A researcher conducts a repeated-measures design study comparing 2 treatment conditions and obtains 20 scores in EACH treatment condition. How many participants participated in the study

Answer:

50 dozen total

Step-by-step explanation:

8/12 & 10/12.... average 9/12

11/12 - 9/12 =

2/12x = 100

2x = 1200

x = 600/12

50 dozen total

Given:

so, total cost fir 200 masks=

200×5

= 1000

therefore, Joe paid Rs. 1000 altogether.

Answer:

$ 1220.00

Step-by-step explanation:

1269.79 = A [tex]e^{.02 * 2}[/tex]

1269.79 /A = [tex]e^{.04}[/tex]

ln(1269.79 /A) = .04 ln(e)

ln(1269.79 /A) = .04

1269.79 /A = [tex]e^{.04}[/tex]

1269.79 /A = 1.0408

A =  1269.79 / 1.0408

$ 1220.00

Answer:

Infinitely many solutions.

They must satisfy [tex]y = \frac{1}{5}(x - 5)[/tex]

Step-by-step explanation:

Given

[tex]x - 5y = 5[/tex]

[tex]-x + 5y = -5[/tex]

Required

The best description

Add both equations

[tex]x - x - 5y + 5y = 5 - 5[/tex]

[tex]0+0 =0[/tex]

[tex]0 = 0[/tex] ---- this means that the system has infinitely many solutions.

Make y the subject in: [tex]-x + 5y = -5[/tex]

Add x to both sides

[tex]5y = x - 5[/tex]

Divide through by 5

[tex]y = \frac{1}{5}(x - 5)[/tex]

Hence, they must satisfy: [tex]y = \frac{1}{5}(x - 5)[/tex]

I believe your answer is D.) $900

204 + 96 = 300

300 x 3 = 900

I hope this is correct and helps!

Answer:

The standard error of your estimate of the average height in the city is 0.5 inches.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

You begin by collecting the heights of a random sample of 196 people from the city.

This means that [tex]n = 196[/tex]

The standard deviation of the heights in your sample is 7 inches.

This means that [tex]\sigma = 7[/tex]

The standard error of your estimate of the average height in the city is

[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{7}{\sqrt{196}} = 0.5[/tex]

The standard error of your estimate of the average height in the city is 0.5 inches.

Answer:

115

Step-by-step explanation:

Answer:

Area of a trapezoid= (big base+small base)/2 x height

A=(67+54)/2 x 18

A=60.5 x 18

A=1089  

Options :

A.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded below the line

B.The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded above the line.

C. The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded below the line.

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Answer:

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Step-by-step explanation:

The equation y > 3x – 8

Interpreting as a linear relation :

y > ax + b

Where, a = slope ; b = intercept

a = 3 ; that is a slope value of 3

b = -8 ; that is an intercept value of - 8

Since the inequality is >, a dashed line is used (dashed like is used for > and <) ; since we a have a greater than sign, the graph will be shaded above the dashed line.

Answer: The answer is D on edu 2021

Step-by-step explanation:

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Step-by-step explanation:

1/6

1/6- 1/2 = 1/4

1/4*1/2= 1/8

Answer:

Step-by-step explanation:

-6z²-10z-3=0

multiply by -1

6z²+10z+3=0

disc .=b²-4ac=10²-4×6×3=100-72=28≥0

also it is not a perfect square.

so roots are real,irrational and different.

[tex]z=\frac{-6 \pm\sqrt{28} }{2 \times 6} \\=\frac{-6 \pm 2 \sqrt{7}}{12} \\=\frac{-3 \pm\sqrt{7} }{6}[/tex]

Answer:

[tex] { - 3}^{2} + (4 + 7)(2) \\ = - 9 + 22 \\ = 13[/tex]

Answer:

90 maybe is a correct answer

Answer:

Y=40°

Step-by-step explanation:

VUW~YXZ

VWU~YZX

YXZ+XYZ+YZX=180°

70°+XYX+70°=180°

140°+XYZ=180°

XYZ=180°-140°

XYZ=40°

Pls the answer is

D

Thank you

You are welcome

Answer:

d

Step-by-step explanation:

im smart

Answer:

0.9984

Step-by-step explanation:

we have shape parameter for the first component as 2.1

characteristics life = 100000

for this component

we have

exp(-2000/100000)².¹

= e^-0.0002705

= 0.9997

for the second component

shape parameter = 1.8

characteristic life = 80000

= exp(-2000/80000)¹.⁸

= e^-0.001307

= 0.9987

the reliability oif the system after 2000  events

= 0.9987 * 0.9997

= 0.9984

9514 1404 393

Answer:

  3/4

Step-by-step explanation:

Assuming the faces are numbered 1 to 12, there are 9 faces with values less than 10. Since the outcomes are equally probable and mutually exclusive, the probability of any of the 9 is the sum of their individual probabilities:

  P(n < 10) = 9×1/12 = 9/12 = 3/4

Answer:

Slope is undefined. Line parallel to y-axis.

Step-by-step explanation:

By Analytic Geometry, we can determine the slope of a line by knowing two distinct lines and using the definition of secant line:

[tex]m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] (1)

Where:

[tex](x_{1}, y_{1})[/tex] - Coordinates of the initial point.

[tex](x_{2}, y_{2})[/tex] - Coordinates of the final point.

[tex]m[/tex] - Slope.

If we know that [tex](x_{1}, y_{1}) = (17, -13)[/tex] and [tex](x_{2}, y_{2}) = (17, 8)[/tex], then the slope of the line is:

[tex]m = \frac{8-(-13)}{17-17}[/tex]

[tex]m = \frac{21}{0}[/tex]

The slope is undefined, which means that line is parallel to y-axis.

Answer:

The answer is 1 1/4 or 5/4

Step-by-step explanation:

1/8 · 10 = 10/8

10/8 when simplified is 5/4

Answer:

eh width = 103.5 inches

Step-by-step explanation:

x = width

Length = (x/2 - 5 )*6

so 384=x+3x-30

414=4x

x=414/4=103.5 inches

Answer:

hello there here is your answer

51 is your next term.

Step-by-step explanation:

you are subtracting 9 from each number

95-9= 86

86-9=78

78-9=65

65-9=60

60-9=51

so on and so on

Hope this help

have a good day

bye

Step-by-step explanation:

[tex]here \: is \: your \: solution: - \\ \\ given \: number \: = 95.86.78.71.65.60 \\ \\ = > 95 - 9 = 86 \\ \\ = > 86 - 8 = 78 \\ \\ = > 78 - 7 = 71 \\ \\ = > 71 - 6 = 65 \\ \\ = > 65 - 5 = 60 \\ \\ \: now \: follow \: the \: sequence \: \\ \\ subtract \: 4 \: from \: 60 \\ \\ = > 60 - 4 = 56 \\ \\ = > \: \: 56 \: \:( ANSWER✓✓✓)[/tex]

Answer:

Gary is now 24years

Step-by-step explanation:

let the age of Jan be x and that of Gary be x+15

in six years time they will be as follows

Jan =x+6

Gary=x+15+6=x+21

2(x+6)=x+21

2x+12=x+21

collect the like terms

2x-x=21-12

x=9

Gary =9+15=24years

Answer:

A

Step-by-step explanation:

Number of suitcases on a plane is discrete because you can only have an integer amount. You can't have a fraction of a suitcase on a plane.

Answer:

96 eggs

Step-by-step explanation:

A dozen is equal to 12 eggs, so 15 dozen is equal to 180 eggs

(Because 15*12 = 180)

We already know how many eggs are required for the 1st cake: 12 eggs.

Then it says "each successive cake needs twice as many eggs as the previos cake".

(Successive means the cake directly after the previous cake)

Here's how we find the number of eggs needed for the 2nd cake:

The 1st cake needed 12 eggs, and because the 2nd cake is directly after the 1st cake, we are going to need two times the amount of 12 eggs.

This equation represents the above scenario:

12*2 = 24

So we need 24 eggs for the 2nd cake.

Now we repeat this process for the 3rd cake, finding twice the amount of eggs from the 2nd cake to find the amount of eggs needed for the 3rd cake:

24*2 = 48

And we repeat it once more for the 4th cake, using the eggs from the 3rd cake:

48*2 = 96

So here's the list of how many eggs are required for each of the cakes:

1st cake: 12

2nd cake: 24

3rd cake: 48

4th cake: 96

If you add all the eggs from each of the cakes, you will get 180, which is the number of eggs needed for all four cakes. So our answer is correct.

Hope this helps (●'◡'●)

Answer:

The postage per ounce would be of $2.02.

Step-by-step explanation:

Exponential model:

The postage, in t years after 1963, follows the following format:

[tex]P(t) = P(0)(1+r)^t[/tex]

In which P(0) is the initial value and r is the growth rate, as a decimal.

In 1963, postage was 5 cents per ounce.

This means that [tex]P(0) = 5[/tex]

So

[tex]P(t) = P(0)(1+r)^t[/tex]

[tex]P(t) = 5(1+r)^t[/tex]

In 1981, postage was 18 cents per ounce.

This means that [tex]P(1981 - 1963) = P(18) = 18[/tex]. We use this to find r. So

[tex]P(t) = 5(1+r)^t[/tex]

[tex]18 = 5(1+r)^{18}[/tex]

[tex](1+r)^{18} = \frac{18}{5}[/tex]

[tex]\sqrt[18]{(1+r)^{18}} = \sqrt[18]{3.6}[/tex]

[tex]1 + r = (3.6)^{\frac{1}{18}}[/tex]

[tex]1 + r = 1.0738[/tex]

So

[tex]P(t) = 5(1.0738)^t[/tex]

If the trend had continued through to 2015, what would the postage per ounce be?

2015 - 1963 = 52, so this is P(52).

[tex]P(52) = 5(1.0738)^{52} = 202[/tex]

202 cents, so $2.02.

Answer:

95.4%

Step-by-step explanation:

Z(low)=-2 0.022750132

Z(upper)=2 0.977249868

True

Step-by-step explanation:

[tex]P(t) = I^2(t)R[/tex]

Taking the derivative of P(t) with respect to time,

[tex]\dfrac{dP(t)}{dt} = 2I(t)\dfrac{dI(t)}{dt}R[/tex]

[tex]\:\:\:\:\:\:\:\:= 2(1)(-0.5)(500) = -500[/tex]

Recall that variation of parameters is used to solve second-order ODEs of the form

y''(t) + p(t) y'(t) + q(t) y(t) = f(t)

so the first thing you need to do is divide both sides of your equation by t :

y'' + (2t - 1)/t y' - 2/t y = 7t

You're looking for a solution of the form

[tex]y=y_1u_1+y_2u_2[/tex]

where

[tex]u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt[/tex]

[tex]u_2(t)=\displaystyle\int\frac{y_1(t)f(t)}{W(y_1,y_2)}\,\mathrm dt[/tex]

and W denotes the Wronskian determinant.

Compute the Wronskian:

[tex]W(y_1,y_2) = W\left(2t-1,e^{-2t}\right) = \begin{vmatrix}2t-1&e^{-2t}\\2&-2e^{-2t}\end{vmatrix} = -4te^{-2t}[/tex]

Then

[tex]u_1=\displaystyle-\int\frac{7te^{-2t}}{-4te^{-2t}}\,\mathrm dt=\frac74\int\mathrm dt = \frac74t[/tex]

[tex]u_2=\displaystyle\int\frac{7t(2t-1)}{-4te^{-2t}}\,\mathrm dt=-\frac74\int(2t-1)e^{2t}\,\mathrm dt=-\frac74(t-1)e^{2t}[/tex]

The general solution to the ODE is

[tex]y = C_1(2t-1) + C_2e^{-2t} + \dfrac74t(2t-1) - \dfrac74(t-1)e^{2t}e^{-2t}[/tex]

which simplifies somewhat to

[tex]\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}[/tex]

Answer:

0.0002

Step-by-step explanation:

4 decimal places means tenths, hundredths, thousandths, and ten thousandths places. If we count 4 decimal places, we come to 0.0002. The number next to it, 3, rounds down, so the answer should be 0.0002.