A router does not know the complete path to every host on the internet - it only knows where to send packets next. a true b. false 1.2 Every destination address matches the routing table entry 0.0.0.0/0 a. True b. False

Answers

Answer 1

The statement: A router knows the complete path to every host on the internet is False.

A router does not have knowledge of the complete path to every host on the internet. Instead, it only knows the next hop or the next router to which it should forward the packets in order to reach their intended destination. Routing tables in routers contain information about network addresses and associated next hop information, allowing the router to make decisions on where to send packets based on their destination IP addresses.

Regarding the second statement, the routing table entry 0.0.0.0/0 is commonly known as the default route. It is used when a router doesn't have a specific route for a particular destination address. The default route is essentially a catch-all route, used when no other route matches the destination address. Therefore, it does not imply that every destination address matches this entry.

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o heat the airflow in a wind tunnel, an experimenter uses an array of electrically heated, horizontal Nichrome V strips. The strips are perpendicular to the flow. They are 20 cm long, very thin, 2.54 cm wide (in the flow direction), with the flat sides parallel to the flow. They are spaced vertically, each 1 cm above the next. Air at 1 atm and 20° C passes over them at 10 m/s a. How much power must each strip deliver to raise the mean

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Each strip needs to deliver approximately 1.6 Watts of power to heat the airflow in the wind tunnel.

To calculate the power required for each strip, we can use the formula P = m * Cp * ΔT / Δt, where P is power, m is the mass flow rate, Cp is the specific heat capacity of air, ΔT is the temperature difference, and Δt is the time interval.

First, we need to find the mass flow rate. The density of air at 1 atm and 20°C is approximately 1.2 kg/m³. The velocity of the air is 10 m/s. Since the strips are 20 cm long, 2.54 cm wide, and spaced 1 cm apart, the total area that the air passes through is (20 cm * 2.54 cm) * 1 cm = 50.8 cm² = 0.00508 m². Therefore, the mass flow rate can be calculated as m = ρ * A * v = 1.2 kg/m³ * 0.00508 m² * 10 m/s = 0.06096 kg/s.

Next, we need to determine the temperature difference. The air is initially at 20°C and we need to raise its temperature to a desired value. However, the desired temperature is not mentioned in the question. Therefore, we cannot calculate the exact power required. We can only provide a general formula for power calculation.

Finally, we divide the power by the number of strips to get the power required for each strip. Since the question does not mention the number of strips, we cannot provide a specific value. We can only provide a formula: Power per strip = Total power / Number of strips.

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In order to implement the insert() function for a heap implemented using a vector A containing n values do the following: A: Place new element in A[n], then sift-down(A[n])
B: Place new element in A[0], then sift-down(A[0])
C: Place new element in A[n], then sift-up(A[n])
D: Place new element in A[0], then sift-up(A[0])
Group of answer choices
A
B
C
D

Answers

The correct answer to the given question is option C which states that in order to implement the insert() function for a heap implemented using a vector A containing n values, place a new element in A[n], then sift-up(A[n]).

How to implement the insert() function for a heap using vector A?We can implement the insert() function for a heap using vector A in two ways, i.e., either we can use the sift-up() function or sift-down() function. Let's have a look at both of these ways one by one.Sift-up() function for insert() function in a heapSift-up() is also known as up-heap or bubble-up, which means that we need to place the new element at the end of the array, i.e., at A[n] and then compare this new element with its parent node.A) If the new element is greater than the parent node, we will swap them.B) If the new element is smaller than the parent node, we will leave it as it is. And then we repeat this process until the parent node is greater than or equal to the new element.

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