A stone dropped from a bridge strikes the water 5.6 seconds later. What is the final velocity in meters/s?
A) 179.78 meters/s
B) 5.71 meters/s
C) 1.75 meters/s
D) 54.88 meters/s

Answer:

D

Explanation:

Gravity is always having an effect on every object on earth, whether or not its moving.

Answer:

The value is  [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

Explanation:

From the question we are told that

     The mass of the object is  [tex]m_1 = 5.0 \ g = 0.005 \ kg[/tex]

     The net charge is  [tex]q = 3.8 \mu C= 3.8 *10^{-6} \ C[/tex]

     The mass of the second object is   [tex]m_1 = 2.0 \ g = 0.002 \ kg[/tex]

Generally for the first object the potential energy gained at the end of its acceleration is equal to its  kinetic energy

i.e

            [tex]\frac{ 1}{ 2} * m_1 * v^2_1 = q_1 * \Delta V \ \ --- (1)[/tex]

Here [tex]v_1[/tex] is the velocity of the first object

        [tex]\Delta V[/tex] is the potential difference through which it is accelerated  

Generally for the second object the potential energy gained at the end of its acceleration is equal to its  kinetic energy

i.e

            [tex]\frac{ 1}{ 2} * m_2 * v^2_2 = q_2 * \Delta V[/tex]

Here [tex]v_2[/tex] is the velocity of the second object and from the question it is

        [tex]v_2 = 2 v_1[/tex]

        [tex]\Delta V[/tex] is the potential difference through which it is accelerated        

So

          [tex]\frac{ 1}{ 2} * m_2 * (2v)^2_1 = q_2 * \Delta V[/tex]

=>        [tex]m_2 * 2v^2_1 = q_2 * \Delta V \ \ ---(2)[/tex]

Generally dividing equation 2 by equation 1

            [tex]\frac{2m_2 v^2_1 }{ \frac{1}{2} * m_1 * v_1^2} = \frac{q_2 \Delta V }{ q_1 * \Delta V}[/tex]

=>         [tex]q_2 = \frac{4m_2 * q_1 }{m_1}[/tex]

=>         [tex]q_2 = \frac{4* 0.002 * 3.8 *10^{-6} }{0.005}[/tex]

=>         [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

=>         [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

Answer:

Vs/c = 20 [m/s]

Explanation:

This is a problem of relative velocities, as velocity is a vector we can use addition or subtraction of vectors for the solution.

We are asked for the velocity of the sailboat with respect to an observer located in the canoe.

[tex]V_{s/c}=V_{sailboat}-V_{canoe}\\V_{s/c}=15-(-5)\\V_{s/c}=20[m/s][/tex]

Why is the speed of the canoe negative?, it is negative because the canoe moves in the opposite direction to the sailboat.

Answer: so it can reach the frame

Explanation:

Answer:

To increase force on the door

Answer:

A.reduce by 4.

Explanation:

In Chemistry, an alpha particle which is typically a helium nucleus has an atomic mass (number of nucleons) of four (4). Therefore, the ejection of an alpha particle by any chemical element simply means that, the mass number of that particular chemical element would be reduced by four (4).

Basically, this process is referred to as an alpha decay and can be defined as a radioactive disintegration of a chemical element that causes it to emit an alpha particle and as a result reducing its mass number by four (4).

Hence, when an element ejects an alpha particle, the mass number of that element reduces by 4.

Answer:

The value is  [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]

Explanation:

From the question we are told that  

    The maximized electric field strength is  [tex]E = 3.0 \ MV/m = 3.0 *10^{6} \ V/m[/tex]

     The diameter is  [tex]d = 1.5\ cm = 0.015 \ m[/tex]

Generally the cross -sectional area is mathematically represented as

 =>      [tex]A = \frac{\pi * d^2 }{4}[/tex]

 =>      [tex]A = \frac{3.142 * 0.015^2 }{4}[/tex]

 =>      [tex]A = 0.0001767 \ m^2[/tex]

Generally the maximum power is mathematically represented as

       [tex]P_{max} = \frac{E_{max}^2}{ 2 * \mu_o * c } * A[/tex]

Here c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

        [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4 \pi *10^{-7} \ H/m[/tex]

      [tex]P_{max} = \frac{ (3.0 *10^{6})^2}{ 2 * (4 \pi *10^{-7}) * 3.0 *10^{8} } * 0.0001767[/tex]

=>   [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]

The maximum power that can be delivered by a laser beam propagating through air is equal to [tex]2.11 \times 10^6\;Watts[/tex]

Given the following data:

Radius = [tex]\frac{Diameter}{2} = \frac{0.015}{2} = 0.0075\;meter[/tex]

Scientific data:

To determine the maximum power that can be delivered by a laser beam propagating through air:

First of all, we would solve for the area of the laser beam as follows:

[tex]Area = \pi r^2\\\\Area = 3.142 \times 0.0075^2\\\\Area = 3.142 \times 0.00005625\\\\Area = 1.77 \times 10^{-4}\;m^2[/tex]

Now, we can determine the maximum power that can be delivered by a laser beam:

Mathematically, maximum power is given by the formula:

[tex]P_{max} = \frac{AE_{max}^2}{2 \mu_o c}[/tex]

Substituting the given parameters into the formula, we have;

[tex]P_{max} = \frac{1.77 \times 10^{-4} \;\times \;(3 \times 10^6)^2}{2 \;\times \;1.25663706 \times 10^{-6} \; \times \;3 \times 10^8}\\\\P_{max} = \frac{1.77 \times 10^{-4} \;\times \;9 \times 10^{12}}{753.982236}\\\\P_{max} = \frac{1593000000}{753.982236}\\\\P_{max} = 2.11 \times 10^6\;Watts[/tex]

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Answer: D.

Explanation:

d = ± √ G m 1 m 2 /F

 Because distance cannot be negative there it goes:

d = √ G m 1 m 2 /F

d = √ 6.67 ⋅ 10 − 11 ⋅ 1050 ⋅ 1050 2.27 ⋅ 10 − 7

d = √ 0.0000735 2.27 ⋅ 10 − 7  

d = √ 3239504.405

d ≈ 1799.86 m = 18m

Answer:

Answers at the bottom!!

Explanation:

For the first answer: Gamma ray

Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.

For the second answer: They both have technological uses.

In my opinion I'm pretty sure it's A because we do use microwaves and x-rays as technological uses.

Hope this helps!!

Happy Holidays and Season Greeting!!

ii Feliz Navidad a todos !!

Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.

"A gamma ray (g) is a packet of electromagnetic energy (photon) emitted by the nucleus of some radionuclides following radioactive decay." Gamma photons are the most energetic photons in the electromagnetic spectrum.

"An X-ray, or, much less commonly, X-radiation, is a penetrating form of high-energy electromagnetic radiation." Most X-rays have a wavelength ranging from 10 picometers to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz and energies in the range 145 eV to 124 keV.

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They both have technological uses.

Microwaves and x-rays have in common is all electromagnetic waves, electric and magnetic fields that oscillate together, perpendicular to each other.

"The application of practical sciences to industry or commerce." The methods, theory, and practices governing such application. a highly developed technology.  The total knowledge and skills available to any human society for industry, art, science, etc.

Microwaves are used in spacecraft communication, and much of the world's data, TV, and telephone communications are transmitted long distances by microwaves between ground stations and communications satellites. Microwaves are also employed in microwave ovens and in radar technology.

They are used on such products as aircraft and rocket parts and structures, canned and packaged foods, electronics, semiconductors and microchips, thermal insulations, and automobile tires. Material processing technologies use X-ray systems to automatically control the density or thickness of layers of substances.

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Answer:

See the explanation below.

Explanation:

According to the law of energy conservation. This can be transformed from potential energy to kinetic or vice versa.

For example, when you have a body at rest at a height with respect to the ground level, this body possesses potential energy with respect to the ground, but the moment that the body falls the potential energy decreases as it loses height with respect to the ground, but as the potential energy decreases, the kinetic energy increases, that is to say, the potential energy is transformed into kinetic energy as the body is falling.

As the energy relationship is maintained we can say that the potential and kinetic energies are equal.

[tex]E_{pot}=m*g*h\\E_{kin}=\frac{1}{2} *m*v^{2} \\E_{pot}=E_{kin}[/tex]

Answer:

The new angular speed of both disks when they are rotating together is 2.311 revolutions per second.

Explanation:

This situation can be analyzed by the Principle of Conservation of Angular Momentum since there are no external forces and moments being exerted on the system, whose definition is presented below:

[tex]I_{o}\cdot \omega_{o} = I_{f}\cdot \omega_{f}[/tex] (1)

Where:

[tex]\omega_{o}[/tex], [tex]\omega_{f}[/tex] - Initial and final angular speeds, measured in revolutions per second.

[tex]I_{o}, I_{f}[/tex] - Initial and final moments of inertia, measured in kilograms per square meter.

The initial and final moments of inertia of the system are, respectively:

[tex]I_{o} = \frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}[/tex] (2)

[tex]I_{f} = \frac{1}{2}\cdot \left[m_{o}\cdot r_{o}^{2}+\frac{1}{2}\cdot m_{o}\cdot \left(\frac{1}{2}\cdot r_{o} \right)^{2}\right][/tex]

[tex]I_{f} = \frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}+\frac{1}{16}\cdot m_{o}\cdot r_{o}^{2}[/tex]

[tex]I_{f} = \frac{9}{16}\cdot m_{o}\cdot r_{o}^{2}[/tex] (3)

By applying (2) and (3) in (1), we obtain the following expression:

[tex]\frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}\cdot \omega_{o} = \frac{9}{16}\cdot m_{o}\cdot r_{o}^{2}\cdot \omega_{f}[/tex]

[tex]\frac{1}{2}\cdot \omega_{o} = \frac{9}{16}\cdot \omega_{f}[/tex]

[tex]\omega_{f} = \frac{8}{9}\cdot \omega_{o}[/tex] (4)

If we know that [tex]\omega_{o} = 2.6\,\frac{rev}{s}[/tex], then the new angular speed of both disks when they are rotating together is:

[tex]\omega_{f} = \frac{8}{9}\cdot \left(2.6\,\frac{rev}{s} \right)[/tex]

[tex]\omega_{f} = 2.311\,\frac{rev}{s}[/tex]

The new angular speed of both disks when they are rotating together is 2.311 revolutions per second.

its A or D but im not sure which one ik it moves fast

Answer:

gimmie

Explanation:

Given :

Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal.

To Find :

How long is it in the air.

Solution :

We know, the formula of time of flight is :

[tex]T = \dfrac{2usin\ \theta}{g}\\\\T = \dfrac{2\times 30\times sin\ 30^o}{9.8}\\\\T = 3.06\ seconds[/tex]

Therefore, the ball is in air for 3.06 seconds.

Answer:

50 km/h

Explanation:

200 km = 4 hours

200/4=50

50km/h

Answer: It states that for every action, there is an equal and opposite reaction.

I hope this helps, and Happy Holidays! :)

Answer:

2.94 m/s²

3.43 N

Explanation:

To start with, the combination of rotational and translational kinetic energy can be converted to gravity potential energy. So, we will apply this in solving our question.

PE = KE

mgh = ½mv² + ½Iω²

Moment of inertia of a hollow sphere

I = ⅔mr²

We also know that,

ω = v/r, so if we substitute for ω and I, we have

mgh = ½mv² + ½(⅔mr²)(v/r)², simplifying

gh = ½v² + ½(⅔r²)(v/r)², simplifying further

gh = ½v² + ⅓v², adding up

gh = (5/6)v², making h subject of formula

h = 5v²/6g

Now, we substitute for v and g to have

h = 5(2.63)² / 6(9.81)

h = 34.585 / 58.86

h = 0.588 m

To get the distance that the ball rolls on the ramp before stopping, we say

d = 0.588 / sin30.0

d = 0.588 / 0.5

d = 1.176 m

so acceleration is

a = (2.63² - 0²) / 2(1.176)

a = 6.917 - 0 / 2.352

a = 2.94 m/s

B

Neglecting friction, the sphere acts like a point mass and tends to rise.

mgh = ½mv², simplifying

h = v²/2g

h = 2.63² / 2(9.81)

h = 6.917 / 19.62

h = 0.353 m

The work done by the friction force is the same as the rotational kinetic energy of the sphere, so we say

U = KEr

Fd = ½Iω²

Fd = ½(⅔mr²)(v/r)²

Fd = ⅓mv²

F = mv²/3d

where d is the actual distance up the slope the sphere did roll.

The average friction force is thus

F = 1.75(2.63)² / 3(1.176)

F = 1.75 * 6.917 / 3.528

F = 12.1 / 3.528

F = 3.43 N

Answer: The correct answer is C

Explanation:

Answer:

D 2

Explanation:

Given that

Distance of the object, u = 10 cm

Focal distance of the object, f = 20 cm

Then again, we know from the lens formula that

1/f = 1/u + 1/v

Then we solve for the distance of the image, v

1/20 = 1/10 + 1/v

1/v = 1/20 - 1/10

1/v = (1 - 2) /20

1/v = -1/20

v = -20 cm

Lateral magnification is given as

m = -v/u,

So we input our values

m = - -20/10

m = 20/10

m = 2

Answer:

F = 6[N].

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

[tex]P=m*v\\or\\P=F*t[/tex]

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 10 [kg]

v = velocity [m/s]

F = force [N]

t = time = 5 [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the object = 10 [kg]

v₁ = velocity of the object before the impulse = 1 [m/s]

v₂ = velocity of the object after the impulse = 4 [m/s]

[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]

Answer:

18.392 N

Explanation:

Given that,

Smaller force acting on the car, F₁ = 3.8 N

Radius of smaller radius, r₁ = 10 cm = 0.1 m

The radius of the larger piston, r₂ = 0.22 m

We need to find the force exerted on the larger piston. Let it is F₂.

Using the relation,

[tex]\dfrac{F_1}{F_2}=\dfrac{A_1}{A_2}\\\\\dfrac{F_1}{F_2}=\dfrac{\pi r_1^2}{\pi r_2^2}\\\\\dfrac{F_1}{F_2}=\dfrac{r_1^2}{r_2^2}\\\\F_2=\dfrac{F_1r_2^2}{r_1^2}\\\\F_2=\dfrac{3.8\times (0.22)^2}{(0.1)^2}\\\\F_2=18.392\ N[/tex]

Hence, the force exerted on the larger piston is 18.392 N.

Answer:

Thx for points merry Christmas answer 2

Explanation:

Answer:2

Explanation:

Answer:

52.095 m/s

Motorcycle a was moving faster

Explanation:

We start by using one of the equations of motion

V = u + at

If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as

V(a) = u(a) + a(a).t

If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as

V(b) = u(b) + a(b).t

Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have

0 = u(a) - u(b) + a(a).t - a(b).t

-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have

u(b) - u(a) = [a(a) - a(b)]t

Since we have the values for acceleration and the time, we substitute so that

u(b) - u(a) = (4.55 - 18.9)3.63

u(b) - u(a) = -14.35 * 3.63

u(b) - u(a) = -52.095, or we rearrange to get

u(a) - u(b) = 52.095 m/s

Answer:

The value is [tex]T_2 =416.9 \ K[/tex]

Explanation:

From the question we are told that

     The mass of the aluminum baking sheet is  [tex]m = 225 \ g = 0.225 \ kg[/tex]

      The energy absorbed is [tex]E = 2.4 *10^{4} \ J[/tex]

       The initial  temperature is  [tex]T_1 = 25 ^oC = 25 + 273 = 298 \ K[/tex]

Generally the heat absorbed is mathematically represented as

         [tex]Q = m * c_a * [T_2 - T_1][/tex]

Here  [tex]c_a[/tex] is the specific heat capacity of  aluminum with value  [tex]c_a = 897 \ J / kg \cdot K[/tex]

So

           [tex]2.4 *10^{4 } =0.225 * 897 * [ T_ 2- 298][/tex]

=>         [tex]T_2 - 298 = 118.915[/tex]

=>          [tex]T_2 =416.9 \ K[/tex]

[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

[tex] \underline{\green{\large \sf For\: example :}} [/tex]

[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

Answer:

B, electrons.

Explanation:

An electrical charge is created when electrons are transferred to or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.

Answer:

answer is a very large amount of energy is produced from a very small mass

Explanation:

nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)

Answer:

a = 0.1 m/s²

Explanation:

       [tex]F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)[/tex]

       [tex]F_{net} = m* a = 300 Kg * a = 30 N (2)[/tex]

        [tex]a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)[/tex]

Answer:

b.

Explanation:

The resulting wave pattern when the centers of the two pulses meet is undergo constructive interference.

Waves are pulses of energy that propagate through space periodically. When two waves overlap in the same region of space, interference occurs, which results in another wave with different intensity. These variations in the intensity of the resulting wave are called interference fringes.

The two pulses propagate with the same phase and in opposite directions, when they meet, they suffer constructive interference, which will cause the sum of the amplitudes. After interference, each wave goes its way as if nothing happened.

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