A skateboarder traveling at 10.4 m/s starts getting chased by a grumpy dog. The skateboarder speeds up with a constant acceleration for 39m over a 3.3s. We want to find the acceleration of the skateboarder over the 3.3s time interval. Which kinematic formula would be most useful to solve for the target unknown?

a. V= Vo+a(t)
b. X= (V+Vo/2)t
c. X= Vo(t)+1/2at^2
d. V^2 = Vo^2 +2ax
e. X= vt-1/2at^2

Answer:

The building is 176.4 meters high.

Explanation:

We use the formula for kinematics of an accelerated object (in this case acceleration of gravity):

Distance travelled = 1/2 g  t^2

Distance travelled = 1/2 9.8  (6)^2 = 176.4 meters

Answer:

C

Explanation:

The thermal energy from her hand will go up into the smoothie.

Answer:

C bois

Explanation:

sowwie :( i need points

Explanation:

Answer:

The answer would be 11.6 g/m^3

Explanation:

Knowing that vapor's density at 100% humidity is 20g/m^3 we can calculate the answer using the following math:

0.58 * 20 = 11.6 grams per cubic meter

the units can also be written as g/m^3

The density of water vapor is 11.6 grams/cubic meter.

The quantity of atmospheric moisture that is present compared to the amount that would be there if the air were saturated is known as relative humidity, and it is stated as a percentage. Relative humidity depends on both moisture content and temperature because the latter quantity is temperature-dependent. The related temperature and dew point for the specified hour are used to calculate relative humidity. it is expresses as %.

Now given that the maximum water vapor in air at this temperature is 20 grams/cubic meter at 22°C, that is, density of vapor at 100% humidity is 20g/[tex]m^3[/tex]  at 22°C.

And, The device showing that at 22 degrees Celsius the relative humidity is 58%

So, water vapor density at that moment is = 20g/[tex]m^3[/tex] × 58%

= 11.6 g/[tex]m^3[/tex] .

= 11.6 grams/cubic meter.

Hence, according to the measurement of device, the water vapor density is 11.6 grams/cubic meter.

Learn more about relative humidity here:

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Answer:

E = 105.84  J

Explanation:

Given that,

Mass of cat, m = 3.6 kg

It is laying 3 meters above the ground.

We need to find the cat's potential energy. The formula for the potential energy of an object is given by :

E = mgh

Substituting all the values,

E = 3.6 kg × 9.8 m/s²×3 m

E = 105.84  J

So, the cat's potential energy is 105.84  J.

Answer:

[tex]\frac{dh}{dt}=-0.4125 m/s[/tex]

Explanation:

The very first thing we can do here is to draw a sketch of the situation the problem is presenting. (See attached picture)

As you may see in the picture, we can suppose the spotlight is directly located on the ground so the light of the spotlight together with the person and the wall make two similar triangles.

In this case we need to think about the dimensions of the triangle that will change over time. We will call them:

x= distance between the spotlight and the man.

h= height of the shadow.

So we can build a relation between the height and the length of each triangle:

[tex]\frac{h}{12}=\frac{2}{x}[/tex]

the distance between the spotlight and the wall is constant, so I can directly write the 12 in my equation and the height of the man is constant as well, so I can write the 2 directly into the equation.

Next, we can solve the equation for h (since we are interested in figuring out how fast the height of the shadow is decreasing) so we get:

[tex]h=\frac{24}{x}[/tex]

So next, we need to take the derivative of the equation, since the derivative of a position function will give us the velocity at which that position is changing.

First we rewrite the equation like this:

[tex]h=24x^{-1}[/tex]

and take the derivative:

[tex]dh=-24x^{-2}dx[/tex]

we can rewrite the derivative like this:

[tex]\frac{dh}{dt}=-\frac{24}{x^{2}} \frac{dx}{dt}[/tex]

where:

dh/dt is the velocity at which the height of the shadow is decreasing (that's why our equation has a negative sign in front of it).

dx/dt is the velocity at which the value of x is increasing. In other words, how fast the man is moving away from the spotlight.

So we can go ahead and substitute:

we wish to find the velocity at which the shadow's height is decreasing when the distance between the man and the building is 4m, so in this case, x=12-4=8m

[tex]\frac{dh}{dt}=-\frac{24}{8^{2}}(1.1 m/s)[/tex]

so we get:

[tex]\frac{dh}{dt}=-0.4125 m/s[/tex]

The force acts on this bullet : 4.8456 N

Given

m=0.09 kg

Δt=0.025 s

vo=0(from rest)

vt=1.346 m/s

Required

Force

Solution

Impulse is a change in momentum

I=ΔP

F.Δt=m(vt-vo)

Input the value

F x 0.025 = 0.09(1.346-0)

F=4.8456 N

Answer:

5m

Explanation:

[tex]4^{2}+3^{2}=5^{2}\\5^{2}=25[/tex]

Use the Pythagorean theorem to calculate the long edge of the triangle, which would be his displacement.

The question is missing some parts. Here is the complete question.

A suspension bridge cable is connected to its anchor at a 20° angle. Find the vertical and horizontal component of the force on the anchor by the cable.

Answer: [tex]F_{x}=[/tex] 14095.4 N

              [tex]F_{y}=[/tex] 5130.3 N

Explanation: The force applied to the anchor is not perpendicular to the horizontal plane. So, it can be decomposed into 2 components: a vertical component, which is on the y-axis, and a horizontal component, which is on the x-axis.

The force and its components forms a right triangle, so we can calculate the components by using trigonometric relations:

Horizontal

[tex]cos(20)=\frac{F_{x}}{F}[/tex]

[tex]F_{x}=F.cos(20)[/tex]

[tex]F_{x}=15,000(0.9397)[/tex]

[tex]F_{x}=[/tex] 14,095.4 N

Vertical

[tex]sin(20)=\frac{F_{y}}{F}[/tex]

[tex]F_{y}=Fsin(20)[/tex]

[tex]F_{y}=[/tex] 15,000(0.3420)

[tex]F_{y}=[/tex] 5,130.3 N

The vertical and horizontal components of force on the anchor by the cable are 5130.3 N and 14095.4 N, respectively.

Answer:

Kinetic energy is energy of motion

Explanation:

Of potential energy which is energy that is stored

Answer:

- 670 kg.m/s

Explanation:

Newton's third law states that to every action, there is equal and opposite reaction force. Since the force will be same but different in direction and acted in the same time then the impulses ( force multiply by time) of the two car be same in magnitude but different in direction - 670 kg.m/s

Answer:

[tex]D= -0.42km[/tex]

Explanation:

From the question we are told that

Drifting right with speed 5.0m/s

The motor runs for 6.0 seconds

Leftward acceleration of magnitude 4.0 m/s squared

Generally the equation [tex]V=ut+1/2at^2[/tex] can be used here

[tex]V=ut+1/2at^2[/tex]

Mathematically solving with the newton equation above we have that

   [tex]D=5*6 + \frac{1}{2} (-4)*6^2[/tex]

   [tex]D=30-72[/tex]

   [tex]D=-42m[/tex] [tex]or -0.42km[/tex]

Therefore having this the Displacement is [tex]D= -0.42km[/tex] leftward

Answer:

The correct answer is B. Mika, Chet, Sara, Bill

Explanation:

Look at the picture

hope this helps :)

The  list, that the students in order from the greatest amount of work done to the least, is: Mika, Chet, Sara, Bill.

We can state that Work is the product of the component of the force acting in the displacement's direction and its magnitude.

The joule (J), a unit of work used in the International System of Units (SI), is defined as the amount of work required to move an item one meter in the direction of a force of one newton.

Work done by Mika = 50 × 1.0 Joule = 50 Joule

Work done by Chet  = 40 × 2.0 Joule = 80 Joule

Work done by Sara  = 30 × 1.5 Joule = 45 Joule

Work done by Bill = 60 × 0.5 Joule = 30 Joule  

So, The  list, that the students in order from the greatest amount of work done to the least, is: Mika, Chet, Sara, Bill.

Learn more about work here:

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Answer:

i think it should be 18

Explanation:

Answer:

first where is figure...

silver the is best conducter of electricity.

Answer:

Answer:

It's the number of protons in the nucleus of the atom

Answer:

F = 133.33[N]

Explanation:

This problem can be solved by the principle of momentum conservation, which tells us that momentum is preserved before and after the bounce of the ball on the wall.

In such a way that the movement towards the wall we will take it with a positive sign, and the force of the rebound to the left as negative. The movement to the left will be taken as a negative sign.

[tex]m_{1}*v_{1}-F*t=-m_{1}*v_{2}[/tex]

where:

m₁ = mass of the object = 1.5 [kg]

v₁ = velocity of the ball before hitting the wall = 2.5 [m/s]

F = average force [N]

t = time contact = 0.045 [s]

v₂ = velocity of the ball after hitting the wall = 1.5 [m/s]

Now replacing:

[tex](1.5*2.5)-F*0.045=-(1.5*1.5)\\3.75+2.25=F*0.045\\F=6/0.045\\F=133.33[N][/tex]

Answer:

Explanation:

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects

so a option is correct

Answer:

3 hrs

Explanation:

the distance covered by victor= 210 km

speed= 70 km/hrs

so, 70×3= 210

so the answer is 3 hrs

BTW im a small kid so don't just right away say the explanation sucks and the subject physics is not yet started in my grade.

edit: don't give me brainless answer plz.

Answer:

a)     F _total = 15.08 10⁻³ N ,   b)   m = 1,539 10⁻³ kg

Explanation:

a) To solve this problem we can use Coulomb's law to find the force created by each charge

          F =[tex]k \frac{\ q_{1} q_{2} }{r_{12}^{2} }[/tex]

and the total force is

          F = F₁₅ + F₂₅ + F₃₅ + F₄₅

The bold are vectros, In the exercise they indicate the charges

          q₁ = q₂= q₃ = q₄ =  1 10⁻⁶ C

          q₅ = 2 10⁻⁶ C

Let's set a reference system where the sphere is on the z axis and the other charges on the xy plane, let's write the coordinates of card charge

sphere (subscript 5)

   x₅ = 0

   y₅ = 0

   z₅ = 2 m

charge 1

   x = 0.5 m

   y = 0.5 m

   z = 0

charge 2

   x = -0.5 m

   y = 0.5 m

   z = 0

charge 3

   x = -0.5 m

   y = -0.5 m

   z = 0

charge 4

   x = 0.5 m

   y = -0.5 m

   z = 0

With these values ​​we can calculate the distance between each charge and the sphere

charge 1 and sphere

       r₁₅² = (x₅ -x₁)² + (y₅ - y₁)² + (z₅ -z₁)²

substitute

       r₁₅² = (0- 0.5)² + (0 - 0.5)² + (2 -0)²

       r₁₅² = 0.5² + 0.5² + 2²

       r₁₅² = 4.5

we can see that for the other charges the result is the same since being squared always gives positive

      r₁₅ = r₂₅ = r₃₅ = r₄₅

the force created by the card charge on the sphere is the projection on the Z axis of the total force

Let's find the angle with respect to the Z axis

            tan φ = r / z

where r is the magnitude of the vector in the xy plane

          r = [tex]\sqrt{0.5^{2} + 0.5^{2} }[/tex]

          r = 0.7071 m

         φ = tan⁻¹ r / z

         φ = tan⁻¹ (0.7071 / 2)

         φ = 19.5

consequently the total force is

        F_total = 4 F cos 19.5

        F _total =   [tex]4 \frac{k \ q_{1} q_{5} }{r_{15}^{2}}[/tex]   cos 19.5

let's calculate

        F_toal = 4 9 10⁹ 1 10⁻⁶ 2 10⁻⁶ /4.5    cos 19.5

        F _total = 15.08 10⁻³ N

b) For this part indicate that the sphere is in equilibrium with the weight

           F_total - W = 0

           W = mg

           F_total = mg

           m = F_total / g

           m = 15.08 10³ / 9.8

           m = 1,539 10⁻³ kg

Answer:

3566.26 Watts

Explanation:

From the question given above, the following data were obtained:

Mass (m) of crate = 151 kg

Coefficient of kinetic friction (μ) = 0.399

Velocity (v) = 6.04 m/s

Power (P) =?

Next, we shall determine the normal reaction. This can be obtained as follow:

Mass (m) of crate = 151 kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal reaction (R) = mg

Normal reaction (R) = 151 × 9.8

Normal reaction (R) = 1479.8 N

Next, we shall determine the force applied to move the crate. This can be obtained as follow:

Coefficient of kinetic friction (μ) = 0.399

Normal reaction (R) = 1479.8 N

Force (F) =?

F = μR

F = 0.399 × 1479.8

F = 590.44 N

Finally, we shall determine the power used to move the crate as follow:

Velocity (v) = 6.04 m/s

Force (F) applied = 590.44 N

Power (P) =?

P = F × v

P = 590.44 × 6.04

P = 3566.26 Watts

Therefore, the power used to move the crate is 3566.26 Watts.

Answer:

true

Explanation:

I believe the answer i chose because the earths atmosphere is mostly made up of different things that causes the earth to interact with human life and also interacts with what's in the atmosphere like energy oxygen carbon dioxide and all the stuff like that i hope its right.

momentum (m)=40

velocity (v)=2

now,

momentum (m)=m×v

40=m×2

m=40÷2

m=20kg

Answer:

Explanation:

An object following a circular path can be covering the same distance along the circle's circumference with every passing minute, giving it a constant speed. Since a change in either speed OR direction means a change in velocity, the object's velocity is not constant.

velocity is a vector so therefore direction affects it being constant.

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. If an object's velocity is constant, however, its acceleration will be zero.  

Velocity is a vector so therefore direction affects it being constant.

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time

An object following a circular path can be covering the same distance along the circle's circumference with every passing minute, giving it a constant speed. Since a change in either speed OR direction means a change in velocity, the object's velocity is not constant. An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. If an object's velocity is constant, however, its acceleration will be zero.  

Velocity is a vector so therefore direction affects it being constant.

To learn more about velocity refer to the link

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Complete question is;

What is the electrical potential at the surface of gold nucleus? The radius of a gold atom is 6.6 × 10​^(-5) m and atomic number z = 79.

Answer:

172.36 × 10^(-5) V

Explanation:

We are given;

Radius; r = 6.6 × 10^(-5) m

Atomic number; Z = 79

Formula for Electric potential here is;

V = kZe/r

Where;

e is charge on proton = 1.6 × 10^(-19) C

k has a constant value of 9 × 10^(9) N⋅m²/C²,

​Thus;

V = (79 × 1.6 × 10^(-19) × 9 × 10^(9))/(6.6 × 10^(-5))

V = 172.36 × 10^(-5) V