A teacher has a 2-gallon (52 cup) container of juice. She gives each student z cup of juice. Which equation represents the amount of juice that remains, y, after x students are served?

Answer:

[tex]31y^{3} -28y^{2}[/tex]+35y

Step-by-step explanation:

Answer:

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Step-by-step explanation:

Given

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2[/tex]

Required

Solve

Start with the bracket

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ (9.1)^2-(-1.4)^2[/tex]

Evaluate all exponents

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ 82.81-1.96[/tex]

Evaluate all products

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 2.4+ 82.81-1.96[/tex]

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Answer:

division is right i hope you understand

9514 1404 393

Answer:

  Multiplication

Step-by-step explanation:

The amount Jaylene got back is 90% of the amount she spent. That value is found by multiplying 90% times $20.

Jaylene got back ...

  90% × $20 = $18

Answer:

554 executives should be surveyed.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Standard deviation of 3 hours.

This means that [tex]\sigma = 3[/tex]

The 95% level of confidence is to be used. How many executives should be surveyed?

n executives should be surveyed, and n is found with [tex]M = 0.25[/tex]. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.25 = 1.96\frac{3}{\sqrt{n}}[/tex]

[tex]0.25\sqrt{n} = 1.96*3[/tex]

[tex]\sqrt{n} = \frac{1.96*3}{0.25}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*3}{0.25})^2[/tex]

[tex]n = 553.2[/tex]

Rounding up:

554 executives should be surveyed.

Answer:

The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.

Step-by-step explanation:

Marla scored 70% on her last unit exam in her statistics class.

This means that in her statistics class, Marla got 70% of her test correct.

When Marla took the SAT exam, she scored at the 70th percentile in mathematics.

This means that on the SAT exam, graded on a curve, Marla scored better than 70% of the students.

Explain the difference in these two scores.

The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.

Answer:

False

Step-by-step explanation:

Each f(x) increases by 8 therefore this equation is a linear function. If you where to graph it would be a straight line

Hope this helped :)

Answer:

False

Step-by-step explanation:

The slope is the same between all pounts which means the function is linear.

Hope this helps!

Complete Question

ymposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use = 0.01.  

a. What is the value of the sample test statistic? (Round your answer to two decimal places.)  

b. Find the P-value of the test statistic. (Round your answer to four decimal places.)

Answer:

a) [tex]Z=2.45[/tex]

b) [tex]P Value=0.0073[/tex]

Step-by-step explanation:

From the question we are told that:

Probability of Wishart and Leach [tex]P=21.4=>0.214[/tex]

Population Size [tex]N=498[/tex]

Sample size [tex]n=12[/tex]

Therefore

[tex]P'=\frac{129}{498}[/tex]

[tex]P'=0.2590[/tex]

Generally the Null and Alternative Hypothesis is mathematically given by

[tex]H_0:P=0.214[/tex]

[tex]H_a:=P>0.214[/tex]

Test Statistics

[tex]Z=\frac{P'-P}{\sqrt{\frac{P(1-P)}{n}}}[/tex]

[tex]Z=\frac{0.2590-0.214}{\sqrt{\frac{0.214(1-0.214)}{498}}}[/tex]

[tex]Z=2.45[/tex]

Therefore P Value is given as

[tex]P Value =P(Z\geq 2.45)[/tex]

[tex]P Value =1-P(Z\leq 2.45)[/tex]

[tex]P Value =1-0.99268525[/tex]

[tex]P Value=0.0073[/tex]

Answer:

z(max) =  2996.13  $

x₁  = 968      x₂  =  430       ( quantities of regular and Decaf coffee respectevely)

Total quantity of BN = 898 pounds

Total quantity of CM =  500 pounds

Step-by-step explanation:

Cost of the beans

Brazilian natural   =  Price market + 10 %    =  0.47 + 0.047  

BN  Cost   = 0.517 $/lb

Clombian Mild      =  Price market + 10 %    =  0.62  +  0.062

CM Cost   =  0.682  $/lb

Composition of the coffee blend

Regular coffee     0.75 BN  +  0.25 CM

De Caf   coffee     0.40 BN + 0.60  CM

PRICES

Regular Roman  =  3.60  $

Decaf                   =  4.40  $

Production costs:

Regular Roman  =  0.80  $/lb

Decaf                   =  1.05  $/lb

Packaging costs:   0.25  $/Lb       both

Profit  =  Price  -  cost

Profit  of regular coffee  =  3.60 - 0.80 - 0.25 -Cost of bean

for regular coffee cost of BN + CM

BN   is :   0.75*BN cost  = 0.75*0.517  =  0.38775       and

CM  is : 0.25*0.682   =   0.1705

Profit  of regular coffee  =  1.99175  $

Profit for Decaf coffee  =  4.4 - 1.05 - 0.25 - ( 0.517*0.4 + 0.6*0.682)

Profit for Decaf coffee  =  4.4  - 1.30 - 0.616

Profit for Decaf coffee  =  2.484  $

Let´s call  x₁  pounds of regular coffee   and  x₂   pounds of Decaf coffee then:

 Objective Function is:  

z  =  1.99175*x₁  +  2.484*x₂      to maximize

Subject to:

Availability of beans for 1000 pounds of Regular coffee means:

750 pounds of BN  +  250 pounds of CM

Availability of beans for 500 pounds of Decaf coffee means

200 pounds of BN  +   300 pounds of CM

Then   750 + 200  =  900 pounds of BN

And     250 + 300 =  550  pounds of CM

Availability of beans for 1000 pounds of Decaf  coffee correspond to

0.75 *x₁  +  0.40*x₂  ≤ 900

Availability of beans for 500 pounds of Regular  coffee correspond to

0.25*x₁  +  0.60*x₂  ≤ 500

Then the model is:

z  =  1.99175*x₁  +  2.484*x₂      to maximize

Subject to:

0.75 *x₁  +  0.40*x₂  ≤ 900

0.25*x₁  +  0.60*x₂  ≤ 500

General constraints  x₁ ≥ 0      x₂ ≥   0  both integers

After 6 iterations optimal solution  ( maximum z) is

z(max) =  2996.13  $

x₁  = 968      x₂  =  430  

x₁   and  x₂  are quantities of  Regular and Decaf coffee respectively, to find out quantities of Brazilian Natural and Colombian Mild

we proceed as follows

Regular coffee is :  0.75*968 =   726 pounds of BN

Decaf coffee is :      0.40*430 =   172  pounds of BN

Total quantity of BN = 898 pounds

Regular coffee is :  0.25*968   =  242 pounds of CM

Decaf coffee is :  0.6*430  =  258 pounds of CM

Total quantity of CM =  500 pounds

Answer:

(1) Ordinal

(2) Such data should not be used for calculations such as an average.

Step-by-step explanation:

Given

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

[tex]Average = 1.3[/tex]

Solving (a): The level of measurement

When observations are presented in ranks such as:

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

The level of measurement of such observation is ordinal

Solving (b): What is wrong with the computation?

Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.

Hence, (a) is correct

Answer:

linear function

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The graph is a straight line, so it's a linear function.

Answer: B

Answer:

350

Step-by-step explanation:

400- 80 ( 20% discount)

=320+30(loss)

=350

Step-by-step explanation:

so  the equation in standard form that models the given scenario is

2x + 3y = 24

Answer:

AB IS THE ANSWER !!!!!!!!!!

Answer: AB

Step-by-step explanation:

Hi! I don't know if you need help anymore ,but here you go!

Because BC=ED, I asume that AE=AB

Answer:

60 marbles in total

Step-by-step explanation:

Find how many marbles there are in total by dividing 42 by 0.7:

42/0.7

= 60

So, there are 60 marbles in total

Answer:

r = 4.1231055

Step-by-step explanation:

So to do this, you need to find the distance between the two points:

(-7,1) and (1,3).

To do this, the distance or diameter (d) is equal to:

d = sqrt ((x2-x1)^2 + (y2-y1)^2)

In this case:

d = sqrt( (1 - (-7))^2 + (3 - 1)^2 )

d = sqrt( 8^2 + 2^2)

d = sqrt( 64 + 4)

d = sqrt( 68 )

The radius is half of the diameter, so:

r = 1/2 * d

r = 1/2 * sqrt( 68 )

r~ 4.1231055

Answer:

y = 5x + 1

Step-by-step explanation:

Given the coordinate points (0,1) and (5,0)

First, get the slope

Slope m =(0-1)/5-0

m = -1/5

Since the required line is perpendicular, then the required slope is;

M = -1/(-1/5)

M = 5

Since 1the y intecept id (0,1) i.e. 1

Required equation is y = mx+b

y = 5x + 1

This gives the required equation

Note that the coordinate (0,1) was used instead os (0,0)

Answer:

36

Step-by-step explanation:

10-3=7+2=9

4×9=36

36 is the answer

Answer:

56.5 degrees

Step-by-step explanation:

Because complementary angles are when their sum is 90, you get the equation:

P + Q = 90

Since Q is 33.5,

P + 33.5 = 90

Subtracting 33.5 from both sides,

P = 56.5

Answer:

[tex] \large{ \tt{❀ \: m \: \angle \: NML= m \: \angle \:QML + m \: \angle \: NMQ}}[/tex]

[tex] \large{ \tt{⤇m \: \angle \:NML= 115 \degree + 28 \degree }}[/tex]

[tex] \boxed{ \large{ \tt{⤇ \: m \: \angle \:NML = 143 \degree }}}[/tex]

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

$3.22 per square feet

Step-by-step explanation:

To solve, I usually set up an equation:

sq ft  = 12 1/2 = 1

 $        40.21     x

Then, use cross multiplication.

(12 1/2)x=40.21

Divide both sides by 12 1/2 or 12.5

x = 3.2168

Round to the hundredths place [because we're dealing with money]

$3.22

I hope this helps!

Answer:

3.22 per sq ft

Step-by-step explanation:

Take the total cost and divide by the amount of tiles

40.21 / 12.5

3.2168 per sq ft

Rounding to the nearest cent

3.22 per sq ft

Answer:

is 22

Step-by-step explanation:

Answer:

It doesn't have a slope?

Step-by-step explanation:

Knowing that the slope equation is y2-y1/x2-x1

9-4       5

----- = ------   = 0

4-4       0

this means that the slope is 0...

Answer:

ya the equation divides y as a function of x

Answer:

10 hours

Step-by-step explanation:

ok so we know he is getting payed $20 + $7 every hour so what i would do is keep the multiply the 7 till you get 70 so thats 7x10=70 and 70+20=90 so he worked for 10 hours last week :)  i hope this helps, i tried my best to explain it

Answer:

yes I look this problem in this figure

Answer:

58.80

Step-by-step explanation:

84 x .7(70%) =58.80

Answer:

1. -6x + 14 < -28

6x<42

x<7

2.  3x + 28 < 25

3x < -3

x<-1

Hope This Helps!!!

Answer:

v=-6 or 4

Step-by-step explanation:

Answer:

the answer would be 5

Step-by-step explanation:

have to do the question multiply add and divide to find your answer

Answer:

The numerical values of the circumference and area of the circle are equal.

Answer:

No, a quadrilateral with the given vertices is not  an isosceles trapezoid.

Step-by-step explanation:

We are given that

A(3,3), B(5,3), C(8,1), D(1,1)

Slope formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Slope of AB=[tex]\frac{3-3}{5-3}=0[/tex]

Slope of BC=[tex]\frac{1-3}{8-5}=\frac{-2}{3}[/tex]

Slope of CD=[tex]\frac{1-1}{1-8}=0[/tex]

Slope of AD=[tex]\frac{1-3}{1-3}=1[/tex]

Slope of AB=Slope of CD

When slopes of two lines are equal then the lines are parallel.

Therefore, AB is parallel to CD.

When one pair of quadrilateral is parallel then the  quadrilateral is trapezoid.

[tex]\implies [/tex]ABCD is a trapezoid.

Distance formula:

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the formula

Length of BC=[tex]\sqrt{(8-5)^2+(1-3)^2}[/tex]

Length of BC=[tex]\sqrt{9+4}=\sqrt{13}[/tex] units

Length of AD=[tex]\sqrt{(1-3)^2+(1-3)^2}[/tex]

Length of AD=[tex]\sqrt{4+4}=2\sqrt{2}[/tex]

Length of AD is not equal to length of BC.

Hence, trapezoid is not an isosceles trapezoid.