A square has an area of 64 square ft. What would be the measureme of its side? * ​

Answer:

1.7 pounds

Step-by-step explanation:

7.9 - 6.2= 1.7

Answer:

i got B for my answer

Answer:

/_ 12 is the angle of depression from the firefighter to the second story window.

Step-by-step explanation:

Hope it helps!

#CarryOnLearning

Answer:

2nd option is the correct answer

Step-by-step explanation:

[tex] \angle 12[/tex] is the angle of depression from the second story window to the firefighter.

Answer:

 can put this solution on YOUR website!

margin of error is t(0.995 df=67)*s/sqrt(n)

t=2.65

the margin of error is 2.65*885/sqrt(68)=$284.40

Answer:

a. 135 g

b. 60.6 min

Step-by-step explanation:

a. What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.

The chemical equation for the reaction is given below

Cu²⁺(aq) + 2e⁻ → Cu(s)

We find the number of moles of Cu that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 28.5 A and t = time = 4.00 h = 4.00 × 60 min/h × 60 s/min = ‭14,400‬ s

So, n = It/F = 28.5 A × ‭14,400‬ s/96485 C/mol = ‭410,400‬ C/96485 C/mol = 4.254 mol

Since 2 moles of electrons deposits 1 mol of Cu, then 4.254 mol of electrons deposits 4.254 mol × 1 mol of Cu/2 mol = 2.127 mol of Cu

Now, number of moles of Cu = n' = m/M where m = mass of copper and M = molar mass of Cu = 63.546 g/mol

So, m = n'M

= 2.127 mol × 63.546 g/mol

= 135.15 g

≅ 135 g to 3 significant figures

b. How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)?

The chemical equation for the reaction is given below

Au⁺(aq) + e⁻ → Au(s)

We need to find the number of moles of Au in 37.1 g

So, number of moles of Au = n = m/M where m = mass of gold = 37.1 g and M = molar mass of Au = 196.97 g/mol

So, n = m/M = 37.1 g/196.97 g/mol = 0.188 mol

Since 1 mol of Au is deposited  by 1 moles of electrons, then 0.188 mol of Au deposits 0.188 mol of Au × 1 mol of electrons/1 mol of Au = 0.188 mol of electrons

We find the time it takes to deposit 0.188 mol of electrons that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 5.00 A and t = time

So, t = nF/It

= 0.188 mol × 96485 C/mol ÷ 5.00 A

= ‭18173.30‬ C/5.00 A

= 3634.66 s

= 3634.66 s × 1min/60 s

= 60.58 min

≅ 60.6 min to 3 significant figures

Answer:

the answer is d because it's reflects

Answer:

Ok so first he bought the road and pancakes with means he speant 134.85 dollars which mean he out himself in the negatives after he bought the his items

Answer:

It is closer to 1

Step-by-step explanation:

3/4 is 1/4 away from 1, whereas 0 is 3/4 away from 3/4. So, 1 is closer.

The fraction 3/4 is closer to 1.

We have,

To determine whether the fraction 3/4 is closer to 0 or 1, we can compare the distances between 3/4 and 0, and between 3/4 and 1.

The distance between 3/4 and 0 is 3/4.

The absolute value of the difference is |3/4 - 0| = 3/4.

The distance between 3/4 and 1 is 1 - 3/4 = 1/4.

Since the distance between 3/4 and 1/4 (which is 1/4) is smaller than the distance between 3/4 and 0 (which is 3/4), we can conclude that 3/4 is closer to 1 than to 0.

In other words, if we were to plot the fractions 0, 3/4, and 1 on a number line, the distance between 3/4 and 1 would be smaller than the distance between 3/4 and 0.

Therefore,

The fraction 3/4 is closer to 1.

Learn more about fractions here:

https://brainly.com/question/24370499

#SPJ2

Answer:

150°

Step-by-step explanation:

We know each angle in a equilateral triangle is 60° and that of a rectangle is 90° . So ,

[tex]\implies \angle ABC = \angle DBC + \angle ABD \\\\\implies \angle ABC = 90^o + 60^o \\\\\implies \boxed{\boxed{ \angle ABC = 150^o }}[/tex]

Answer:

The slope of these coordinates is 0.

It is a horizontal line.

Step-by-step explanation:

Answer:

[tex]P(Green\ or\ Red) = 0.30[/tex]

Step-by-step explanation:

Given

[tex]White = 40[/tex]

[tex]Green = 24[/tex]

[tex]Red = 12[/tex]

[tex]Yellow = 24[/tex]

[tex]Blue = 20[/tex]

Required

[tex]P(Green\ or\ Red)[/tex]

The total numbe of candy is:

[tex]Total = 40 + 24 + 12 + 24 + 20[/tex]

[tex]Total = 120[/tex]

This probability is calculated as:

[tex]P(Green\ or\ Red) = P(Green) + P(Red)[/tex]

For each, we have:

[tex]P(Green\ or\ Red) = \frac{Green}{Total} + \frac{Red}{Total}[/tex]

Take LCM

[tex]P(Green\ or\ Red) = \frac{Green+Red}{Total}[/tex]

[tex]P(Green\ or\ Red) = \frac{24+12}{120}[/tex]

[tex]P(Green\ or\ Red) = \frac{36}{120}[/tex]

[tex]P(Green\ or\ Red) = 0.30[/tex]

C.) 6x^2-5x+10/x(x-2)

Answer:

Step-by-step explanation:

D beause less then 5 that means it gose down the grid

Answer:

<3=105°

Step-by-step explanation:

The angle directly to the right of the 75° angle is 105°, as the angles along a straight line add to 180.

<3=105° because they are corresponding angles

Answer:

Solution given:

<3+75=180[co- interior angle]

<3=180°-75°=105°

<3=105°

Answer:

1.

mean= 84.6

median=84

mode=84

2.

mean=10.14

median=9

mode=9

3.

mean=22.3

median=21

mode=phi

Step-by-step explanation:

mean: the sum of of the quantities by their number

median: the median value after rearranging the values

mode: the value that occurs most frequently

in the second question

mean = (8+9+9+9+9+10+11+15)/8

median(even number) =(9+9)/2=9

mode=9

Answer:

for data set 1

1.mean-84.6

2.median-(84+84)/2 = 84

3.mode-84

for data set 2

1.mean-9.25

2.median-(9+9)/2 = 9

3.mode-9

for data set 3

1.mean-22.3

2.median-21

3.mode-no mode with this data set

hope this helped!!

Answer:

Im pretty sure its 130%

Step-by-step explanation:

Answer:

1/3 * 84 = 28 were under 25

2/7 * 84 = 24 were at least 50

28 + 24 = 52

84-52 = 32 were between 25 and 50

Step-by-step explanation:

Answer:

Weight before 18 month = 18 pound

Step-by-step explanation:

Given:

Current weight of dog = 14 pound

Weight lose each month = 2/9 pound

Total number of month = [tex]1\frac{1}{2}[/tex] year = 18 month

Find:

Weight before 18 month

Computation:

Total weight lose = Weight lose each month x Total number of month

Total weight lose = 2/9 x 18

Total weight lose = 4 pound

Weight before 18 month = Current weight of dog + Total weight lose

Weight before 18 month = 14 + 4

Weight before 18 month = 18 pound

Answer:

no correlation

Step-by-step explanation:

it shows no trend or a line thing

also i think your pic is upside down haha

Answer:

Here, the test statistics ( 20.951 ) is greater than the critical value ( 7.815 )

Therefore, we reject H₀ at 0.05 level of significance.

Hence, there is significant evidence to support the claim that In this community, vehicle ownership distribution is NOT like that of all U.S household

Step-by-step explanation:

Given the data in the question;

Number of vehicle owned                 Number of households

0                                                             20

1                                                              35

2                                                             23

3 or more                                               22

Total ( n )                                               100

so

Null hypothesis           H₀ : In this community, vehicle ownership distribution is like that of all U.S household

Alternative hypothesis Hₐ : In this community, vehicle ownership distribution is NOT like that of all U.S household

Also given that, ∝ = 0.05

Now, we compute the test statistics;

x² = ∑[ ( O[tex]_i[/tex] - E[tex]_i[/tex] ) / E[tex]_i[/tex] ]

where E[tex]_i[/tex] is expected frequency and O[tex]_i[/tex] is observed frequency.

so we make our table for chi square test statistics

No. of                 O[tex]_i[/tex]            P                E[tex]_i[/tex]            (O[tex]_i[/tex] - E[tex]_i[/tex])²             (O[tex]_i[/tex] - E[tex]_i[/tex])²/E[tex]_i[/tex]

Vehicle                                              (n×P)

owned

0                        20         0.087          8.7            127.69                 14.677

1                         35         0.331           33.1            3.61                     0.109

2                        23         0.381           38.1           228.01                 5.985

3 or more          22         0.201          20.1           3.61                      0.180

Total                  100                           100                                        20.951

hence, x² = 20.951

Now, degree of freedom df = k - 1 = 4 - 1 = 3

From Chi-Square critical value table; ( right tailed test ) for ∝ = 0.05

[tex]x_{0.05, 3[/tex] = 7.815

Decision Rule

Reject H₀ if x² is greater than xₐ².

Here, the test statistics ( 20.951 ) is greater than the critical value ( 7.815 )

Therefore, we reject H₀ at 0.05 level of significance.

Hence, there is significant evidence to support the claim that In this community, vehicle ownership distribution is NOT like that of all U.S household

Answer:

sorry I donot know the answer never mind ok

Answer:

4

Step-by-step explanation:

Answer:

2,1,0 is the sequence of its terms

Answer:

The 3rd one

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

=============================================================

Explanation:

Multiply out those values mentioned to get the final answer: 3*3*2 = 9*2 = 18.

There are 18 different outfit combos.

---------------

Further explanation (optional section):

Let's say we only worried about the sweaters and shoes, and for now there's only one color for the skirt. We have 3 colors for the sweaters and 2 for the shoes. Imagine a table with 3 rows and 2 columns. Each row is a different color for the sweater and each column is a different color for the shoe. There are 3*2 = 6 cells inside the table. Each cell is a different outfit.

For instance, we could have R = red sweater and G = gold shoe. Then that means RG = red sweater + gold shoe outfit. So we'd have RG as one of the cells of this 6 cell table.

Now imagine that we laid out a table that is 6 by 3. The 6 is from the 6 outfits calculated earlier, and the 3 is now accounting for the colors of the skirts. We'd then have 6*3 = 18 combos total. Again, each cell inside the table represents a different outfit combo.

Here's the solution,

By using Trigonometry :

=》

[tex] \sin(30) = \dfrac{7}{x} [/tex]

=》

[tex] \dfrac{1}{2} = \dfrac{7}{x} [/tex]

=》

[tex]x = 14[/tex]

hence, the value of x = 14 units

Answer:

14

Step-by-step explanation: