Answer:
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A color image uses 16bits to represent a pixel. What is the maximum number of different colors that can be represented?
Answer: A color image uses 16 bits to represent a pixel. What is the maximum number of different colors that can be represented? With 16 bits, we can represent up to 2^16 different colors. Assume six devices are arranged in a mesh topology.
Explanation:
The terms 16-bit picture, high color image, and 32K color image are all used to describe images that have 16 bits per pixel.
What is a pixel?The smallest addressable element in a raster image or the smallest point in an all points addressable display device is known as a pixel (abbreviated as px), pel, or picture element in digital imaging.
The smallest component in most digital display systems that can be changed by software are pixels.
Photos with 16 bits per pixel are referred to as 16-bit pictures, high color images, and 32K color images.
The number of distinct colors that can be represented by 16 bits, where there are 5 bits for each of the red, green, and blue values and the 16th bit can be the alpha bit, is around 32 thousand.
Thus, the maximum number of different colors that can be represented is 32 thousand.
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Write a program that prompt the user to enter a bank balance. The balance entered by the user is read into a variable named balance. The program then prompts the user to enter the amount to be deposited. The amount entered by the user is read into a variable named deposit. The program that calculates the new balance, which is the present balance plus the deposit. The program then displays the new balance.
Answer:
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Explanation:
look for the words
Your worksheet contains a price in cell A5 and many formulas refer to that price how would you refer to that price in the formula
Answer:
$A$5
Explanation:
The A$5 would allow the row part of the reference to stay in place but would allow the column to change.
What does '$' mean in Excel formula?
An absolute reference in Excel exists as a cell address with the dollar symbol ($) in the row or column coordinates, like $A$1. The dollar sign specifies the connection to a given cell so that it stays unchanged no matter where the formula moves.
The A$5 would permit the row position of the authority to remain in place but would permit the column to modify. The location of the $ before either the row or column or both exists what specifies what component stands frozen. Therefore, the correct answer is option b) $A$5.
Complete question:
Your worksheet contains a price in cell A5, and many formulas refer to that price. How would you refer to that price in the formulas?
a. A5
b. $A$5
c. $A5
d. A$5
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How do I get fix the code to make it input 3 values and get the correct output
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12.20 LAB: Driving costs - functions
Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both floats) as input, and output the gas cost for 10 miles, 50 miles, and 400 miles.
Output each floating-point value with two digits after the decimal point, which can be achieved as follows:
print('{:.2f}'.format(your_value))
Ex: If the input is:
20.0
3.1599
the output is:
1.58
7.90
63.20
Your program must define and call the following driving_cost() function. Given input parameters driven_miles, miles_per_gallon, and dollars_per_gallon, the function returns the dollar cost to drive those miles.
Ex: If the function is called with:
50 20.0 3.1599
the function returns:
7.89975
def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon)
Your program should call the function three times to determine the gas cost for 10 miles, 50 miles, and 400 miles.
---------------------------------------------------
I need help for this part
Ex: If the function is called with:
50 20.0 3.1599
how do I get it to input the three to get the output of 7.89975?
-------------------------------------
My code:
# Define your function here.
def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):
return (driven_miles/miles_per_gallon) * dollars_per_gallon
if __name__ == '__main__':
# Type your code here.
# Miles per gallon from input
miles_per_gallon = float(input())
#Dollars per gallon from input
dollars_per_gallon = float(input())
# Display the results as output
print('{:.2f}'.format(driving_cost(10, miles_per_gallon,dollars_per_gallon)))
print('{:.2f}'.format(driving_cost(50, miles_per_gallon,dollars_per_gallon)))
print('{:.2f}'.format(driving_cost(400, miles_per_gallon,dollars_per_gallon)))
Answer:Change your logic to:
for (int i = 0; i < 4; i++) {
System.out.println("Please input a number between zero to 3");
// use input and don't advance the scanner every time
int input = sc.nextInt();
if (input == 0) {
System.out.println("You have selected " + right);
}
if (input == 1) {
System.out.println("You have selected " + left);
}
// so on and so forth
}
By using sc.nextInt() four times, you are looking for the next token of the input which isn't there. So fetch the input for each run of the for-loop and it will work as expected.
Explanation:
Given the following code, what logic would you need to include to print all even values stored within the array:
int[] myArray = {1,2,38,4,54,6,7,8,9,10};
for (int i = 0; i < myArray.length; i++) {
//your code goes here
}
NOTE: Your response should be just the missing logic--not the entire problem set.
The missing logic whigh would allow all the even numbers stored within the array to be printed is if(myArray[i]%2 == 0)
Even numbers are divisible by 2, and hence, will leave no remainder when divided by 2. Using the modulo operator, each iterated value in the array should be checked if it has a remainder of 0, when divided by 2.Hence, if the remainder is 0, then the value is even and the value should be printed.
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