A taste test asks people from Texas and California which pasta they prefer, brand A or brand B. The table shows the results. A person is randomly selected from those tested. What is the probability that the person is from Texas, given that the person prefers Brand B? PLEASE HELP! I'll name you Brainliest if you're answer is the best!

A Taste Test Asks People From Texas And California Which Pasta They Prefer, Brand A Or Brand B. The Table

Answers

Answer 1

Answer:

A

Step-by-step explanation:

It would be A because there are 45 people in Texas that prefer brand B. There are 105 people in total that prefer brand B. 45/105 is .42857... so rounded it would be .43, therefore A. I hope this helps.

Answer 2

Answer:

A

Step-by-step explanation:


Related Questions

Which expression would produce the largest answer? Select one: a. 3(9 + 3) + 4(6 ÷ 2) b. 2(32) + 3(2 • 2) c. 12(8 ÷ 1) + 5(4 - 5) d. 15(2 + 3) - 3(1 + 3)

Answers

Answer:

C

Step-by-step explanation:

In order to solve these you have to use pemdas, which is the order for which you solve these equations from left to right.

Its, parenthesis, exponents, multiplication, division, addition, subtraction.

when using this strategy it will show that

a=48

b=76

c=91

d=63

Pimeter or area of a rectangle given one of these...
The length of a rectangle is three times its width.
If the perimeter of the rectangle is 48 cm, find its area.

Answers

Answer:

A=108 cm²

Step-by-step explanation:

length (l)=3w

perimeter=2l+2w

P=2(3w)+2w

48=6w+2w

width=48/8

w=6

l=3w=3(6)=18

l=18 cm  ,  w=6 cm

Area=l*w

A=18*6

A=108 cm²

A washer and dryer cost a total of $980. The cost of the washer is three times the cost of the dryer. Find the cost of each item.

Answers

Answer:

Washer $735

Dryer $245

Step-by-step explanation:

If x is the cost of the washer, and y is the cost of the dryer, then:

x + y = 980

x = 3y

Solve with substitution.

3y + y = 980

4y = 980

y = 245

x = 735

please help me to answer this question​

Answers

Where’s the question

Answer:

I can not see any questions

(1 point) Consider the function f(x)=2x3−9x2−60x+1 on the interval [−4,9]. Find the average or mean slope of the function on this interval. Average slope: By the Mean Value Theorem, we know there exists at least one value c in the open interval (−4,9) such that f′(c) is equal to this mean slope. List all values c that work. If there are none, enter none . Values of c:

Answers

Answer: c = 4.97 and c = -1.97

Step-by-step explanation: Mean Value Theorem states if a function f(x) is continuous on interval [a,b] and differentiable on (a,b), there is at least one value c in the interval (a<c<b) such that:

[tex]f'(c) = \frac{f(b)-f(a)}{b-a}[/tex]

So, for the function f(x) = [tex]2x^{3}-9x^{2}-60x+1[/tex] on interval [-4,9]

[tex]f'(x) = 6x^{2}-18x-60[/tex]

f(-4) = [tex]2.(-4)^{3}-9.(-4)^{2}-60.(-4)+1[/tex]

f(-4) = 113

f(9) = [tex]2.(9)^{3}-9.(9)^{2}-60.(9)+1[/tex]

f(9) = 100

Calculating average:

[tex]6c^{2}-18c-60 = \frac{100-113}{9-(-4)}[/tex]

[tex]6c^{2}-18c-60 = -1[/tex]

[tex]6c^{2}-18c-59 = 0[/tex]

Resolving through Bhaskara:

c = [tex]\frac{18+\sqrt{1740} }{12}[/tex]

c = [tex]\frac{18+41.71 }{12}[/tex] = 4.97

c = [tex]\frac{18-41.71 }{12}[/tex] = -1.97

Both values of c exist inside the interval [-4,9], so both values are mean slope: c = 4.97 and c = -1.97

The screening process for detecting a rare disease is not perfect. Researchers have developed a blood test that is considered fairly reliable. It gives a positive reaction in 94.8% of the people who have that disease. However, it erroneously gives a positive reaction in 3.3% of the people who do not have the disease. Consider the null hypothesis "the individual does not have the disease" to answer the following questions.

a. What is the probability of Type I error?
b. What is the probability of Type II error?

Answers

Answer:

Probability of Type 1 error = 0.033

Probability of type II error = 0.952

Step-by-step explanation:

H0: Individual does not have disease

H1: individual has disease

Type 1 error occurs when we fail to accept a correct null hypothesis and accept an alternate Instead

Type ii error occurs when we accept a false null hypothesis instead of the alternate hypothesis

Probability of people with disease = 98.4%

Probability of people without disease = 3.3%

1.probability of type 1 error = 3.3/100

= 0.033

2. Probability of type ii error = (1-98.4%) = 1-0.948

= 0.052

find the straight time pay $7.60 per hour x 40 hours

Answers

Answer:

The straight time pay for $ 7.60 per hour and 40 work hours per week is $ 304.

Step-by-step explanation:

Let suppose that worker is suppose to work 8 hours per day, so that he must work 5 days weekly. The straight time is the suppose work time in a week, the pay is obtained after multiplying the hourly rate by the amount of hours per week. That is:

[tex]C = \left(\$\,7,60/hour\right)\cdot (40\,hours)[/tex]

[tex]C = \$\,304[/tex]

The straight time pay for $ 7.60 per hour and 40 work hours per week is $ 304.

Determine the decision criterion for rejecting the null hypothesis in the given hypothesis​ test; i.e., describe the values of the test statistic that would result in rejection of the null hypothesis. Suppose you wish to test the claim that ​, the mean value of the differences d for a population of paired​ data, is greater than 0. Given a sample of n15 and a significance level of ​0.01, what criterion would be used for rejecting the null​ hypothesis?

Answers

Answer:

reject null hypothesis if calculated t value > 2.624

Step-by-step explanation:

n = 15

To calculate degree of freedom, n -1 = 14

The claim says ud>0

The decision rule would be to reject this null hypothesis if the test statistics turns out to be greater than the critical value.

With df =14

Confidence level = 0.01

Critical value = 2.624 (for a one tailed test)

If the t value calculated is > 2.624, we reject null hypothesis.

Using the t-distribution and it's critical values, the decision rule is:

t < 2.624: Do not reject the null hypothesis.t > 2.624: Reject the null hypothesis.

At the null hypothesis, we test if the mean is not greater than 0, that is:

[tex]H_0: \mu \leq 0[/tex]

At the alternative hypothesis, we test if the mean is greater than 0, that is:

[tex]H_1: \mu > 0[/tex].

We then have to find the critical value for a right-tailed test(test if the mean is more than a value), with 15 - 1 = 14 df and a significance level of 0.01. Using a t-distribution calculator, it is [tex]t^{\ast} = 2.624[/tex].

Hence, the decision rule is, according to the test statistic t:

t < 2.624: Do not reject the null hypothesis.t > 2.624: Reject the null hypothesis.

A similar problem is given at https://brainly.com/question/13949450

Which of the following represents "next integer after the integer n"? n + 1 n 2n

Answers

Answer:

n + 1

Step-by-step explanation:

Starting with the integer 'n,' we represent the "next integer" by n + 1.

Hayley bought a bike that was on sale with a 15% discount from the original price of $142. If there is a 6% sales tax to include after the discount, how much did Hayley pay for the bike?

Answers

Answer:

$12,78

Step-by-step explanation:

$142 × 0,15 = $21,3

$21,3 × 0,6 = $12,78

4.9x10^_8 In decimal notation

Answers

Answer:

490000000

Step-by-step explanation:

For every exponent of 10, move the decimal point one place to the right.

i will rate you brainliest

Answers

Answer:

Option (3)

Step-by-step explanation:

For a geometric progression,

[tex]a,ar,ar^{2},ar^3.........a(r)^{n-1},a(r)^n[/tex]

First term of the progression = a

Common ratio of each successive term to the previous term = r

Recursive formula for geometric progression will be,

[tex]a_1=a[/tex]

And [tex]a_{n}=a_{n-1}(r)[/tex]

Following this rule for the G.P. given in the question,

[tex]a_1=4[/tex]

[tex]a_n=-1.5a_{n-1}[/tex]

Therefore, from the recursive formula,

Common ration 'r' = -(1.5)

Option (3) will be the correct option.

PLEASE HELP ! (4/5) - 50 POINTS -

Answers

Answer:

[tex]\large \boxed{\sf A) \ 12}[/tex]

Step-by-step explanation:

Frequency of a specific data value at an interval is the number of times the data value repeats in that interval.

Cumulative frequency is found by adding each frequency to the frequency that came before it.

cStep-by-step explanation:

The greater than symbols looks like this ____________, and the less than symbol looks like?

Answers

Answer:

The greater than symbols looks like this    >    , and the less than symbol looks like? <

Answer:

Greater than symbol: >

Less than symbol: <

Greater than or equal to symbol: ≥

Less than or equal to symbol: ≤

Equal symbol: =

In this case, you are answering with the greater than symbol as well as the less than symbol.

The greater than symbols looks like this > , and the less than symbol looks like < .

Graph the following set of parametric equations on your calculator and select the matching graph.

Answers

Answer:

Graph 2

Step-by-step explanation:

As you can see the first equation is present with a negative slope, and none of the graphs have a line plotted with a negative slope, besides the second graph. That is your solution.

A regular polygon inscribed in a circle can be used to derive the formula for the area of a circle. The polygon area can be expressed in terms of the area of a triangle. Let s be the side length of the polygon, let r be the hypotenuse of the right triangle, let h be the height of the triangle, and let n be the number of sides of the regular polygon. polygon area = n(12sh) Which statement is true? As h increases, s approaches r so that rh approaches r². As r increases, h approaches r so that rh approaches r². As s increases, h approaches r so that rh approaches r². As n increases, h approaches r so that rh approaches r².

Answers

Answer:

Option (D)

Step-by-step explanation:

Formula to get the area of a regular polygon in a circle will be,

Area = [tex]n[\frac{1}{2}\times (\text{Base})\times (\text{Height})][/tex]

        = [tex]n[\frac{1}{2}\times (\text{s})\times (\text{h})][/tex]

Here 'n' is the number of sides.

If n increases, h approaches r so that 'rh' approaches r².

In other words, if the number of sides of the polygon gets increased, area of the polygon approaches the area of the circle.

Therefore, Option (4) will be the answer.

In this exercise it is necessary to have knowledge about polygons, so we have to:

Letter D

Then using the formula for the area of ​​a regular polygon we find that:

[tex]A=n(1/2*B*H)\\=n(1/2*S*H)[/tex]

So from this way we were not able to identify the option that best corresponds to this alternative.

See more about polygons at  brainly.com/question/17756657

What is the percentage of 204 over 1015, 1 over 8120, 1 over 5832, and 1 over 6?

Answers

Answer:

204/1015 (irreducible) = 20.1%

1/8120 (irreducible) = 0.01232%

1/5832 (irreducible) = 0.01715%

1/6 (irreducible) = 16.67%

Step-by-step explanation:

Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.028; confidence level: 99%; p and q unknown

Answers

Answer:

The minimum sample size is [tex]n = 2123[/tex]

Step-by-step explanation:

From the question we are told that

    The margin of error is  [tex]E = 0.028[/tex]

   

Given that the confidence level is  99% then the level of significance is evaluated as

        [tex]\alpha = 100 - 99[/tex]

        [tex]\alpha = 1 \%[/tex]

        [tex]\alpha =0.01[/tex]

Next we obtain the critical value of  [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table

   The  value is  [tex]Z_{\frac{ \alpha }{2} } = 2.58[/tex]

Now let  assume that the sample proportion is  [tex]\r p = 0.5[/tex]

  hence  [tex]\r q = 1 - \r p[/tex]

=>            [tex]\r q = 0.50[/tex]

   Generally the sample size is mathematically represented as

                [tex]n =[ \frac{Z_{\frac{ \alpha }{2} }}{ E} ]^2 * \r p * \r q[/tex]

                [tex]n =[ \frac{2.58}{ 0.028} ]^2 * 0.5 * 0.5[/tex]

              [tex]n = 2123[/tex]

A new fast-food firm predicts that the number of franchises for its products will grow at the rate dn dt = 6 t + 1 where t is the number of years, 0 ≤ t ≤ 15.

Answers

Answer:

The answer is "253"

Step-by-step explanation:

In the given- equation there is mistype error so, the correct equation and its solution can be defined as follows:

Given:

[tex]\bold{\frac{dn}{dt} = 6\sqrt{t+1}}\\[/tex]

[tex]\to dn= 6\sqrt{t+1} \ \ dt.....(a)\\\\[/tex]

integrate the above value:

[tex]\to \int dn= \int 6\sqrt{t+1} \ \ dt \\\\\to n= \frac{(6\sqrt{t+1} )^{\frac{3}{2}}}{\frac{3}{2}}+c\\\\\to n= \frac{(12\sqrt{t+1} )^{\frac{3}{2}}}{3}+c\\\\[/tex]

When the value of n=1 then t=0

[tex]\to 1= \frac{12(0+1)^{\frac{3}{2}}}{3}+c\\\\ \to 1= \frac{12(1)^{\frac{3}{2}}}{3}+c\\\\\to 1-\frac{12}{3}=c\\\\\to \frac{3-12}{3}=c\\\\\to \frac{-9}{3}=c\\\\\to c=-3\\[/tex]

so the value of  n is:

[tex]\to n= \frac{(12\sqrt{t+1} )^{\frac{3}{2}}}{3}-3\\\\[/tex]

when we put the value t= 15 then,

[tex]\to n= \frac{(12\sqrt{15+1} )^{\frac{3}{2}}}{3}-3\\\\\to n= \frac{(12\sqrt{16} )^{\frac{3}{2}}}{3}-3\\\\\to n= \frac{(12\times 64)}{3}-3\\\\\to n= (4\times 64)-3\\\\\to n= 256-3\\\\\to n= 253[/tex]

The mean area of 7 halls is 55m².If the mean of 6 of them be 58m², find the area of the seventh all.​

Answers

Answer:

Area of 7th hall = 37 m^2

Step-by-step explanation:

Total area of 7 halls = 7*55 = 385

Total area of 6 halls = 6*58 = 348

Area of 7th hall = 385-348 = 37 m^2

Answer:

The area of the seventh hall = 37m²

Step-by-step explanation:

for 6 halls

Mean area of 6 halls = 58m²

[tex]Mean\ area = \frac{sum\ of\ areas}{Number\ of\ halls} \\58\ =\ \frac{sum\ of\ areas}{6} \\sum\ of\ areas\ of\ 6\ halls\ = 58\ \times\ 6 = 348\\sum\ of\ areas\ of\ 6\ halls\ = 348[/tex]

Let the area of the 7th hall be x

The sum of the areas of 7 halls = 348 + x   - - - - - - (1)

[tex]Mean = \frac{sum\ of\ the\ areas\ of\ 7\ halls}{7} \\55 = \frac{sum\ of\ the\ areas\ of\ 7\ halls}{7} \\sum\ of\ the\ areas\ of\ 7\ halls\ = 55\ \times\ 7\ = 385\\sum\ of\ the\ areas\ of\ 7\ halls\ =\ 385 - - - - (2)[/tex]

notice that equation (1) = equation (2)

348 + x = 385

x = 385 - 348 = 37m²

Therefore, the area of the seventh hall = 37m²

Suppose we randomly selected 250 people, and on the basis of their responses to a survey we assigned them to one of two groups: high-risk group and low-risk group. We then recorded the blood pressure for the members of each group. Such data are called

Answers

Answer:

Matched or paired data

Step-by-step explanation:

In statistics the different types of study included experimental and observational with the matched or paired data.

The observational study is one in which there is no alteration in the obseravtions or any change. It is purely based on observations.

The experimental study is one in which some experiment or change is brought about to see the effects of the experiment and the results are recorded as before and after treatment etc.

The matched or paired study is one in which two or more groups are simultaneously observed , recorded to find the difference between them or other parameters which maybe useful for the differences or similarities.

Suppose that Y1, Y2,..., Yn denote a random sample of size n from a Poisson distribution with mean λ. Consider λˆ 1 = (Y1 + Y2)/2 and λˆ 2 = Y . Derive the efficiency of λˆ 1 relative to λˆ 2.

Answers

Answer:

The answer is "[tex]\bold{\frac{2}{n}}[/tex]".

Step-by-step explanation:

considering [tex]Y_1, Y_2,........, Y_n[/tex] signify a random Poisson distribution of the sample size of n which means is λ.

[tex]E(Y_i)= \lambda \ \ \ \ \ and \ \ \ \ \ Var(Y_i)= \lambda[/tex]

Let assume that,  

[tex]\hat \lambda_i = \frac{Y_1+Y_2}{2}[/tex]

multiply the above value by Var on both sides:

[tex]Var (\hat \lambda_1 )= Var(\frac{Y_1+Y_2}{2} )[/tex]

            [tex]=\frac{1}{4}(Var (Y_1)+Var (Y_2))\\\\=\frac{1}{4}(\lambda+\lambda)\\\\=\frac{1}{4}( 2\lambda)\\\\=\frac{\lambda}{2}\\[/tex]

now consider [tex]\hat \lambda_2[/tex] = [tex]\bar Y[/tex]

[tex]Var (\hat \lambda_2 )= Var(\bar Y )[/tex]

             [tex]=Var \{ \frac{\sum Y_i}{n}\}[/tex]

             [tex]=\frac{1}{n^2}\{\sum_{i}^{}Var(Y_i)\}\\\\=\frac{1}{n^2}\{ n \lambda \}\\\\=\frac{\lambda }{n}\\[/tex]

For calculating the efficiency divides the [tex]\hat \lambda_1 \ \ \ and \ \ \ \hat \lambda_2[/tex] value:

Formula:

[tex]\bold{Efficiency = \frac{Var(\lambda_2)}{Var(\lambda_1)}}[/tex]

                  [tex]=\frac{\frac{\lambda}{n}}{\frac{\lambda}{2}}\\\\= \frac{\lambda}{n} \times \frac {2} {\lambda}\\\\ \boxed{= \frac{2}{n}}[/tex]

An inequality is shown: −np − 4 ≤ 2(c − 3) Which of the following solves for n?

Answers

Answer:

[tex]\huge\boxed{n\leq\dfrac{2-2c}{p}\ \text{for}\ p<0}\\\boxed{n\geq\dfrac{2-2c}{p}\ \text{for}\ p>0}[/tex]

Step-by-step explanation:

[tex]-np-4\leq2(c-3)\qquad\text{use the distributive property}\\\\-np-4\leq2c-6\qquad\text{add 4 to both sides}\\\\-np\leq2c-2\qquad\text{change the signs}\\\\np\geq2-2c\qquad\text{divide both sides by}\ p\neq0\\\\\text{If}\ p<0,\ \text{then flip the sign of inequality}\\\boxed{n\leq\dfrac{2-2c}{p}}\\\text{If}\ p>0 ,\ \text{then}\\\boxed{n\geq\dfrac{2-2c}{p}}[/tex]

sorry to keep asking questions

Answers

Answer:

y = [tex]\sqrt[3]{x-5}[/tex]

Step-by-step explanation:

To find the inverse of any function you basically switch x and y.

function = y = x^3 + 5

Now we switch x and y

x = y^3 +5

Solve for y,

x - 5 = y^3

switch sides,

y^3 = x-5

y = [tex]\sqrt[3]{x-5}[/tex]

Answer:

[tex]\Large \boxed{{f^{-1}(x)=\sqrt[3]{x-5}}}[/tex]

Step-by-step explanation:

The function is given,

[tex]f(x)=x^3 +5[/tex]

The inverse of a function reverses the original function.

Replace f(x) with y.

[tex]y=x^3 +5[/tex]

Switch variables.

[tex]x=y^3 +5[/tex]

Solve for y to find the inverse.

Subtract 5 from both sides.

[tex]x-5=y^3[/tex]

Take the cube root of both sides.

[tex]\sqrt[3]{x-5} =y[/tex]

will rate7 you brainliest

Answers

Answer:

[tex]\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }[/tex]

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

[tex]\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)[/tex]

[tex]\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)[/tex]

[tex]\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)[/tex]

[tex]\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)[/tex]

Now, let's compute the product.

[tex]\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}[/tex]

So the correct answer is the first one.

Thank you.

What expression is equal to6 e + 3 (e-1)

Answers

Answer:

9e -3

Step-by-step explanation:

Perform the indicated multiplication:

6 e + 3 (e-1) = 6e + 3e - 3

This, in turn, simplifies to

9e -3, or 3(3e - 1).

Answer:

ANSWER: 9e-3

Step-by-step explanation:

6e+3(e−1)

As we need to simplify the above expression:

First we open the brackets :

3(e-1)=3e-33(e−1)=3e−3

Now, add it to 6e.

So, it becomes,

$$\begin{lgathered}6e+3e-3\\\\=9e-3\end{lgathered}$$

Hence, equivalent expression would be 9e-3.

which of the following not between -10 and -8

-17/2
-7
-9
-8.5​

Answers

The answer is -7 because -17/2=-8.5 and 9 and 8.5 are both in between -10 and -8

Answer:

-7

Step-by-step explanation:

This is best read on the number line.

Look at the picture.

[tex]-\dfrac{17}{2}=-8\dfrac{1}{2}=-8.5[/tex]

Determina el valor absoluto de 13 – 11|

Answers

Responder:

2

Explicación paso a paso:

El valor absoluto de una expresión es el también conocido como valor positivo devuelto por la expresión. Una expresión en un signo de módulo se conoce como valor absoluto de la expresión y dicha expresión siempre toma dos valores (tanto el valor positivo como el negativo).

Por ejemplo, el valor absoluto de x se escribe como | x | y esto puede devolver tanto + x como -x debido al signo del módulo.

Pasando a la pregunta, debemos determinar el valor absoluto de | 13-11 |. Esto significa que debemos determinar el valor positivo de la expresión como se muestra;

= | 13-11 |

= | 2 |

Este módulo de 2 puede devolver tanto +2 como -2, pero el valor absoluto solo devolverá el valor positivo, es decir, 2.

Por tanto, el valor absoluto de la expresión es 2

Need help!!!! Show work plz

Answers

Answer:

24 units²

Step-by-step explanation:

A rhombus is divided into 4 right triangles when it's two diagonals intersect at right angles. All the sides are of equal lengths.

Therefore, a simple method to use to find the area of the given rhombus is to calculate the area of one of the right triangles, and multiply by 4.

Area of right triangle = ½*base*height

Height = 3

Base = [tex]\sqrt{5^2 - 3^2} = \sqrt{16} = 4[/tex] (Pythagorean theorem)

Area of right triangle = ½*4*3 = 2*3 = 6 units²

Area of rhombus = 4(6 units²) = 24 units²

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag
the item to the trashcan. Click the trashcan to clear all your answers.
Perform the following computation with radicals. Simplify the answer.
V6 18
311
123 45
6
7
8
+
x

Answers

Question: Perform the following computation with radicals. Simplify the answer.  √6 • √8

Answer:

[tex] 4\sqrt{3} [/tex]

Step-by-step explanation:

Given, √6 • √8, to perform the computation, we would simply evaluate the radicals and try as much as possible to leave the answer in the simplest form in radicals.

Thus,

[tex] \sqrt{6}*\sqrt{8} = \sqrt{6*8} [/tex]

[tex] = \sqrt{48} [/tex]

[tex] = \sqrt{16*3} = \sqrt{16}*\sqrt{3}[/tex]

[tex] = 4\sqrt{3} [/tex]

Other Questions
Which of the following compounds is more soluble in a 0.10 M NaCN solution than in pure neutral water? Ca3(PO4)2 AgBr CaCO3 Mg(OH)2 NH4ClO4 for n prove by[tex]3 + 3 {}^{2} + 3 {}^{3} ... + 3 {}^{n} = \frac{3(3 {}^{n} - 1) }{2} [/tex]thank you Which of the following is not an example of a counterproductive cultural trait that adversely impacts a company's work climate, performance, and strategy execution initiatives? a) Heavily politicized decision-making b) The presence of incompatible, clashing subcultures c) Strictly enforced policies and conservative financial management practices d) Hostility to change e) Unethical and greed-driven behaviors What is the correct standard form of the equation of the parabola? Enter your answer below. Be sure to show each step of your work. A landscaper is designing a wall of white bricks . The pattern consists of 130 white bricks in the bottom row , 110 white bricks in the second row , and 90 white bricks in the third row . How meany white bricks will the 6th row have Find the value of x. A. 53 m B. 241 m C. 6 m D. 6+35 m what type of environment would you most likely find fish species 1? Robert: Hola. El ao pasado estuve en Nicaragua. Pepa: _________ Robert: En la Isla de Ometepe. A quin viste? Cunto compraste? Dnde estuviste? Qu hiciste? What is a categorical variable Please give me the correct answer People who identify with collservative ideals would most likely associate with which group?The Communist PartyThe Republican PartyThe Democratic PartyThe Green Party If Social Media Apps had a Rap Battle Mr. Grande lyrics 2020 Does anyone know the lyrics? Word phrase for algebraic expression 15-1.5/d The Adjacent Coins Problem Published on 2017-08-30 Consider N coins aligned in a row. Each coin is showing either heads or tails. The adjacency of these coins is the number of adjacent pairs of coins with the same side facing up. Write a program that given a non-empty zero-indexed array A consisting of N integers representing the coins, returns the maximum possible adjacency that can be obtained by reversing exactly one coin (that is, one of the coins must be reversed). Consecutive elements of array A represent consecutive coins in the row. Array A contains only 0s and/or 1s: Tatham Corporation produces a single product. The standard costs for one unit of its Clan product are as follows: Direct materials (8 pounds at $0.70 per pound) $5.60Direct labor (2 hours at $8 per hour) 16.00 Variable manufacturing overhead (2 hours at $7 per hour) 1,400Total 3,560During November Year 2, 3,500 units of Clan were produced. The costs associated with November operations were as follows: Material purchased (35,000 pounds at $0.80 per pound) 28,000Material used in production (31,500 pounds) Direct labor (7,500 hours at $7.50 per hour) 56,250Variable manufacturing overhead incurred 55,500What is the variable overhead efficiency variance for Clan for November Year 2?1. $3,500 favorable.2. $3,500 unfavorable.3. $4,000 favorable. 4. $4,000 unfavorable. Jane Cagles company wants to establish kanbans to feed a newly established work cell. The following data have been provided. How many kanbans are needed?Daily demand 750 unitsLead time 1/2 daysSafety stock 1/4 daysKanban size 25 untis Please help!Explain how changes in the dimensions of a cube dimensions affect the volume of a cube. Be specific, explaining how much the volume will change with each increase of 1 unit on the side lengths. Select the correct answer. Which is the best example of a primary source document useful in the study of history? A. a documentary with expert analysis of the event in question B. a peer-reviewed article written about the event by a respected historian C. a professorial analysis of key battlefield strategies of the event D. a journal excerpt from a person involved in the event in question Why can the 2000s be considered a neoprogressive era?O A. Progressive politicians won majorities in Congress in 2006andwon the White House in 2008.O B. With the election of Barack Obama, the United States shifted awayfrom conservative politics.OC. Progressives supported the wars that the United States wasfighting in Iraq and Afghanistan.O D. Some people believe that progressive policies of nonregulation ofbanks led to the recession in 2008. Many managers describe performance appraisal as the responsibility that they like least. Why is this so? What could be done to improve the situation?