Answer:
[tex]\Rightarrow V_2 = 389mL[/tex]
Explanation:
To solve this question, we could use Charles' law since both the number of mole and pressure are constant
At STP pressure P = 760 tor and Temperature = 273K
V1 =425mL, T1 =298K and T2 =273K
and [tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]
[tex]\Rightarrow V_2 =T_2\times\frac{V_1}{T_1}[/tex]
[tex]\Rightarrow V_2 =273\times\frac{425}{298}[/tex]
Therefore, [tex]\Rightarrow V_2 = 389mL[/tex]
What three temperature measurements Inust you make to calculate the specific heat of a sample using a calorimeter?
Answer:
Explanation:
Heat and temperature are two different but closely related concepts. Note that they have different units: temperature typically has units of degrees Celsius ( ∘ C ^\circ\text C ∘Cdegrees, start text, C, end text) or Kelvin ( Kstart text, K, end text), and heat has units of energy, Joules ( Jstart text, J, end text).
Ca(NO3)2 wht is the mass
Answer:
164.088 g/mol
Explanation: hope this helps
Answer:
Calcium nitrate
Explanation:
164.088 g/mol
give me the brainliest plss
i hate chemistry but someone help please, no links or you’ll be reported
Answer:
A, D, E
Explanation:
Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con 1 g de H2O.
Answer:
0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.
Explanation:
¡Hola!
En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:
[tex]Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3[/tex]
Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:
[tex]2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3[/tex]
De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.
¡Saludos!
Which statement explains why carbon-14 dating cannot be used to date ancient rocks?
O Carbon-14 decays at a varying rate.
O Carbon-14 decays quickly leaving the amount too small to measure.
O Carbon-14 can be used only to date the remains of organisms.
O Carbon-14 has a half-life that is much longer than potassium.
Answer: Carbon-14 decays quickly leaving the amount too small to measure.
Explanation:
Answer:
b
Explanation:
i did it
What is a precipitation
reaction?
Answer:
A precipitation reaction is one in which substances in solution are mixed and an insoluble product is made. The insoluble product is called a precipitate and can be seen as a solid forming in the reaction mixture.
Which two moon phases can occur while the
relative positions of the sun, Earth, and moon
form a straight line?
Answer:
its the lunar and solar eclipse
Explanation:
the solar eclipse happens when the moon is in between the sun and earth
If 4.04g of h2 gas react with oxygen gas to create 36.36g of water, how many grams of oxygen reacted?
Answer:
gO₂ = 32.32 g
Explanation:
In this case, let's write the general equation:
2H₂ + O₂ -------> 2H₂O
In this case, we can use the 1° law, which is mass conservation. If the product has 36.36 g of water, then in the reactants we should have the same 36.36 g.
According to this, we already have 4.04 of hydrogen, then the remaining to reach the 36.36 g would be:
gO₂ = 36.36 - 4.04
gO₂ = 32.32 gHope this helps
*
14. An AREA which drains into a common river system.
watershed
tributary
drainage divide
riparian zone
Sample A has a mass of 40g and a volume of 10cm^3. Sample B has a volume of 15cm^3 and a mass of 45g. Which sample has a greater density? Show your work.
The Answer Is Sample A
Density -
[tex]density = \frac{mass}{volume} [/tex]
Input The Formula For Both Equations To Find Density.
Sample A -
[tex]d = \frac{40}{10} [/tex]
[tex]d = 4[/tex]
Sample B -
[tex]d = \frac{45}{15} [/tex]
[tex]d = 3[/tex]
Please answer all of the examples below!
Answer:
The first one is balanced. The second one is not.
Explanation:
The first one is balanced because there are the same amount of elements on the reactant side as there are on the product side. The second one is not balanced because there are not the same amount of elements on the reactant side as there are on the product side. Therefore, it is not balanced
More Detailed: first example
Reactant side (left of arrow)
H: 2
C: 1
O: 3
Product side (right of arrow)
H: 2
C: 1
O: 3
More detailed: second example
Reactant side:
Na: 1
O: 1
H: 1
C: 1
Product side:
Na: 2
O: 4
H: 2
C: 1
the variables needed to balance this equation is 2,1, 1, 1.
What is the purpose of a buffer?
Answer: A buffer solution is a solution made to prevent the pH level of something from changing when you add a base or an acid to it. For example, if you put a buffer solution in a pool, and then you put chlorine in it, the chlorine's effect on the PH level will be suppressed.
Consider the following balanced equation:
3 H2 + N2 --> 2 NH3
What volume of hydrogen gas will react in a perfect ratio
with 3 liters of nitrogen gas?
Answer:
[tex]from \: avogadros \: hypothesis \\ 1 \: mole \: of \: nitrogen \: reacts \: with \: 3 \: moles \: of \: hydrogen \\ 3 \: litres \: of \: nitrogen \: react \: with \: ( \frac{3 \times 3}{1} ) \\ 9 \: litres \: of \: hydrogen[/tex]
9.49.8 grams of Kl is dissolved in 1.00 kg of solvent. What is the molality?
Answer:
Molality = 9.498 mol k g − 1
Explanation:
A final way to express the concentration of a solution is by its molality. The molality ( m ) of a solution is the moles of solute divided by the kilograms of solvent. A solution that contains 1.0 mol of NaCl dissolved into 1.0 kg of water is a “one-molal” solution of sodium chloride.
molality = number of moles of solute/ mass of solvent in kg
number of moles of KI = mass of KI / molar mass of KI
number of moles of KI = 9.49.8 g / 1.00 g m o l − 1
number of moles of KI = 9.498 moles
molality = 9.498 moles / 1kg
molality = 9.498 mol k g − 1
