A sample of radioactive material starts with 80 grams. After 3 half-lives have passed, how much radioactive sample remains?

Answers

Answer 1

Answer:

After 3 half lives 10 g of radio active material left.

Explanation:

Given data:

Total amount of radio active material = 80 g

Amount left after 3 half lives = ?

Solution:

At time zero = 80 g

At first half life = 80 g/2 = 40 g

At 2nd half life = 40 g/2 = 20 g

At 3rd half life = 20 g/2 = 10 g

Thus, after 3 half lives 10 g of radio active material left.


Related Questions

If 18.00 mL of 0.1000 M magnesium hydroxide reacts with 10.00 mL of hydrochloric acid, what is the molarity of the acid solution?

Answers

Answer:

0.36M HCl

Explanation:

The reaction of Mg(OH)₂ with HCl is:

Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O

Where 1 mole of magnesium hydroxide reacts with 2 moles of HCl

To solve this question, we need to find the moles of Mg(OH)₂ that reacted and, with chemical equation, solve for the moles of HCl and its molarity (Using the 10.00mL = 0.01000L) as follows:

Moles of Mg(OH)₂:

18mL = 0.018L * (0.100mol / L) = 0.0018 moles Mg(OH)₂

Moles HCl:

0.0018 moles Mg(OH)₂ * (2 moles HCl / mol Mg(OH)₂) = 0.0036 moles HCl

Molarity HCl:

0.0036 moles HCl / 0.0100L =

0.36M HCl

Write the formula for diphosphorous pentoxide

Answers

Answer:

P4O10

Explanation:

Pro
∆G0=-RT in k Known as​

Answers

Answer:

Gibbs free energy equation

Explanation:

what is the molarity of a solution made by adding 0.720 mole of NaOH to 2.40 liters of water

Answers

Answer:

Molarity = 0.3 M

Explanation:

Given data:

Moles of NaOH = 0.720 mol

Volume of water = 2.40 L

Molarity = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Molarity = 0.720 mol / 2.40 L

Molarity = 0.3 mol/L

Molarity = 0.3 M

These allow electricity to flow easily through them (think copper and aluminum).
(Lessons 5.01-5.03)
Insulators
Electric Currents
Conductors
Resistors

Answers

Answer:

conductors

Explanation:

Which of the following statements is true?

Question 10 options:

a chromosome is larger than a cell


a DNA strand is made of many chromosomes


a gene contains may chromosomes


a chromosome contains many genes

Answers

Answer:

a chromosome contains many genes

Explanation:

A 12.0% sucrose solution by mass has a density of 1.05 gem, what mass of sucrose is present in a 32.0-mL sample of this solution?
A) 0.126g
B) 3.66g
C) 4.03g
D) 3.84g
E) 280 g

Answers

Answer:

Option C. 4.03 g

Explanation:

Firstly we analyse data.

12 % by mass, is a sort of concentration. It indicates that in 100 g of SOLUTION, we have 12 g of SOLUTE.

Density is the data that indicates grams of solution in volume of solution.

We need to determine, the volume of solution for the concentration

Density = mass / volume

1.05 g/mL = 100 g / volume

Volume =  100 g / 1.05 g/mL → 95.24 mL

Therefore our 12 g of solute are contained in 95.24 mL

Let's finish this by a rule of three.

95.24 mL contain 12 g of sucrose

Our sample of 32 mL may contain ( 32 . 12) / 95.24 = 4.03 g

Polonium-214 went through a series of radioactive decays to produce a stable isotope of bismuth-210 choose the correct decay series that would produce bismuth-210
A: Polonium-214 undergoes 2 beta decay and 1 gamma emission
B: Polonium-214 undergoes 1 alpha decay and 2 gamma emission
C: Polonium-214 undergoes 2 alpha decay and 1 beta decay
D: Polonium-214 undergoes 1 alpha decay 1 beta decay and 1 gamma emission.

Answers

The correct decay series :

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+₂He⁴+ ₋₁e⁰+ ₀γ⁰

Further explanation

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

alpha α particles ₂He⁴ beta β ₋₁e⁰ particles gamma particles ₀γ⁰ positron particles ₁e⁰ neutron ₀n¹

Decay's reaction :

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+x+y+z

From this decay reaction can be concluded

mass number decreased by 4

atomic number decreased by 1

Then the most suitable are:

Polonium-214 undergoes 1 alpha decay 1 beta decay and 1 gamma emission.

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+₂He⁴+ ₋₁e⁰+ ₀γ⁰

So that the mass number and atomic number are the same both before and after decay

what is made from a chemical reaction?

Answers

Answer:

the Product

Explanation:

A candle made of certain wax blend burns at a rate of 44.2 mg/min. What is the value of this burn rate if expressed in grams/hour

Answers

Answer:

2.652 g/h.

Explanation:

Burn rate (in mg/min) = 44.2 mg/min

Burn rate (in m/h) =?

We'll begin by converting 44.2 mg/min to g/min. This can be obtained as follow:

1 mg/min = 0.001 g/min

Therefore,

44.2 mg/min = 44.2 mg/min × 0.001 g/min / 1 mg/min

44.2 mg/min = 0.0442 g/min

Finally, we shall convert 0.0442 g/min to g/h. This can be obtained as follow:

1 g/min = 60 g/h

Therefore,

0.0442 g/min = 0.0442 g/min × 60 g/h / 1 g/min

0.0442 g/min = 2.652 g/h

Therefore, 44.2 mg/min is equivalent to 2.652 g/h.

Thus, the burn rate (in m/h) is 2.652 g/h.

How many mL of 0.125 M Ba(OH)2 would be required to completely neutralize 75.0 mL of 0.845 M HCl? What is the pH of the solution at the equivalence point?

Answers

Answer:

253.5mL of Ba(OH)₂ are required to neutralize the HCl solution

The pH at equivalence point is = 7

Explanation:

The reaction of Ba(OH)₂ with HCl is:

Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O

First, we need to find moles of HCl. With these moles and the chemical equation we can find the moles of Ba(OH)₂ and the volume required:

Moles HCl:

75.0mL = 0.075L * (0.845mol / 1L) = 0.063375moles HCl

Moles Ba(OH)₂:

0.06338moles HCl * (1mol Ba(OH)₂ / 2mol HCl) = 0.03169 moles Ba(OH)₂

Volume of the 0.125M Ba(OH)₂:

0.03169 moles Ba(OH)₂ * (1L / 0.125mol) = 0.2535L are required =

253.5mL of Ba(OH)₂ are required to neutralize the HCl solution

As the titration was of a strong acid, HCl, with a strong base, Ba(OH)₂, the pH at equivalence point is = 7

What is the total charge of an iron nucleus

Answers

i believe it’s a positive charge

How many joules are required to melt 250 grams of water

Answers

Answer:

i not sure but i searched it up and it said Q=104525J

Explanation:

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