a square + 7 a + 12 =A + 4 ​

Answer: Top right.

Step-by-step explanation:

After plotting the points on a graph, you will see that the points create a negative linear function.

Answer:

433

Step-by-step explanation:

433. . . . . . . ............,.. srry it made me write this much to answer

Answer:

Step-by-step explanation:

Employee's salary: $52,000

Months in a year: 12

52000 / 12 = 4,333.333(r)

Closest answer: D

Answer:

Step-by-step explanation:

1) 7/10 × 2/21

1/15

2) 9/16 × 10/21

90/336

15/56

3) 11/12 × 26/55

13/30

4) 2/6 × 18/12 × 2/3

72/216

1/3

5) ⅚ × 9/10

45/60

3/4

Answer:

k + 8 = y

9x - 17

4(x²-8)

Answer:

Step-by-step explanation:

y = k x

Total cost = y

number of pounds = x

constant = 0.59

Equation

y = 0.59 x

Answer:

x = 2

Step-by-step explanation:

(x+16)/3 = 3x

=> x+16 = 3x × 3

=> x+16 = 9x

=> 16 = 9x - x

=> 16 = 8x

=> 16/8 = x

=> 2 = x

Answer:

A

Step-by-step explanation:

-2x-4>8

-2x>12

-x>6

x<-6

Answer:

[tex]x < - 6[/tex] (first option)

Step-by-step explanation:

[tex] - 2x - 4 > 8[/tex]

[tex] - 2x > 8 + 4[/tex]

[tex] - 2x > 12[/tex]

[tex] = x < - 6[/tex]

Answer:

{0, 1, -1}

Step-by-step explanation:

2x - 6 = 3x + 1 - x - 7

2x - 6 = 2x - 6

0 gives you -6 = -6

1 gives you -4 = -4

-1 gives you -8 = -8

Answer:

slope formula

Step-by-step explanation:

Answer:

Step-by-step explanation:

Solve the equation for n:

The number is 80

Answer:

Number is 40

Step-by-step explanation:

Let the number be n

(n - 20)/2 = 30

(n - 20) = 2 × 30

n = (2 × 30) + 20

n = 60 + 20

n = 80

Answer:

x = 7 would be the correct answer to your question.

I hope this helped! :D

Answer

7, 1

Step-by-step explanation:

do math

Answer:

64/672/882(986)*866772

Answer:

thequantity in column b is greater

Step-by-step explanation:

7a+b=33......(1)

3a-b=7.........(2)

(1)+(2)

7a+b+3a-b=33+7

10a+b-b=40

10a=40

a=4

in equation (1)

7*4+b=33

28+b=33

b=33-28

b=5

b>a

Answer:

320/420 = 4/3

Step-by-step explanation:

4/7= x /560

Cross multiply

7x = 2240

Divide by 7:

x=320

The school has 320 boys and 240 girls

I hope this helps u:)

Answer:

Problem(1):     [tex]21[/tex]

Problem(2):     Side length = [tex]\frac{1}{4}[/tex]    Area = [tex]\frac{1}{16}[/tex]

Problem(3):     Boys = [tex]320[/tex]     Girls = [tex]240[/tex]

Step-by-step explanation:

(Notes steps are cut from this answer so that it isn't too long)

1. Problem (1)

One is given the following information:

The most logical first step is to solve for the value of (x). One can solve for the numerical value of (x) with the first equation.

[tex]x+\frac{1}{x}=5[/tex]

Multiply the entire equation by (x),

[tex]x^2+1=5x[/tex]

Inverse operations put the equation in the general format of a quadratic equation. The general format of a quadratic equation is as follows,

[tex]ax^2+bx+c=0[/tex]

Put the given equation in this format,

[tex]x^2-5x+1=0[/tex]

Now use the quadratic formula to solve for the value of (x). The quadratic formula uses the coefficients of the terms in a quadratic equation to find the roots of the equation. The quadratic formula is as follows,

[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]

Use the coefficients of the terms in the given quadratic equation in the formal, then simplify to solve for solutions of the given equation,

[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(1)(1)}}{2(1)}[/tex]

Simplify,

[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(1)(1)}}{2(1)}[/tex]

[tex]\frac{5(+-)\sqrt{21}}{2}[/tex]

Now substitute these values into the equation and simplify, even though there are two values of (x), there will only be one solution,

[tex]((\frac{5+\sqrt{21}}{2}-\frac{1}{\frac{5+\sqrt{21}}{2}})^2[/tex]                                      [tex]((\frac{5-\sqrt{21}}{2}-\frac{1}{\frac{5-\sqrt{21}}{2}})^2[/tex]  

[tex](\frac{5+\sqrt{21}}{2}-\frac{2}{5+\sqrt{21}})^2[/tex]                                      [tex](\frac{5-\sqrt{21}}{2}-\frac{2}{5-\sqrt{21}})^2[/tex]

Convert to a common denominator,

[tex](\frac{5+\sqrt{21}}{2}*\frac{5+\sqrt{21}}{5+\sqrt{21}}-\frac{2}{5+\sqrt{21}}*\frac{2}{2})^2[/tex]                   [tex](\frac{5-\sqrt{21}}{2}*\frac{5-\sqrt{21}}{5-\sqrt{21}}-\frac{2}{5-\sqrt{21}}*\frac{2}{2})^2[/tex]

[tex](\frac{(5+\sqrt{21})^2-4}{2(5+\sqrt{21})})^2[/tex]                                           [tex](\frac{(5-\sqrt{21})^2-4}{2(5-\sqrt{21})})^2[/tex]

Simplify,

[tex](\frac{25+10\sqrt{21}+21-4}{10+2\sqrt{21}})^2[/tex]                                     [tex](\frac{25-10\sqrt{21}+21-4}{10-2\sqrt{21}})^2[/tex]

[tex](\frac{42+10\sqrt{21}}{10+2\sqrt{21}})^2[/tex]                                              [tex](\frac{42-10\sqrt{21}}{10-2\sqrt{21}})^2[/tex]

[tex]\frac{1764+840\sqrt{21}+2100}{100+40\sqrt{21}+84}[/tex]                                      [tex]\frac{1764-840\sqrt{21}+2100}{100-40\sqrt{21}+84}[/tex]

[tex]\frac{3864+840\sqrt{21}}{184+40\sqrt{21}}[/tex]                                               [tex]\frac{3864-840\sqrt{21}}{184-40\sqrt{21}}[/tex]

[tex]21[/tex]                                                            

2. Problem (2)

All four sides of a square are congruent (have the same measure), thus dividing the perimeter of a square by (4) will yield the side length of the square,

[tex]Perimeter\ of\ the\ square: 4\\Side\ length: \frac{1}{4}[/tex]

The area is the two-dimensional space that a figure takes up, in the case of a square, the area is the side length times itself:

[tex]A=(\frac{1}{4})^2=\frac{1}{16}[/tex]

3. Problem (3)

Let (x) represent the amount by which the ratio of boys to girls was scaled down. Assuming that these are the only two genders in the school, one can state that the sum ratio coefficients times the scaling value for both boys and girls, will equal the total number of people in the school. Thus, one can form the following equation and solve it with inverse operations and simplification,

[tex]boys + girl = total\ students\\4x + 3x = 560\\7x = 560\\x = 80[/tex]

Now substitute this into the expression for the two genders in this scenario, respectively, to solve for the actual number of students of that gender,

Boys,                         Girls,

[tex]4(x)[/tex]                             [tex]3(x)[/tex]

[tex]4(80)[/tex]                           [tex]3(80)[/tex]

[tex]320[/tex]                              [tex]240[/tex]

If 101 is given in base b, then in base 10 you have

[tex]101_b = 1\times b^2 + 0\times b^1 + 1\times b^0 = b^2 + 1[/tex]

For instance, if b = 2, then

101₂ = 2² + 1 = 5₁₀

If b = 3, then

101₃ = 3² + 1 = 9₁₀

If b = 4, then

101₄ = 4² + 1 = 17₁₀

The answer depends entirely on the base of the given number.

Answer:

Hope it helped

Step-by-step explanation:

The restricted domain that makes the given function one to one is (-∞,0] or [0.∞) and the inverse function  would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

An inverse function or an anti function is defined as a function, which can reverse into another function.

Now the given quadtratic function is,

f(x) = x² + 2

Now vertex of the given quadratic function is (0,2)

Thus the range of the function is [2,∞)

If we restrict the domain of this function to either (-∞,0} or [0.∞), it will become one to one function.

Now the inverse function is given as,

y = x² + 2

Upon interchanging x and y, we get:

x = y² + 2

⇒ y² = x - 2

or, y = ±[tex]\sqrt{x-2}[/tex]

Hence, the inverse function would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

Thus, the restricted domain that makes the given function one to one is (-∞,0] or [0.∞) and the inverse function  would be f⁻¹ (x) = [tex]\sqrt{x-2}[/tex] if we restrict the domain of original function to [0.∞) and the inverse function would be  f⁻¹ (x) = -[tex]\sqrt{x-1}[/tex] if we restrict the domain to (-∞,0] .

To learn more about function :

https://brainly.com/question/17210215

#SPJ2

Answer:

(-3,-4)

Step-by-step explanation:

Answer:

C and E

Step-by-step explanation:

[tex]3 \tan( \beta ) = 2. \: \: \: \: \tan( \beta ) = \frac{2}{3} [/tex]

[tex] \frac{h}{x} = \tan( \beta ) = \frac{2}{3} [/tex]

[tex]if \: \: h = 2 \: \: \: x = 3 \: \: \: and \: \: \: t = \sqrt{ {h}^{2} + x } [/tex]

C. [tex]t = \sqrt{13} [/tex] ✅

○♧○♧○♧○♧○♧○♧○♧○♧○♧○♧○♧○

[tex] if \: \: \: h = 4 \: \: \: \: x = 6 \: \: \: and \: \: \: t = \sqrt{ {h}^{2} + {x}^{2} } [/tex]

E. [tex]t = 2 \sqrt{13} [/tex] ✅

Answer:

Reflection is shown in the graph.

Answer:

√2 and √3

Step-by-step explanation:

Answer:

Step-by-step explanation:

√2 and 5√2 are two irrational numbers

√2 * 5√2 = [tex]5*\sqrt{2*2} = 5 * 2 = 10[/tex]

and here 10 is an integer

Answer:

BC = 12

Step-by-step explanation:

23 - (2 + 9)

23 - 11 = 12

BC = 12

Answer:

4

Step-by-step explanation:

4 times 4 is 16. 7 less than 16 is 9.

Answer:

4

Step-by-step explanation:

You can use a simple formula for finding the answer to problems like these. You read it out and put your information in order and use a variable (such as x) in place of the number.

4 * x - 7 = 9

Then solve by getting your variable alone on one side.

Add 7 to both sides: 4 * x = 16

Divide both sides by 4: x = 4

Hi ;-)

[tex]-u+114=262\\\\-u=262-114\\\\-u=148 \ \ /:(-1)\\\\\huge\boxed{u=-148}[/tex]

Answer:

[tex] - u + 114 = 262 \\ u = 114 - 262 \\ u = - 148 \\ thank \: you[/tex]

MACARONI AND AN POT THATS AN WAAAAAPP

Answer:

3,594

Step-by-step explanation:

It is asking *than* which means subtraction. so simply subtract and you get the answer

not hard!