls
Answer: $15
Step-by-step explanation:
-$50 + $75 = $15
PLEASE HELP! Which of the following ordered pairs is a solution to the given system of equations?
A. (12, 8)
B. (3, 5)
C. (-3, 3)
D. (0, 4)
please don’t use this for points.
Answer:
A.............
Step-by-step explanation:
. ..........
Answer:
C. (3,3)
Step-by-step explanation:
When These equations are both graphed the solution for these equations when they intersect is (-3,3)
In the figure above the ratio of the area of WXZ to the area of WYZ is 7:2. If XY = 21, what is the length of segment WY?
[tex]{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}[/tex]
Because ∆XZW and WYZ is the same height and
Because ∆XZW and WYZ is the same height and the are of ∆WXZ to the the WYZ
[tex]so \:( \frac{1}{2}xw \times h)( \frac{1}{2} w)=7:2[/tex]
Because xy=21
[tex]so \: WY=2 \frac{1}{2}(7 + 2x2) \\ = 21 \frac{1}{2}p \times 2 \\ =\small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: WY=\frac{14}{3}\:\:\:\: }}}}[/tex]
The length of the line segment WY is [tex]\frac{14}{3}[/tex] unit.
What is the area of triangle?The area of a triangle is defined as the total region that is enclosed by the three sides of any particular triangle.
What is the formula for the area of triangle?Area of triangle = (1/2)base × height
According to the given question.
The ratio of the area of triangle WXZ to the area of triangle WYZ is 7:2.
Since, the height WZ for both the triangles WXZ and WYZ is same.
Let, WZ = h
Therefore, the ratio of the area of the triangles is given by
[tex]\frac{\frac{1}{2}WX(h) }{\frac{1}{2}(WY)(h) } =\frac{7}{2}[/tex]
⇒ [tex]\frac{WX}{WY} =\frac{7}{2}[/tex]
⇒ [tex]WX = \frac{7}{2} WY..(i)[/tex]
Since, in the given figure
[tex]XY = WY + WX[/tex]
⇒ [tex]21 = WY + \frac{7}{2} WY[/tex] (from i)
⇒ [tex]21 = \frac{9}{2}WY[/tex]
⇒ [tex]WY = \frac{14}{3}[/tex]
Hence, the length of the line segment WY is [tex]\frac{14}{3}[/tex] unit.
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A house plan Is drawn to a scale 1cm to 2m. What is the length of a window 2.5cm long on the plan?
1cm = 2m
=> 1cm = 200cm
2.5cm = 2.5 × 200cm = 500 cm = 5m
So, the length of window is 500cm or 5m.
Pls help plz help pls plz help plz plz help
Answer:
The first choice, Equation A and equation C.
Step-by-step explanation:
The lines A and C are intersecting in the point (0,8). That is the solution for those lines.
if the diagonal of a square is √48 what is the area of a square
Answer:
using Pythagoras' theorem c²=a²+b²
the diagonal is the hypotenuse of one of the triangles formed
let x represent one side of the square
√48²=x²+x²
√48²=2x²
48=2x²
48/2=2x²/2
24=x²
√24=√x²
4.8989794855663561=x
~4.90
Area of the square=side x side
4.90x4.90
24.01units²
There is $1.90 in a jar filled with
quarters, dimes, and nickels.
There are 2 more quarters than
dimes and there are 2 more
nickels than quarters.
How many of each coin are there?
Answer:
7 nickels, 5 quarters, 3 dimes
Step-by-step explanation:
7 nickels= 35 cents
5 quarters= $1.25
3 dimes= 30 cents
35+ 1.25+ 30= $1.90
Hope this helps!
Plz mark Brainliest if u can :)
How many terms are in the algebraic expression
Also, What do they mean by "Terms"
Answer:
There are 4 terms
Step-by-step explanation:
A term is a single mathematical expression. Terms can be identified with a plus or minus sign in front of them. Terms can also be multiplied and divided.
So, in this case, the terms are:
-7
12x^4
-5y^8
x
HELP ME PLSSSSSSS!!!!!!!!!
Domain of the function
[-3,5)Solve 3x – ly= 11 and -2x – 4y=-26 by elimination
If anyone can help me with this it’d be appreciated
Answer:
(5, 4 )
Step-by-step explanation:
Given the 2 equations
3x - y = 11 → (1)
- 2x - 4y = - 26 → (2)
Multiplying (1) by - 4 and adding to (2) will eliminate the y- term
- 12x + 4y = - 44 → (3)
Add (2) and (3) term by term to eliminate y
- 14x + 0 = - 70
- 14x = - 70 ( divide both sides by - 14 )
x = 5
Substitute x = 5 into either of the 2 equations and solve for y
Substituting into (1)
3(5) - y = 11
15 - y = 11 ( subtract 15 from both sides )
- y = - 4 ( multiply both sides by - 1 )
y = 4
solution is (5, 4 )
