Answer:
B. 275 kPa
Explanation:
Since we need to find the greater value, because 1.50<2.5, then the only greater value would be 275 kPa.
How much faster will Xenon escape out and opening than carbon dioxide gas?
gas with the smallest amount of molecular weight will effuse the quickest
What is frequency and what unit is it measured in?
Answer: The rate at which a vibration occurs that constitutes a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light), usually measured per second. Also it is measured in Hertz.
Explanation:
Answer frequency is the number of occurrences of a repeating event per unit of time. Frequency is measured in Hertz. Unit frequency is measured as the number of wave cycles that occur in one second.
The unit of frequency measurement is hertz
Explanation:
Which is the control center for the endrocrine system?
Answer:
hypothalamus
Explanation:
Molecules have Question 1 options: A) both potential and kinetic energy. B) neither kinetic nor potential energy. C) only kinetic energy. D) only potential energy.
Answer:A
Explanation:
Answer: A
Explanation:
How many copper atoms are in a 70g copper
Answer:
[tex]x = 6.634\times 10^{23}\,atoms[/tex]
Explanation:
The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:
[tex]x = \left(\frac{70\,g}{63.546\,\frac{g}{mol}} \right)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)[/tex]
[tex]x = 6.634\times 10^{23}\,atoms[/tex]
Answer:
6.64x10^23 atoms.
Explanation:
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This implies that 1 mole of Cu also contains 6.02x10^23 atoms.
1 mole of Cu = 63.5g
If 63.5g of Cu contains 6.02x10^23 atoms,
Then 70g of Cu will contain = (70x6.02x10^23) /63.5 = 6.64x10^23 atoms.
Therefore, there are 6.64x10^23 atoms in 70g oh Cu
Which statements describe prominences? Check all that apply.
Prominences are dark, cool areas on the surface of the Sun.
Prominences are composed of cool, dense gas.
Prominences can disturb radio communications on Earth.
Prominences cycle over an 11-year period.
Prominences are loop shaped.
Prominences appear in groups.
Answer:
B. Prominences are composed of cool, dense gas.
C. Prominences can disturb radio communications on Earth.
D. Prominences cycle over an 11-year period.
E. Prominences are loop shaped.
Explanation:
Prominence is the release of high energy particles or dense gases in the form of a loop shape from the surface of the sun. It is cooler and flows out into the Sun's hot atmosphere known as corona.
Once formed, prominence can be quiescent in the space for some period of time before it erupt and get ejected. This eruption and ejection can lead to coronal mass ejections which extends over a very long distance.
When compared to the Sun's temperature, prominences are cooler.
Answer:
B C E
Explanation:
Calculate the hyrdrogen ion concentration [h+] for the aquesous solution in which [oh-] is 1 x 10-2 mol/l.Is the solution acidic,basic,or neutral? Show your work
Answer:
- [tex][H^+]=1x10^{-12}[/tex]
- Basic.
Explanation:
Hello,
In this case, given the concentration of hydroxyl ions, one could compute the pOH as shown below:
[tex]pOH=-log([OH^-])=pOH=-log(1x10^{-2})=2[/tex]
Then, since the pOH and the pH are related by:
[tex]pH+pOH=14[/tex]
One computes the pH:
[tex]pH=14-pOH=14-2=12[/tex]
Now, we compute the concentration of hydronium by:
[tex][H^+]=10^{-pH}=10^{-12}[/tex]
[tex][H^+]=1x10^{-12}[/tex]
Finally, since the pH is greater than 7 (neutral point) we conclude that the solution is basic.
Best regards.
Answer:
A. Hydrogen ion concentration, [H+] is 1x10^–12 mol/L
B. Since the pH is 12, the solution is basic.
Explanation:
Data obtained from the question. This includes the following:
Concentration of Hydroxide ion, [OH-] = 1x10^–2 mol/L
Concentration of Hydrogen ion, [H+] =.?
pH =..?
A. Determination of the hydrogen ion concentration, [H+] .
The hydrogen ion concentration, [H+] can be obtained as follow:
[H+] x [OH-] = 1x10^–14
[OH-] = 1x10^–2
[H+] x 1x10^–2 = 1x10^–14
Divide both side by 1x10^–2
[H+] = 1x10^–14 / 1x10^–2
[H+] = 1x10^–12 mol/L
B. Determination of the pH of the solution.
The pH of the solution can be obtained as follow:
pH = –Log [H+]
[H+] = 1x10^–12 mol/L
pH = –Log 1x10^–12
pH = 12.
Then pH of a solution ranges between 0 and 14.
A pH reading between 0 and 6 is termed an acidic solution, a pH reading of 7 is termed a neutral solution and a pH reading between 8 and 14 indicates an alkaline or a basic solution.
The higher the pH value, the more alkaline or basic the solution becomes.
Since the pH is 12, the solution is basic.
A 0.80 L sample of gas has a temperature of 27°C and a pressure of 0.925 atm. How many moles of gas are present?
Answer:
n= 0.03 moles
Explanation:
Using the ideal gas law:
PV=nRT
nRT=PV
n= PV/RT
n: moles
P: pressure in atm
V= volume in L
R= Avogadro's constant = 0.0821
T= Temperature in K => ºC+273.15
n= (0.925 atm)(0.80 L) / (0.0821)(300.15 K)
n= 0.03 moles
Particles of the substance have the most kinetic energy when the substance is(a)_______. The part of the graph that represents where the substance has the least amount of potential energy is labeled(b)_______.
multiple choice answers available.
(a)
1. A gas
2. A solid
3. Melting
4. vaporizing
(b)
1. Solid
2. Vaporizing
3. melting
4.liquid
5.gas
Answer: 1- gas 2- solid
Explanation:
Oxygen decays to form nitrogen.
3
150
->
19N + e
8
1
This type of nuclear decay is called
Answer:
Radioactive isotopes ranging from 11O to 26O have also been characterized, all short-lived. The longest-lived radioisotope is 15O with a half-life of 122.24 seconds, while the shortest-lived isotope is 12O with a half-life of 580(30)×10−24 seconds (the half-life of the unbound 11O is still unknown).
What conclusion can you draw from the heating curve?
Answer:A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.
ANSWER IT PLEASE!!!!! A virus is a genome, or set of chromosomes, contained inside a protein capsule called a capsid. A virus can be either a single or double strand of RNA or DNA. Although viruses are made of genetic information, they do not have cells. They also need to attach to a host cell in order to live and reproduce. Host cells can be from animals, plants and even bacteria and fungi. Scientists debate whether or not viruses are considered living organisms. Most agree that viruses are not living.
Which of these statements is true based on the information in the passage?
Answer:
?
Explanation:
What are the statements? You've given the passage but not the statements
Have scientists found any reliable predictors for earthquakes, like radon gas release or weird animal behavior?
Answer:
The "Parkfield earthquake prediction experiment" was the most heralded scientific earthquake prediction ever. It was based on an observation that the Parkfield segment of the San Andreas Fault breaks regularly with a moderate earthquake of about M 6 every several decades: 1857, 1881, 1901, 1922, 1934, and 1966.
Explanation:
this is the best I could come up with. luv u.
what is the type of bonding for ammonium lauryl sulfate?
Answer:
Hydrogen bonding.
Explanation:
Ammonium lauryl sulfate is also known as ammonium dodecyl sulfate there are two parts in Ammonium lauryl sulfate one is nonpolar hydrocarbon and other part polar sulfate group.
Due to polarity of sulfate group its form hydrogen bond very easily.
It is mainly used as foaming agent the main reason of its use is very much soluble in water and making hydrogen bond with water.
Assuming a car (with a 70-L) gas tank can hold approximately 50,000 (5.00 * 10^4) g of octane(C8H18) or 50,000 (5.00 * 10^4) g of ethanol (C2H6O). How much carbon dioxide (CO2), in grams, is produced in one tank of gas from the combustion of each amount?
Answer:
- From octane: [tex]m_{CO_2}=1.54x10^5gCO_2[/tex]
- From ethanol: [tex]m_{CO_2}=9.57x10^4gCO_2[/tex]
Explanation:
Hello,
At first, for the combustion of octane, the following chemical reaction is carried out:
[tex]C_8H_{18}+\frac{25}{2} O_2\rightarrow 8CO_2+9H_2O[/tex]
Thus, the produced mass of carbon dioxide is:
[tex]m_{CO_2}=5.00x10^4gC_8H_{18}*\frac{1molC_8H_{18}}{114gC_8H_{18}}*\frac{8molCO_2}{1molC_8H_{18}}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=1.54x10^5gCO_2[/tex]
Now, for ethanol:
[tex]C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O[/tex]
[tex]m_{CO_2}=5.00x10^4gC_2H_6O*\frac{1molC_2H_6O}{46gC_2H_6O}*\frac{2molCO_2}{1molC_2H_6O}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=9.57x10^4gCO_2[/tex]
Best regards.
Which phrase describes a volcano that is not expected to erupt again?
quiet volcano
extinct volcano
dormant volcano
explosive volcano
Give the molecular geometry and number of electron groups for sf4. give the molecular geometry and number of electron groups for . square planar, 6 electron groups square pyramidal, 6 electron groups t-shaped, 5 electron groups octahedral, 6 electron groups seesaw, 5 electron groups
Answer:
5 electron groups, see saw
Explanation:
During the formation of SF4, the sulfur atom usually bonds with each of four fluorine atoms where 8 of valence electrons are used. The four fluorine atoms have 3 lone pairs of electrons in its octet which will further utilize 24 valence electrons. In addition, two electrons are present as a lone pair on the sulfur atom. We can determine sulfur’s hybridization state by counting of the number of regions of electron density on sulphur (the central atom in the molecule). When bonding takes place there is a formation of 4 single bonds to sulfur and it has 1 lone pair. Looking at this, we can say that the number of regions of electron density is 5. The hybridization state is sp3d.
SF4 molecular geometry is seesaw with one pair of valence electrons. The molecule is polar. The equatorial fluorine atoms have 102° bond angles instead of the actual 120° angle. The axial fluorine atom angle is 173° instead of the actual 180° bond angle.
What mass of sulfuric acid (H2SO4) is contained in 50.00 mL of a 5.85 M solution? grams
Answer:
28.69 grams
Explanation:
To find the mass, we first need to find the moles. Once we have the moles, it is easy to use the molar mass of H2SO4 to find its mass.
To find the moles, remember that molarity (M) is equal to the moles divided by the volume (L). The volume HAS TO be converted to liters!
M = moles / V
5.85 M = moles / 0.05 L
moles = 0.2925
Now we know that we have 0.2925 moles of sulfuric acid. The molar mass of sulfuric acid is 98.08 g/mol.
0.2925 moles * (98.08 g / mol) = 28.69 grams
Make sense? If you have any questions, don't hesitate to ask!
Gas Laws
Assignment Active
Applying Gas Laws to Aerosol Can D
(国座
Explain why it is not a good idea to throw an
aerosol can into a fire. Which gas law applies?
DONE
Answer:
Ideal Gas Law
PV = nRT
Explanation:
Pressure is proportional to temperature;
The heat of the fire would cause increased pressure inside the closed aerosol vessel, eventually resulting in explosion of the vessel, once the temperature rises enough.
En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L alcancen el equilibrio a 150°C. ¿Cuáles son las presiones parciales de equilibrio de IBr, I2 y Br2?
Answer:
P IBr: 15.454atm
I₂: 0.923 atm
P Br₂: 0.923atm
Explanation:
Basados en la reacción:
I₂(g) + Br₂(g) ⇄ 2 IBr(g)
La constante de equilibrio, Keq, es definida como:
[tex]Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}[/tex]
Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio
Usando PV = nRT, la presión inicial de IBr es:
P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = 17.3 atm
Siendo las presiones en equilibrio:
P IBr: 17.3 - 2X
P I₂: X
P Br₂: X
Donde X representa el avance de reacción.
Remplazando en Keq:
280 = (17.3 - 2X)² / X²
280X² = 4X² - 69.2X + 299.29
0 = -276X² - 69.2X + 299.29
Resolviendo para X:
X = -1.174 → Solución falsa. No existen presiones negativas
X = 0.923 → Solución real
Así, las presiones parciales en equilibrio de cada compuesto son:
P IBr: 17.3 - 2X = 15.454atm
P I₂: X = 0.923atm
P Br₂: X = 0.923atm
Answer:
[tex]p_{I_2}=0.926atm\\p_{Br_2}=0.926atm\\p_{IBr}=15.5atm[/tex]
Explanation:
Hello,
In this case, given the initial load of 0.500 mol of IBr in the 1.00-L, we compute its initial concentration:
[tex][IBr]_0=\frac{0.500mol}{1.00L}=0.500M[/tex]
Hence, by knowing the original reaction, we should invert it as IBr will produce iodine and bromine considering the initial load:
[tex]2IBr(g)\rightleftharpoons I_2(g) + Br_2(g)[/tex]
Therefore, the equilibrium constant should be inverted:
[tex]K'=\frac{1}{Keq}=\frac{1}{280}=3.57x10^{-3}[/tex]
So we write the law of mass action:
[tex]K'=\frac{[I_2][Br_2]}{[IBr]^2}[/tex]
That in terms of the change [tex]x[/tex] due to the reaction extent turns out:[tex]3.57x10^{-3}=\frac{(x)(x)}{(0.500-2x)^2}[/tex]
In such a way, solving by using solver or quadratic equation we obtain:
[tex]x_1=-0.0339M\\x_2=0.0267M[/tex]
Clearly, the solution is 0.0267M, thus, the equilibrium concentrations are:
[tex][I_2]=x=0.0267M[/tex]
[tex][Br_2]=x=0.0267M[/tex]
[tex][IBr]=0.5M-2x=0.5M-2*0.0267M=0.447M[/tex]
Thus, with the given temperature (150+273.15=423.15K), we compute the partial pressures by using the ideal gas equation:
[tex]p_{I_2}=[I_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{I_2}=0.926atm\\\\p_{Br_2}=[Br_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{Br_2}=0.926atm\\\\p_{IBr}=[IBr]RT=0.447\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{IBr}=15.5atm[/tex]
Best regards.
2
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Physical Changes Versus Chemical Changes: Mastery Test
Submit Test
2
Select the correct answer.
The metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off. This simple process is
which kind of a change?
ОА a physical change
B. a chemical change
ca nuclear change
OD. an lonic change
A group of tissues working together is?
Answer:
An organ
Explanation:
An organ is one or more tissues that work together to form a specific function.
- Hope that helps! Please let me know if you need further explanation.
Which statements describe gridlines on a map? Select three options. They are measured in degrees. They set up a reference system. They make straight lines on a globe. They run north to west and south to east. They divide Earth into four equal parts.
Answer:
The options that apply to the description of grid-lines of the map are;
They are measured in degrees
They set up a reference system
They divide Earth into four equal parts
FIRST OPTION , SECOND OPTION and FIFTH OPTION are correct.
Explanation:
FIRST OPTION gave the describtion that the grid-lines of the map are measure in degrees,this option is applied to the gridlines on a map because the grid are lined as a result of angular measurement which makes it to makes the unit to be measured degrees and angles.
SECOND OPTION described it as been set up by a reference system which let us know that the area that are plotted were all grid as a result of the size
FIFTH OPTION also applied to the
description of the gridlines on a map because the Earth is divided into 4 equal parts through the Prime Meridian i.e the latitudinal line and longitudinal line .
.
Answer:
They are measured in degrees.
They set up a reference system.
They divide Earth into four equal parts.
Explanation:
i took the test
A reaction starts with 20.0 grams of lithium hydroxide (LiOH) and produces 31.0 grams of lithium chloride (LiCl), what is the percent yield of lithium chloride (LiCl)? *
LiOH + KCl - LiCl + KOH
A) 64.5%
B) 88.6%
C) 81.5%
D) 92.8%
Answer:
B) 88.6%
Explanation:
Percent yield equals actual yield divided by theoretical yield
actual yield is 31.0g
theoretical yield is 35g
percent yield was 88.57 which rounds up to 88.6%
How many moles are in 100g of carbon dioxide?
A.2.27 mol
B.3.51 mol
C. 2.36 mol
D. 1.49 mol
Answer:
A
Explanation:
First, let's find the molar mass of CO₂. This is 12 + 2(16) = 44 g/mole.
Now we can write 100g * (1 mole / 44g) = 2.27 mol, or A. Hope this helps!
what is the molarity of 2.3 mol of Kl dissolved in 0.5 L of water
Answer:
[tex]4.6\,\,moL\,\,L^{-1}[/tex]
Explanation:
Molarity refers to a measure of concentration.
Molarity = moles of solute/Litres of solution
Molarity refers to number of moles of solute present in this solution.
In order to find a solution's molarity, use value for the number of moles of solute and the total volume of the solution expressed in liters
As molarity of 2.3 mol of Kl is dissolved in 0.5 L of water,
Molarity = [tex]\frac{2.3}{0.5} =4.6\,\,moL\,\,L^{-1}[/tex]
Which statement describes a gas condensing into a liquid?
A.
The atoms in the molecules get heavier so they move less.
B.
The molecules break into smaller pieces that take up less space.
C.
The molecules stick together to make bigger molecules.
D.
The molecules get closer together and move more slowly.
Answer: molecules get closer
Explanation:
Condensation is the process in which molecules of a gas slow down, come together, and form a liquid. When gas molecules transfer their energy to something cooler, they slow down and their attractions cause them to bond to become a liquid
hope this helps
pls mark me brainliest
Answer:
D. The molecules get closer together and move more slowly.
C2H6O(g) + 3O2(g) 2CO2(g) + 3H2O(g) Inside the piston of an automobile engine, 0.461 g of ethanol (C2H6O) gas reacts with 0.640 grams of oxygen gas to produce carbon dioxide and water, according to the balanced equation shown above. What is the limiting reagent?
Answer:
Oxygen is the limiting reactant.
Explanation:
Hello,
In this case, given the reaction:
[tex]C_2H_6O(g) + 3O_2(g)\rightarrow 2CO_2(g) + 3H_2O(g)[/tex]
Hence, given the masses of both ethanol and oxygen, we are able to compute the available moles ethanol by:
[tex]n_{C_2H_6O}^{available}=0.461g*\frac{1mol}{46g}=0.01mol C_2H_6O[/tex]
Next, we compute the moles of ethanol that react with the 0.640 grams of oxygen considering their 1:3 molar ratio in the chemical reaction:
[tex]n_{C_2H_6O}^{consumed\ by\ O_2}=0.64gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6O}{3molO_2} =0.0067molC_2H_6O[/tex]
In such a way, since there are 0.01 available moles of ethanol but just 0.0067 moles are reacting, we evidence ethanol is in excess, therefore the oxygen is the limiting reactant.
Best regards.
Answer:
Oxygen O₂ will be the limiting reagent.
Explanation:
C₂H₆O(g) + 3 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(g)
First of all you must know by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction) how much mass of each compound reacts. First of all, being:
C: 12 g/moleH: 1 g/moleO: 16 g/molethe molar mass of each reagent is:
C₂H₆O: 2*12 g/mole + 6* 1 g/mole + 16 g/mole= 46 g/moleO₂: 2*16 g/mole= 32 g/moleThen, since 1 mol of C₂H₆O and 3 moles of O₂ react by stoichiometry, the amount of mass that reacts is:
C₂H₆O: 1 mole* 46 g/mole= 46 gO₂: 3* 32 g/mole= 96 gNow you apply a rule of three as follows: if 46 g of C₂H₆O reacts with 96 g of O₂ by stoichiometry, 0.461 g of C₂H₆O with how much mass of O₂ will they react?
[tex]mass of O_{2} =\frac{0.461 grams of C_{2}H_{6} O*96 grams ofO_{2} }{46 grams of C_{2}H_{6} O}[/tex]
mass of O₂= 0.962 grams
But 0.962 grams of O₂ are not available, 0.640 grams are available. Since you have less mass than you need to react with 0.461 g of C₂H₆O, oxygen O₂ will be the limiting reagent.
I need help. Please give a detailed answer:
Hydrogen cyanide (HCN) is a colorless gas. It is poisonous and smells like almonds. Draw a Lewis structure for this compound, explain why you drew the Lewis structure the way that you did, and predict the shape of the molecule.
Answer:
What ever you want. I made it like this because it would make the most logical sense with a mix of the Dot system.
Explanation:
Since the question says to explain yourself, and to predict, really any answer would be correct since it sounds like it's not asking for a correct answer, but more of an answer that would make sense to you and explain it. That's really what chemistry is, a bunch of educated responses and guesses with confidence.
PLEASE HELP
Consider the chemical equations shown here.
3 equations. 1: upper N upper O gas plus upper O subscript 3 gas right arrow upper N upper O subscript 2 gas plus upper O subscript 2 gas. Delta H subscript 1 equals 198.9 kilojoules. 2: StartFraction 3 over 2 EndFraction upper O gas right arrow upper O subscript 3 gas. Delta H subscript 2 equals 142.3 kilojoules. 3: upper O gas right arrow one half upper O subscript 2 gas. Delta H subscript 3 equals negative 247.5 kilojoules.
What is DeltaHrxn for the reaction shown below?
NO(g)+O(g)->NO2(g)
Answer:
-304.1
I had this question and that’s what I got
Answer:
-867.7
Explanation:
yeah
