A simple random sample of students could be achieved by stopping every other student who enters the library.
a. True
b. False

Answer:

0.235 = 0.24

13.467 = 13.47

0.24+13.47=13.71

Answer:An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.

Step-by-step explanation:

Answer:

[tex]ıf \: {3x}^{3x - 2} = 81[/tex]

Step-by-step explanation:

use logarithmic function

[tex] log_{3x}(81) = 3x - 2[/tex]

Answer:

4 and x=2

Step-by-step explanation:

:}

Answer:

1¼ cups

Step-by-step explanation:

2¼ ÷ 1/4/5 =

9/4 ÷ 9/5 =

9/4 x 5/9 =

5/4 = 1¼

The temperature in Buffalo, New York, was -2 °F one day. This was 42 degrees warmer than the temperature in Nome, Alaska, on the same day. Find the temperature in Nome. Justify your answer by writing and solving an equation

Answer:

40

Step-by-step explanation:

[tex]Here, h=41,0.25,y=1+x21

[/tex]

[tex]x     y101.020.25     0.9413 0.250.94140.750.64510.5

[/tex]

[tex]By Simpson's Rule:

[/tex]

[tex]∫011+x2dx=4×31

[/tex]

[tex][(1+0.5)+4(0.941+0.941+0.64)+2(0.8)]

[/tex]

[tex]=121[9.424]=0.785

[/tex]

The major axis of the eclipse is 12 units long

The given parameters can be represented as:

[tex]Red = 8[/tex]

[tex]Blue = 4[/tex]

See attachment for illustration

To solve this question, we make use of the following theorem

The distance between a point and the foci sums up to the major axis

This translates to:

[tex]Major\ axis = Red + Blue[/tex]

[tex]Major\ axis = 8 + 4[/tex]

[tex]Major\ axis = 12[/tex]

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Answer:

850,000

Step-by-step explanation:

Answer: 850,000

Concept:

Here, we need to know the order and name of each place value.

Please refer to the attachment below for the specified names.

Solve:

8 = Hundred thousands

4 = Ten thousands

9 = One thousands

7 = Hundreds

0 = Tens

9 = Ones

Since the values before the ten thousands place, which would be the one thousands place, is greater than 5, then we should round up.

Therefore, the rounded value would be [tex]\boxed{850,000}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Cost of 1kg tomato=rs.75

Cost of 14kg tomato=(75×14)

rs.1050

Answer:

The answer would be -7x^2 - 14!

Step-by-step explanation:

We can remove the parentheses by distributing the subtraction sign! -2x^2 + x + 1 - x^2 + x - 7 - 4x^2 - 2x - 8. Simplifying this gives us -7x^2 - 14. Hope this helped! :)

Step-by-step explanation:

here's the answer to your question

Answer:

-2

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals

Take the slope of AB = 1/2

-1/(1/2)

-1 * 2/1

-2

The slope of a line perpendicular is -2

9514 1404 393

Answer:

  16.9

Step-by-step explanation:

The marked sides are the hypotenuse and the one opposite the angle. The relevant trig function is ...

  Sin = Opposite/Hypotenuse

Multiplying by the hypotenuse gives an equation for the opposite side.

  x = 22·sin(50°)

  x ≈ 16.9

Step-by-step explanation:

you gave me only one system of 2 equations. not 2 systems or more.

maybe you missed something.

I can solve this one system in two ways, though.

substitution :

x - 3y = 16

3x - 2y = 13

the first equation gives us

x = 3y + 16

that we can use now in the second equation

3×(3y+16) - 2y = 13

9y + 48 - 2y = 13

7y + 48 = 13

7y = -35

y = -5

x = 3y + 16 = 3×-5 + 16 = -15 + 16 = 1

that's it. that is all the secret of substitution. you use one equation to express one variable by the other. and then you use that in the second equation to have suddenly only one equation with one variable that you can solve. and then from that result you calculate back the other "substituted" variable.

elimination :

x - 3y = 16

3x - 2y = 13

we multiply one equation completely by a factor and then add both equations. of course we should pick a factor that will eliminate one variable, when we add the equations.

e.g.

multiply the first equation by -3

-3x + 9y = -48

3x - 2y = 13

--------------------

0 7y = -35

y = -5

now we pick any one of the equations to use that result and calculate the other variable

e.g. the second equation

3x - 2×-5 = 13

3x + 10 = 13

3x = 3

x = 1

done.

as you can see : of course, both results are identical.

use the described principles to solve any other systems of equations you might have missed here.

Answer:

-11°C or 1°C

Step-by-step explanation:

The question said that, by the noon, the temperature changes by 6°C, but it doesn't tell you if it changes for a hotter or colder temperature, so its possible the temperature at the noon to be:

-5 -6 = -11°C

or

-5 +6 = 1°C

To graph the possible temperatures, you have to draw a dot at the numbers -11 and 1

Answer:

192

Step-by-step explanation:

geometric mean theorem :

with p and q being the segments of the Hypotenuse, then

h = x = sqrt(p×q)

p = 144

q = 400-144 = 256

h = x = sqrt(144×256) = 12×16 = 192

Answer:

GHC22.5

Step-by-step explanation:

90/3=30

30=0.75

30×0.75

=22.5

Answer:

Step-by-step explanation:

770 = 2*5*7*11

So they are:

2*385

10*77

5*154

7*110

14*55

11*70

22*35

Answer:

<4 = <1

Step-by-step explanation:

Judging from the picture, <1 and <4 are opposite angles. Opposite angles are always congruent. Hope this helps!

Answer:

[tex]2x^3-9x^2+7x+6[/tex]

Step-by-step explanation:

The standard form of a polynomial is a method of writing a polynomial such that the terms are organized by degrees. In essence, the first term, or the left-most term has the highest degree or largest exponent. The right-most term or last term has the lowest degree or smallest exponent. One is given an expression in factored form. Distribute, multiply every term by another in the parenthesis, then simplify. Repeat this process until there are no more factored terms. Finally, rewrite the expression in standard form.

[tex](2x+1)(x-3)(x-2)[/tex]

Distribute,

[tex](2x+1)(x-3)(x-2)[/tex]

[tex]((2x)(x)+(-3)(2x)+(1)(x)+(1)(-3))(x-2)[/tex]

Simplify,

[tex]((2x)(x)+(-3)(2x)+(1)(x)+(1)(-3))(x-2)[/tex]

[tex](2x^2-6x+x-3)(x-2)[/tex]

[tex](2x^2-5x-3)(x-2)[/tex]

Distribute,

[tex](2x^2-5x-3)(x-2)[/tex]

[tex](2x^2)(x)+(-5x)(x)+(-3)(x)+(-2)(2x^2)+(-2)(-5x)+(-3)(-2)[/tex]

Simplify,

[tex](2x^2)(x)+(-5x)(x)+(-3)(x)+(-2)(2x^2)+(-2)(-5x)+(-3)(-2)[/tex]

[tex]2x^3-5x^2-3x-4x^2+10x+6[/tex]

[tex]2x^3-9x^2+7x+6[/tex]

This polynomial is already in standard form, thus there is no need to reorganize it. The leading term or the left-most term has the highest degree, three, the succeeding terms are in respective order of decreasing exponents.

Answer:

[tex]P(C'\ and\ H') =0. 2178[/tex]

Step-by-step explanation:

Let

[tex]C \to[/tex] Student with cat

[tex]H \to[/tex] Student has HBO sub

[tex]P(C) = 66\% \\ P(H) = 37\%[/tex]

Required

[tex]P(C'\ and\ H')[/tex]

This is calculated as:

[tex]P(C'\ and\ H') = P(C') * P(H')[/tex]

Using complement rules, we have:

[tex]P(C'\ and\ H') = [1 - P(C)] * [1 - P(H)][/tex]

So, we have:

[tex]P(C'\ and\ H') = [1 - 66\%] * [1 - 37\%][/tex]

[tex]P(C'\ and\ H') = [33\%] * [66\%][/tex]

[tex]P(C'\ and\ H') =0. 2178[/tex]

Answer:

A

Step-by-step explanation:

They are different exponents but they have the same bas so you add them up.

4x^5+3 = 4x^8

[tex] \pink{ \boxed{\boxed{\begin{array}{cc} \maltese \bf \: \: as \: we \: know \: that \\ \\ \bf\: \: \rightarrow \: {(xy)}^{n} = {x}^{n} . {y}^{n} \\ \\ \bf \rightarrow \: {( {a}^{m} })^{n} = {a}^{m \times n} \\ \\ \bf \: now \\ \: \\ \blue{ {\boxed{\begin{array}{cc} \maltese \bf\: \: \: {(4 {x}^{5} })^{3} \\ \bf = {4}^{3} \times ({x}^{5} )^{3} \\ \bf = {4}^{3} \times {x}^{5 \times 3} \end{array}}}}\end{array}}}}[/tex]

So option D) is the correct answer

Answer:

(8x²+7y²–z²+2yz+3xz–5xy) × ( 2x–3y)

= (16x³+14xy²–2z²x+4yzx+6x²z–10x²y –24yx²–21y³+3z²y–6y²z–9xzy+15xy²)

=( 16x³+29xy²–2z²x–5xyz+6x²z–34x²y–21y³+3z²y–6y²z)

[tex] = 16 {x}^{3} - 21 {y}^{3} - 2 {z}^{2}x + 3 {z}^{2} y - 5xyz - 6 {y}^{2} z + 6 {x}^{2} z - 34 {x}^{2} y+ 29x {y}^{2} [/tex]

I hope I helped you^_^

Answer: [tex]10,000\ lb.ft[/tex]

Step-by-step explanation:

Given

Initial weight of the bucket is [tex]145\ lb[/tex]

It is lifted at constant rate and rate of sand escaping is [tex]0.5\ lb/ft[/tex]

At any height weight of the sand is [tex]w(h)=145-0.5h[/tex]

Work done is given by the product of applied force and displacement or the area under weight-displacement graph

from the figure area is given by

[tex]\Rightarrow W=\int_{0}^{80}\left ( 145-0.5h \right )dh\\\\\Rightarrow W=\left | 145h-\dfrac{0.5h^2}{2} \right |_0^{80}\\\\\Rightarrow W=\left [ 145\times 80-\dfrac{0.5(80))^2}{2} \right ]-0\\\\\Rightarrow W=11,600-1600\\\\\Rightarrow W=10,000\ lb.ft[/tex]

Answer:

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Does the answer help you?Please choose my answer as a brainliest answer and please rate.It take a few mins to solve your question.

Answer:

V≈696.91

Step-by-step explanation:

V=4

3πr3=4

3·π·5.53≈696.90997

We have that with a brief introduction to Algebra you are required to You are to refer to your curriculum and teachings and discover the foundational, or key, concepts of Algebra that you  have learned so far and  structure its respectively as you have learned

For This Question you are a asked to highlight what the are the foundational and  key concepts of algebra

So you are tasked to refer to your Notes and pick out the  foundational, or key, concepts of algebra that you  have learned so far according to your curriculum.

Algebra

This is a branch of mathematics that strictly focuses on mathematical Operator or Arithmetic operators and how the are used in there variant ways or combined to solve problems.

Mathematical  Operators(-,+,/,*)

To Identify some fundamental and  key concepts of Algebra like there use in

In conclusion

You are to refer to your curriculum and teachings and discover the foundational, or key, concepts of Algebra that you  have learned so far and  structure its respectively as you have learned.

For more information on this visit

https://brainly.com/question/14413003

Answer:

Some of the foundational key concepts I have learned from algebra so far are: we have learned Expressions, Equations, we have Used Graphs, we have learned how to resolve Inequalities on the Number line, I have learned how to do variables, constants, linear equations, and quadratic equations. those are just very few examples of things me and so many have learned so far in Algebra.

Step-by-step explanation:

Answer:

40141

Step-by-step explanation:

Answer:

I think i don't know the answer i am so sorry!!!

maybe someone else can Answer