A scientist sets up an experiment to see how colored lights affect the height of plant growth. He grows one group of plants in full sunlight, one group under red lights, one group under blue lights, and one group under green lights. All the plants are exactly that same type and all receive an equal intensity (brightness) of light. At the end of the experiment he measures all the plants. What is the dependent variable?
A) The intensity of the light
B) The color of the light
C) The height of the plant
D) Sunlight

Answers

Answer 1

Answer:

C) The height of the plant

Explanation:

Dependent variable - is the variable that can not be manipulated and the one that's being observed.

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Related Questions

what is corona virus and its symptoms?​

Answers

Answer:

 fever, cough and shortness of breath. In more severe cases, infection can cause pneumonia, severe acute respiratory syndrome and sometimes death.

Ph, Acids and Bases Quick Check
Which statement best describes the difference between a substance with a pH of 3.0 and a substance with a pH of 6.0? (1 point)
O The substance with the higher pH has twice as many hydrogen ions per volume of water.
The substance with the lower pH has twice as many hydrogen ions per volume of water.
The substance with the higher pH has 1,000 times as many hydrogen ions per volume of water. O
O The substance with the lower pH has 1,000 times as many hydrogen ions per volume of water.

Answers

Answer: c

Explanation: 3.0 is 1,000 times as many ions

The statement that best describes the difference is ; The substance with the lower pH has 1000 times as many hydrogen ions per volume of water. ( D )

Given that the substance have pH ; 3 and 6

To prove the statement above we will make use of the pH formula

pH =  -log(H⁺)

for substance with pH = 3

3 = - log(H)

H( hydrogen ions ) = 10⁻³

for substance with pH = 6

6 = - log(H)

H ( hydrogen ions ) = 10⁻⁶

Hence we can state that the substance with the lower pH has 1000 times as many hydrogen ions per volume of water

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Drag each tile to the correct location. Match each type of plant to the correct image.

Answers

Answer:

How is anyone supposed to answer that when there’s no pictures to match so we can answer it

Explanation:

Visualize It!
6 Identify Name three examples of matter found in
this photo.

Answers

Answer:

bag, human beings and bridge

Describe how scientific investigations lead to new scientific questions.

Answers

Answer: if new investigations occur, new questions would have to be asked to find out the things that are being researched.

Explanation:

Which change of state is shown in the model?

A. condensation
B. evaporation
C. sublimation
D. deposition

Answers

Hey there!

The correct option is:

B. Evaporation

Explanation:

Because the molecules inside the jar are moving upwards, which shows Evaporation.

Hope it help you

Please help! How does the circulatory system work at the tissue level?

A) The heart pumps the blood.

B (Blood cells carry nutrients.

C) Nutrients are delivered throughout the body.

D) Cardiac muscle contracts.

Answers

Answer:

B

Explanation:

The circulatory system is a network consisting of blood, blood vessels, and the heart. This network supplies tissues in the body with oxygen and other nutrients, transports hormones, and removes unnecessary waste products.

Answer:

The circulatory system work at tissue level by following points

=nutrients are delivered throughout the body

Are male butterflies and moths the same species?

Answers

Answer:

Explanation: No they are not.

4. Estimate the size of the outlined (yellow) onion cell under high power (40x). Use the dFOV values calculated from question no. 3. 10 points​

Answers

The following formula is useful to determine the size of the cellSize of the object = FOV / Fit number = dFOV / Fit number. If you have this data, you can estimate the size of the onion cell. According to the values we used, the estimated size of this onion cell is 112 μm.

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Cells are too small to measure their sizes, so to know their actual size, we can make mathematical estimations to know their sizes, or we can use software programs. In this case, we are estimating their size using the following formula,

Size of the object = FOV / Fit number = dFOV / Fit number

Size of the object = size of the cellFOV = eyepiece (mm)/objective magnification               Fit number = The number of times the object -cell- fits in the field of view

To answer this question, we will replace the terms in the given formula.

→ First, we will get the FOV value. From references, we can assume that

under 4X  ⇒ FOV = 4.5 mmunder 10X ⇒ FOV = 1.8 mmunder 40X ⇒ FOV = 0.45 mm

You can also calculate the FOV by using a millimeter paper or rule.

Note: We will use these values to replace terms in the formula, but you can use the dFOV value calculated in question no. 3.

→ Second, we will count the number of cells that fit the field. We can see about four cells across the field of view.

→ Finally, we will replace the terms in the formula.

Size of the object = FOV / Fit number

Size of the object = 0.45 mm / 4

Size of the object = 0.112 mm

Since we generally use μm when referring to cell sizes, we need to multiply 0.112 x 1000 to get the size of the cell expressed in μm.

Size of the cell (μm) = 0.112 mm x 1000 = 112 μm

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