A student performs an experiment to determine the molar mass of magnesium oxide. The student repeats the experiment five times and collects the following data: 40.220gmol, 40.654gmol, 40.314gmol, 40.165gmol, and 40.554gmol. What is the relative standard deviation (RSD) for this set of data?

Answers

Answer 1

The relative standard deviation for the set of data obtained by the student is 0.470%

The formula for calculating the relative standard deviation is given below as:

Relative standard deviation (RSD) = (S * 100)/x

where S stands for the standard deviation and x is the mean of the data set.

The following are the steps to calculate to determine the relative standard deviation using the given formula:

Step 1: Calculate the mean of the numbers in the data set.

mean, x = sum of numbers / number of numbers

(40.220 + 40.654 + 40.314 + 40.165 + 40.554)/5

mean = 40.381 g/mol

Step 2: Subtract the mean from each number in the data to determine the deviation for each number and then square the deviations.

(40.220 - 40.381)² = 0.0259

(40.654 - 40.381)² = 0.0745

(40.314 - 40.381)² = 0.00449

(40.165 - 40.381)² = 0.0466

(40.554 -40.381)² = 0.0299

Step 3: Sum the squared deviations.

0.0259 + 0.0745 + 0.00449 + 0.0466 + 0.0299 = 0.181

Step 4: Determine the variance by dividing the sum of the squared deviations by the total number of values.

Variance = 0.181/5 = 0.0362

Step 6: Determine the standard deviation of the data by taking square root of the variance.

Standard deviation, S = √0.0362 = 0.190

Step 7: Determine the relative standard deviation by inserting the values in the formula, (RSD) = (S * 100)/x

RSD = (0.190 * 100)/40.381

RSD = 0.470%

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