A toy car travels down a sloping ramp at constant speed. toy car Which statement about
the forces acting on the car is correct?

A There are no forces acting on the car vertically.

B There is no resultant force acting on the car.

C There is no gravitational force acting on the car.

D There is no frictional force acting on the car.

A Toy Car Travels Down A Sloping Ramp At Constant Speed. Toy Car Which Statement About The Forces Acting

Answers

Answer 1

Answer:

D There is no frictional force acting on the car.

Explanation:

There isnt any friction acting on the car while its going down.


Related Questions

The _____________ experiences a temperature increase primarily due to the absorption of gamma rays and X-rays.

Answers

Answer:

The thermosphere experiences a temperature increase primarily due to the absorption of gamma-rays and X-rays.

4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?

Answers

Answer:

A.)a=44.57m/s

B.)f=38,909.61

C.)f=666.4

Explanation:

A.) A=v/t 26.3/0.590=44.57

B.) 873kg x 44.57= 38,909.61

C.) 68kg x 9.8=666.4

which wave has a higher frequency and why?

Answers

Explanation:

the figure in the left side has higher frequency.

because it has more nos. of wave in 1sec.

What symbols are these?

Answers

Answer:

the bottom one is wollsiegel

What’s the mass of the continent?

Answers

Answer:

Assume that the north american continent can be respanterd by a slab of rock 4000 km on a side and 30 km deep and that the rock

iam help for youthankscommentflowing

How fast is an object going if it travels from San Diego to Anaheim in 1.25 hours (hr)? The distance from San Diego to Anaheim is 93 miles (mi).

a) 74.4 mi/hr

b) 116.25 mi/hr

c) 0.013 mi/hr

d) 84.25 mi/hr

e) None of the answers

Answers

Answer:

74.4 mph

Explanation:

Since we have the distance in miles and the time it took in hours, we can divide the two to get miles per hour.

speed = mi/hr

speed = 93/1.25

speed = 74.4 mph

someone throws a rubber ball vertically upward from the roof of a building 8.2m in height. the ball rises, then falls.it just misses the edge of the roof, and strikes the ground.if the ball is in the air for 6.2s, what was its initial velocity?(disregard air resistance. a=-g=-10m/s²

Answers

Answer:

H = V t - 1/2 g t^2         V and g are in different directions

-8.2 = V * 6.2 - 1/2 * 10 * 6.2*2 = 6.2 V - 192.2

V = 184 / 6.2 = 29.7 m/s

Check: find time for ball to return to zero height

0 = 29.7 T - 5 T^2

T = 29.7 / 5 = 5.94 sec

The ball must have fallen 8.2 m in (6.2 - 5.94) sec = .26 sec

S = 29.7 * .26 + 5 * .26^2 = 8.1

Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, this gun accelerates a 5.6-kg projectile from rest to a speed of 3.5 × 103 m/s. The net force accelerating the projectile is 2.5 × 105 N. How much time is required for the projectile to come up to speed?

Answers

Answer:

7.84 s

Explanation:

Ok, one step at a time. We know the mass of the projectile, we know the force. Acceleration is easily obtained from Newton second law:

[tex]\vec F = m\vec a[/tex][tex]2.5\times 10^5 = 5.6a \rightarrow a = (2.5/5.6) \times 10^5 = 4.46 \times 10^4 ms^-^2[/tex].

At this point, we know the acceleration, we know initial and final velocity, we can time the ammount of time it took to get there.

[tex]v= v_0 +at \rightarrow 3.5\times10^3 = 0 + 4.46\times10^4 t\\t= \frac{3.5\times10^3}{4.46\times10^4} = 7.84 s[/tex]

Alejandro Kirk is the catcher for the Blue Jays’ baseball team. He exerts a forward force on the 0.145-kg baseball to bring it to rest from a speed of 38.2 m/s. During the process, his hand recoils a distance of 0.135 m.
Determine is the acceleration of the ball.
Determine the force applied by Alejandro.

Answers

The kinematics and Newton's second law allow to find the results for the questions about the motion of the ball are:

The acceleration is: a = 5.4 10³ m / s² The force is: F = 7.84 10² N

Given parameters

Mass of the ball m = 0.145 kg Ball starts speed vo = 38.2 m / s Setback distance x = 0.135 m

To find

Acceleration The force

Kinematics studies the movement of bodies, looking for relationships between the position, speed and acceleration of bodies.

         v² = v₀² - 2 ax

Wher vo es la initial veloicity, a the acceleration y x is the distance,

When the ball stops the velocity is zero.

         0 = v₀² - 2ax

         a = [tex]\frac{v_o^2}{2x}[/tex]  

Let's calculate

         a = [tex]\frac{38.2^2}{2 \ 0.135}[/tex]  

         a = 5.4 10³ m / s²

Newton's second law establishes a relationship between force, mass, and acceleration of the body.

             F = ma

             F = 0.145 5.4 10³

             F = 7.84 10² N

In conclusion using kinematics and Newton's second law we can find the results for the questions about the motion of the ball are:

The acceleration is: a = 5.4 10³ m / s² The force is: F = 7.84 10² N

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what is the molecular formula for the hydrocarbon in the mass spectrum above?

Answers

What is the structure of a hydrocarbon that has $\mathrm{M}^{+}=120$ in its mass spectrum and has the following $1 \mathrm{H}$ NMR spectrum? 7.25 $\delta(5 \mathrm{H}, \text { broad singlet); } 2.90 \delta(1 \mathrm{H}, \text { septet, } J=7 \mathrm{Hz}) ; 1.22 \delta(6 \mathrm{H},\text { doublet, }$ $J=7 \mathrm{Hz})$

The wave height is equal to twice the _____.wave period wave height wave amplitude wave velocity wavelength

Answers

The wave height is equal to twice the amplitude of the wave.

The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.

The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.

Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.

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Analyze the effects on a passenger riding in a car traveling at
50 km/h that collides head-on with a solid object.

Answers

Without:

The passenger will get seriously injuredColliding with the windshield at 50km/hCould result in death

With safety:

The seatbelt holds tge passengers body back so they dont collide with anythingTheir head is cushioned by the airbagThe passenger might get minor injuries but nothing serious will happen

What happens if you drop a chicken wing from the top of the Eiffel Tower

Answers

Answer:

I think it will brake or squashed

A) infrared energy
B) microwave energy
C) radio wave energy

Answers

Answer:

Infrared energy

Explanation:

Answer:

A) infrared energy

Explanation:

Without friction, what is the mass of an ball accelerating at 1.8 m/sec2 to which an
an unbalanced force of 42 Newtons has been applied?
A 75.60 kg
B 00.04 kg
C 23.33 kg
D 43.80 kg

Answers

Answer:

23.33 kg

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]

We have the final answer as

23.33 kg

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.

Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².

F= 42 kg*m/s² a= 1.8 m/s²

Substitute the values into the formula.

[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]

The units of meters per second squared cancel.

[tex]\frac {42 \ kg}{1.8 } =m[/tex]

[tex]23.3333333 \ kg=m[/tex]

Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.

[tex]23.33 \ kg \approx m[/tex]

The mass of the ball is approximately 23.33 kilograms.

1. When a 50,000 kg rocket blasts off there is a large force that acts on the rocket at the moment
of take off. In 0.137 seconds, the rocket suddenly has traveled 4.2 meters. What force from
the rocket engines caused the acceleration? (Hint: first find acceleration.)

Answers

Hi there!

We can begin by calculating the acceleration using the kinematic equation:

d = vit + 1/2at²

Since the rocket starts from rest, we can rewrite this as:

d = 1/2at²

Plug in given values:

4.2 = 1/2a(0.137²) ⇒ a = 447.55 m/s²

Now, we can use Newton's Second Law to find the appropriate force:

∑F = m · a

∑F = 50,000 · 447.55 = 22,377,500 N

can someone sent some gravity questions

Answers

What do you mean ???

Answer:

can gravity from waves

Explanation:

yes gravity can froms way

What is the best reference point for the car that is not in motion

Answers

Answer:

A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.

Explanation:

when light enters water, it bends. what does the amount of bending depend on?

Answers

Answer:

the change of speed!

Explanation:

if light speeds up or slow down more it bend more

Bella wants to know which mode of transportation is the fastest for getting from her home to the grocery store. She can drive her car, ride her bike, walk, or charter a helicopter.
Independent variable
Dependent variable
Controlled variables
Hypothesis

Answers

Based on the question, the following applies:

Independent variable: Time Dependent variable: Mode of transportationControlled variable: Distance traveledHypothesis: IF Bella charters a helicopter, THEN she will get to the grocery store faster.

VARIABLES IN AN EXPERIMENT:

The following are definitions of some variables in an experiment:

Independent variable in an experiment is the variable that is altered or changed by the experimenter. Dependent variable is the variable that is measured or recorded in an experiment. Controlled variable is the variable that is kept constant or unchanged throughout the experiment.

According to this question, Bella wants to know which mode of transportation is the fastest for getting from her home to the grocery store. The following are the variables in this experiment:

Independent variable: Time Dependent variable: Mode of transportationControlled variable: Distance traveledHypothesis: IF Bella charters a helicopter, THEN she will get to the grocery store faster.

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A particular roller coaster has a mass of 3500 kg, a height of 4.0, and a velocity of 12m/s. What is the potential energy? If needed, use g=10.m/s^2

Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Gravitational Potential Energy of an object is calculated by formula ~

[tex] \large\boxed{\sf P = mgh}[/tex]

where,

m = mass of the object = 3500 kg

g = Acceleration due to gravity = 12 m/s²

h = height attained by the object = 4 m

Now, let's calculate its potential energy ~

[tex]3500 \times 10 \times 4[/tex]

[tex]140000 \: \: joules[/tex]

[tex]140 \: \: kj[/tex]

Answer:

Potential Energy of an object is calculated by formula:

Potential Energy (P.E)=m×g×h

Where,

m=mass of bodyg=acceleration due to gravityh=height from the earth surface

Now, let's solve the question.

Given,

mass(m)=3500 kgheight (h)=4mvelocity (v)=10m/s²

Now,

We know that,

Potential Energy (P.E)=mgh

[tex] = 3500 \times 10 \times 4[/tex]

[tex] = 3500 0\times 4[/tex]

[tex] =140000 joules [/tex]

[tex]\mathfrak{\blue{DisneyPrincess29}}[/tex]

Which of the following is NOT true of a hotspot?

Answers

Given what we know about hotspots and their characteristics, we can confirm that the option that is false regarding hotspots is "A. Hotspots are constantly moving forming chains of volcanoes".

In regards to the study of geology, we refer to hotspots as spots in an oceanic mantle where magma located below causes them to become intensely hot. This heat forces magma and therefore the mantle itself upwards as a tectonic plate moves across the spot, and therefore results in the formation of volcanic chains. Some very popular examples of volcanoes and volcanic islands formed by this method include:

Yellowstone National ParkHawaiiThe country of Iceland

Despite the other options being true, option A is false given that hotspots are stationary elements of the oceanic mantle. Although some scientists believe that there is evidence of the movement of hotspots, this movement is slow enough to not be taken into account.

This question was answered in regards to the complete question found online which states:

Which of the following is NOT TRUE about hotspots? a. Hotspots are constantly moving forming chains of volcanoes.

b. Hotspots are stationary.

c. Hotspots form volcanic island arcs

d. Hotspots lie along an oceanic plate

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Estimate under what set of conditions it is possible, despite the spherical shape of the working electrode, to use linear diffusion equations to theoretically predict the current vs voltage curve expected in this experiment.

Answers

When the experimental measurements diverge at very low values of the voltages. When the ratio of current to saturated current is very small. That is, i/I less than or equal to 1/100. When there is a finite current at Voltage

V = 0

Diffusion will have influence on current - voltage curve in the working electrode which is ionization detector.

The estimation under set of conditions that is possible, despite the spherical shape of the working electrode, to use linear diffusion equations to theoretically predict the current vs voltage curve expected in this experiment will be:

When the experimental measurements diverge at very low values of the voltageswhen the ratio of current to saturated current is very small. That is, i/I less than or equal to 1/100When there is a finite current at Voltage V = 0

Where

i = electric current

I = saturated current

V = voltage supplied

The curve expected will therefore give exponential curve from positive to negative domain because of the diffusion of ions from different directions

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Which of toby's answers is a correct description of what happens when a 1-kg cart traveling at 1 m/s collides inelastically with another 1-kg cart at rest?.

Answers

Answer:

hi I don't know sorry sorry forgive me

Explanation:

sorry

. Quỹ đạo chuyển động của một vật là

Answers

Answer:

you are very kind Po lang

how do i do this question in science?

Answers

simple subtract and ummmmmm.....

pls pls pls help i need to know the correct answer and why it’s correct, thanks in advance

What is the relationship between power, work, and time?
A
As the amount of time increases,
power and work both increase.
B
As the amount of time increases,
power and work both decrease.
С
As the amount of time increases,
power increases and work is not affected. D. As the amount of time increases power decreases and work is not affected.

Answers

Answer:

it's ans is D because all three are wrong

a bus increase its velocity from 30m/s to 45m/s and covers 300m distance. Find the time​

Answers

Answer:

3.5 m/s²

Hope this helps, have a nice day/night! :D

PLS HELP ASAP it's just 2 questions and they are multiple choice!

Answers

It’s the first option heat factories (A)

Describe the steps in solving the problem below.
A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of +4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of +8 m/s. Calculate the velocity of the red cart after the collision. ;)


Answers

The velocity of the red cart after the collision is 2 m/s

From the law of conservation of momentum, initial momentum of system = final momentum of system.

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.

Substituting the values of the variables into the equation, we have,

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄

4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s

16 kgm/s + 0 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s - 8 kgm/s =  (4 kg)v₃

(4 kg)v₃ = 8 kgm/s

Divide both sides by 4 kg, we have

v₃ = 8 kgm/s ÷ 4 kg

v₃ = 2 m/s

The velocity of the red cart after the collision is 2 m/s.

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