Answer:
82.31
Step-by-step explanation:
I believe this is correct, if it isn't feel free to let me know and I will fix it. I'm sorry in advance if this is incorrect.
HI CAN SOMEONE THAT REALLY KNOWS ABOUT THIS HELP ME WITH FINAL EXAM...
The data represented by the following stem-and-leaf plot range from
to
489
5147
6235
769
A. 49; 79
B. 48; 79
C. 48; 76
D. 49; 76
Someone help please!!
Answer:
9 (a) [tex]d = \frac{\sqrt{e}}{\sqrt{3}}[/tex]
9 (b) [tex]d = \frac{\sqrt{7k}}{\sqrt{2}}[/tex]
Step-by-step explanation:
Hope this helped!
A box with a square base and open top must have a volume of 256000 c m 3 . We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only x , the length of one side of the square base.
Answer:
Follows are the response to the given question:
Step-by-step explanation:
The volume of the box:
[tex]V = x\times x \times h = 256000 \ cm^3\\\\\to x^2 \times h = 256000\\\\\to h = \frac{256000}{x^2}[/tex]
The surface area of the open box is:
[tex]A(x) = x \times x + 2 \times (x \times h +x \times h)\\\\A(x) = x^2 + 4 \times x \times h\\\\A(x) = x^2 + \frac{1024000}{x}\\\\\frac{d(x^n)}{dx} = n \times x^{(n - 1)}\\\\[/tex]
Use above formula
[tex]A'(x) = 2 \times x - \frac{1024000}{x^2}\\\\[/tex]
[tex]A'(x) = 0\\\\2\times x - \frac{1024000}{x^2} = 0\\\\2x = \frac{1024000}{x^2}\\\\x^3 = 512000\\\\x = (512000)^{(\frac{1}{3})} = 80\ cm\\\\[/tex]
Now
[tex]A''(x) = 2\times 1 + 2\times \frac{1024000}{x^3}\\\\A''(x) = 2 + \frac{2048000}{x^3}\\\\x = 80 \ cm\\\\A''(80) = 2 + \frac{2048000}{80^3} = 6\\\\[/tex]
therefore [tex]A"(x) > 0,[/tex] x amount of material used in minimum.
[tex]h = \frac{256000}{80^2} = 40\ cm[/tex]
This is a 30-60-90 triangle. What is the measure of x? rationalize the denominator.
Answer:
[tex] x=\frac{[2] \sqrt {[21] }}{[3] }[/tex]
Step-by-step explanation:
Since, given is a 30°-60°-90° triangle.
[tex] \therefore \sqrt 7 = \frac{\sqrt3}{2} \times x[/tex]
[tex] \therefore 2\sqrt 7 = \sqrt3 \times x[/tex]
[tex] \therefore x=\frac{2\sqrt 7}{\sqrt 3}[/tex]
[tex] \therefore x=\frac{2\sqrt 7(\sqrt 3)}{\sqrt 3(\sqrt 3)}[/tex]
[tex] \huge \therefore x=\frac{[2] \sqrt {[21] }}{[3] }[/tex]
Write the equation of the circle with center C(-5,8) and radius = 7
Answer:
( h + 5 )^2 + ( y - 8 ) ^2 = 49
Step-by-step explanation:
Equation of a circle:
( x - h )^2 + ( y - k )^2 = r^2
Where ( h , k ) = center and r = radius
We are given that the circle has a center at ( -5 , 8 ) meaning that h = -5 and k = 8
We are also given that the circle has a radius of 7 meaning that r = 7
Now that we have identified each variable we plug the values into the equation
( h - (-5)^2 + ( y - 8 )^2 = 7^2
Our final step is to simplify
we get that the equation of the circle is
( h + 5 )^2 + ( y - 8 ) ^2 = 49
By the way ^ means exponent
Help please which option
Answer:
Step-by-step explanation:
-1<x<3. I hope it helpful!
If F(x)= 3x-2 and G(x)= x^2+8, what is G(F(x))?
Answer:
(3x-2)^2+8= 9x^2-12x+12
Select the correct answer.
What is the solution to this equation?
log3 (4x) – 2log3x =2
A. 36
B. 9/4
C. 4/9
D. 1/36
9514 1404 393
Answer:
C. 4/9
Step-by-step explanation:
There are a couple of ways you can do this.
[tex]\log_3{4x}-2\log_3{x}=2\\\\\log_3{4}+\log_3{x}-2\log_3{x}=2\\\\\log_3{4}-2=\log_3{x}\\\\4\cdot3^{-2}=x\qquad\text{take antilogs}\\\\\boxed{x=\dfrac{4}{9}}\\\\\textsf{or}\\\\\dfrac{4x}{x^2}=3^2\qquad\text{take antilogs}\\\\\dfrac{4}{9}=x\qquad\text{cancel $x$, multiply by $\dfrac{x}{9}$}[/tex]
I need help with this.
9514 1404 393
Answer:
$400
Step-by-step explanation:
The word "per" in math often means "divided by". To find price per square foot, find price divided by square feet.
$700,000/(1750 ft²) = $400 /ft²
The price per square foot of House 4 was $400.
Find the value of y and show work
Answer:
75
Step-by-step explanation:
∠K and ∠ R are congruent (equal)
Triangle Sum Theory - angles of all triangles add to 180
180 - 79 - 26 = 75
Translate the phrase into an algebraic expression.
3 more than b
Answer:
b+3 or 3+b
Step-by-step explanation:
Solve the equation.
(X-5)(x + 7) = 0
X=
-D
(Use a comma 6 separate answers as needed.)
9514 1404 393
Answer:
x = -7, 5
Step-by-step explanation:
The equation is written as a product equal to zero. The "zero product rule" tells us that a product is zero if and only if one or more factors are zero. Each factor will be zero when x takes on a value equal to the opposite of the constant in that factor.
x -5 = 0 ⇒ x = 5
x +7 = 0 ⇒ x = -7
The solutions to the equation are x = -7, 5.
EXPAND AND SIMPLIFY
Answer:
5⁴a²
Step-by-step explanation:
(5³a³)÷5a-¹×5-²a²
5³a³÷5a-¹×5-²a²
5³a³÷5¹-²×a-¹+²
5³a³÷5-¹a
5³a³/5-¹a
5³-(-¹)a³-¹
5⁴a²
When comparing two box-plots that show the same type of information, what determines agreement within the data?
A.the range of the quartiles in each data set
B.the median of each data set
C.the mean of each data set
D.the number of values in each data set
Answer:
c.the mean of each data set
Answer:
A
Step-by-step explanation:
Simplify -4 + (-3) + 6.
Answer:3/6 in simplest fraction form is 1/2.
Step-by-step explanation:EASY and my chanel is FireFlameZero if u can check dat out
add negative 4 plus negative 6
-10
thats it, thats what i know
4n-6 in as a undistributed expression
Answer:
2( 2n-3)
Step-by-step explanation:
4n-6
2*2 n - 2*3
Factor out the greatest common factor
2( 2n-3)
anyone help me, let's prove
Answer:
In my opinion the limit is equal to 1 not 0, sorry.
Step-by-step explanation: 6 25 13 43
lim n ⇒∞ ((2n - 1)/2n)
lim n ⇒∞ (2n/2n) - 1)/2n) 2n/2n = 1 1/∞ = 0
= 1 - 0
= 1
when I graphed the function I also got 1
There are 200 students in a particular graduate program at a state university. Of them, 110 are female and 125 are out-of-state students. Of the 110 females, 70 are out-of-state students. If two of these 200 students are selected at random, what is the probability that both of them are out-of-state students?
evaluate g(x)=x/x-3, if g(1/2)
Answer:
-1/5
Step-by-step explanation:
g(x) = x/(x-3)
Substituting x = 1/2 in g(x),
g(1/2) = 1/2/(1/2-3)
= 1/2/(1/2-6/2)
= 1/2/(-5/2)
= 1/2 ÷ - 5/2
= 1/2 x -2/5
= - 1/5
Step-by-step explanation:
here is your answer
here is your answer
What are the rational roots of f(d) = 5d - 6 + d-8?
Question 11 of 45
Which similarity postulate or theorem can be used to verify that the two
triangles shown below are similar?
12
6 R
X 2 z
O A. Similarity cannot be determined,
B. SSS theorem
O C. AA postulate
D. SAS theorem
Answer:
You are only given a Side, an Angle, and then a side. So that is what I would choose. It can't be AA because you weren't given two angles. It can't be SSS because you weren't given 3 sides.
Step-by-step explanation:
ΔPQR and ΔXYZ are similar due to the SSS theorem.
Option B is the correct answer.
What is triangle congruency?There are ways to prove that two triangles are congruent.
- Side-Side-Side (SSS) Congruence.
The three sides of one triangle are equal to the corresponding three sides of another triangle.
- Side-Angle-Side (SAS) Congruence.
The two sides and the included angle of one triangle are equal to the corresponding two sides and included angle of another triangle.
- Angle-Side-Angle (ASA) Congruence.
The two angles and the included side of one triangle are equal to the corresponding two angles and included side of another triangle.
- Angle-Angle-Side (AAS) Congruence.
We have,
Similar triangles are triangles that have the same shape but may have different sizes.
Two triangles are similar if their corresponding angles are equal, and their corresponding sides are proportional.
When two triangles are similar, they have the same shape, but one may be larger or smaller than the other.
Now,
ΔPQR and ΔXYZ
PQ/XY = 12/4 = 3
PR/XZ = 6/2 = 3
Since the two sides are proportional,
QR/YZ will be proportional.
Now,
PQ/XY = PR/XZ = QR/YZ
ΔPQR and ΔXYZ are similar due to the SSS theorem.
Thus,
ΔPQR and ΔXYZ are similar due to the SSS theorem.
Learn more about triangle congruency here:
https://brainly.com/question/12413243
#SPJ7
the volume of a cylinder is 44cm3. find the volume of another cylinder of the same height and double the base radius
Answer:
[tex]Volume \ of \ other\ cylinder = 176 \ cm^3[/tex]
Step-by-step explanation:
Let the volume of cylinder Vₐ = 44cm³
Let radius of cylinder " a " be = rₐ
Let height of cylinder " b" be = hₐ
[tex]Volume_a = \pi r_a^2 h_a\\\\44 = \pi r_a^2 h_a[/tex]
Given cylinder " b ", Radius is twice cylinder " a " , that is [tex]r_b = 2 r_a[/tex]
Also Height of cylinder " b " is same as cylinder " a " , that is [tex]h_b = h_a[/tex]
[tex]Volume_b = \pi r_b^2 h_b[/tex]
[tex]= \pi (2r_a)^2 h_a\\\\=4 \times \pi r_a^2 h_a\\\\= 4 \times 44\\\\= 176 \ cm^3[/tex]
The radius of a plant pot is 4.5 cm, and its height is 6 cm. What is the volume of the pot?
Use the value 3.14 for , and round your answer to the nearest whole number.
Be sure to include the correct unit in your answer.
Answer:
381 cm³
Step-by-step explanation:
Volume of the pot = volume of a cylinder
Volume of the pot = πr²h
Where,
π = 3.14
radius (r) = 4.5 cm
h = 6 cm
Substitute
Volume of the pot = 3.14*4.5²*6
Volume of the pot = 381.51 ≈ 381 cm³ (nearest whole number)
Find the missing segment in the image below
A person invests $3,500 in an account that earns 7.5% interest compounded continuously. What is the value of the investment after 4 years?
I think it's: 4,674.14$
Answer:
A = $4724.36
Step-by-step explanation:
P = $3500
r = 7.5% = 0.075
t = 4years
n = 365
[tex]A = P(1 + \frac{r}{n})^{nt}\\\\[/tex]
[tex]=3500(1 + \frac{0.075}{365})^{365 \times 4}\\\\=3500(1.00020547945)^{365\times4}\\\\= 3500 \times 1.34981720868\\\\= 4724.36023037\\\\= \$ 4724.36[/tex]
Find the measure of WX and show work
Ans : the measure of WX = 8
WILL MARK YOU JF YOU HELP PLEASE HELP ME!!
This are diferente question help me please
Step-by-step
28.26 in84.9 m5024 cm277.45 mi 452.16 in1.36 mi44.15 m3.14 cmI hope it helps you
Segment [tex]$s_1$[/tex] has endpoints at [tex]$(3+\sqrt{2},5)$[/tex] and[tex]$(4,7)$[/tex]. Segment [tex]$s_2$[/tex] has endpoints at [tex]$(6-\sqrt{2},3)$[/tex] and[tex]$(3,5)$[/tex]. Find the midpoint of the segment with endpoints at the midpoints of [tex]$s_1$[/tex] and [tex]$s_2$[/tex]. Express your answer as [tex]$(a,b)$[/tex].
Answer:
The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).
Step-by-step explanation:
Midpoint of a segment:
The coordinates of the midpoint of a segment are the mean of the coordinates of the endpoints of the segment.
Midpoint of s1:
Using the endpoints given in the exercise.
[tex]x = \frac{3 + \sqrt{2} + 4}{2} = \frac{7 + \sqrt{2}}{2}[/tex]
[tex]y = \frac{5 + 7}{2} = \frac{12}{2} = 6[/tex]
Thus:
[tex]M_{s1} = (\frac{7 + \sqrt{2}}{2},6)[/tex]
Midpoint of s2:
[tex]x = \frac{6 - \sqrt{2} + 3}{2} = \frac{9 - \sqrt{2}}{2}[/tex]
[tex]y = \frac{3 + 5}{2} = \frac{8}{2} = 4[/tex]
Thus:
[tex]M_{s2} = (\frac{9 - \sqrt{2}}{2}, 4)[/tex]
Find the midpoint of the segment with endpoints at the midpoints of s1 and s2.
Now the midpoint of the segment with endpoints [tex]M_{s1}[/tex] and [tex]M_{s2}[/tex]. So
[tex]x = \frac{\frac{7 + \sqrt{2}}{2} + \frac{9 - \sqrt{2}}{2}}{2} = \frac{16}{4} = 4[/tex]
[tex]y = \frac{6 + 4}{2} = \frac{10}{2} = 5[/tex]
The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).
