A tour group is going sea diving. Sea level is O feet. The ocean
floor is -18 feet. One diver is already at -11 feet. The tour guide
is keeping watch on the deck at 5 feet above sea level directly
above the diver. What is the distance from the tour guide to the
diver? Draw and label a number line to justify your answer.​

Answer:

C.) 7.14 in²

Step-by-step explanation:

The figure is made up of a square and a circle. The circle is divided in half and each piece is set on one side of the square. This means that the diameter of the circle is equal to the length of the sides of the square, 2 inches.

The area of the square can be found by multiplying length times the width:

[tex]2*2=4[/tex]

The area of the square is 4 inches, and since we multiplied two lengths, we square the value:

A=4in²

Now find the area of the circle using the formula:

[tex]A=\pi r^2[/tex]

The radius is half of the diameter, so the radius is 1. Insert values and solve:

[tex]A=\pi *1^2\\\\A=\pi *1\\\\A=\pi[/tex]

The area of the circle is equal to π. Add the values together:

[tex]4+\pi =7.14[/tex]

The area of the figure is 7.14 in²

:Done

Answer:

Q1 is the 25th percentile

Step-by-step explanation:

Quartiles are known to be one-fourth of an entity, that is, 1/4th with the whole evaluating to 1. The numerator cannot exceed four, as the division compares an item in an entity to the whole of the entity or sample.

Percentiles represents a whole entity as a 100 with the symbol "%" which denote its use.

The first quartile is 25th percentile, the second is the 50th percentile, the third is the 75th percentile while the fourth quartile which is 4/4 is the 100th percentile mark.

Answer:

Step-by-step explanation:

Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.

On expanding the left hand side of the expression we have;

= (8x² −15x)−(x² −27x)

Open the paranthesis

= 8x² −15x−x²+27x

collect the like terms

= 8x²−x²+27x −15x

=  7x²+12x

Comparing the resulting expression with ax²+bx

7x²+12x =  ax²+bx

7x² = ax²

a = 7

Also;

12x = bx

b =12

The value of b - a = 12 - 7

b -a = 5

Hence the value of b-a is equivalent to 5

The value of b minus a is 5

Since the expression is

[tex](8x^2 -15x)-(x^2 -27x) = ax^2 +bx[/tex]

Here we have to expand the left-hand side of the expression so it should be like

[tex]= (8x^2 -15x)-(x^2 -27x)\\\\= 8x^2 -15x-x^2+27x\\\\= 8x^2-x^2+27x -15x\\\\= 7x^2+12x[/tex]

Now

[tex]7x^2+12x = ax^2+bx\\\\7x^2 = ax^2[/tex]

a = 7

Also;

12x = bx

b =12

So,

The value of b - a = 12 - 7

b -a = 5

Hence the value of b-a should be 5

Learn more about equation here: https://brainly.com/question/24540444

We need to simplify the left side first.

On the left side, all the terms can be combined.

So 4w - 3w + 2w is 3w.

So we have 3w = 24.

Next, dividing both sides by 3, we have w = 8.

So our solution is w = 8.

Answer

[tex] \boxed{ \huge{ \bold{ \sf{ \boxed{w = 8}}}}}[/tex]

Step by step explanation

[tex] \sf{4w - 3w + 2w = 24}[/tex]

Collect like terms

⇒[tex] \sf{w + 2w = 24}[/tex]

⇒[tex] \sf{3w = 24}[/tex]

Divide both sides of the equation by 3

⇒[tex] \sf{ \frac{3w}{3} = \frac{24}{3} }[/tex]

Calculate

⇒[tex] \sf{w = 8}[/tex]

Hope I helped!

Best regards!!

===========================================

Explanation:

Refer to the diagram below.

In order for triangle TOP to be isosceles, the missing side x must be either 5 or 7. This way we have exactly two sides that are the same length.

--------

If TP = 5, then the value of y could be either 5 or 11 to ensure that triangle TIP has exactly two sides the same length.

If TP = 7, then y = 7 or y = 11 for similar reasons.

--------

Therefore, the possible lengths for segment TO are 5, 7, and 11.

Answer:

7, 11

Step-by-step explanation:

its right- trust me-

Answer:

[tex]\huge \boxed{14}[/tex]

Step-by-step explanation:

Q is a point on the line segment PR.

PQ = 3

QR = 11

PR = PQ + QR

PR = 3 + 11 = 14

Answer:

[tex]\huge\boxed{PR = 14}[/tex]

Step-by-step explanation:

QR = 11

PQ = 3

Given that Q is on line segmant PR

So,

PR = PQ + QR

PR = 3 + 11

PR = 14

Step-by-step explanation:

Hi, there!!!

Here, the question is about the volume of cone,

given that,

diameter = 12m

radius of a circle= 12m/2= 6m

height (h)=9 m

now, we have,

volume of a cone= 1/3×pi× r^2×h

or, v= 1/3×3.14×(6)^2×9

After simplifying it we get,

v= 339.12 m^3

Hope it helps....

Answer:

A. 260

Step-by-step explanation:

Answer:

square root 260

Step-by-step explanation:

On mine it is D. but the answer is the square root of 260

Answer:

[tex]\frac{64}{27}[/tex] cm³

Step-by-step explanation:

The volume (V) of the prism is calculated as

V = lbh ( l is length, b is breadth and h is height ), thus

V = [tex]\frac{4}{3}[/tex] × [tex]\frac{4}{3}[/tex] × [tex]\frac{4}{3}[/tex] = [tex]\frac{4^3}{3^3}[/tex] = [tex]\frac{64}{27}[/tex] cm³

Answer:

Step-by-step explanation:

I am more than happy to answer anymore questions. If needed an explanation I can put one in the comments.

Answer:

5

Step-by-step explanation:

|3 - 5 + 7|

= |-2 + 7|

= |5| = 5

Answer:

The correct answer would be 5.

Step-by-step explanation:

Answer:

75 cm

Step-by-step explanation:

∅=90° , r = 21 cm

Arc length= (2πr∅)/360

=(2π×21×90)/360

=33 cm

Perimeter= arc length + 2(radius)

=33+2(21)

=33 + 42

= 75 cm

Answer:

The value of the derivative at x = 9 is -25

Step-by-step explanation:

Here in this question, we are told to find the derivative of the given equation at the point where x = 9

What we need to do here is simply, differentiate f(x), then substitute that value x = 9 into the differentiated equation

In notation form, what we are to find is f’(9)

So;

f(x) = -2x^2 + 11x

f’(x) = -4x + 11

So therefore;

f’(9) = -4(9) + 11

f’(9) = -36 + 11

f’(9) = 11-36

f’(9) = -25

Answer:

16%

Step-by-step explanation:

rental charge per year = $80

rental charge at the rate $8 per year = 8 * 12 = 96

the increased amount = 96 - 80 = 16

% = 16 / 100 = 16%

Answer:

EF = 2 units

Step-by-step explanation:

Given:

Line segment DF and point E on it.

DF = 11 unit

DE = 9 Unit

Find:

EF

Computation:

We know that,

DF = DE + EF

11 = 9 + EF

EF = 11-9

EF = 2 units

Answer:

628 [tex]cm^{3}[/tex]

Step-by-step explanation:

Since the formula to find the volume of a cylinder is [tex]\pi r^{2}[/tex]h, we just need to fill things in.

Since the radius is 5 and the height is 8 and we know that pi=3.14, our new equation is:

3.14*5^2*8.

5*5=25. Now we simplify.

3.14 * 25 * 8

78.5 * 8

628 [tex]cm^{3}[/tex]

Hope this helps!! <3 :)

Answer:

628.32

Step-by-step explanation: googled it lol

Answer:

grade point average​ (GPA) as a weighted mean = 3.14

Yes, student makes the Dean's list.

Step-by-step explanation:

Since the data is not given I will explain the question with a relevant example:

For example

Data:

Students grades are:  A, C, B, A, D

The corresponding number of credit hours: 3, 3, 3, 4, 1

The grading system assigns quality points to letter grades as​:

A = 4

B = 3

C = 2

D = 1

F = 0

To find:

grade point average​ (GPA) as a weighted mean

If the​ Dean's list requires a GPA of 3.00 or​ greater, did this student make the​ Dean's list?

Solution:

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]

Here

Using the earned grades of A, C, B, A, D and corresponding quality points to these letter grades we get:

A = 4

C = 2

B = 3

A = 4

D = 1

So the values in x[tex]_{i}[/tex] are:

x

4

2

3

4

1

Now the number of credit hours are represented as weights w[tex]_{i}[/tex] :

w

3

3

3

4

1

In order to calculate weighted mean first multiply x[tex]_{i}[/tex] with w[tex]_{i}[/tex]

x[tex]_{i}[/tex] w[tex]_{i}[/tex]

4 * 3 = 12

2 * 3 = 6

3 * 3 = 9

4 * 4 = 16

1 * 1 = 1

The sum of x[tex]_{i}[/tex] w[tex]_{i}[/tex] is :

Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] = 12 + 6 + 9 + 16 + 1 = 44

Σx[tex]_{i}[/tex] w[tex]_{i}[/tex]  =  44

Now compute the sum of w[tex]_{i}[/tex]

Σw[tex]_{i}[/tex] = 3 + 3 + 3 + 4 + 1 = 14

Σw[tex]_{i}[/tex] = 14

Putting the values in the weighted mean formula:

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]

                           =  44 / 14

                           = 3.1429

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex] = 3.14

Since the​ Dean's list requires a GPA of 3.00 or​ greater and the grade point average​ (GPA) as a weighted mean of the student is 3.14 so the student makes the​ Dean's list because his/her GPA is higher than 3.00

Answer:

False

Step-by-step explanation:

Because the question says you pick a different shirt on Tuesday than on Monday, that means you have one less shirt you can select, so the event is dependent.

Answer:

3

= 15/5

= [tex]\sqrt[3]{27}[/tex]

= 1.5*2

= 3/1

= 3*1

= 3¹

= 1/3⁻¹

= 3⁴ / 3³

= 3⁵ * 3⁻⁴

Answer:

x = 3

Step-by-step explanation:

Given

5 - (4 - 3x) = 10 ← distribute the terms in the parenthesis by - 1

5 - 4 + 3x = 10, that is

1 + 3x = 10 ( subtract 1 from both sides )

3x = 9 ( divide both sides by 3 )

x = 3

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Answer:.

Step-by-step explanation:.

Answer: [tex]y-1=\dfrac32(x+3)[/tex]

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = [tex]\dfrac{d-b}{c-a}[/tex]

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) =[tex]\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}[/tex]

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope =  is given by

[tex](y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)[/tex]

Required equation: [tex]y-1=\dfrac32(x+3)[/tex]

Hello, we know that for a and b real numbers

[tex]a^2-b^2=(a-b)(a+b)[/tex]

So,

[tex](2a-b)^2-(a-2b)^2=(2a-b-a+2b)(2a-b+a-2b)\\\\=(a+b)(3a-3b)\\\\\boxed{=3(a+b)(a-b)}[/tex]

Thank you.

Answer:

D

Step-by-step explanation:

-1/2x > 6 (you have to flip the sign when you multiply or divide by negative

x < -12

Answer:

2

Step-by-step explanation:

Let Ishan’s age equal an unknown quantity we’ll call “x”.

An age 4 times Ishan’s would be 4 times x, written “4x”.

An age 6 years older than Ishan’s would be written “x+6”.

Now, through the magic of algebra, we can write an equation: 4x = x+6 . This means that “four times Ishan’s age is equal to his age plus six.”

The magic continues: you can subtract an”x” from each side of the equation. You can subtract any quantity from either side, but subtracting”x” will leave 6 on the right and “3x” on the left: 3x = 6.

Divide both sides by the same quantity: 3.

This will give you x =2. This indicates Ishan’s age is 2.

Answer:

Ishaan is 2 years old.

Step-by-step explanation:

We can create a systems of equations for this, assuming b is Ben's age and i is Ishaan's age.

[tex]b = 4i[/tex]

[tex]b = i+6[/tex]

Let's solve via substitution.

[tex]4i = i+6[/tex]

Subtract i from both sides:

[tex]3i = 6[/tex]

Divide both sides by 3:

[tex]i = 2[/tex]

So Ishaan is 2 years old. Ben is:

[tex]4(2) = 8[/tex] years old.

Hope this helped!

==================================================

Work Shown

We'll be using these vector properties

To get the following

-2u + v = -2*(-1, 5) + (2,7)

-2u + v = (-2*(-1), -2*5) + (2,7) .... apply rule 2

-2u + v = (2, -10) + (2, 7)

-2u + v = (2+2, -10+7) .... use rule 1

-2u + v = (4, -3)

Answer:

Step-by-step explanation:

Given,

Cost price of 25 kg of vegetables ( CP ) = 25 × 20

= Rs 500

Loss amount = Rs 50

Selling price ( SP ) = ?

Loss percent = ?

Now, let's find the loss percent :

[tex] \mathsf{ \frac{loss}{cost \: price} \times 100\%}[/tex]

[tex] \mathsf{ = \frac{50}{500} \times 100\%}[/tex]

[tex] \mathsf{ = 10\%}[/tex]

Loss % = 10 %

Now, let's find the selling price:

[tex] \mathsf{ \frac{CP(100 - l\%)}{100} }[/tex]

[tex] \mathsf{ = \frac{500(100 - 10)}{100}} [/tex]

[tex] \mathsf{ = \frac{500 \times 90}{100} }[/tex]

[tex] \mathsf{ = \frac{45000}{100} }[/tex]

[tex] \mathsf{= 450}[/tex]

Hope I helped!

Best regards!

Hi there! :)

Answer:

[tex]\huge\boxed{A = 119.44 cm^{2} }[/tex]

To find the area of the shaded region, we will need to find the areas of both the rectangle and the circle:

Rectangle: A = l × w

A = 11 × 12

A = 132 cm²

Circle: A = πr²  (Let π = 3.14)

A = π(2)²

A = 4π

A ≈12.56 cm²

Subtract the area of the circle from the area of the rectangle:

132 - 12.56 = 119.44 cm².

Answer:

10 cm is the answer because 30÷3 angles

Answer:

If an event is affected by previous events then it is a dependent event, while if an event is not affected by the previous event then it is an independent event.

Since we have replaced the card that we first drew from the deck, it wont affect the event of pulling a card second time.

So, we can say that it is an example of independent event.

Answer:

  PQRS is a parallelogram with right-angle corners

Step-by-step explanation:

We know that the midsegment of a triangle is parallel to the base.

  QR is the midsegment of triangle BCD, so is parallel to BD.

  SP is the midsegment of triangle DAB, so is parallel to BD.

QR and SP are both parallel to BD, so are parallel to each other.

  RS is the midsegment of triangle CAD, so is parallel to AC.

  PQ is the midsegment of triangle ABC, so is parallel to AC.

RS and PQ are both parallel to AC, so are parallel to each other.

__

We have shown that opposite sides of PQRS are parallel to each other, so the figure is at least a parallelogram.

__

By virtue of the congruence of corresponding angles where a transversal crosses parallel lines, each of the so-far named lines can be shown to be perpendicular to any of the lines it meets.* Hence the figure PQRS must be a parallelogram with right angles, a rectangle.

_____

* Transversal BD crosses PQ, AC, and RS at right angles. Hence, transversals RS and PQ cross QR, BD, and SP at right angles. That is, the angles at corners P, Q, R, and S of the parallelogram are right angles.