A sound wave with amplitude xo is measured by an observer to have an intensity of I0 when the observer is standing 4.0 meters from the source. Which best describes the amplitude of a sound wave and distance from the source where it will be measured with an intensity of 16Io?

Answer:

1/4

Step-by-step explanation:

2x=-1/10 + 3/5

2x=1/2

x=1/4

Answer:

Option C

Step-by-step explanation:

From the picture attached,

In ΔABC,

m∠BAC + y° = 180° [Linear pair of angles are supplementary]

m∠BAC = 180° - y°

m∠ABC = x° [Vertically opposite angles]

m∠ACB = z° [Vertically opposite angles]

By triangle sum theorem,

m∠BAC + m∠ABC + m∠ACB = 180°

(180 - y)° + x° + z° = 180°

x - y + z = 180 - 180

x - y + z = 0

Option C will be the answer.

Answer: 3.5 inches

Step-by-step explanation:

Answer:

Step-by-step explanation:

b

Answer:

b hope it helps make brainlliest ty

Step-by-step explanation:

can you make me brainlliest

Answer: The answer is 3.

Step-by-step explanation: You would multiply 9x1/3 which would give you 3. If you want to understand even better here's how to do so: Put 3(the answer that you got from multiplying 9x1/3) into the fraction 1/3 as 1. In other words,  it would look something like this 3/3. Then, just multiply the two numbers 3x3 and that equals 9, the number you started with.

Hope that this helped!!:)

Considering the provided information in the given question, we have :

We need to find how many seashells did Saniyah have left.

⇒ Number of seashells Saniyah have left = Total seashells – Number of seashells she gave to her sister

⇒ [tex] \sf {Left \: seashells = 9 - \Bigg \lgroup \dfrac{1}{3} \times 9 \Bigg \rgroup } [/tex]

⇒ [tex] \sf {Left \: seashells = 9 - \Bigg \lgroup 1 \times 3 \Bigg \rgroup } [/tex]

⇒ Left seashells = 9 – 3

⇒ Left seashells = 6

Therefore, Saniyah have left [tex] \bf {6 \: seashells } [/tex].

Answer:

[tex]f^{-1}(6) = 50[/tex]

Step-by-step explanation:

Given

[tex]f(x) = \sqrt{2x} - 4[/tex]

Required

Find [tex]f^{-1}(6)[/tex]

First, we calculate the inverse function

[tex]f(x) = \sqrt{2x} - 4[/tex]

Express f(x) as y

[tex]y = \sqrt{2x} - 4[/tex]

Swap the positions of x and y

[tex]x = \sqrt{2y} - 4[/tex]

Solve for y: Add 4 to both sides

[tex]4 + x = \sqrt{2y} - 4+4[/tex]

[tex]4 + x = \sqrt{2y}[/tex]

Square both sides

[tex](4 + x)^2 = 2y[/tex]

Divide both sides by 2

[tex]y = \frac{(4 + x)^2}{2}[/tex]

Express y as an inverse function

[tex]f^{-1}(x) = \frac{(4 + x)^2}{2}[/tex]

Next, solve for: [tex]f^{-1}(6)[/tex]

Substitute 6 for x

[tex]f^{-1}(6) = \frac{(4 + 6)^2}{2}[/tex]

[tex]f^{-1}(6) = \frac{(10)^2}{2}[/tex]

[tex]f^{-1}(6) = \frac{100}{2}[/tex]

[tex]f^{-1}(6) = 50[/tex]

Is this the problem?

[tex]18x^{2+4+4} = 18^{9x+18}[/tex]

Answer

The Answer is C                    

x=-2 and x=7                      

Answer:

The chocolate covered pretzels in Sophie's bag weighed [tex]\frac{2}{3} = 0.6667[/tex] kilograms.

Step-by-step explanation:

Sophie filled a bag with 2 2/3 kilograms of candy.

This means that the total weight is of:

[tex]2\frac{2}{3} = 2 + \frac{2}{3} = \frac{6}{3} + \frac{2}{3} = \frac{8}{3}[/tex]

The total weight is of 8/3 kilograms.

1/4 of the weight of the candy was from chocolate covered pretzels. How much did the chocolate covered pretzels in Sophie's bag weigh?

1/4 of 8/3. So

[tex]\frac{1}{4} \times \frac{8}{3} = \frac{1*8}{4*3} = \frac{2}{3} = 0.6667[/tex]

The chocolate covered pretzels in Sophie's bag weighed [tex]\frac{2}{3} = 0.6667[/tex] kilograms.

Answer:

The bottom table.

Step-by-step explanation:

It's the only one that shows options for heads and tails for every number.

Answer:

D the last one

Answer:

later ill answer this .. read and understand

Answer:

0.51 seconds

Step-by-step explanation:

49.55 - 49.06 = 0.51 seconds

Answer:

A

Step-by-step explanation:

Answer:

b+c+h=50

Step-by-step explanation:

Its the first one because you need to have the same amount of hats as cupcakes cause the hat really stands for people.

Answer:

990 cars

Step-by-step explanation:

Find how many cars pass through at 6am, t=0:

r(0)= 300+600(0)-90(0²) = 300

Find how many cars pass through at 9am, t=3:

r(3)= 300+600(3)-900(3²)=300+1800-810=1290

Find the difference (how many cars pass between 6am and 9am): 1290-300=990

Answer:

Ha: μ < 24

The test statistic is z = -1.75.

The pvalue of the test is 0.0401 > 0.02, which means that we do not reject the null hypothesis, as there is insufficient evidence.

Step-by-step explanation:

A recent survey reported that small businesses spend 24 hours a week marketing their business.

This means that the null hypothesis is:

[tex]H_0: \mu = 24[/tex]

A local chamber of commerce claims that small businesses in their area are not growing because these businesses are spending less than 24 hours a week on marketing.

This means that the alternate hypothesis is:

[tex]H_a: \mu < 24[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

24 is tested at the null hypothesis:

This means that [tex]\mu = 24[/tex]

The chamber conducts a survey of 93 small businesses within their state and finds that the average amount of time spent on marketing is 23.0 hours a week.

This means that [tex]n = 93, X = 23[/tex]

The population standard deviation is 5.5 hours

This means that [tex]\sigma = 5.5[/tex]

Value of the test-statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{23 - 24}{\frac{5.5}{\sqrt{93}}}[/tex]

[tex]z = -1.75[/tex]

The test statistic is z = -1.75.

Do we reject the null hypothesis? Is there sufficient or insufficient evidence?

The pvalue of the test is the probability of finding a sample mean below 23, which is the pvalue of z = -1.75.

Looking at the z table, z = -1.75 has a pvalue of 0.0401

The pvalue of the test is 0.0401 > 0.02, which means that we do not reject the null hypothesis, as there is insufficient evidence.

9514 1404 393

Answer:

  3 +3d ≥ 15

  d ≥ 4

Step-by-step explanation:

Since Joe runs 3 miles for each day he runs, the number of miles he runs in d days is 3d. That, added to the distance he has already run, will total the amount for the week. He wants that to be at least (greater than or equal to) 15 miles:

  3 + 3d ≥ 15

__

We can divide by 3 to get ...

  1 + d ≥ 5

  d ≥ 4 . . . . . . . subtract 1

Joe must run at least 4 additional days this week to run at least 15 miles.

D-Salary(33) or S(33)

D is correct hope this helps

Answer:

[tex]\frac{x}{9}[/tex]

Step-by-step explanation:

Given

[tex]\frac{x^2 - 9}{9x + 27} \div \frac{x - 3}{x}[/tex]

Required

Solve

[tex]\frac{x^2 - 9}{9x + 27} \div \frac{x - 3}{x}[/tex]

Change the division to multiplication

[tex]\frac{x^2 - 9}{9x + 27} * \frac{x}{x - 3}[/tex]

Apply difference of 2 squares

[tex]\frac{(x - 3)(x+3)}{9x + 27} * \frac{x}{x - 3}[/tex]

Cancel out x - 3

[tex]\frac{x+3}{9x + 27} * \frac{x}{1}[/tex]

Factorize 9x + 27

[tex]\frac{x+3}{9(x + 3)} * \frac{x}{1}[/tex]

Cancel out x + 3

[tex]\frac{1}{9} * \frac{x}{1}[/tex]

Finally, this gives:

[tex]\frac{x}{9}[/tex]

Answer:

I've never had to deal with this before but I would say C

Answer:

The best option is C ( y=(1/4) x +3)

Answer:

Answer is in the step by step explanation

Step-by-step explanation:

Since we are given parallel lines, we know <BCA is congruent to <DAC because of alternate interior angles

Then AC is congruent to AC, that's reflexive prop

Now we have SAS, so Tri. ABC cong to tri. CDA,

Then you're done

Answer:

Step-by-step explanation:

BC = AD                           Given

<BCA = <CAD                  Alternate interior angles of parallel lines cut by a transversal.

AC = AC                           That's the reflexive property. A line is equal to itself

Triangle BCA = Triangle CAD    SAS

Notice that the angle is included inside the two lines that define it (the angle). That's a very important consideration when using SAS. SAA doesn't always work. You can draw exceptions. SAS has no exceptions. It always works.

Answer:

Part A

Yes

Part B

He will land at a point 30 meters from Cannon

Step-by-step explanation:

Part A

The given function that represent the path of the Cannon, which is the path of a parabolic arc, is presented as follows;

f(x) = -0.05·(x² - 26·x - 120)

We note that the height, 'h', of the path of a parabola at a horizontal distance, 'x' from the origin is equal to f(x)

Therefore, given that at the ground level, at the start and end of the flight, the f(x) = 0, we can write;

-0.05·(x² - 26·x - 120) = 0

∴ x² - 26·x - 120 = 0

x = (26 ± √((-26)² - 4 × 1 × (-120)))/(2 × 1)

Which gives;

x = 30 or x = -4

Therefore, he lands at a point 30 meters from the starting point

Therefore, the function gives enough information to tell where he will land

Part B

He lands at the point, x = 30 from the point the cannon was fired.

Answer:

0.125 = 12.5% probability that they are a great match now.

Step-by-step explanation:

To solve this question, we need the probability of a person being a great match, which i will use 0.1.

This question is solved using conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Is kind to animals.

Event B: Is a great match.

Probability of being kind to animals:

0.9 of 0.1(Is a great match).

0.7 of 1 - 0.1 = 0.9(is not a great match). So

[tex]P(A) = 0.9*0.1 + 0.7*0.9 = 0.72[/tex]

Probability of being kind to animals and a great match:

0.9 of 0.1. So

[tex]P(A \cap B) = 0.9*0.1 = 0.09[/tex]

What is the probability that they are a great match now?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09}{0.72} = 0.125[/tex]

0.125 = 12.5% probability that they are a great match now.

Answer:

8b = 48

Step-by-step explanation:

this is because you would substitute the b for the 6 and then multiply straight across giving you a total of 48.

Answer:

8b = 48

Step-by-step explanation:

8 x 6 = 48

Answer:

2

Step-by-step explanation:

on Edge

Answer: 2

Step-by-step explanation:

have a great day!

Answer:

-14

Step-by-step explanation:

[tex]f(x) = -4x – 7 \\ plug \: x = - 1 \\ f( - 1) = - 4( - 1) - 7 = 4 - 7 = - 3 \\g(x) = x² + 7x – 2 \\g(f( - 1)) = {( - 3)}^{2} + 7( - 3) - 2 \\ = 9 - 21 - 2 \\= - 14[/tex]

Answer:

Step-by-step explanation:

3x = 12

x=4

x+y =5y

4+y = 5y

4 = 4y

1=y

Answer:

x-5 = y

72 -5 = 67

y=67

x = 72

Step-by-step explanation:

In a parallelogram, the diagonals bisect each other.

That being the case,

6x = 72

x = 12 In a parallelogram, the diagonals bisect each other.

That being the case,

6x = 72

x = 12 and the diagonals measure

144 and 134

i hope this helps!! ^_^

Answer: Because the question uses the word “distinct” meaning obvious, and clear, I would select AB, AC, CB. (If it’s asking for all the possible line segments, I would select AB, AC, CB, BA, CA, BC).

Answer:

4.71 minutes

Step-by-step explanation:

Incomplete question [See comment for complete question]

Given

Shape: Cone

[tex]r = 3[/tex] -- radius

[tex]h = 7[/tex] --- height

[tex]Rate = 14in^3/min[/tex]

Required

Time to pass out all liquid

First, calculate the volume of the cone.

This is calculated as:

[tex]V = \frac{1}{3} \pi r^2h[/tex]

This gives:

[tex]V = \frac{1}{3} * 3.14 * 3^2 * 7[/tex]

[tex]V = \frac{1}{3} * 197.82[/tex]

[tex]V = 65.94in^3[/tex]

To calculate the time, we make use of the following rate formula.

[tex]Rate = \frac{Volume}{Time}[/tex]

Make Time the subject

[tex]Time= \frac{Volume}{Rate }[/tex]

This gives:

[tex]Time= \frac{65.94in^3}{14in^3/min}[/tex]

[tex]Time= \frac{65.94in^3}{14in^3}min[/tex]

Cancel out the units

[tex]Time= \frac{65.94}{14} min[/tex]

[tex]Time= 4.71 min\\[/tex]

Answer:

The time it will take for all the liquid to pass through is 4.71 minutes.

-Don't worry it's been already verified by myself .