Answer:
7.00864
Step-by-step explanation:
The upper control limit for R -chart can be computed by using following formula
UCL=Rbar*D4.
We are given that average range R bar is
Rbar=3.76.
The value of D4 for n=8 is also given that is
D4=1.864.
Thus, the required computed upper control limit is
UCL=3.76*1.864=7.00864.
Allowance bank received a deposit of 28,000 and is free to lend out 25,480 what is the reserve rate?
Answer:
Reserve rate = 9%
Step-by-step explanation:
Reserve ratio/rate is the percentage of deposits which commercial banks are required to keep as cash, as directed by the central banks.
first, let us calculate the reserve amount as follows:
Reserve = Deposit - (free amount to lend out)
Reserve = 28,000 - 25,480 = $2,520
[tex]Reserve\ rate = \frac{Reserves}{Deposits} \times100\\Reserve\ rate = \frac{2520}{28000} \times100\\=\frac{252000}{28000} =9\%[/tex]
Therefore the reserve rate = 9%
You missed your payment due date and now have $300 on your card that has a 24% APR. You are able to pay $100 in one month and then every month after that. How many months will it take you to pay this credit card off?
Which relationships have the same constant of proportionality between y and x as the equation 3y=2x? SELECT 3 ANSWERS
*Correct Question:
Which relationships have the same constant of proportionality between y and x as the equation 3y=27x?
Answer:
A, B, C
Step-by-step explanation:
Given that [tex] 3y = 27x [/tex] , we can simplify to get a proportionality statement that exists between X and y. Thus
[tex] 3y = 27x [/tex]
Divide both sides by 3
[tex] \frac{3y}{3} = \frac{27x}{3} [/tex]
[tex] y = 9x [/tex]
Thus, we can say, y would always be 9 times the quantity of x.
From the options given, examine which options have this proportionality statement as well.
Option A, y = 9x is same as the statement.
Option B, 2y = 18x, conforms to the same statement. If we simply further, we would have y = 9x
Option C, the graph shows that when x = 1, y = 9. This also confirms to the same constant of proportionality in the given equation.
Option D and E do not have same constant of proportionality.
The right options are A, B, and C.
A computer store sells new computers for $500 and refurbished computers for
$200. In March, the store sold 20 computers for $6,400, meaning they sold ?
refurbished computers.
Answer:
no of new computers sold : 8
no. of refurbished computer sold : 12
Step-by-step explanation:
Let the no. of new computers sold be x
let the no. of refurbished computers sold be y
Given
In March, the store sold 20 computers
x + y = 20
y = 20-x ----- equation 2
selling price of new computer = $500
selling price of x new computer = 500*x = 500x
selling price of refurbished computer = $200
selling price of y refurbished computer = 200*y = 200y
Total selling price of x new computer and y refurbished computers = 500x+200y
given that
total prioce of computer is $6400
thus
500x+200y = 6400
using y = 20-x from equation 2
500x+200(20-x) = 6400
=> 500x+ 4000 - 200x = 6400
=> 300x = 6400 - 4000 = 2400
=> x = 2400/300 = 8
Thus,
no of new computers sold = 8
no. of refurbished computer sold = 20 -8 = 12
GIVING BRAINLIEST TO THE FIRST PERSON TO ANSWER!
A 16-inch piece of string is 40.64 centimeters long. To the nearest 0.01 centimeter, how long will a 42-inch price of string be?
A. 56.64 cm
B. 82.64 cm
C. 106.68 cm
D. 1,706.88 cm
Please show ALL work! <3
Answer:
106.68 centimeters
Step-by-step explanation:
40.64 cm/16 in = x cm/42 in
Cross multiplying, we get:
16x = 40.64(42)
16x = 1706.88
x = 106.68 centimeters
help help help help help help
Answer:
75 yards long and 90 yards wide.
Step-by-step explanation:
Let's first find the perimeter of the main rectangle:
100x2 + 65x2 =
330
_________________________________________
Next we need to find two numbers that match:
75 and 90
75x2 + 90x2 =
330
_________________________________________
75x90 is 6750 (More Area)
100x60 is 6500 (Less Area)
Find x.
A. 21(route)2
B. 7
C.21(route)3/2
D. 21(route)2/2
Answer:
Option (D)
Step-by-step explanation:
By applying Sine rule in the right ΔABD,
Sin(A) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
Sin(60)° = [tex]\frac{\text{BD}}{\text{AB}}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\text{BD}}{7\sqrt{3}}[/tex]
BD = [tex]7\sqrt{3}\times \frac{\sqrt{3} }{2}[/tex]
= [tex]\frac{21}{2}[/tex]
Now by applying Cosine rule in the right ΔBDC,
Cos(45)° = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{1}{\sqrt{2}}=\frac{\frac{21}{2}}{x}[/tex]
x = [tex]\frac{21}{2}\times \sqrt{2}[/tex]
x = [tex]\frac{21\sqrt{2}}{2}[/tex]
Therefore, Option (D) is the correct option.
Please answer this correctly without making mistakes
Answer:
151 9/19
Step-by-step explanation:
Step-by-step explanation:
Option A is the correct answer because it is equal to 151.47
Find the area of the surface generated by revolving x=t + sqrt 2, y= (t^2)/2 + sqrt 2t+1, -sqrt 2 <= t <= sqrt about the y axis
The area is given by the integral
[tex]\displaystyle A=2\pi\int_Cx(t)\,\mathrm ds[/tex]
where C is the curve and [tex]dS[/tex] is the line element,
[tex]\mathrm ds=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt[/tex]
We have
[tex]x(t)=t+\sqrt 2\implies\dfrac{\mathrm dx}{\mathrm dt}=1[/tex]
[tex]y(t)=\dfrac{t^2}2+\sqrt 2\,t+1\implies\dfrac{\mathrm dy}{\mathrm dt}=t+\sqrt 2[/tex]
[tex]\implies\mathrm ds=\sqrt{1^2+(t+\sqrt2)^2}\,\mathrm dt=\sqrt{t^2+2\sqrt2\,t+3}\,\mathrm dt[/tex]
So the area is
[tex]\displaystyle A=2\pi\int_{-\sqrt2}^{\sqrt2}(t+\sqrt 2)\sqrt{t^2+2\sqrt 2\,t+3}\,\mathrm dt[/tex]
Substitute [tex]u=t^2+2\sqrt2\,t+3[/tex] and [tex]\mathrm du=(2t+2\sqrt 2)\,\mathrm dt[/tex]:
[tex]\displaystyle A=\pi\int_1^9\sqrt u\,\mathrm du=\frac{2\pi}3u^{3/2}\bigg|_1^9=\frac{52\pi}3[/tex]
Nine less than the quotient of
twice a number and four.
Answer:
-1
Step-by-step explanation:
Twice a number of 4 equals 8
4×2=8
less than 9 of the quotient (answer) of twice a number of 4, is -1
8-9= -1
The required expression for Nine less than the quotient of twice a number and four gives the equation, y =2x/4 - 9.
An expression Nine less than the quotient of twice a number and four. is to be determined.
The process in mathematics to operate and interpret the function to make the function simple or more understandableis called simplify and the process is called simplification.
The quotient is the result when one value gets divided by some other value.
Using simple arithmetic,
Let the number be x,
A number y is equal to nine less than the quotient of twice of x and four. So,
y = quotient of 2x and four - 9
y = 2x/4 - 9
Thus, the required expression for Nine less than the quotient of twice a number and four gives the equation, y =2x/4 - 9.
Learn more about simplification here: https://brainly.com/question/12501526
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(Small sample confidence intervals for a population mean) suppose you are taking a sampling of 15 measurements. you find that x=75 and s =5. assuming normality, the 99% confidence interval for the population mean is:__________
Answer:
The 99% confidence interval is [tex]71.67 < \mu < 78.33[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is [tex]n = 15[/tex]
The sample mean is [tex]\= x = 75[/tex]
The standard deviation is [tex]s = 5[/tex]
Given that confidence is 99% then the level of significance is mathematically represented as
[tex]\alpha = 100 - 99[/tex]
[tex]\alpha = 1\%[/tex]
[tex]\alpha = 0.01[/tex]
Next we obtain the critical values of [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table
The value is
[tex]Z_{\frac{ \alpha }{2} } = 2.58[/tex]
Generally the margin for error is mathematically represented as
[tex]E = Z_{\frac{ \alpha }{2} } * \frac{ s}{ \sqrt{n} }[/tex]
=> [tex]E = 2.58 * \frac{ 5}{ \sqrt{15} }[/tex]
=> [tex]E = 3.3307[/tex]
The 99% confidence interval is mathematically represented as
[tex]\= x -E < \mu < \= x +E[/tex]
=> [tex]75 - 3.3307 < \mu <75 + 3.3307[/tex]
=> [tex]71.67 < \mu < 78.33[/tex]
Matrices and determinants What is 4c?
Answer:
Answer is D.
Step-by-step explanation:
do 4 times every value in the ( )
Answer:
[tex]\boxed{\sf D}[/tex]
Step-by-step explanation:
Help please, I don't understand :(
Answer:
38 = JKL
Step-by-step explanation:
JKM = JKL + LKN + NKM
Substituting what we know
104 = JKL + LKN +33
KN bisects LKM so NKM = LKN
33 = LKN
104 = JKL + 33 +33
104 = JKL + 33 +33
Combine like terms
104 = JKL +66
104 - 66 = JKL
38 = JKL
Answer: ∡JKL=38°
Step-by-step explanation:
KN bidects ∡LKM => ∠KLN=∡NKM=33°
=> ∡LKM=∠KLN+∡NKM=33°+33°=66°
=>∡JKL= ∡JKM-∡LKM= 104°-66°=38°
∡JKL=38°
List three methods of assigning probabilities. (Select all that apply.)
a. histogram.
b. intuition .
c. guessing .
d. equally likely outcomes .
e. relative frequency.
f. cumulative frequency.
Answer:
a,b and d
Step-by-step explanation:
●You can assign a probality based on your judgement and intuition.
●You can also assigni it based on the data of an histogram, in wich you see the frequency of the event you are interested in.
● Then there is the classical method based on mathematical calculations of equaly likely outcomes.
The three methods of assigning probabilities are:
b. intuition
e. relative frequency
d. equally likely outcomes
What are probabilities?Probabilities may occasionally be determined by a person's subjective opinion or personal conviction. This approach depends on the individual's perception of an event's probability or intuition. It is crucial to remember that probabilities based on intuition may not always be precise or trustworthy.
With this approach, probabilities are calculated based on the relative frequencies of historical events that have been observed. Probabilities can be calculated based on the relative frequency of different outcomes by gathering data and calculating their frequencies.
This approach makes the supposition that each potential result has an equal likelihood of happening.
Learn more about probabilities:https://brainly.com/question/29381779
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Find the value of x.
Answer:
5
Step-by-step explanation:
This shape is formed by two right triangles.
Let's start by the little one.
Let y be the third side.
Using the Pythagorian theorem we get:
y^2 = 6^2 + 3^2
y^2 = 36 + 9
y^2 = 45
y = 3√(5)
●●●●●●●●●●●●●●●●●●●●●●●●
Now let's focus on the second triangle. Let z be the third side.
The Pythagorian theorem:
6^2 + x^2 = z^2
Using the Pythagorian theorem on the big triangle :
[3√(5)]^2 + z^2 = (3+x)^2
45 + z^2 = 3x^2 + 6x + 9
36 +z^2 = 3x^2 +6x
So we have a system of equations.
36+ x^2 = z^2
36 +z^2 = 3x^2 +6x
We want to khow the value of x so we will eliminate z .
Add (36+x^2 -z^2 =0) to the second one.
36 + x^2-z^2+36+z^2 = 3x^2+6x
72 + x^2 = 3x^2 +6x
72 - 2x^2 -6x = 0
Multipy it by -1 to reduce the number of - signs
2x^2 + 6x -72 = 0
This is a quadratic equation
Let A be the discriminant
● a = 2
● b = 6
● c = -72
A = b^2-4ac
A = 36 -4*2*(-72) = 36 + 8*72 =612
So this equation has two solutions
The root square of 612 is approximatively 25.
● (-6-25)/4 = -31/4 = -7.75
● (-6+25)/4 = 19/4 = 4.75 wich is approximatively 5
A distance cannot be negative so x = 5
If the length of the legs of a right triangle are 13 and 13,what is the length of the hypotenuse? Round your answer to the nearest tenth,if necessary.
Answer:
a² + b² = c²
13² + 13² = c²
169 + 169 = c²
338 = c²
c = √338 or 18.385 or 13√2
Answer:
18.4
Step-by-step explanation:
13² + 13² = x²
169 + 169 = x²
338 = x²
x = 18.38477....
In a recent year, a sample of grade 8 Washington State public school students taking a mathematics assessment test had a mean score of 281 with a standard deviation of 34.4. Possible test scores could range from 0 to 500. Assume that the scores are normally distributed. Question 9 (2.5 points) If 2000 students are randomly selected, how many would you expect to have a score between 250 and 305?
Answer:
The number is [tex]N =1147[/tex] students
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 281[/tex]
The standard deviation is [tex]\sigma = 34.4[/tex]
The sample size is n = 2000
percentage of the would you expect to have a score between 250 and 305 is mathematically represented as
[tex]P(250 < X < 305 ) = P(\frac{ 250 - 281}{34.4 } < \frac{X - \mu }{\sigma } < \frac{ 305 - 281}{34.4 } )[/tex]
Generally
[tex]\frac{X - \mu }{\sigma } = Z (Standardized \ value \ of \ X )[/tex]
So
[tex]P(250 < X < 305 ) = P(-0.9012< Z<0.698 )[/tex]
[tex]P(250 < X < 305 ) = P(z_2 < 0.698 ) - P(z_1 < -0.9012)[/tex]
From the z table the value of [tex]P( z_2 < 0.698) = 0.75741[/tex]
and [tex]P(z_1 < -0.9012) = 0.18374[/tex]
[tex]P(250 < X < 305 ) = 0.75741 - 0.18374[/tex]
[tex]P(250 < X < 305 ) = 0.57[/tex]
The percentage is [tex]P(250 < X < 305 ) = 57\%[/tex]
The number of students that will get this score is
[tex]N = 2000 * 0.57[/tex]
[tex]N =1147[/tex]
What is f ( 1/3)? When the function is f(x) =-3x+7
Answer:
f(1/3) = 6
Step-by-step explanation:
f(x) =-3x+7
Let x = 1/3
f(1/3) =-3*1/3+7
= -1 +7
= 6
Answer:
f(1/3) = 6
Step-by-step explanation:
The function is:
● f(x) = -3x+7
Replace x by 1/3 to khow the value of f(1/3)
● f(1/3) = -3×(1/3) +7 = -1 +7 = 6
A box is 30 inches wide, 16 inches long, and 14 inches high. To the nearest cubic inch, what is the volume of the box?
Answer:
6720 in ^3
Step-by-step explanation:
Volume = length * width * height
= 30*16*14
=6720 in ^3
Randy is walking home from school. According to the diagram above, what is his total distance from school to home? Show your work and include units. If he had a jet pack, would you use distance or displacement? Why?
Answer:
if he needs to walk, we can see that between the street and his house he must walk 4 times a distance of 0.5km, so this is a total of 4¨*0.5km = 2km.
Now he has a jet-pack, he can ignore the buildings and just travel in the shorter path, so we can draw a triangle rectangle, in such a way that the hypotenuse of this triangle is the distance between the home and the school.
One of the cathetus is the vertical distance, in this case, is 1km, and the other one is the horizontal distance, also 1km.
So the actual distance is given by the Pythagorean's theorem:
A^2 + B^2 = H^2
Where A and B are the cathetus, and H is the hypotenuse, then:
H^2 = 1km^2 + 1km^2
H = (√2)km = 1.41km.
Now, in the case that he has a jet-pack, he can actually go to the school using this hypotenuse line as his path, so in this case the distance and the displacement would be the same.
Distance: "how much ground an object has covered"
Displacement: "Difference between the final position and the initial position"
When he walks, the distance is 2km, but the displacement is 1.41km
When he uses the jet-pack, both the distance and the displacement are 1.41km
Answer and Step-by-step explanation:
The first thing is we can see in the image, when he walks, that between the house and his school he has to walk four times a distance of 0.5 km. The result of this is a total of 4¨*0.5 km = 2 km. The second thing is that he must walk 2 kilometers. On the other hand, if he has a jetpack, he can simply take the shorter path by ignoring all the buildings. This idea is where we can draw a triangular rectangle on the map in a way so that the hypotenuse of the triangle is the distance between the school and the home. As for the Catheti, it is a vertical distance which in this case is two blocks of 0.5 km. The result is that these catheti have a length of 2*0.5 km = 1 km. The other is the distance of the horizontal line, which is 1 km. The absolute distance of this path is given by Pythagorean's theorem, which is A^2 + B^2 = H^2. Here, A and B are the cathetus, and H is the hypotenuse, then, H^2 = 1 km^2 + 1 km^2. As well, H = (√2)km = 1.41 km. Currently, in the situation where he has a jetpack, he can literally fly to the school utilizing this hypotenuse line for the path he would need to follow. For this specific situation, the displacement, and the distance would be the exact same. The reason for this is that the definitions of displacement and distance are displacement is the difference between the final position and the initial position and distance is how much area an item has covered. Also, when he walks, the distance is 2 km and the displacement is 1.41 km. Also, when he utilizes the jet pack, the distance is equal to the displacement. Both of these are 1.41 km.
6 people consists of 3 married couples. Each couple wants to sit with older partner on the left.
Required:
a. How many ways can they be seated together in the row?
b. Suppose one of the six is a doctor who must sit on the aisle in case she is paged. How many ways can the people be seated together in the row with the doctor in an aisle seat?
c. Suppose the six people consist of three married couples and each couple wants to sit together with the husband on the left. How many ways can the six be seated together in the row?
a. The first part asks for how many ways they can be seated together in a row. Therefore we want the permutations of the set of 6 people, or 6 factorial,
6! = 6 [tex]*[/tex] 5
= 30 [tex]*[/tex] 4
= 360 [tex]*[/tex] 2 = 720 possible ways to order 6 people in a row
b. There are two cases to consider here. If the doctor were to sit in the left - most seat, or the right - most seat. In either case there would be 5 people remaining, and hence 5! possible ways to arrange themselves.
5! = 5 [tex]*[/tex] 4
= 20 [tex]*[/tex] 3
= 120 [tex]*[/tex] 1 = 120 possible ways to arrange themselves if the doctor were to sit in either the left - most or right - most seat.
In either case there are 120 ways, so 120 + 120 = Total of 240 arrangements among the 6 people if the doctor sits in the aisle seat ( leftmost or rightmost seat )
c. With each husband on the left, there are 3 people left, all women, that we have to consider here.
3! = 3 [tex]*[/tex] 2 6 ways to arrange 3 couples in a row, the husband always to the left
ASAP!!!!!!!asap!!!!!!!!!!!! asap asap asap
Answer:
7). x = 3.2, AC = 42.8
8). a = 6, YZ = 38
Step-by-step explanation:
It is given in the question that a point B is between A and C of the line segment AC.
⇒ AB + BC = AC
By substituting the values of segments,
5x + (9x - 2) = (11x + 7.6)
14x - 2 = 11x + 7.6
14x - 11x = 7.6 + 2
3x = 9.6
x = 3.2
Therefore, AC = 11x + 7.6
= 11(3.2) + 7.6
= 35.2 + 7.6
= 42.8
Question (8).
If Y is a point between X and Z,
⇒ XY + YZ = XZ
By substituting the measures of these segments given in the question,
(3a - 4) + (6a + 2) = (5a + 22)
9a - 2 = 5a + 22
9a - 5a = 22 + 2
4a = 24
a = 6
Since, length of segment YZ = 6a + 2
= 6(6) + 2
= 38
LOOK AT CAPTURE AND ASNWER 100 POINTS
Answer:
132 degrees
Step-by-step explanation:
Looking at angle A and angle B, they are alternate interior angles. That means they are congruent to one another. Knowing that, we can set up an equation A=B
We can now fill A and B with their given equations
5x-18=3x+42
Now we solve
2x=60
x=30
Now that we know x is 30, we can replace it in the equation for A
5x-18
5(30)-18
150-18
132 degrees
Answer:
132
Step-by-step explanation:
ANGLE A = ANGLE B
(INTERIOR ALTERNATE ANGLES)
5x - 18 = 3x + 42
2x = 60
x = 30
angle a = 150 - 18
= 132
The volume of a gas in a container varies inversely as the pressure on the gas. If a gas has a volume of 356 cubic inches under a pressure of 6 pounds per square inch, what will be its volume if the pressure is increased to 7 pounds per square inch? Round your answer to the nearest integer if necessary.
Answer:
[tex]V_2=305.14\ \text{inch}^3[/tex]
Step-by-step explanation:
The volume of a gas in a container varies inversely as the pressure on the gas.
[tex]V\propto \dfrac{1}{P}\\\\V_1P_1=V_2P_2[/tex]
If V₁ = 356 inch³, P₁ = 6 pounds/in², P₂ = 7 pounds/in², V₂ = ?
So, using the above relation.
So,
[tex]V_2=\dfrac{V_1P_1}{P_2}\\\\V_2=\dfrac{356\times 6}{7}\\\\V_2=305.14\ \text{inch}^3[/tex]
So, the new volume is [tex]305.14\ \text{inch}^3[/tex].
find the area of this figure to the nearest hundredth. Use 3.14 to approximate pi.
Answer:
86.28 ft²
Step-by-step explanation:
The figure given consists of a rectangle and a semicircle.
The area of the figure = area of rectangle + area of semicircle
Area of rectangle = [tex] l*w [/tex]
Where,
l = 10 ft
w = 8 ft
[tex] area = l*w = 10*8 = 80 ft^2 [/tex]
Area of semicircle:
Area of semicircle = ½ of area of a circle = ½(πr²)
Where,
π = 3.14
r = ½ of 8 = 4 ft
Area of semi-circle = ½(3.14*4) = 6.28 ft²
Area of the figure = area of rectangle + area of semi-circle = 80 + 6.28 = 86.28 ft² (nearest hundredth)
Answer:
the area of the figrue is 105.12
Step-by-step explanation:
area of rectangle A= l · w10 x 8= 80area of simi-circle= 1/2(3.14 x r²)1/2 x 3.14 x 4²=25.1280+25.12=105.12 (nearest Hundredth)perform the indicated operation (8-15i)(-3 + 2i)
Answer:
[tex] - 24 + 16i + 45i + 15 = 9 + 61i[/tex]
5* (?)-8= 77
Please help me!!!
Answer:
work is shown and pictured
how to find the roots of a quadratic equation -10x^2 + 0x +250
Answer:
Step-by-step explanation:
The first thing you want to do is to factor in any quadratic equation.
So, -10(x^2-25)
Now, we see this is a special case, whenever we see a equation in this case, x^2 - b^2, we factor it to this (x+b)(x-b)
So, -10(x+5)(x-5)
x = -5 and x = 5
B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of length 4. The number of binary code words, B(n), of length n, is shown above. If the length is increased from n to n+1, how many more binary code words will there be? The answer is 2^n, but I don't get how they got that answer. I would think 2^n+1 minus 2^n would be 2. Please help me! Thank you!
Answer:
More number of words that can be made: [tex]\bold{2^n}[/tex]
Please refer to below proof.
Step-by-step explanation:
Given that:
The number of binary code words that can be made:
[tex]B(n) =2^n[/tex]
where n is the length of binary numbers.
Binary numbers means 2 possibilities either 0 or 1.
Here, suppose if we have 5 as the length of binary number.
And there are 2 possibilities for each digit.
So, total number of possibilities will be [tex]2\times 2\times 2\times 2\times 2 = 2^5[/tex]
If the length of binary number is 2.
The total words possible are [tex]2^2[/tex].
These numbers are:
{00, 01, 10, 11}
If the length of binary number is 3. (increasing the 'n' by 1)
The total words possible are [tex]2^3[/tex].
These words are:
{000, 001, 010, 100, 011, 101, 110, 111}
So, number of More binary words = 8 - 4 = 4 or [tex]2^2[/tex] or [tex]2^n[/tex].
So, the answer is [tex]2^n[/tex].
Let us try to prove in generic terms:
[tex]B(n) = 2^n[/tex]
Increasing the n by 1:
[tex]B(n+1) = 2^{n+1}[/tex]
Number of more words made by increasing n by 1:
[tex]B(n+1) -B(n)= 2^{n+1} -2^n\\\Rightarrow 2\times 2^{n} -2^n\\\Rightarrow 2^n(2-1)\\\Rightarrow \bold{2^n}[/tex]
Hence, proved that:
More number of words that can be made: [tex]\bold{2^n}[/tex]
Which option is correct and how would one solve for it?
Answer:
2+4+6+8
Step-by-step explanation:
We have the sum of 2n where n runs from 1 to 4
n=1 2(1) = 2
n=2 2(2) = 4
n=3 2(3) = 6
n=4 2(4) = 8
The sum is add
2+4+6+8
