A stone is released from a height of 80m above the ground. Calculate its velocity just before it strikes th ground​

Answer:

(A)   9.2 Newtons

(B)   200.8 Newtons

Explanation:

Attached is the free body diagram I drew along with some of the work/formulas I used. Please ask me any questions you have in the comments about my diagram/work. I'd be happy to walk you through it.

The magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.

Magnitude is a measure of the size or intensity of a physical quantity. It is usually defined as the absolute value of the numerical value of the physical quantity, and is often expressed in terms of a unit of measurement. Magnitude can refer to a variety of different physical quantities, such as size, intensity, brightness, or energy. Magnitude can also refer to the relative size or intensity of two or more physical quantities, when compared to each other.

The resultant force on the horizontal gate is equal to the sum of the hydrostatic forces acting on the gate.
Since the gate is horizontal, the hydrostatic forces acting on the gate will be equal to the pressure difference between the top and bottom of the gate.
This pressure difference is equal to the product of the fluid density, gravitational acceleration, and the gate width.
Therefore, the magnitude of the resultant force on the gate will be:
F = w * r * g
The location of the resultant force on the gate will be at the center of the gate, which is point A.
Therefore, the magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.

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All galaxies outside the Local Group are moving away from us, and the farther away they are, the faster they're going.

We may learn a lot about the nature of the cosmos from Hubble's rule, which states essentially that a known universe velocity (or, as it is commonly displayed, its redshift) is precisely proportionate to its distance. The relationship between distance and speed should not exist if the cosmos is constant and unchanging.

The Hubble-Lemaître law, commonly referred to as Hubble's law, is the finding in astrophysics that planets are eloping from Earth at rates proportionate to their separation. In other words, they are travelling away from Earth more quickly the more away they are.

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Three helium-4 nuclei (alpha particles) are turned into carbon by a series of nuclear fusion processes known as the triple-alpha process.

What results from the triple-alpha procedure as the finished product?

The triple-alpha process and the alpha process are two classes of nuclear fusion reactions that stars use to change helium into heavier elements. The alpha process is also referred to as the alpha ladder. [1] Only helium is used in the triple-alpha process, which also yields carbon.

Which statement concerning alpha particles in an atom is accurate?

Two protons and two neutrons make up alpha particles, which are identical to helium nuclei and have a positive charge.

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Answer: Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.Substituting the values in, we get:F=100*(0.65-0.5)=100*0.15=15N

The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.

To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.

Now, we know that momentum =mass × velocity

So, initial momentum of first object=6.2×3=18.6Kg-m/sec

Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec

Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg

Now, both objects are moving with common velocity, so assume both have velocity v

=>So, final momentum of both objects is =14.2×v

according to law of conservation of momentum

=>18.6+25=14.2v

=>43.6=14.2v

=>v=43.6/14.2

=>v=3.07m/sec

Hence, final velocity of objects are 3.07m/sec.

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The final temperature of the piece of iron with the mass of 9.8 grams on the absorption of 365J of energy is 113.56°C.

The specific heat capacity of a material can be defined as the quantity of heat energy (J) which is absorbed per unit mass (kg) of the material when its temperature is increased by 1 K (or 1 °C). The SI unit of specific heat capacity is J/(kg K) or J/(kg °C).

The specific heat capacity of a material can be calculated by the formula:

Q = m × c × ΔT

where, Q = heat energy,

m = mass of the material,

c = specific heat capacity,

ΔT = change in temperature

The final temperature of the piece of iron can be calculated by the formula:

Q = m × c × ΔT

ΔT = (Final temperature - initial temperature)

365J = 9.8 × 0.46 × ΔT

365J = 4.508 × ΔT

ΔT = 80.96

ΔT = Final temperature = initial temperature

ΔT = (T - 32.6)

80.96 = (T - 32.6)

T = 80.96 + 32.6

T = 113.56°C

Therefore, the final temperature of the piece of iron is 113.56°C.

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Explanation:

If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.

Answer:

Explanation:

Fg = W = mg = (5.0 kg)(9.8 m/s²) = 49 N

Fnormal = W = 49 N

Ff = μFn = (0.10)(49 N) = 4.9 N

Fnet = 15 N - 4.9 N = 10.1 N

a = Fnet/m = (10.1N)/(5.0kg) = 2.02 m/s²

Let us find first the forces at 1, 2 & 3 points.

We know that ke= 8.99 * 109N.m2 / C2

The forces are: -

F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2

F1 = 359.6 N

F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2

F2 = 29.96 N

F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2

F3 = 269.7 N

Now,

The net force on q1 is F1 – F2,

i.e. F1 + F2 = 359.6 + 29.96

F(q1) = 389.56 N to the left

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The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:

Mass flow rate = Density * Flow rate

= Density * (Area * Velocity)

Where:

Density is the density of the fluid

Flow rate is the volume flow rate, or the rate at which volume flows through the pipe

Area is the cross-sectional area of the pipe

Velocity is the velocity of the fluid

The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.

The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:

A = pi * r^2

Where:

A is the cross-sectional area of the pipe

r is the radius of the pipe

The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:

A = pi * (1.5 cm)^2

= 7.07 cm^2

The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:

A = pi * (3 cm)^2

= 28.27 cm^2

Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:

(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)

Solving for v, the velocity on the narrow side, you get:

v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)

= 11.6 m/s

The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

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The second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.

To determine the location of the second weight that will keep the meter stick balanced, we need to consider the principles of equilibrium.

The weight of the meter stick can be calculated as follows:

Weight of meter stick = mass * acceleration due to gravity

= 24 g * 9.8 m/s^2

= 235.2 N

The total weight of the two hanging weights is 96 g + 96 g = 192 g = 1.92 N.

The sum of the forces acting on the meter stick is equal to zero when:

235.2 N + 1.92 N = 0

This equation tells us that the sum of the forces acting on the meter stick is equal to zero when the total weight of the two hanging weights is equal to the weight of the meter stick.

To determine the location of the second weight, we also need to consider the moments about the pivot point. The moment of a force is calculated as the product of the force and the distance from the pivot point. The moments about the pivot point are equal to zero when the sum of the moments of the forces on one side of the pivot point is equal to the sum of the moments of the forces on the other side of the pivot point.

The moment of the weight of the meter stick about the pivot point is calculated as follows:

Moment of the weight of meter stick = force * distance from pivot point

= 235.2 N * 0.4 m

= 94.08 N*m

The moment of the weight hanging from the 9 cm mark about the pivot point is calculated as follows:

Moment of weight hanging from 9 cm mark = force * distance from pivot point

= 1.92 N * 0.09 m

= 0.1728 N*m

To keep the meter stick balanced, the moment of the second weight must be equal in magnitude but opposite in direction to the moment of the weight hanging from the 9 cm mark. The moment of the second weight can be calculated as follows:

Moment of second weight = force * distance from pivot point

= 1.92 N * distance from pivot point

Substituting the value of the force and setting the moment equal to the negative of the moment of the weight hanging from the 9 cm mark, we get the following equation:

1.92 N * distance from pivot point = -0.1728 N*m

Solving for the distance from the pivot point, we find that the second weight must be located at a distance of 0.09 m from the pivot point, or 9 cm. This is the same distance from the pivot point as the weight hanging from the 9 cm mark.

Therefore, the second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.

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The new gravitational force between the object will be 1/20.25 times of the original force.

The gravitational force between any two object is defined as the product of the masses of the object and it is inversely proportional to the square of the distance between them which is given by,

F = GMm/R²

Here,

G is the universal gravitational constant, M and m are the mass of the body and R is the distance between them.

As per the given question the distance between the object is increased 4.5 times the original separation.

R' = 4.5R.

The new force of attraction between the object will be,

F' = GMm/(R')²

F' = GMm/(4.5R)²

F' = GMm/20.25R²

F' = F/20.25

So, the new force of attraction between the two objects will become 1/20.25 times of original force.

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(a) The normal force is 267.7 N and frictional force is 980 N.

(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.

(c) The direction of the contact force is 1016 N.

∈(t) = 0

N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )

N₂ = 267.7 N

(a) Normal force F(d) = N₂ = 267.7 N

Frictional force N = 800 + 180

                         N = 980 N

(b) The minimum coefficient of static friction,

F(d) = μ N₁

μ = F / N₁

μ = 267.7 / 980

μ = 0.27

(c) The direction of the contact force,

R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]

R = 1016 N

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The required values are a) T = 2.3 seconds, b)  f = 0.434 Hz, c) ω = 2.7 rd/s.

Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.

Given,

Time = 11.5 seconds to five complete vibrations.

a) Time period is time taken to complete one vibration,

So T = 11.5/5 = 2.3 seconds

b) Frequency(f) = 1/T

f = 1/2.3 = 0.434 second inverse.

c) By using formula of angular frequency ω = 2π/T

ω = 2π/2.3 = 2.7 hz

Thus, final values are a) T = 2.3 seconds, b)  f = 0.434 second inverse, c) ω = 2.7 rd/s.

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The heater needs to provide 540 W of power just to make up for the heat lost through this one wall.

Styrofoam is a trademarked brand of foam insulation and craft material manufactured by the Dow Chemical Company. It is made from expanded polystyrene (EPS) beads that are fused together with steam and pressure. EPS is a lightweight and rigid material that is used for insulation, packaging, and soundproofing. Its properties make it an ideal material for crafting, floristry, model building, and other art projects. Styrofoam is stable in most environments and is resistant to water, oil, and most chemicals. It can be cut, shaped, and painted easily and is an excellent thermal insulator. In addition, it is also non-toxic and non-carcinogenic, making it a safe and economical choice for many applications.

Assuming that the wall is a perfect insulator, the heater will have to provide enough power to make up for the heat lost due to conduction and convection. The rate of heat loss per unit area is given by:

Q = λ*A*(T2 - T1)/d
Where:
λ = thermal conductivity of styrofoam (see table above)
A = Area of wall (3*3) = 9 m2
T2 = Temperature inside the house (25C)
T1 = Temperature outside the house (0C)
d = thickness of styrofoam insulation (2.5 cm)

Plugging in the values we get:
Q = 0.045*9*(25-0)/0.025 = 540 W
Therefore, the heater needs to provide 540 W of power just to make up for the heat lost through this one wall.

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Mass of the fertilizer bag is 165.82 kg

According to Newton's law,

F = m*a

So, m= F/a

m= 131/0.790

m= 165.82 kg

Mass is the measure of matter of a body.

Newton has stated three laws of motion. The first law states that every object will remain at rest or in uniform motion in a straight line unless an external force compels it to change its state of action .

The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.

The third law states that every action has an equal and opposite reaction.

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Answer:

None of the choices you provided are correct. When a gas burns, it releases energy in the form of heat and light. Some of this energy is transferred to the pot of water, increasing its temperature, but some of the energy is also released as light. However, the rest of the energy is not transformed into chemical, electrical, or nuclear energy. Instead, it is lost to the environment in the form of waste heat. This is why gas stoves can become hot to the touch - they are releasing excess energy in the form of heat that is not being used to heat the pot of water.

Explanation:

The kind of spring should be held constant so as to improve the validity of the experiment.

Hooke's law states that the force that acts on a spring is directly proportional to the extension of the spring as long as the elastic limit is not exceeded.

As such, we can now understand that we can only be able to talk about the Hooke's law if there is no way in which the material has passed the elastic limit of the material. In this case, we are told that the students just embarked on a kind of experiment and they want to be able to verify the validity of the Hooke's law.

We saw that the masses that were hanged were increased but the springs were also changed. This would not allow us to determine the force constant and the Hooke's law accurately.

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4.71 s long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot.

The average position of an object's weight is known as its center of gravity. Any object's travel through space may be entirely explained in terms of how its gravitational center moves from one location to another and, if it is free to spin, how it rotates around that center of gravity. Calculations combining gravitation and dynamics may be made much simpler by treating an object's mass as though it were concentrated at a single location.

T=2π√(l/g)

T=2π√(5.53/9.81)

T=4.71

T =4.71 s

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Answer:

Here is answer

Explanation:

a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.

b) The characteristics of the weight of solid 'S' are:

It acts in the downward direction.

It is a gravitational force that is exerted by the Earth on the solid 'S'.

It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).

c) The weight of solid 'S' can be represented by a vector as shown below:

[asy]

unitsize(1cm);

draw((0,0)--(0,15),Arrow(6));

label("$W$", (0,7.5), W);

[/asy]

a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.

b) These forces can be represented by vectors as shown below:

[asy]

unitsize(1cm);

draw((0,0)--(0,15),Arrow(6));

label("$W$", (0,7.5), W);

draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));

label("$N$", (7.5sqrt(2),7.5), NE);

draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));

label("$F_f$", (-7.5sqrt(2),-7.5), SW);

[/asy]

c) The characteristics of these forces are:

The normal force acts perpendicular to the surface of the inclined plane.

The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.

The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.

The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.

a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.

b) The characteristics of the gravitational force are:

It acts in the downward direction.

It is a force that is exerted by the Earth on the solid 'S'.

Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):

[asy]

unitsize(1cm);

draw((0,0)--(0,-1.3),Arrow(6));

label("$W$", (0,-0.65), S);

[/asy]

To keep the car from slipping, the road and tires need to have a minimum coefficient of friction of 0.188.

The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, but it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible. Yes. Because the adhesive forces between molecules are stronger when the contact surface is substantially polished, frictional force increases. In this situation, the friction coefficient will be higher than one.

Here m= 1402 kg

r=53

v= 9.9 m/s

g=9.8

coefficient = (v^2) / rg

coefficient = (9.9^2) / (53*9.8)

coefficient = 98.01/519.4

coefficient = 0.188

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Answer:

x = A cos ω t          at t = zero, x displacement equals amplitude

x = .088 m cos ω t             describes the motion

We need yet to find ω in terms of P which is given

ω = √(k / m)        

P = 1 / f      and f = ω / (2 π)

Thus ω = 2 π f = 2 π / P       since 1 / f = P

This gives us

x = .088 m cos 2 π / .66 * t    

The correct expression for the resulting velocity is -1/2 vcar. The correct option is c.

The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.

A car travels down a road at a certain velocity, is Vcar.

Let the initial velocity of the car travel downward be -V car

It is also, given, that the driver slows down so that the car is traveling only half as fast as before.

Resulting velocity = -1/2 vcar

Therefore, the correct option is c. -1/2vcar.

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A tension of 3.5 to 4.5 is advised when sewing tough fabric, such denim or leather. This allows you to effortlessly maintain neatness across the fabric when sewing through it. Before starting to sew any thick material, check the attachments on your sewing machine and adjust the tension.

Depending on the thickness of the denim, I use a straight-stitch length between 3.0 mm and 4.0 mm. I also increase the tension on my machine to 4.6 (up from 4.0 for lightweight woven fabrics). If my denim has spandex in it, I use a stretch stitch, such as a narrow zigzag.

Linen, cotton and denim: These fabrics hold wrinkles well, so they require the highest heat, from 150 to 200 degrees. If needed, you may also use steam or spray water from a bottle or your iron.

The longer the stitch length, the easier and faster it will be to pull the fabric along the gathering threads. However, the shorter the stitch length, the easier it will be to achieve even gathers. We find a 4.5 mm setting to be a good compromise, but it's always a good idea to test and see what you prefer.

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The required force is F = 3240 N.

As a result,

1200 kg is the car's mass.

Initial speed of the vehicle, u = 0.

The car's final speed is 27 meters per second.

Thus we have to first calculate the acceleration and then substitutes its value in the force formula

Taking time, t = 10 s

F = m a, where a represents the vehicle's acceleration, is the formula for the required force.

a= v - u / t

thus a = 27 - 0/ 10

a = 27/ 10

F = 1200 X 27 / 10

F = 3240 N.

Therefore, this is the necessary solution.

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The system that is more energy efficient is system A because it makes use of electricity to produce more results.

Energy efficiency is the use of less energy to perform the same task or produce the same result.

Energy-efficient homes and buildings use less energy to heat, cool, and run appliances and electronics, and energy-efficient manufacturing facilities use less energy to produce goods.

Energy efficiency has the following benefits:

According to this question, the following applies:

Based on the above explanation, it can be observed that system A is more energy efficient because it uses the same electricity to achieve more.

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Answer:

Below

Explanation:

Normal force will be   mg cos 15° = 1.5*9.81 cos 15°   Newtons

Downplane force will be  mg sin 15° = 1.5 * 9.81  sin 15°    N

Acceleration

F = ma

F/m = a

1.5 ( 9.81) sin 15° / 1.5   m/s^2  = a

The kinetic energy is 939.87 J.

Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. The object will be moving at a new, constant speed once the work is done because energy has been transferred to it.

A particle, an object, or a collection of particles can move because of kinetic energy, which is the force that drives motion. Kinetic energy is used by objects in motion like a person walking, a baseball being thrown, food falling from a table, and charged particles in an electric field.

Kinetic energy = 1/2mv²

Kinetic energy =  1/2×0.06×177²

Kinetic energy = 939.87 J.

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The maximum height an object will reach if it is thrown vertically upwards at 24.0 m/s will be equal to 29.35 meters.

Kinetic energy is the term used in physics to describe the force that a moving item has.

It is described as the amount of effort necessary to accelerate anybody with a particular mass from rest to a given velocity. Except for variations in speed, the body retains the kinetic energy it gains during acceleration.

As per the given information in the question,

The formula of kinetic energy is,

K.E = 1/2 mv²   (i)

The formula of gravitational potential energy is,

u = mg     (ii)

Equate equations (i) and (ii)

1/2 mv² = mgh

h = 1/2 v²/g

h = 1/2 (24)²/9.81

= 576/19.62

h = 29.35 meters.

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